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    Mechanics of Materials II

    UET, Taxila

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    References:

    - Strength and fracture of engineering

    solids. David K. Felbeck & A. G. Atkins,Prentice Hall (1995)

    ISBN: 9780138561130

    - Mechanics of materials (An Introductioto the Mechanics of Elastic

    nd Plastic Deformation of Solids andtructural Materials, E. J. Hearn,

    utterworth (1997) ISBN 0750632658

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    How Materials Carry Load Basic modes of loading amaterial are:

    Tension,

    compression

    and shear

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    Tension Compression Shear

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    Definition of Stress:

    Loads applied on amaterial which are

    distributed over asurface.

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    For example, the pointload shown in the

    following figure mightactually be a uniformlydistributed load that hasbeen replaced by itsequivalent point load.

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    P

    A

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    Another Definition of stress

    Stress is the loadapplied per unit area

    of the surface it isapplied on.

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    Normal stress

    Normal stress is the stressnormal to a surface and isdenoted by the symbol

    "" (sigma). In the abovefigure the normal stress is

    uniform over the surfaceof the bar and is givenby:

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    Normal Stress Equation

    A

    P=

    Where:

    P is the normal load &

    A is the area

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    Shear Stress

    Shear stress is the

    stress tangent to asurface.

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    If in the following figurethe shear stress (tau)that results in the shear

    load V is uniformlydistributed over thesurface, then the shear

    stress can be calculatedby dividing the shear forceby the area it is appliedon.

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    Shear Stress Equation

    AV=

    Where:

    V is the shear load &

    Ais the area

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    V

    A

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    Units of Stresses

    The units of stress arethe units of load

    divided by the units ofarea.

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    In the SI system the unitof stress is "Pa"

    and in the U.S. system it is"Psi".

    Pa and Psi are related tothe basic units throughfollowing relations:

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    Pa & Psi Equations

    KsiPsi

    in

    lbPsi

    MPaPam

    NPa

    110

    1

    11

    1101

    11

    3

    2

    6

    2

    ==

    ==

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    Pressure gauge (Same units as stress)

    http://www.answers.com/main/Record2?a=NR&url=http%3A%2F%2Fcommons.wikimedia.org%2Fwiki%2FImage%3APsidial.jpg
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    Conversion

    1 Pa = 145.04106

    psi

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    Basic modes of deformation

    Basic modes of deformation of a materialare:

    Extension,Contraction &

    shearing

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    Material element can beextended, compressed, orsheared. The following

    figure shows how thesquare section to the left

    changes its shape duringextension, contraction andshearing.

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    Extension Contraction Shearing

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    Definition of Strain:

    Strain is the wayengineers represent

    the distortion of abody.

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    Another definition

    strain is thegeometrical expression

    of deformation causedby the action of stress

    on a physical body.

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    Axial strain

    Axial strain (normalstrain) in a bar is a

    measure of theextension of a bar per

    unit length of the barbefore deformation.

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    The following figureshows a bar of initial

    length lo that isextended by theapplication of a load

    to the length l

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    Representation of strain

    lo

    l

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    Axial StrainThe axial strain, denoted by

    (epsilon), in a

    homogeneously deformingbar is calculated by dividingthe amount the bar extendsby its initial length.

    Strain Equation

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    Strain Equation

    This yield the equation:

    lll

    =

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    Positive and negative strains

    A positive axial strainrepresents extension and

    a negative axial strainrepresents a contraction.Strain has no units since itis one length divided byanother length.

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    Shear Strain

    Shear strain, denoted by (gamma), is a measure of howthe angle between orthogonallines drawn on an undeformedbody changes with

    deformation. In the followingfigure the square has beensheared into a parallelogram.

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    Shear Strain

    1h

    u

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    Equation of Shear Strain

    The shear strain is calculated from theequation:

    hu

    =

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    As can be seen from the followingfigure, the shear strain is equal to thetangent of the change in angle or thetwo orthogonal sides.

    h

    u

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    Another Equation of shear strain

    h

    u== )tan(

    Th diff b t

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    The difference between and becomes less and

    less as the angle (inradians) becomes small.

