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    Metabolism of Carbohydrates

    Difficulty Level : One

    QNo: 1

    QStem:The heptose ketose sugar formed in HMP shunt is :

    Ch1: Glucoheptose

    Ch2: Sedoheptose

    Ch3: Sedoheptulose

    Ch4: Mannoheptose

    Reference: Harper's Biochemsitry 24th Edition. PP : 207

    Explanation: The answer is 'C' :

    A molecule of Sedoheptulose-7-P and one of Glyceraldehyde-3-P are formed

    by the Transketolase reaction in HMP shunt.

    Transketolase (with the help of coenzyme thiamine pyrophosphate, TPP)

    transfers a two-carbon unit comprising carbon 1 and 2 of a ketose to thealdehyde carbon of an aldose sugar. Therefore, it converts an Aldose

    (Ribose-5-P) to a ketose with two carbon more (Sedoheptulose-7-P).

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    QNo: 2

    QStem:Glucose yields how many ATPs by Glycolysis (1 NADH = 3 ATP)?

    Ch1: 5

    Ch2: 11

    Ch3: 8

    Ch4: 10

    Reference: Chawla and Tarek, PP: 230

    Explanation: The answer is 'C' :

    Oxidation of Glucose by Glycolysis yields :

    y One NADH at Gl-3-P DH step.y Two ATPs are generated by substrate level phosphorylation at

    phosphoglycerokinase & Pyruvate kinase steps.

    y Since one glucose gives rise to two Gl-3-P, net yield is 2 NADH and4 ATP.

    y One NADH can roughly be considered to yield 3 ATPs, therefore 2NADH = 6 ATP.Total = 10 ATP.

    Two ATPs are utilized for phosphorylation of glu and fru-6-P.

    Therefore net yield is 10 - 2 = 8 ATP

    QNo: 3

    QStem:Glycolysis of Glucose, under anaerobic conditions, yields how many ATPs?

    Ch1: 2

    Ch2: 6

    Ch3: 8

    Ch4: 10

    Reference: Chawla and Tarek, PP: 230

    Explanation: The answer is 'A' :

    Under Anaerobic conditions, NADH cannot yield ATP as Electron transportchain is blocked. Therefore, Pyruvate is converted to Lactate by using one ( x

    2 ) NADH.

    Net yield = 2 ATP only.

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    QNo: 4

    QStem:Which one of the following is an intermediate in HMP shunt

    Ch1: D-Ribulose

    Ch2: D-Arabinose

    Ch3: D-Xylose

    Ch4: D-Lyxose

    Reference: Harpers Biochemistry 26th Edition, pp: 164.

    Explanation: The answer is 'A' :

    Ribulose-5-P is the first pentose sugar of HMP shunt generated by oxidative

    decarboxylation of 6-Phosphogluconate with the generation of the second

    molecule of NADPH.

    The only potent distractant in the options is Xylose, but it is Xylulose-5-P

    that is formed from Ribulose and not Xylose-5-P.

    QNo: 86 QTopic: Metabolism of CHODifficulty Level: 2

    QStem:Galactose is phosphorylated by galactokinase to form

    Ch1: Galactose-6-phosphate

    Ch2: Galactose-1,6-diphosphate

    Ch3: Galactose-1-phosphate

    Ch4: All of the above

    Reference: Lehninger's Biochemistry. 5th Edition. PP : 536

    Explanation: The answer is 'C' :

    D-Galactose, a product of hydrolysis of the disaccharide

    lactose (milk sugar), passes in the blood from the intestine to the liver,

    where it is first

    phosphorylated at C-1, at the expense of ATP, by the

    enzyme galactokinase:

    Galactose + ATP --> galactose 1-phosphate + ADP

    QNo: 79 QTopic: Metabolism of CHODifficulty Level: 2

    QStem:The reaction involved in conversion of succinyl CoA tosuccinate in TCA cycle

    requires

    Ch1: CDP

    Ch2: ADP

    Ch3: GDP

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    Ch4: NADP+

    Reference: Biochemistry by Lubert Stryer. 3rd Edition. PP : 376

    Explanation: The answer is 'C' :

    The enzyme Succinyl CoA synthetase mediates this substrate level

    phosphorylation reaction.

