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    Photon Momentum and Uncertainty Principle

    Outline 

    - Photons Have Momentum (Compton Scattering)

    - Wavepackets - Review

    - Resolution of an Optical Microscope

    - Heisenbergs Uncertainty Principle

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    TRUE / FALSE

    1.  The photoelectric effect was used to show that light

    was composed of packets of energy proportional toits frequency.

    2.  The number of photons present in a beam of light is

    simply the intensity  I  divided by the photon energy hν.

    3. 

    Infrared light at a wavelength of 1.24 microns hasphoton energy of 1.5 eV.

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     So is Light aWave or a Particle ? 

     

    Light is always both

    Wave and Particle !

    On macroscopic scales, large number of photons looklike they exhibit only wave phenomena.

    A single photon is still a wave, but your act of trying tomeasure it makes it look like a localized particle.

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    Do Photons Have Momentum ? 

    What is momentum ?

    1E  =   mv2

      1 1= (mv)

    2 2  · v =   p

    2  · v

    Photons have energy and a finite velocity so theremust be some momentum associated with photons !

    E hν  p = =

    c c

    Just like Energy,TOTAL MOMENTUM IS ALWAYS CONSERVED

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     Photon Momentum

    IN FREE SPACE:

    E     ωE  = cp ⇒  p = = =   kc c

    IN OPTICAL MATERIALS:

    E     ωE  = v p p ⇒  p = = =   kvacnv p   v p

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    φ

    θλi

    λf 

    Compton Scattering

    incidentphoton

    targetelectron

    at rest

    recoilelectron

    scatteredphoton

    Compton found that if you treat the photons as if they were particlesE   = hc/λ   p = h/λof zero mass, with energy and momentum .

    the collision behaves just as if it were two billiard balls colliding !(with total momentum always conserved)

    In 1924, A. H. Compton performed an experimentwhere X-rays impinged on matter,

    and he measured the scattered radiation.

    It was found that the scatteredX-ray did not have the same

    wavelength !

    hλf  − λi  = ∆λ = (1moc   − cos θ)

    Image by GFHund http://commons.wikimedia.org/wiki/File:Compton,Arthur_1929_Chicago.jpg

    Wikimedia Commons.

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    Manifestation of the Photon Momentum

    Conservation of linearmomentum implies that an

    atom recoils when it

    undergoes spontaneous

    emission. The direction of

     photon emission (and atomicrecoil) is not predictable.

     A w be

    w be

     pcollimatingdiaphragms

    beam spreads laterallybecause of spontaneous

    emission s

    ell-collimated atomicam of excited atoms

    ill spread laterallycause of the recoil

    associated with

    ontaneous emission.

     A source emitting a sphericalwave cannot recoil, because

    the spherical symmetry of

    the wave prevents it from

    carrying any linear

    momentum from the source.

    SOURCE EMITT ING A PHOTON

    SOURCE EMIT T ING AN EM WAVE

    excited atom

    de -excited atom

     photonθ

    source ofexcited atoms

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    SOLAR SAILat rest

    INCOMING PHOTONS1000 W/m2

    every secondphotons with momentum

    + (1000 J/m2)/c impact the sail

    SOLAR SAILmoves

    REFLECTED PHOTONS1000 W/m2

    every secondphotons with momentum

    - (1000 J/m2)/c leave the sail

    withmomentum

    + (2000 J/m2)/c

    … and gets that

    much more

    Pressure acting on the sail = (2000 J/m2) /c /second = 6.7 Newtons/km2 momentumevery second …

    Photon Momentum - Moves Solar SailsPhoton Momentum - Moves Solar Sails

    Image by D. Kassing http://en.wikipedia.org/wiki/File:SolarSail-DLR-ESA.jpg on Wikipedia

    Image in the Public Domain

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    Optoelectric Tweezers

    Transforms optical energy to electrical energy through theuse of a photoconductive surface. The idea is similar to

    that used in the ubiquitous office copier machine. In

    xerography, a document is scanned and transferred onto a

    photosensitive drum, which attracts dyes of carbon

    particles that are rolled onto a piece of paper to reproducethe image.

    In this case, the researchers use a photosensitive surface

    made of amorphous silicon, a common material used in

    solar cells and flat-panel displays. Microscopic polystyrene

    particles suspended in a liquid were sandwiched between apiece of glass and the photoconductive material. Wherever

    light would hit the photosensitive material, it would

    behave like a conducting electrode, while areas not

    exposed to light would behave like a non-conductingtng

    e

    ITO Glass

    ProjectedImage

    Glass Substrate

    Nitride

    Undoped a-Si:H

    n+a-Si:H

    ITO

    10x

    LighEmitti

    DiodDMD Microdisplay

    insulator. Once a light source is removed, the

    photosensitive material returns to normal.

