metabolism of chos
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Metabolism of Carbohydrates
Difficulty Level : One
QNo: 1
QStem:The heptose ketose sugar formed in HMP shunt is :
Ch1: Glucoheptose
Ch2: Sedoheptose
Ch3: Sedoheptulose
Ch4: Mannoheptose
Reference: Harper's Biochemsitry 24th Edition. PP : 207
Explanation: The answer is 'C' :
A molecule of Sedoheptulose-7-P and one of Glyceraldehyde-3-P are formed
by the Transketolase reaction in HMP shunt.
Transketolase (with the help of coenzyme thiamine pyrophosphate, TPP)
transfers a two-carbon unit comprising carbon 1 and 2 of a ketose to thealdehyde carbon of an aldose sugar. Therefore, it converts an Aldose
(Ribose-5-P) to a ketose with two carbon more (Sedoheptulose-7-P).
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QNo: 2
QStem:Glucose yields how many ATPs by Glycolysis (1 NADH = 3 ATP)?
Ch1: 5
Ch2: 11
Ch3: 8
Ch4: 10
Reference: Chawla and Tarek, PP: 230
Explanation: The answer is 'C' :
Oxidation of Glucose by Glycolysis yields :
y One NADH at Gl-3-P DH step.y Two ATPs are generated by substrate level phosphorylation at
phosphoglycerokinase & Pyruvate kinase steps.
y Since one glucose gives rise to two Gl-3-P, net yield is 2 NADH and4 ATP.
y One NADH can roughly be considered to yield 3 ATPs, therefore 2NADH = 6 ATP.Total = 10 ATP.
Two ATPs are utilized for phosphorylation of glu and fru-6-P.
Therefore net yield is 10 - 2 = 8 ATP
QNo: 3
QStem:Glycolysis of Glucose, under anaerobic conditions, yields how many ATPs?
Ch1: 2
Ch2: 6
Ch3: 8
Ch4: 10
Reference: Chawla and Tarek, PP: 230
Explanation: The answer is 'A' :
Under Anaerobic conditions, NADH cannot yield ATP as Electron transportchain is blocked. Therefore, Pyruvate is converted to Lactate by using one ( x
2 ) NADH.
Net yield = 2 ATP only.
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QNo: 4
QStem:Which one of the following is an intermediate in HMP shunt
Ch1: D-Ribulose
Ch2: D-Arabinose
Ch3: D-Xylose
Ch4: D-Lyxose
Reference: Harpers Biochemistry 26th Edition, pp: 164.
Explanation: The answer is 'A' :
Ribulose-5-P is the first pentose sugar of HMP shunt generated by oxidative
decarboxylation of 6-Phosphogluconate with the generation of the second
molecule of NADPH.
The only potent distractant in the options is Xylose, but it is Xylulose-5-P
that is formed from Ribulose and not Xylose-5-P.
QNo: 86 QTopic: Metabolism of CHODifficulty Level: 2
QStem:Galactose is phosphorylated by galactokinase to form
Ch1: Galactose-6-phosphate
Ch2: Galactose-1,6-diphosphate
Ch3: Galactose-1-phosphate
Ch4: All of the above
Reference: Lehninger's Biochemistry. 5th Edition. PP : 536
Explanation: The answer is 'C' :
D-Galactose, a product of hydrolysis of the disaccharide
lactose (milk sugar), passes in the blood from the intestine to the liver,
where it is first
phosphorylated at C-1, at the expense of ATP, by the
enzyme galactokinase:
Galactose + ATP --> galactose 1-phosphate + ADP
QNo: 79 QTopic: Metabolism of CHODifficulty Level: 2
QStem:The reaction involved in conversion of succinyl CoA tosuccinate in TCA cycle
requires
Ch1: CDP
Ch2: ADP
Ch3: GDP
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Ch4: NADP+
Reference: Biochemistry by Lubert Stryer. 3rd Edition. PP : 376
Explanation: The answer is 'C' :
The enzyme Succinyl CoA synthetase mediates this substrate level
phosphorylation reaction.