    The cleavage of the thioester bond of Succinyl CoA is coupled to the

    phosphorylation of GDP.

    QNo: 70 QTopic: Metabolism of CHODifficulty Level: 2

    QStem:Hexokinase has a high affinity for glucose than

    Ch1: Fructokinase

    Ch2: Galactokinase

    Ch3: GlucokinaseCh4: All of the above

    Reference: Biochemistry by Lubert Stryer, 3rd Edition. PP : 361

    Explanation: The answer is 'D' :

    The students would be tempted to answer 'C' Glucokinase. But this is a

    distractor.

    All the enzymes in the options have lesser affinity (if not zero) than that of

    hexokinase.

    QNo: 65QTopic: Metabolism of CHODifficulty Level: 2

    QStem:Cyclic AMP is formed from ATP by the enzyme adenylate

    cyclase which is

    activated by the hormone

    Ch1: Insulin

    Ch2: Epinephrine

    Ch3: Testosterone

    Ch4: Progesterone

    Reference: Chatterjea and Shinde, 5th Edition, 2005. PP : 289

    Explanation: The answer is 'B' :

    Epinephrine and Glucagon stimulate adenylate cyclase on the plasma

    membrane and enhance the synthesis of cAMP.

    cAMP is the second messenger for these hormones and stimulates a

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    cascade of kinase enzymes that result in phosphorylation of a number of

    proteins.

    The phosphorylation / dephosphorylation is a major mechanism of

    QNo: 66QTopic: Metabolism of CHODifficulty Level: 2

    QStem:The synthesis of adenylate cyclase is increased by :

    Ch1: Thyroid hormones

    Ch2: Epinepherine

    Ch3: Prolactin

    Ch4: Follicle Stimulating Hormone

    Reference: .

    Explanation: The Answer is 'A' :

    Thyroid hormones stimulate the synthesis of a number of proteins includingadenylate cyclase.

    Epinephrine, although acts through stimulation of adenylate cyclase, does

    not increase its synthesis.

    QNo: 15QTopic: Metabolism of CHO Difficulty Level: 2

    QStem:Which one of the following is an intermediate in HMP shunt

    Ch1: D-Ribulose

    Ch2: D-Arabinose

    Ch3: D-Xylose

    Ch4: D-Lyxose

    Reference: .

    Explanation: The answer is 'A' :

    Ribulose-5-P is the first pentose sugar of HMP shunt generated by oxidative

    decarboxylation of 6-Phosphogluconate with the generation of the second

    molecule of NADPH.

    The only potent distractant in the options is Xylose, but it is Xylulose-5-P

    that is formed from Ribulose and not Xylose-5-P.

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    QNo: 9 QTopic: Metabolism of CHO Difficulty Level: 3

    QStem:Which of the following can be said to act as a carrier ofCitric acid cylce

    Ch1: ACETYL CoA

    Ch2: a-KETOGLUTARATE

    Ch3: MALATE

    Ch4: OXALOACETATE

    Reference: .

    Explanation: The answer is 'D' :

    Oxaloacetic acid (OAA) can be called as the carrier of TCA cycle because

    Acetyl CoA enters the cycle after combining with OAA to from Citric acid.

    At the end of each cycle, OAA is regenerated to accept a new Acetyl CoA

    unit.

    The pace of TCA cycle is also dependent upon the availability and

    QNo: 42QTopic: Metabolism of CHODifficulty Level: 3

    QStem:Which of the following glycolytic enzymes is inhibited by

    fluoride:Ch1: Glyceraldehyde 3-P dehydrogenase

    Ch2: Phospholglycerate kinase

    Ch3: Enolase

    Ch4: Fructose1-6 diphosphate

    Reference: Chatterjea and Shinde, Sixth Edition PP : 272

    Explanation: The answer is 'C' :

    Fluoride inhibits ENOLASE enzyme that carries out the formation of

    Phosphoenol pyruvate from 2-Phosphoglycerate during glycolysis.

    Fluoride is added to the vials for collection of blood samples for estimation

    of blood glucose. Fluoride inhibits Enolase and hence stops the utilisation of

    glucose by RBCs in the blood samples. In the absence of fluoride glucose

    estimation could give false low values.