    Depending upon the properties of the particles or cellsbeing studied, they will either be attracted to or repelled

    by the electric field generated by the optoelectronic

    tweezer. Either way, the researchers can use that behavior

    to scoot particles where they want them to go.

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    Review of Wavepackets

    WHAT WOULD WE GET IF WE SUPERIMPOSED

    WAVES OF MANY DIFFERENT FREQUENCIES ?

    +∞

     E  = E    (   kzo 

      f  (k) e+j ωt−   )dk−∞

    LET’S SET THE FREQUENCY DISTRIBUTION as GAUSSIAN

    1f  (k) = √    o

    2πσk   kf (k)

    k

    σk

      (k −   2k   )

    exp   −  2σ2

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    Reminder: Gaussian Distributionσ50% of data within ±√ 

    2

    1   −   2

    x   √   −

    (x µ)

    f  ( ) =   e   2  μ specifies the position of the bell curve’s central peak

    2σ σ  specifies the half-distance between inflection points2πσ

    FOURIER TRANSFORM OF A GAUSSIAN IS A GAUSSIAN

    F x   e−ax

    2

    (k) = π

    e−

      2 2π k

    aa

    0.4

    0.3

    0.2

    0.1

    µ0.1%   0.1%

    2.1%   2.1%

    13.6%13.6%

    34.1% 34.1%

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    REMEMBER:

    Gaussian Wavepacket in Space

    Re{E n (z, to)}

    WE SET THE FREQUENCY DISTRIBUTION as GAUSSIAN

    t = to

    n

    Re{E n (z, to)

    } SUM OF SINUSOIDS= WAVEPACKET1 (k

    f  (k) =  √    exp  − 2ko)

    2πσ   2k

      2σk

    f (k)

    ko k

    σk

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    Gaussian W Gaussian W Gaussian Wavepacket in Spaceavepacket in Spaceavepacket in Space

    k   2E (z, t) = E oexp

      σ2

    −   (ct2

      − z)

    cos(ωot− koz)

    GAUSSIANENVELOPE

    ∆z = √ 2σk1

    ∆k∆z  = 1/2 

    f (k)

    ko k

    ∆k =  σk√ 

    2

    In free space …

    ω   2πE k = =

    c hc… this plot then shows the PROBABILITY OF

    WHICH k (or ENERGY) EM WAVES are

    MOST LIKELY TO BE IN THE WAVEPACKET

    WAVE PACKET

    λo

    λo  = 2π

    ko

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    UNCERTAINTY RELATIONS

    Gaussian Wavepacket in Time

    σ2E (z, t) = E oexp   − k (ct

    2  − 2z) cos (ωot− koz)

    WAVE PACKETλo

    λo =  2π

    ko

    ∆z = ∆tn

    nk = ∆ω

    c

    c

    ∆k∆z = 1/2

    ∆ω∆t = 1/2

    ∆ p∆z  =   /2

    ∆E ∆t =  

    /2

    ∆k

    ∆z

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     Crookes Radiometer 

    Today   s Culture Moment 

    The crookes radiometer spins because of

    thermal processes, but he initially guessed itwas due to photon momentum…

    invented in 1873 by the chemist

    Sir William Crookes

    Image by Rob Iretonhttp://www.flickr.com

    /photos/aoisakana/

    3308350714/ from Flickr.

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    Heisenberg realized that ...

      In the world of very small particles, one cannot measure any

    property of a particle without interacting with it in some way

      This introduces an unavoidable uncertainty into the result

      One can never measure all the

    properties exactly

    Werner Heisenberg (1901-1976)

    Image in the Public Domain16

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    t

    BEFORE

    ELECTRON-PHOTONCOLLISION

    electron

    cidenthoton

     Measuring Position and Momentum

    of an Electron

      Shine light on electron and detect

    reflected light using a microscope

      Minimum uncertainty in position

    is given by the wavelength of the ligh

      So to determine the position

    accurately, it is necessary to use

    light with a short wavelengthin p

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    on

    AFTER

    ELECTRON-PHOTONCOLLISION

    recoilingelectron

    red n

      By Plancks law E  = hc/λ, a photon with a

    short wavelength has a large energy

      Thus, it would impart a large kick to the electr

      But to determine its momentum accurately,

    electron must only be given a small kick

      This means using light of long wavelength !