The cleavage of the thioester bond of Succinyl CoA is coupled to the
phosphorylation of GDP.
QNo: 70 QTopic: Metabolism of CHODifficulty Level: 2
QStem:Hexokinase has a high affinity for glucose than
Ch1: Fructokinase
Ch2: Galactokinase
Ch3: GlucokinaseCh4: All of the above
Reference: Biochemistry by Lubert Stryer, 3rd Edition. PP : 361
Explanation: The answer is 'D' :
The students would be tempted to answer 'C' Glucokinase. But this is a
distractor.
All the enzymes in the options have lesser affinity (if not zero) than that of
hexokinase.
QNo: 65QTopic: Metabolism of CHODifficulty Level: 2
QStem:Cyclic AMP is formed from ATP by the enzyme adenylate
cyclase which is
activated by the hormone
Ch1: Insulin
Ch2: Epinephrine
Ch3: Testosterone
Ch4: Progesterone
Reference: Chatterjea and Shinde, 5th Edition, 2005. PP : 289
Explanation: The answer is 'B' :
Epinephrine and Glucagon stimulate adenylate cyclase on the plasma
membrane and enhance the synthesis of cAMP.
cAMP is the second messenger for these hormones and stimulates a
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cascade of kinase enzymes that result in phosphorylation of a number of
proteins.
The phosphorylation / dephosphorylation is a major mechanism of
QNo: 66QTopic: Metabolism of CHODifficulty Level: 2
QStem:The synthesis of adenylate cyclase is increased by :
Ch1: Thyroid hormones
Ch2: Epinepherine
Ch3: Prolactin
Ch4: Follicle Stimulating Hormone
Reference: .
Explanation: The Answer is 'A' :
Thyroid hormones stimulate the synthesis of a number of proteins includingadenylate cyclase.
Epinephrine, although acts through stimulation of adenylate cyclase, does
not increase its synthesis.
QNo: 15QTopic: Metabolism of CHO Difficulty Level: 2
QStem:Which one of the following is an intermediate in HMP shunt
Ch1: D-Ribulose
Ch2: D-Arabinose
Ch3: D-Xylose
Ch4: D-Lyxose
Reference: .
Explanation: The answer is 'A' :
Ribulose-5-P is the first pentose sugar of HMP shunt generated by oxidative
decarboxylation of 6-Phosphogluconate with the generation of the second
molecule of NADPH.
The only potent distractant in the options is Xylose, but it is Xylulose-5-P
that is formed from Ribulose and not Xylose-5-P.
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QNo: 9 QTopic: Metabolism of CHO Difficulty Level: 3
QStem:Which of the following can be said to act as a carrier ofCitric acid cylce
Ch1: ACETYL CoA
Ch2: a-KETOGLUTARATE
Ch3: MALATE
Ch4: OXALOACETATE
Reference: .
Explanation: The answer is 'D' :
Oxaloacetic acid (OAA) can be called as the carrier of TCA cycle because
Acetyl CoA enters the cycle after combining with OAA to from Citric acid.
At the end of each cycle, OAA is regenerated to accept a new Acetyl CoA
unit.
The pace of TCA cycle is also dependent upon the availability and
QNo: 42QTopic: Metabolism of CHODifficulty Level: 3
QStem:Which of the following glycolytic enzymes is inhibited by
fluoride:Ch1: Glyceraldehyde 3-P dehydrogenase
Ch2: Phospholglycerate kinase
Ch3: Enolase
Ch4: Fructose1-6 diphosphate
Reference: Chatterjea and Shinde, Sixth Edition PP : 272
Explanation: The answer is 'C' :
Fluoride inhibits ENOLASE enzyme that carries out the formation of
Phosphoenol pyruvate from 2-Phosphoglycerate during glycolysis.
Fluoride is added to the vials for collection of blood samples for estimation
of blood glucose. Fluoride inhibits Enolase and hence stops the utilisation of
glucose by RBCs in the blood samples. In the absence of fluoride glucose
estimation could give false low values.