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    QNo: 43QTopic: Metabolism of CHODifficulty Level: 3

    QStem:Pompe's disease is characterized by the deficiencey of :

    Ch1: Glucose-6-phosphatase

    Ch2: Debranching enzyme

    Ch3: Acid maltase

    Ch4: Liver phosphorylase

    Reference: Chatterjea and Shinde, Sixth Edition PP : 294

    Explanation: The answer is 'C' :

    Pompe's disease is caused by the inherited deficiency of Acid maltase,

    lysosomal enzyme that hydrolyses oligosaccharides.

    Inheritence : Autosomal recessive.

    'Normal' type of glycogen is deposited in excess in heart, liver, smooth and

    striated muscles.

    Cardiomegali and muscle hypotonia are the features and cardiac failure is

    the cause of death.

    QNo: 45QTopic: Metabolism of CHODifficulty Level: 3

    QStem:All of the following antibodies are Beta-cytolytic (Pancreatic

    beta cells),

    except:

    Ch1: Insulin Ab

    Ch2: Islet cell Ab

    Ch3: Glutamic acid decarboxylase Ab

    Ch4: Insulin receptor Ab

    Reference: .

    Explanation: The answer is 'D' :

    Type II diabetes mellitus is now recognised as an autosomal disease. A

    number of antibodies have been implicated in the progressive destruction of

    beta cells leading to DM.

    Insulin antibodies which attach the insulin granules and deplete the beta

    cells, Islet cell antibodies attach the membrane antigens of islet cells.

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    Similarly Glutamic acid decarboxylase antobodies that attach the lysosomal

    enzyme are also cytolytic and are being used as markers for developing DM.

    Insulin receptor antibodies bind with the Insulin receptors in peripheral

    tissues and make them unavailable to Insulin leading to insulin resistance.

    These antibodies donot bind to the beta cells.

    QNo: 46QTopic: Metabolism of CHODifficulty Level: 3

    QStem:Which of the following enzyme carries out an anapleurotic

    reaction:

    Ch1: Pyruvate kinase

    Ch2: Pyruvate carboxylase

    Ch3: Pyruvate carboxykinase

    Ch4: Pyruvate dehydrogenaseReference: Lehninger's Biochemistry, 5th Edition. PP : 617

    Explanation: The answer is 'B' :

    Anapleurotic reactions or 'Filling-up' reactions are those that provide

    intermediates of the TCA cycle and hence increase the pace of the cycle.

    The major enzymes that carryout anapleurotic reactions are :

    a) Malic enzyme - produces Malate from Pyruuvate

    b) Pyruvate carboxylase - produces Oxaloacetate from Pyruvate

    c) Transaminases that pour amino acid carbon skeleton into the cycle.

    QNo: 50QTopic: Metabolism of CHODifficulty Level: 3

    QStem:Lumber spinal fluid glucose concentration ischaracteristically low in patients

    with:

    Ch1: Meningioma

    Ch2: Cerebral haemorrhage

    Ch3: Multiple sclerosis

    Ch4: Coccal Meningitis

    Reference: Chatterjea and Shinde, Sixth Edition PP : 639

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    Explanation: The answer is 'D' :

    Bacterial infection in the CSF lowers the glucose concentration as the

    bacterial utilise the glucose.

    All the other options in the question are non-infectious disease conditions.

    QNo: 61QTopic: Metabolism of CHODifficulty Level: 4

    QStem:The GIT absorption of glucose is interferred by the

    deficiency of:

    Ch1: Vitamin A

    Ch2: Thiamine

    Ch3: Biotin

    Ch4: InsulinReference: Chatterjea and Shinde, 5th Edition, 2005. PP : 264

    Explanation: The answer is 'B' :

    The absorption of glucose from GIT is diminished in case of deficiency of a

    number of B-complex vitamins e.g. Thiamine, Pyridoxine and pentothenic

    acid.