    This is since the tangent ofan angle, given in radians,

    can be approximated bythe angle for small values

    of the angle.

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    In most structuralmaterials, the shearing is

    small and we can use theapproximation

    1

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    Tensile behavior different

    materials:In a typical tensile test one

    tries to induce uniformextension of the gage

    section of a tensilespecimen.

    Th ti f th

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    The gage section of the

    tensile specimen isnormally of uniform

    rectangular or circularcross-section.

    The following figureshows a typical dog-

    bone sample P

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    Gage length

    P

    P

    P

    P

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    The two ends are used forfixing into the grips, whichapply the load. As can be

    seen from the free-bodydiagram to the right, the

    load in the gage section isthe same as the load appliedby the grips.

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    Using extensometers to measure the

    change of length in the gage sectionand a load cells to measure the loadapplied by the grips on the sample one

    calculates the axial strain and normalstress (knowing the initial gage lengthand cross-sectional area of the gage

    section).

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    The result is a stress-strain diagram, a

    diagram of how stress is changing inthe sample as a function of the strainfor the given loading. A typical stress-

    strain diagram for a mild steel is shownbelow.

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    Mild Steel Stress-Strain Curve

    Yield stress, y

    Ultimate stress, u

    Stress,

    Strain,

    The different regions of the area response

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    The different regions of the area response

    denoted by their characteristics as follows

    Yield stress, y

    Ultimate stress, u

    Stress,

    Strain,

    12

    34 5

    1. Linear elastic: region of proportional elastic loading2. Nonlinear elastic: up to yield3. Perfect plasticity: plastic flow at constant load4. Strain hardening: plastic flow with the increase of stress

    5. Necking: localization of deformation and rupture

    B i l D il b h i

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    Brittle versus Ductile behavior

    Brittle materials fail at small strains and

    in tension. Examples of such materialsare glass, cast iron, and ceramics.Ductile materials fail at large strains

    and in shear. Examples of ductilematerials are mild steel, aluminum andrubber.

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    The ductility of a material is

    characterized by the strain at which thematerial fails. An alternate measure isthe percent reduction in cross-sectional

    area at failure.

    Different types of response:

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    Different types of response:

    Elastic response:

    If the loading and unloading stress-strain plot overlap each other theresponse is elastic. The response of

    steel below the yield stress isconsidered to be elastic.

    El ti R (Li & N li )

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    Elastic Response (Linear & Non-linear)

    LinearElastic

    NonlinearElastic

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    After loading beyond the yield point,

    the material no longer unloads alongthe loading path. There is a permanentstretch in the sample after unloading.

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    The strain associated with this

    permanent extension is called the

    plastic strain p (on the figure).

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    As shown in the figure, the unloading

    path is parallel to the initial linearelastic loading path.

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    Unloading

    Loading

    Most plastics when loaded continue to

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    Most plastics when loaded continue todeform over time even without increasingthe load. This continues extension under

    constant referred to as creep. If held atconstant strain, the load required to holdthe strain decreases with time.

    R l ti

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    Relaxation

    The decrease in load over time at

    constant stretch is referred to asrelaxation.

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    Bearing Stress:

    Even though bearing stress is not afundamental type of stress, it is auseful concept for the design ofconnections in which one part pushesagainst another. The compressive load

    divided by a characteristic areaperpendicular to it yields the bearing

    stress which is denoted by b.

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    Therefore, in form, the bearing stress is

    no different from the compressive axialstress and is given by

    A

    Fb =

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    Where:

    F is the compressive load and

    A is a characteristic area perpendicularto it.

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    F

    p

    F

    F F

    F

    F

    F

    F

    d

    t

    t

    t

    t

    Cylindrical bolt or rivet

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    For example, if two plates are

    connected by a bolt or rivet as shown,each plate pushes against the side ofthe bolt with load F. It is not clear what

    the contact area between the bolt andthe plate is since it depends on the sizeof the bolt and the shape of the

    deformation that results.

    Also, the distribution of the load on the

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    ,bolt varies from point to point, but as afirst approximation one can use the

    shown rectangle of area A=td to get arepresentative bearing stress for thebolt as

    Fb =