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QNo: 43QTopic: Metabolism of CHODifficulty Level: 3
QStem:Pompe's disease is characterized by the deficiencey of :
Ch1: Glucose-6-phosphatase
Ch2: Debranching enzyme
Ch3: Acid maltase
Ch4: Liver phosphorylase
Reference: Chatterjea and Shinde, Sixth Edition PP : 294
Explanation: The answer is 'C' :
Pompe's disease is caused by the inherited deficiency of Acid maltase,
lysosomal enzyme that hydrolyses oligosaccharides.
Inheritence : Autosomal recessive.
'Normal' type of glycogen is deposited in excess in heart, liver, smooth and
striated muscles.
Cardiomegali and muscle hypotonia are the features and cardiac failure is
the cause of death.
QNo: 45QTopic: Metabolism of CHODifficulty Level: 3
QStem:All of the following antibodies are Beta-cytolytic (Pancreatic
beta cells),
except:
Ch1: Insulin Ab
Ch2: Islet cell Ab
Ch3: Glutamic acid decarboxylase Ab
Ch4: Insulin receptor Ab
Reference: .
Explanation: The answer is 'D' :
Type II diabetes mellitus is now recognised as an autosomal disease. A
number of antibodies have been implicated in the progressive destruction of
beta cells leading to DM.
Insulin antibodies which attach the insulin granules and deplete the beta
cells, Islet cell antibodies attach the membrane antigens of islet cells.
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Similarly Glutamic acid decarboxylase antobodies that attach the lysosomal
enzyme are also cytolytic and are being used as markers for developing DM.
Insulin receptor antibodies bind with the Insulin receptors in peripheral
tissues and make them unavailable to Insulin leading to insulin resistance.
These antibodies donot bind to the beta cells.
QNo: 46QTopic: Metabolism of CHODifficulty Level: 3
QStem:Which of the following enzyme carries out an anapleurotic
reaction:
Ch1: Pyruvate kinase
Ch2: Pyruvate carboxylase
Ch3: Pyruvate carboxykinase
Ch4: Pyruvate dehydrogenaseReference: Lehninger's Biochemistry, 5th Edition. PP : 617
Explanation: The answer is 'B' :
Anapleurotic reactions or 'Filling-up' reactions are those that provide
intermediates of the TCA cycle and hence increase the pace of the cycle.
The major enzymes that carryout anapleurotic reactions are :
a) Malic enzyme - produces Malate from Pyruuvate
b) Pyruvate carboxylase - produces Oxaloacetate from Pyruvate
c) Transaminases that pour amino acid carbon skeleton into the cycle.
QNo: 50QTopic: Metabolism of CHODifficulty Level: 3
QStem:Lumber spinal fluid glucose concentration ischaracteristically low in patients
with:
Ch1: Meningioma
Ch2: Cerebral haemorrhage
Ch3: Multiple sclerosis
Ch4: Coccal Meningitis
Reference: Chatterjea and Shinde, Sixth Edition PP : 639
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Explanation: The answer is 'D' :
Bacterial infection in the CSF lowers the glucose concentration as the
bacterial utilise the glucose.
All the other options in the question are non-infectious disease conditions.
QNo: 61QTopic: Metabolism of CHODifficulty Level: 4
QStem:The GIT absorption of glucose is interferred by the
deficiency of:
Ch1: Vitamin A
Ch2: Thiamine
Ch3: Biotin
Ch4: InsulinReference: Chatterjea and Shinde, 5th Edition, 2005. PP : 264
Explanation: The answer is 'B' :
The absorption of glucose from GIT is diminished in case of deficiency of a
number of B-complex vitamins e.g. Thiamine, Pyridoxine and pentothenic
acid.