    QNo: 62QTopic: Metabolism of CHODifficulty Level: 4

    QStem:Glucose absorption from intestine may be decreased in caseof severe -

    Ch1: Oedema

    Ch2: Nephritis

    Ch3: Rickets

    Ch4: Osteomyelitis

    Reference: Chatterjea and Shinde, 5th Edition, 2005. PP : 264

    Explanation: The answer is 'A' :

    The transporters responsible for absorption of glucose need sufficient

    concentration of Sodium for the abswortion of glucose since Sodium is Co-

    transported along with Glucose.

    Oedema, most often than not, is associated with low sodium concentrations

    therefore low sodium availability can affect the glucose absorption.

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    QNo: 63QTopic: Metabolism of CHODifficulty Level: 3

    QStem:Glycogen synthetase activity is depressed by :

    Ch1: Glucose

    Ch2: InsulinCh3: Cyclic AMP

    Ch4: Citrate

    Reference: Chatterjea and Shinde, 5th Edition, 2005. PP : 293

    Explanation: The answer is 'C' :

    Epinephrine and glucagon hormones act through the formation of cAMP.The

    mechanism involves a cascade of phosphorylation reactions mediated by a

    number of kinases.

    Glycogen Synthase is phosphorylated by the cAMP stimulated Protein

    Kinase. The phosphorylated Synthase in inactive.

    QNo: 64QTopic: Metabolism of CHODifficulty Level: 3

    QStem:The branching enzyme acts on the glycogen when theglycogen chain has

    been lengthened to a minimum of _____ glucose units:

    Ch1: 5

    Ch2: 8

    Ch3: 11

    Ch4: 16

    Reference: Lehininger's Biochemistry, 5th Edition. PP : 568

    Explanation: The answer is 'C' :

    Glycogen synthase cannot make the (a1-6) bonds

    found at the branch points of glycogen; these are formed

    by the glycogen-branching enzyme, also called amylo

    (1-4) to (1-6) transglycosylase or glycosyl-(4-6)-transferase.

    The glycogen-branching enzyme catalyzes transfer of a terminal fragment of

    6 or 7 glucose residues from the nonreducing end of a glycogen

    branch having at least 11 residues to the C-6 hydroxyl

    group of a glucose residue at a more interior position of

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    the same or another glycogen chain, thus creating a new

    branch.

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    QNo: 67QTopic: Metabolism of CHO Difficulty Level: 4

    QStem:Which of the following is a substrate for Lactose synthase

    enzyme

    Ch1: UDP-GLucose

    Ch2: UDP-Galactose

    Ch3: Galactose

    Ch4: Galactose-1-Phosphate

    Reference: Biochemistry by Lubert Stryer, 3rd Edition. PP : 340

    Explanation: The answer is 'B' :

    Lactose synthase consists of tow subunits viz . a Catalytic subunit

    (galactosyl transferase) and a-lactalbumin.

    The catalytic subunit transfers Galactosyl residue from a UDP-Galactose toGlucose and forms a B-1-4 glycosidic linkage.

    Lactalbumin is the modifier subunit and serves to modify the specificity of

    the catalytic subunit so that Galactose is transferred to Glucose rather than

    N-acetylglucosamine (for the synthesis of glycoproteins).

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    QNo: 68QTopic: Metabolism of CHODifficulty Level: 3

    QStem:The coenzyme essential for activity of muscle Glycogenphosphorylase is

    Ch1: Cyclic AMP

    Ch2: NAD+

    Ch3: Pyridoxal phosphate

    Ch4: Coenzyme A

    Reference: Lehininger's Biochemistry, 5th Edition. PP : 562

    Explanation: The answer is 'C' :

    Pyridoxal phosphate is an essential cofactor in the

    glycogen phosphorylase reaction; its phosphate group

    acts as a general acid catalyst, promoting attack by Pi

    on the glycosidic bond.

    This is an unusual role for this

    cofactor; its more typical role is as a cofactor in transamination and

    decarboxylation reactions.

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    QNo: 69QTopic: Metabolism of CHODifficulty Level: 3

    QStem:Inactive muscle phosphorylase b is activated by activePhosphorylase kinase

    which is stimulated by :

    Ch1: Calcium ions

    Ch2: Cyclic AMP

    Ch3: Cyclic GMP

    Ch4: A & B

    Reference: Biochemistry by Lubert Stryer, 3rd Edition. PP : 462

    Explanation: The answer is 'D' :

    The muscle glycogenolysis responds not only to the hormonal regulation but

    is also synchronised with muscle contraction.

