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Memory System

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Computer Architecture Design

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Page 1: Memory 1

Memory System

Page 2: Memory 1

•Smaller access time, greater cost per bit

•Greater capacity, smaller cost per bit

•Greater capacity, greater access time

Page 3: Memory 1

Characteristics

� Location� Capacity� Unit of transfer� Access method� Performance� Physical type� Physical characteristics� Organisation

Page 4: Memory 1

Location

� CPU� Internal (main)� External (secondary)

Page 5: Memory 1

Capacity

� Word size� The natural unit of organization

� Number of words� or Bytes

Page 6: Memory 1

Unit of Transfer

� Internal� Usually governed by data bus width

� External� Usually a block which is much larger than a word

� Addressable unit� Smallest location which can be uniquely

addressed

Page 7: Memory 1

Access Methods (1)

� Sequential� Start at the beginning and read through in order� Access time depends on location of data and previous

location� e.g. tape

� Direct� Individual blocks have unique address� Access is by jumping to vicinity plus sequential search� Access time depends on location and previous location� e.g. disk

Page 8: Memory 1

Access Methods (2)

� Random� Individual addresses identify locations exactly� Access time is independent of location or previous access� e.g. RAM

� Associative� Data is located by a comparison with contents of a portion

of the store� Access time is independent of location or previous access� e.g. cache

Page 9: Memory 1

Performance

� Access time� Time between presenting the address and getting

the valid data

� Memory Cycle time� Time may be required for the memory to “recover”

before next access� Cycle time is access + recovery

� Transfer Rate� Rate at which data can be moved

Page 10: Memory 1

Physical Types

� Semiconductor� RAM

� Magnetic� Disk & Tape

� Optical� CD & DVD

Page 11: Memory 1

Physical Characteristics

� Decay� Volatility/non-volatile� Erasable/nonerasable� Power consumption

Page 12: Memory 1

Organisation

� Physical arrangement of bits into words� e.g. interleaved

Page 13: Memory 1

Memory Hierarchy - Diagram

Page 14: Memory 1
Page 15: Memory 1
Page 16: Memory 1
Page 17: Memory 1

The Bottom Line

� How much?� Capacity

� How fast?� Time is money

� How expensive?

Page 18: Memory 1

Memory Hierarchy

� Registers� In CPU

� Internal or Main memory� May include one or more levels of cache� “RAM”

� External memory� Backing store

Page 19: Memory 1

Hierarchy List

� Registers� L1 Cache� L2 Cache� Main memory� Disk cache� Disk� Optical� Tape

Page 20: Memory 1

So you want fast?

� It is possible to build a computer which uses only static RAM

� This would be very fast� This would need no cache� This would cost a very large amount

Page 21: Memory 1

Locality of Reference

� During the course of the execution of a program, memory references tend to cluster

� e.g. loops

Page 22: Memory 1

Cache

� Small amount of fast memory� Sits between normal main memory and CPU� May be located on CPU chip or module

Page 23: Memory 1

Cache/Main Memory Structure

Page 24: Memory 1

Cache operation - overview

� CPU requests contents of memory location� Check cache for this data� If present, get from cache (fast)� If not present, read required block from main

memory to cache� Then deliver from cache to CPU� Cache includes tags to identify which block of

main memory is in each cache slot

Page 25: Memory 1

Cache Design

� Size� Mapping Function� Replacement Algorithm� Write Policy� Block Size� Number of Caches

Page 26: Memory 1

Size does matter

� Cost� More cache is expensive

� Speed� More cache is faster (up to a point)� Checking cache for data takes time

Page 27: Memory 1

Typical Cache Organization

Page 28: Memory 1

Cache Read Operation

Page 29: Memory 1

Mapping Function� It is the correspondence between the main

memory blocks and those in the cache memory.

� When the cache is full and the processor references a location not in the cache:� A block from the cache should be removed (or

returned to memory)� The cache control hardware uses replacement

algorithm to select this block

� The required block is transferred from the memory to the cache (in the place of the recently removed block).

Page 30: Memory 1

Cache Management

� To find:� Which blocks in the main memory are currently

existing in the cache.� The position of the blocks in the cache.

� In case of blocks replacement, it is required to select the block (Victim) that will be removed from the cache.