QNo: 62QTopic: Metabolism of CHODifficulty Level: 4
QStem:Glucose absorption from intestine may be decreased in caseof severe -
Ch1: Oedema
Ch2: Nephritis
Ch3: Rickets
Ch4: Osteomyelitis
Reference: Chatterjea and Shinde, 5th Edition, 2005. PP : 264
Explanation: The answer is 'A' :
The transporters responsible for absorption of glucose need sufficient
concentration of Sodium for the abswortion of glucose since Sodium is Co-
transported along with Glucose.
Oedema, most often than not, is associated with low sodium concentrations
therefore low sodium availability can affect the glucose absorption.
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QNo: 63QTopic: Metabolism of CHODifficulty Level: 3
QStem:Glycogen synthetase activity is depressed by :
Ch1: Glucose
Ch2: InsulinCh3: Cyclic AMP
Ch4: Citrate
Reference: Chatterjea and Shinde, 5th Edition, 2005. PP : 293
Explanation: The answer is 'C' :
Epinephrine and glucagon hormones act through the formation of cAMP.The
mechanism involves a cascade of phosphorylation reactions mediated by a
number of kinases.
Glycogen Synthase is phosphorylated by the cAMP stimulated Protein
Kinase. The phosphorylated Synthase in inactive.
QNo: 64QTopic: Metabolism of CHODifficulty Level: 3
QStem:The branching enzyme acts on the glycogen when theglycogen chain has
been lengthened to a minimum of _____ glucose units:
Ch1: 5
Ch2: 8
Ch3: 11
Ch4: 16
Reference: Lehininger's Biochemistry, 5th Edition. PP : 568
Explanation: The answer is 'C' :
Glycogen synthase cannot make the (a1-6) bonds
found at the branch points of glycogen; these are formed
by the glycogen-branching enzyme, also called amylo
(1-4) to (1-6) transglycosylase or glycosyl-(4-6)-transferase.
The glycogen-branching enzyme catalyzes transfer of a terminal fragment of
6 or 7 glucose residues from the nonreducing end of a glycogen
branch having at least 11 residues to the C-6 hydroxyl
group of a glucose residue at a more interior position of
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the same or another glycogen chain, thus creating a new
branch.
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QNo: 67QTopic: Metabolism of CHO Difficulty Level: 4
QStem:Which of the following is a substrate for Lactose synthase
enzyme
Ch1: UDP-GLucose
Ch2: UDP-Galactose
Ch3: Galactose
Ch4: Galactose-1-Phosphate
Reference: Biochemistry by Lubert Stryer, 3rd Edition. PP : 340
Explanation: The answer is 'B' :
Lactose synthase consists of tow subunits viz . a Catalytic subunit
(galactosyl transferase) and a-lactalbumin.
The catalytic subunit transfers Galactosyl residue from a UDP-Galactose toGlucose and forms a B-1-4 glycosidic linkage.
Lactalbumin is the modifier subunit and serves to modify the specificity of
the catalytic subunit so that Galactose is transferred to Glucose rather than
N-acetylglucosamine (for the synthesis of glycoproteins).
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QNo: 68QTopic: Metabolism of CHODifficulty Level: 3
QStem:The coenzyme essential for activity of muscle Glycogenphosphorylase is
Ch1: Cyclic AMP
Ch2: NAD+
Ch3: Pyridoxal phosphate
Ch4: Coenzyme A
Reference: Lehininger's Biochemistry, 5th Edition. PP : 562
Explanation: The answer is 'C' :
Pyridoxal phosphate is an essential cofactor in the
glycogen phosphorylase reaction; its phosphate group
acts as a general acid catalyst, promoting attack by Pi
on the glycosidic bond.
This is an unusual role for this
cofactor; its more typical role is as a cofactor in transamination and
decarboxylation reactions.
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QNo: 69QTopic: Metabolism of CHODifficulty Level: 3
QStem:Inactive muscle phosphorylase b is activated by activePhosphorylase kinase
which is stimulated by :
Ch1: Calcium ions
Ch2: Cyclic AMP
Ch3: Cyclic GMP
Ch4: A & B
Reference: Biochemistry by Lubert Stryer, 3rd Edition. PP : 462
Explanation: The answer is 'D' :
The muscle glycogenolysis responds not only to the hormonal regulation but
is also synchronised with muscle contraction.