    The hormonal arm works through cAMP whereas the synchronisation with

    muscle contraction is provided by Calcium ions.

    The delta subunit of Phosphorylase kinase is Calmodulin, a calcium binding

    protein that regulates many enzymes in eukaryotes.

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    QNo: 71 QTopic: Metabolism of CHO Difficulty Level: 4

    QStem:Fructose - 1,6 -diphosphate is converted to Fructose-6-

    phosphate by the

    enzyme Fructose-1.6-bisphosphatase which is stimulated by

    Ch1: Glucagon

    Ch2: Insulin

    Ch3: AMP

    Ch4: None of the above

    Reference: Biochemistry by Lubert Stryer, 3rd Edition. PP : 443

    Explanation: The answer is 'A' :

    Interconversion of Fr-6-P and Fr-1,6-BP is a key point of control. AMP

    stimulates Phosphofructokinase (PFK), whereas it inhibits the enzyme Fr-

    1,6-

    bisphosphatase (FBPase). Citrate has the opposite effect.

    During starvation (high Glucagon), the level of Fr-2,6-BP drops due to

    phosphoryltic inhibition of Phsophofructokinase2.

    Low FBP2 decreases the activity of PFK and increases that of FBPase.

    Consequently Fr-1,6-BP is converted to Fr-6-P to generate glucose by

    gluconeogenesis.

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    QNo: 72 QTopic: Metabolism of CHODifficulty Level: 4

    QStem:Phosphofructokinase 2 (PFK-2) is a 'tandem enzyme', whichholds another

    enzyme activity on it, which is :

    Ch1: Phosphofructokinase 1

    Ch2: Fructose-bisphosphatase 2

    Ch3: Aldolase

    Ch4: Triose-phosphate isomerase

    Reference: Biochemistry by Lubert Stryer, 3rd Edition. PP : 365

    Explanation: The answer is 'B' :

    PFK2 mediates the synthesis of Fru-2,6-bisphosphate (FBP2), which ismajor

    regulator of glycolysis and gluconeogenesis.

    The enzyme that hydrolysis FBP2 is Fr-2,6-bisphosphatase. The twoenzymes

    activities are present in a single 53 kD polypeptide chain, which thus is

    called a tandem enzyme.

    The activites of FBP2 and FBP2ase are reciproclly regulated by

    phosphorylation of a single serine residue. When glucose is scarce,

    Glucagon triggers this phosphorylation activating the FBPase and inhibits

    PFK2.

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    QNo: 73 QTopic: Metabolism of CHODifficulty Level: 3

    QStem:In liver, Glyceraldehyde-3-phosphate may be converted to

    Ch1: Glycerol-3-Phosphate

    Ch2: Dihydroxyacetone phosphate

    Ch3: 1,3-Bisphosphoglycerate

    Ch4: All of the above

    Reference: Lehninger's Biochemistry, 3rd Edition. PP : 804

    Explanation: The answer is 'D' :

    Glyceraldehyde-3-P has multiple fates in Liver - it can be converted to

    Glycerol-3-P for the sythesis of triglycerides, or to DHAP for glycolysis or

    to

    1,3-bisphosphoglycerate by Rappaport Lubering shunt.

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    QNo: 74 QTopic: Metabolism of CHODifficulty Level: 4

    QStem:In the presence of Arsenate

    Ch1: Enzyme Glyceraldehyde3-P dehydrogenase is inhibited

    Ch2: Enzyme Phosphoglycerokinase is inhibited

    Ch3: Substrate level phosphorylation is uncoupled from glycolysis

    Ch4: 1,3-di-arsenoglycerate is produced

    Reference: Chatterjea and Shinde, 5th Edition, 2005. PP : 271

    Explanation: The best answer is 'A' :

    Although the staement is not exactly true. The enzyme Glyceraldehyde-3-P

    DH carries out the conversion of Glyal-3-P to 1,3-Diphosphoglycerate.