� Memory Mapping:� Direct Mapping� Associative Mapping� Set-Associative Mapping

Page 31: Memory 1

Cache Management

� Assume that:� The memory and the cache are divided into blocks.

Each block has 16 words.

� The cache is 2 K Words (2 * 1024 = 2048 Words)� The cache consists of 128 blocks (2048/16)

� The memory is 64 K Words (64 * 1024 = 65536 Words)� The memory consists of 4096 blocks (65536/16)

Page 32: Memory 1

Direct mapping address structure

Tag s-r Line or Slot r Word w

8 14 2

� 24 bit address� 2 bit word identifier (4 byte block)� 22 bit block identifier

� 8 bit tag (=22-14)� 14 bit slot or line

� No two blocks in the same line have the same Tag field� Check contents of cache by finding line and checking Tag

Page 33: Memory 1

Direct Mapping

� Each block of main memory maps to only one cache line� i.e. if a block is in cache, it must be in one specific

place

� Address is in two parts� Least Significant w bits identify unique word� Most Significant s bits specify one memory

block� The MSBs are split into a cache line field r

and a tag of s-r (most significant)

Page 34: Memory 1

Direct Mapping

Page 35: Memory 1

Main memory blocks 0, 128, 256, … to block 0 of cache

Main memory blocks 1, 129, 257, … to block 1 of cache

Main memory blocks 2, 130, 258, … to block 2 of cache

Main memory blocks 127, 255, 383, … to block 127 of cache

Direct Mapping

Page 36: Memory 1

Tag = 0

Tag = 1

Tag = 31

64 K memory

Memory has 32 Tags

Each Tag has 128 Blocks

Each Block has 16 words

216 Memory

Memory has 2 5 Tags

Each Tag has 2 7 Blocks

Each Block has 2 4 words

5-bit 7-bit 4-bit

Tag Block word

16-bit memory address

Direct Mapping

Page 37: Memory 1

Direct Mapping

Cache Line Table� Cache line Main Memory blocks held� 0 0, m, 2m, 3m…2s-m� 1 1,m+1, 2m+1…2s-m+1

� m-1 m-1, 2m-1,3m-1…2s-1

Page 38: Memory 1

Direct Mapping Summary

� Address length = (s + w) bits� Number of addressable units = 2s+w words or bytes� Block size = line size = 2w words or bytes� Number of blocks in main memory = 2s+ w/2w = 2s

� Number of lines in cache = m = 2r

� Size of tag = (s – r) bits

Page 39: Memory 1

Direct Mapping pros & cons

� Simple� Inexpensive� Fixed location for given block

� If a program accesses 2 blocks that map to the same line repeatedly, cache misses are very high

Page 40: Memory 1

Tag 22 bitWord2 bit

Associative Mapping

Address Structure

� 22 bit tag stored with each 32 bit block of data� Compare tag field with tag entry in cache to check for hit� Least significant 2 bits of address identify which 16 bit

word is required from 32 bit data block� e.g.

� Address Tag Data Cache line� FFFFFC FFFFFC 24682468 3FFF

Page 41: Memory 1

Associative Mapping

� A main memory block can load into any line of cache

� Memory address is interpreted as tag and word

� Tag uniquely identifies block of memory� Every line’s tag is examined for a match� Cache searching gets expensive

Page 42: Memory 1

tagtag

tag

Cache

Main memory

Block 0

Block 1

Block i

Block 4095

Block 0Block 1

Block 127

Main memory address

Associative Mapping

Any block of main memory can be placed in any block position in the cache

Tags are searched

“associatively”to find the

referenced block

Page 43: Memory 1

64 K memory

Memory has 4096 Tags

Each Tag has 1 Blocks

Each Block has 16 words

216 Memory

Memory has 2 12 Tags

Each Tag has 2 0 Blocks

Each Block has 2 4 words

12-bit 4-bit

Tag word

16-bit memory address

Block 0

Block 1

Block i

Block 4095

Associative Mapping

Page 44: Memory 1

Associative Mapping Summary

� Address length = (s + w) bits� Number of addressable units = 2s+w words or bytes� Block size = line size = 2w words or bytes� Number of blocks in main memory = 2s+ w/2w = 2s