The hormonal arm works through cAMP whereas the synchronisation with
muscle contraction is provided by Calcium ions.
The delta subunit of Phosphorylase kinase is Calmodulin, a calcium binding
protein that regulates many enzymes in eukaryotes.
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QNo: 71 QTopic: Metabolism of CHO Difficulty Level: 4
QStem:Fructose - 1,6 -diphosphate is converted to Fructose-6-
phosphate by the
enzyme Fructose-1.6-bisphosphatase which is stimulated by
Ch1: Glucagon
Ch2: Insulin
Ch3: AMP
Ch4: None of the above
Reference: Biochemistry by Lubert Stryer, 3rd Edition. PP : 443
Explanation: The answer is 'A' :
Interconversion of Fr-6-P and Fr-1,6-BP is a key point of control. AMP
stimulates Phosphofructokinase (PFK), whereas it inhibits the enzyme Fr-
1,6-
bisphosphatase (FBPase). Citrate has the opposite effect.
During starvation (high Glucagon), the level of Fr-2,6-BP drops due to
phosphoryltic inhibition of Phsophofructokinase2.
Low FBP2 decreases the activity of PFK and increases that of FBPase.
Consequently Fr-1,6-BP is converted to Fr-6-P to generate glucose by
gluconeogenesis.
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QNo: 72 QTopic: Metabolism of CHODifficulty Level: 4
QStem:Phosphofructokinase 2 (PFK-2) is a 'tandem enzyme', whichholds another
enzyme activity on it, which is :
Ch1: Phosphofructokinase 1
Ch2: Fructose-bisphosphatase 2
Ch3: Aldolase
Ch4: Triose-phosphate isomerase
Reference: Biochemistry by Lubert Stryer, 3rd Edition. PP : 365
Explanation: The answer is 'B' :
PFK2 mediates the synthesis of Fru-2,6-bisphosphate (FBP2), which ismajor
regulator of glycolysis and gluconeogenesis.
The enzyme that hydrolysis FBP2 is Fr-2,6-bisphosphatase. The twoenzymes
activities are present in a single 53 kD polypeptide chain, which thus is
called a tandem enzyme.
The activites of FBP2 and FBP2ase are reciproclly regulated by
phosphorylation of a single serine residue. When glucose is scarce,
Glucagon triggers this phosphorylation activating the FBPase and inhibits
PFK2.
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QNo: 73 QTopic: Metabolism of CHODifficulty Level: 3
QStem:In liver, Glyceraldehyde-3-phosphate may be converted to
Ch1: Glycerol-3-Phosphate
Ch2: Dihydroxyacetone phosphate
Ch3: 1,3-Bisphosphoglycerate
Ch4: All of the above
Reference: Lehninger's Biochemistry, 3rd Edition. PP : 804
Explanation: The answer is 'D' :
Glyceraldehyde-3-P has multiple fates in Liver - it can be converted to
Glycerol-3-P for the sythesis of triglycerides, or to DHAP for glycolysis or
to
1,3-bisphosphoglycerate by Rappaport Lubering shunt.
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QNo: 74 QTopic: Metabolism of CHODifficulty Level: 4
QStem:In the presence of Arsenate
Ch1: Enzyme Glyceraldehyde3-P dehydrogenase is inhibited
Ch2: Enzyme Phosphoglycerokinase is inhibited
Ch3: Substrate level phosphorylation is uncoupled from glycolysis
Ch4: 1,3-di-arsenoglycerate is produced
Reference: Chatterjea and Shinde, 5th Edition, 2005. PP : 271
Explanation: The best answer is 'A' :
Although the staement is not exactly true. The enzyme Glyceraldehyde-3-P
DH carries out the conversion of Glyal-3-P to 1,3-Diphosphoglycerate.