    Arsenate competes with inroganic phosphate in the reaction and produces

    1-Arseno-3-phsopho-glyceratewhich hydrolyses spontaneously to yield 3-phosphoglycerate and heat.

    Therefore, the enzyme is not inhibited but is not able to form its normal

    product.

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    QNo: 75 QTopic: Metabolism of CHODifficulty Level: 4

    QStem:Coenzyme for the reoxidation of reduced lipoate in pyruvatedehydrogenase

    reaction is

    Ch1: FAD+

    Ch2: NADP+

    Ch3: NAD+

    Ch4: FMN

    Reference: Chatterjea and Shinde, 5th Edition, 2005. PP : 277

    Explanation: The answer is 'A' :

    Enzyme Dihydrolipoyl dehydrogenase, involved in the reoxidation of lipoic

    acid, is a flavoprotein and contains FAD as the prosthetic group.

    The hydrogen from reduced DH-lipoic acid are recieved by FAD to form

    FADH2 which transfers them onward to NAD.

    Therefore, although the final recipient in the reaction is NAD, the enzyme

    first accepts the hydrogens on FAD molecule.

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    QNo: 76 QTopic: Metabolism of CHODifficulty Level: 3

    QStem:The approximate number of copies of dihydrolipoyltransacetylase in E.Coli

    Pyruvate dehydrogenase complex is :

    Ch1: 8

    Ch2: 24

    Ch3: 34

    Ch4: 1

    Reference: Lehninger's Biochemistry, 3rd Edition. PP : 604

    Explanation: The answer is 'B' :

    The PDH complex contains three enzymespyruvate

    dehydrogenase (E1), dihydrolipoyl transacetylase

    (E2), and dihydrolipoyl dehydrogenase (E3)each

    present in multiple copies.

    The number of copies of each

    enzyme and therefore the size of the complex varies

    among species.

    In the bovine enzyme, 60 identical copies of E2 form a pentagonal

    dodecahedron (the core) with a diameter of

    about 25 nm. (The core of the Escherichia coli enzyme contains 24 copies ofE2.)

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    QNo: 77 QTopic: Metabolism of CHODifficulty Level: 4

    QStem:Pyruvate is accumulated in case of the dietary deficiency ofvitamin -

    Ch1: Pyridoxine

    Ch2: Folic acid

    Ch3: Cobalamine

    Ch4: Thiamine

    Reference: Biochemistry by Lubert Stryer. 3rd Edition. PP :

    383.

    Explanation: The answer is 'D' :

    The major enzymes that has Thiamine pyrophosphate as coenzyme are :

    Pyruvate dehydrogenase, a-Keto-dehydrogenase and Transketolase.

    Dietary deficiency or chronic alcoholism (excessive consumptoin of TPP)can

    affect the activity of these enzymes. Lower activity of Pyruvate

    dehydrogenase would lead to accumulation of pyruvate.

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    QNo: 78 QTopic: Metabolism of CHODifficulty Level: 3

    QStem:Citrate is converted to isocitrate by aconitase which contains:

    Ch1: Ca++

    Ch2: Fe++

    Ch3: Zn++

    Ch4: Mg++

    Reference: Biochemistry by Lubert Stryer. 3rd Edition. PP : 375

    Explanation: The answer is 'B' :

    Citrate is converted to Isocitrate by a dehydration followed by hydration

    steps. The enzyme Aconitase has been named after the intermediate

    'Aconitate' in the reaction.

    The enzyme contains four Iron atoms complexed to four inorganic sulfidesand four cysteine sulfur atoms. This Fe-S cluster binds Citrate and

    participates in dehydrating tha rehydrating the bound substrate.

    The enzyme Aconitase is thus an Iron-Sulfur protein.

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    QNo: 81 QTopic: Metabolism of CHO Difficulty Level: 2

    QStem:Glucose-6-phosphatase is absent from which of the following

    tissues

    Ch1: Brain

    Ch2: Intestine

    Ch3: Kidney

    Ch4: Heart

    Reference: Biochemistry by Lubert Stryer. 3rd Edition. PP : 454

    Explanation: The answer is 'A' :

    The enzyme Glu-6-phosphatase is located on the luminal side of the smooth

    endoplasmic reticulum in the Liver cells and is essential for

    gluconeogenesis.