� Number of lines in cache = undetermined� Size of tag = s bits

Page 45: Memory 1

Set Associative Mapping

� Cache is divided into a number of sets� Each set contains a number of lines� A given block maps to any line in a given set

� e.g. Block B can be in any line of set i

� e.g. 2 lines per set� 2 way associative mapping� A given block can be in one of 2 lines in only one

set

Page 46: Memory 1

tagtagtag

Cache

Main memory

Block 0

Block 1

Block i

Block 4095

Block 0Block 1Block 2

Main memory address

Set-Associative Mapping

Assume two blocks per set

Blocks 0 – 64 – 128 – … - 4032 can map into set 0

Blocks 1 – 65 – 129 – … - 4033 can map into set 1

Blocks 63 – 127 – 191 – … - 4095 can map into set 63

tag

tag

tag

Block 3

Block 100

Block 127

Set 0

Set 1

Set 50

Set 63

Page 47: Memory 1

64 K memory

Memory has 64 Tags

Each set has 2 Blocks; Cache has 64 Sets

Each Block has 16 words

216 Memory

Memory has 2 6 Tags

Cache has 2 6 Sets

Each Block has 2 4 words

tagtagtag

Cache

Block 0Block 1Block 2

tag

tag

tag

Block 3

Block 100

Block 127

Set 0

Set 1

Set 50

Set 63

6-bit 6-bit 4-bit

Tag Set word

16-bit memory address

Set-Associative Mapping

Page 48: Memory 1

Set Associative Mapping

Example� 13 bit set number� Block number in main memory is modulo 213

� 000000, 00A000, 00B000, 00C000 … map to same set

Page 49: Memory 1

Set Associative Mapping Summary

� Address length = (s + w) bits� Number of addressable units = 2s+w words or bytes� Block size = line size = 2w words or bytes� Number of blocks in main memory = 2d

� Number of lines in set = k� Number of sets = v = 2d

� Number of lines in cache = kv = k * 2d

� Size of tag = (s – d) bits

Page 50: Memory 1

Set-Associative Mapping

� The number of blocks in each set may increase or decrease.

� If the number of blocks in each set is 4, then the set field is 5-bit (cache is divided into 32 sets), the block field is 7-bit, and the word field is 4-bit.

� If the number of blocks in each set is 8, then the set field is 4-bit (cache is divided into 16 sets), the block field is 8-bit, and the word field is 4-bit.

� If the number of blocks in each set is 128, then the set field is 0-bit (cache is one set), the block field is 12-bit, and the word field is 4-bit. [Associative mapping]

� If the number of blocks in each set is 1, then the set field is 7-bit (cache is divided into 128 sets), the block field is 5-bit, and the word field is 4-bit. [Direct mapping]

Page 51: Memory 1

� Valid Bit:

� When the memory is updated from the Disk through the Direct Memory Access (DMA), the cache memory is bypassed

� In this case the contents of some blocks in the cache differ from the corresponding blocks in memory. these blocks are marked with 0 value in valid bit.

Mapping Function

Page 52: Memory 1

� Valid Bit:

� If a block in the cache and the cache applies the write-back protocol; the block in the cache may differ than its corresponding block in the memory

� If the memory tries to send this block of data to Disk through DMA

� The dirty bits in this block is first transferred to the memory to update its content, then the block is send to the Disk.

Mapping Function

Page 53: Memory 1

Replacement Algorithms (1)

Direct mapping� No choice� Each block only maps to one line� Replace that line

Page 54: Memory 1

Replacement Algorithms (2)

Associative & Set Associative

� Hardware implemented algorithm (speed)� First in first out (FIFO)

� replace block that has been in cache longest

� Least frequently used� replace block which has had fewest hits

� Random

Page 55: Memory 1

Write Policy

� Must not overwrite a cache block unless main memory is up to date

� Multiple CPUs may have individual caches� I/O may address main memory directly

Page 56: Memory 1

Write through

� All writes go to main memory as well as cache

� Multiple CPUs can monitor main memory traffic to keep local (to CPU) cache up to date

� Lots of traffic� Slows down writes

Page 57: Memory 1

Write back

� Updates initially made in cache only� Update bit for cache slot is set when update

occurs� If block is to be replaced, write to main

memory only if update bit is set� I/O must access main memory through cache� N.B. 15% of memory references are writes