Arsenate competes with inroganic phosphate in the reaction and produces
1-Arseno-3-phsopho-glyceratewhich hydrolyses spontaneously to yield 3-phosphoglycerate and heat.
Therefore, the enzyme is not inhibited but is not able to form its normal
product.
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QNo: 75 QTopic: Metabolism of CHODifficulty Level: 4
QStem:Coenzyme for the reoxidation of reduced lipoate in pyruvatedehydrogenase
reaction is
Ch1: FAD+
Ch2: NADP+
Ch3: NAD+
Ch4: FMN
Reference: Chatterjea and Shinde, 5th Edition, 2005. PP : 277
Explanation: The answer is 'A' :
Enzyme Dihydrolipoyl dehydrogenase, involved in the reoxidation of lipoic
acid, is a flavoprotein and contains FAD as the prosthetic group.
The hydrogen from reduced DH-lipoic acid are recieved by FAD to form
FADH2 which transfers them onward to NAD.
Therefore, although the final recipient in the reaction is NAD, the enzyme
first accepts the hydrogens on FAD molecule.
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QNo: 76 QTopic: Metabolism of CHODifficulty Level: 3
QStem:The approximate number of copies of dihydrolipoyltransacetylase in E.Coli
Pyruvate dehydrogenase complex is :
Ch1: 8
Ch2: 24
Ch3: 34
Ch4: 1
Reference: Lehninger's Biochemistry, 3rd Edition. PP : 604
Explanation: The answer is 'B' :
The PDH complex contains three enzymespyruvate
dehydrogenase (E1), dihydrolipoyl transacetylase
(E2), and dihydrolipoyl dehydrogenase (E3)each
present in multiple copies.
The number of copies of each
enzyme and therefore the size of the complex varies
among species.
In the bovine enzyme, 60 identical copies of E2 form a pentagonal
dodecahedron (the core) with a diameter of
about 25 nm. (The core of the Escherichia coli enzyme contains 24 copies ofE2.)
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QNo: 77 QTopic: Metabolism of CHODifficulty Level: 4
QStem:Pyruvate is accumulated in case of the dietary deficiency ofvitamin -
Ch1: Pyridoxine
Ch2: Folic acid
Ch3: Cobalamine
Ch4: Thiamine
Reference: Biochemistry by Lubert Stryer. 3rd Edition. PP :
383.
Explanation: The answer is 'D' :
The major enzymes that has Thiamine pyrophosphate as coenzyme are :
Pyruvate dehydrogenase, a-Keto-dehydrogenase and Transketolase.
Dietary deficiency or chronic alcoholism (excessive consumptoin of TPP)can
affect the activity of these enzymes. Lower activity of Pyruvate
dehydrogenase would lead to accumulation of pyruvate.
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QNo: 78 QTopic: Metabolism of CHODifficulty Level: 3
QStem:Citrate is converted to isocitrate by aconitase which contains:
Ch1: Ca++
Ch2: Fe++
Ch3: Zn++
Ch4: Mg++
Reference: Biochemistry by Lubert Stryer. 3rd Edition. PP : 375
Explanation: The answer is 'B' :
Citrate is converted to Isocitrate by a dehydration followed by hydration
steps. The enzyme Aconitase has been named after the intermediate
'Aconitate' in the reaction.
The enzyme contains four Iron atoms complexed to four inorganic sulfidesand four cysteine sulfur atoms. This Fe-S cluster binds Citrate and
participates in dehydrating tha rehydrating the bound substrate.
The enzyme Aconitase is thus an Iron-Sulfur protein.
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QNo: 81 QTopic: Metabolism of CHO Difficulty Level: 2
QStem:Glucose-6-phosphatase is absent from which of the following
tissues
Ch1: Brain
Ch2: Intestine
Ch3: Kidney
Ch4: Heart
Reference: Biochemistry by Lubert Stryer. 3rd Edition. PP : 454
Explanation: The answer is 'A' :
The enzyme Glu-6-phosphatase is located on the luminal side of the smooth
endoplasmic reticulum in the Liver cells and is essential for
gluconeogenesis.