    The enzyme is also present in kidney and intestine but is absent in the brain

    tissue and muscles.

    Brain and Muscle need a large amount of Glucose. The absence of Glu-6-

    phosphatase helps them to retain glucose since Glu-6-P cannot escape the

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    QNo: 82 QTopic: Metabolism of CHODifficulty Level: 4

    QStem:6-Phosphogluconate is converted to Ribulose-5-P in thepresence of coenzyme

    Ch1: FAD+

    Ch2: NAD+

    Ch3: NADP+

    Ch4: ATP

    Reference: Lehninger's Biochemistry. 5th Edition. PP : 550

    Explanation: The answer is 'C' :

    6-phosphogluconate

    undergoes oxidation and decarboxylation by

    6-phosphogluconate dehydrogenase enzyme to form the ketopentose

    ribulose 5-phosphate.

    The oxidation takes place in the presence of NAPD+ and requires Mg++ions.

    This reaction provides the second molecule of NADPH generated in HMP

    shunt.

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    QNo: 83 QTopic: Metabolism of CHODifficulty Level: 4

    QStem:UDP-Glucose is oxidized to UDP-glucuronic acid by adehydrogenase in the

    presence of

    Ch1: FAD+

    Ch2: NAD+

    Ch3: NADP+

    Ch4: ADP

    Reference: .

    Explanation: The answer is 'B' :

    The uronic acid pathway is primarily involved in the synthesis of Glucuronic

    acid required for a) synthesis of glycosaminoglycans b) Glucuronides.

    UDP-G Dehydrogenase oxidises the carbon C6 of UDPG to form UDP

    glucuronic acid. The acceptor of hydrogen in the reaction is NAD+.

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    QNo: 84 QTopic: Metabolism

    of CHO Difficulty Level: 3

    QStem:Fructokinase is present in which of the tissues

    Ch1: Liver

    Ch2: Adipose tissue

    Ch3: Heart

    Ch4: Brain

    Reference: Lehninger's Biochemistry. 5th Edition. PP : 536

    Explanation: The answer is 'A' :

    The pathway of entry of Fructose in the glycolytic pathway is different in the

    peripheral tissues and Liver.

    In the peripheral tissues, Fructose is phosphorylated by Hexokinase t Fru-6-

    P.

    In liver, fructokinase phosphorylates it to Fru-1-P. Fr-1-P then is acted upon

    by Fr-1-P Aldolase to split it into glyceraldehyde and dihydroxyacetone

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    QNo: 85 QTopic: Metabolism of CHODifficulty Level: 4

    QStem:Fructose-1-phosphate is splitted into glyceraldehyde anddihydroxyacetone

    phosphate by the enzyme which is also known as

    Ch1: Fructose-Biphosphate Aldolase

    Ch2: Aldolase A

    Ch3: Enolase

    Ch4: Fructolase

    Reference: IUB Website.

    Explanation: The answer is 'A' :

    The enzyme commission of International Union of Biologists and

    Biochemists now lists the Aldolase-1 and Aldolase-2 together as single

    enzyme but the enzyme cleaving Fr-1-P is also listed as Fructose-

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    QNo: 87 QTopic: Metabolism of CHO Difficulty Level: 4

    QStem:In galactosemic individuals deficient in uridyltransferase,

    UDP-Galactose may

    be formed from

    Ch1: Glucose

    Ch2: UDP-Glucose

    Ch3: Galactose-1-Phosphate

    Ch4: All of the above

    Reference: Lehninger's Biochemistry. 5th Edition. PP : 537

    Explanation: The answer is 'B' :

    Galactosaemia is an inherited disorder (incidence 1 :18000) characterised

    by impaired utilization of Galactose, hence its accumulation in blood.

    The major enzyme defect is Gal-1-P Uridyl transferase but the deficiency of

    Galactokinase and Epimerase are also known causes of Galactosaemia.

    Even if the patients are kept on a Galactose free diet, the Galactose can be

    formed from UDP-Glucose by epimerization to meet the body requirements

    of galactose.