    Measuring Position and Momentumof an Electron

    scatte photo

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     Implications

      It is impossible to know both the position and momentum

    exactly, i.e., Δ x =0 and Δ p=0

      These uncertainties are inherent in the physical world and

    have nothing to do with the skill of the observer

      Because h is so small, these uncertainties are not observable in

    normal everyday situations

        .= 1 054 × 10−34 [J · s]

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    Example of Baseball

      A pitcher throws a 0.1-kg baseball at 40 m/s

      So momentum is 0.1 x 40 = 4 kg m/s

     

    Suppose the momentum is measured to an accuracyof 1 percent , i.e.,

    Δp = 0.01  p = 4 x 10-2 kg m/s

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    Example of Baseball (contd)

      The uncertainty in position is then

    h∆x ≥   .= 1 3

    4π∆ p  × 10−33m

      No wonder one does not observe the effects of the

    uncertainty principle in everyday life!

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     Example of Electron

      Same situation, but baseball replaced by an electron

    which has mass 9.11 x 10-31 kg traveling at 40 m/s

      So momentum = 3.6 x 10-29 kg m/s

    and its uncertainty = 3.6 x 10-31

     kg m/s

      The uncertainty in position is then

    h∆x ≥   .= 1 4

    4π∆ p  × 10−4m

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     Classical World 

      The observer is objective and passive

      Physical events happen independently of whether there is a

    observer or not

      This is known as objective reality

    n

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    Role of an Observer in

    Quantum Mechanics

      The observer is not objective and passive

      The act of observation changes the physical system irrevocably

     

    This is known as subjective reality

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    One might ask:

    If l i ght can behave l i ke a par t i cle,might par t ic les act l i ke waves  ?

    YES !Particles, like photons, also have a wavelength given by:

    The wavelength of a particle depends on its momentum,just like a photon!

    The main difference is that matter particles have mass,and hotons dont!

    λ = h/p = h/mv

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    Matter Waves

    Compute the wavelength of a 10 [g] bullet moving at 1000 [m/s].

    λ = h/mv = 6.6x10-34 [J s] / (0.01 [kg])(1000 [m/s])

    = 6.6x10-35 [m]

    This is immeasureably small 

    For ordinary everyday objects, 

    we dont experience that

    MATTER CAN BEHAVE AS A WAVE  

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    GammaRays

    X Rays

    UV Rays

    InfraredRadiation

    Microwaves

    But, what about small particles ? 

    RadioWaves

    Compute the wavelength of an electron(m = 9.1x10-31 [kg]) moving at 1x107 [m/s].

    λ = h/mv

    = 6.6x10-34 [J s]/(9.1x10-31 [kg])(1x107 [m/s]) = 7.3x10-11 [m].

    = 0.073 [nm] 

    These electronshave a wavelength in the region

    of X-rays

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     Wavelength versus Size

    With a visible light microscope, we are limited to being

    able to resolve objects which are at least about

    0.5*10-6 m = 0.5 μm = 500 nm in size.

    This is because visible light, with a wavelength of ~500 nm cannotresolve objects whose size is smaller than its wavelength.

    Image is in the public domain

    Bacteria, as viewed

    using visible light

    Image is in the public domain

    Bacteria, as viewed

    using electrons!

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     Electron Microscope

    This image was taken with a

    Scanning Electron Microscope (SEM).

    SEM can resolve features as small as 5 nm.

    This is about 100 times better than can be

    done with visible light microscopes!

    The electron microscope is a device which uses the

    wave behavior of electrons to make images

    which are otherwise too small for visible light!

    IMPORTANT POINT:

    High energy particles can be used to reveal the structure of matter !

    Image in the Public Domain

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    SEM of various types of pollenImage in the Public Domain

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    SEM of an ant headImage in the Public Domain

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     Summary 

      Light is made up of photons, but in macroscopic situations

    it is often fine to treat it as a wave.

      Photons carry both energy & momentum.

    E  =  hc/λ   p = E/c = h/λ

     

    Matter also exhibits wave properties. For an object of mass m,and velocity, v, the object has a wavelength, λ = h / mv

      One can probe see the fine details of matter by using

    high energy particles (they have a small wavelength !)

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    MIT OpenCourseWarehttp://ocw.mit.edu

    6.007 Electromagnetic Energy: From Motors to Lasers

    Spring 2011

    For information about citing these materials or our Terms of Use, visit: http://ocw.mit.edu/terms.

    33

    http://ocw.mit.edu/http://ocw.mit.edu/termshttp://ocw.mit.edu/termshttp://ocw.mit.edu/http://ocw.mit.edu/terms