The enzyme is also present in kidney and intestine but is absent in the brain
tissue and muscles.
Brain and Muscle need a large amount of Glucose. The absence of Glu-6-
phosphatase helps them to retain glucose since Glu-6-P cannot escape the
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QNo: 82 QTopic: Metabolism of CHODifficulty Level: 4
QStem:6-Phosphogluconate is converted to Ribulose-5-P in thepresence of coenzyme
Ch1: FAD+
Ch2: NAD+
Ch3: NADP+
Ch4: ATP
Reference: Lehninger's Biochemistry. 5th Edition. PP : 550
Explanation: The answer is 'C' :
6-phosphogluconate
undergoes oxidation and decarboxylation by
6-phosphogluconate dehydrogenase enzyme to form the ketopentose
ribulose 5-phosphate.
The oxidation takes place in the presence of NAPD+ and requires Mg++ions.
This reaction provides the second molecule of NADPH generated in HMP
shunt.
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QNo: 83 QTopic: Metabolism of CHODifficulty Level: 4
QStem:UDP-Glucose is oxidized to UDP-glucuronic acid by adehydrogenase in the
presence of
Ch1: FAD+
Ch2: NAD+
Ch3: NADP+
Ch4: ADP
Reference: .
Explanation: The answer is 'B' :
The uronic acid pathway is primarily involved in the synthesis of Glucuronic
acid required for a) synthesis of glycosaminoglycans b) Glucuronides.
UDP-G Dehydrogenase oxidises the carbon C6 of UDPG to form UDP
glucuronic acid. The acceptor of hydrogen in the reaction is NAD+.
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QNo: 84 QTopic: Metabolism
of CHO Difficulty Level: 3
QStem:Fructokinase is present in which of the tissues
Ch1: Liver
Ch2: Adipose tissue
Ch3: Heart
Ch4: Brain
Reference: Lehninger's Biochemistry. 5th Edition. PP : 536
Explanation: The answer is 'A' :
The pathway of entry of Fructose in the glycolytic pathway is different in the
peripheral tissues and Liver.
In the peripheral tissues, Fructose is phosphorylated by Hexokinase t Fru-6-
P.
In liver, fructokinase phosphorylates it to Fru-1-P. Fr-1-P then is acted upon
by Fr-1-P Aldolase to split it into glyceraldehyde and dihydroxyacetone
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QNo: 85 QTopic: Metabolism of CHODifficulty Level: 4
QStem:Fructose-1-phosphate is splitted into glyceraldehyde anddihydroxyacetone
phosphate by the enzyme which is also known as
Ch1: Fructose-Biphosphate Aldolase
Ch2: Aldolase A
Ch3: Enolase
Ch4: Fructolase
Reference: IUB Website.
Explanation: The answer is 'A' :
The enzyme commission of International Union of Biologists and
Biochemists now lists the Aldolase-1 and Aldolase-2 together as single
enzyme but the enzyme cleaving Fr-1-P is also listed as Fructose-
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QNo: 87 QTopic: Metabolism of CHO Difficulty Level: 4
QStem:In galactosemic individuals deficient in uridyltransferase,
UDP-Galactose may
be formed from
Ch1: Glucose
Ch2: UDP-Glucose
Ch3: Galactose-1-Phosphate
Ch4: All of the above
Reference: Lehninger's Biochemistry. 5th Edition. PP : 537
Explanation: The answer is 'B' :
Galactosaemia is an inherited disorder (incidence 1 :18000) characterised
by impaired utilization of Galactose, hence its accumulation in blood.
The major enzyme defect is Gal-1-P Uridyl transferase but the deficiency of
Galactokinase and Epimerase are also known causes of Galactosaemia.
Even if the patients are kept on a Galactose free diet, the Galactose can be
formed from UDP-Glucose by epimerization to meet the body requirements
of galactose.