motion equations mr. kings science class. work work = force x distance
TRANSCRIPT
Motion EquationsMotion Equations
Mr. King’s Science ClassMr. King’s Science Class
WORKWORK
WORK = FORCE X DISTANCE
WORKWORK
WORK = FORCE X DISTANCE
Feet or cm
WORKWORK
WORK = FORCE X DISTANCE
Feet or cm
Pounds or grams
WORKWORK
WORK = FORCE X DISTANCE
Feet or centimeters
Pounds or grams
Foot pounds or gram centimeters
WORKWORK
WORK = FORCE X DISTANCE
Feet or centimeters
Pounds or grams
Foot pounds or gram centimeters
10 cm
WORKWORK
WORK = FORCE X DISTANCE
Feet or centimeters
Pounds or grams
Foot pounds or gram centimeters
10 cmX
WORKWORK
WORK = FORCE X DISTANCE
Feet or centimeters
Pounds or grams
Foot pounds or gram centimeters
10 cmX20 g
WORKWORK
WORK = FORCE X DISTANCE
Feet or centimeters
Pounds or grams
Foot pounds or gram centimeters
10 cmX20 g=
WORKWORK
WORK = FORCE X DISTANCE
Feet or centimeters
Pounds or grams
Foot pounds or gram centimeters
10 cmX20 g=200 joules
WORKWORK
Let’s try a word problem!
Johneal pulled a 100 gram weight using a spring scale up the smooth side of a chalk board. The spring scale read 80 grams as she pulled it evenly 25 centimeters. How muchwork did Johneal do?
WORKWORK
Let’s try a word problem!
Johneal pulled a 100 gram weight using a spring scale up the smooth side of a chalk board. The spring scale read 80 grams as she pulled it evenly 25 centimeters. How muchwork did Johneal do?
WORK = FORCE X DISTANCE
WORKWORK
Let’s try a word problem!
Johneal pulled a 100 gram weight using a spring scale up the smooth side of a chalk board. The spring scale read 80 grams as she pulled it evenly 25 centimeters. How muchwork did Johneal do?
WORK = FORCE X DISTANCE
? = 80g X 25cm
WORKWORK
Let’s try a word problem!
Johneal pulled a 100 gram weight using a spring scale up the smooth side of a chalk board. The spring scale read 80 grams as she pulled it evenly 25 centimeters. How muchwork did Johneal do?
WORK = FORCE X DISTANCE
? = 80g X 25cm
? = 2,000 joule
POWERPOWER
POWERPOWER
Power
POWERPOWER
Power =
POWERPOWER
Power = Work
POWERPOWER
Power = Work
POWERPOWER
Power = Work
Time
POWERPOWER
Power = Work
Time
Watt
POWERPOWER
Power = Work
Time
Watt
Joules
POWERPOWER
Power = Work
Time
Watt
Joules
Seconds
POWERPOWER
Power = Work
Time
Watt
Joules
Seconds
Now, let’s try a problem!Now, let’s try a problem!
Trevor pulled a 100 gram weight using a spring scale up the smooth side of a chalk board in 5 s. The spring scaleread 80 grams as she pulled it evenly 25 centimeters. HowMuch work did Trevor do?
Now, let’s try a problem!Now, let’s try a problem!
Trevor pulled a 100 gram weight using a spring scale up the smooth side of a chalk board in 5 s. The spring scaleread 80 grams as he pulled it evenly 25 centimeters. HowMuch work did Trevor do?
WORK = FORCE X DISTANCE
= 80 grams x 25 cm
Now, let’s try a problem!Now, let’s try a problem!
Trevor pulled a 100 gram weight using a spring scale up the smooth side of a chalk board in 5 s. The spring scaleread 80 grams as he pulled it evenly 25 centimeters. HowMuch work did Trevor do?
WORK = FORCE X DISTANCE
= 80 grams x 25 cm
= 2000 joules
Now, let’s try a problem!Now, let’s try a problem!
Trevor pulled a 100 gram weight using a spring scale up the smooth side of a chalk board in 5 s. The spring scaleread 80 grams as he pulled it evenly 25 centimeters. HowMuch work did Trevor do?
WORK = FORCE X DISTANCE
= 80 grams x 25 cm
= 2000 joulesPOWER =
WORK
TIME
Now, let’s try a problem!Now, let’s try a problem!
Trevor pulled a 100 gram weight using a spring scale up the smooth side of a chalk board in 5 s. The spring scaleread 80 grams as he pulled it evenly 25 centimeters. HowMuch work did Trevor do?
WORK = FORCE X DISTANCE
= 80 grams x 25 cm
= 2000 joulesPOWER =
WORK
TIME
Now, let’s try a problem!Now, let’s try a problem!
Trevor pulled a 100 gram weight using a spring scale up the smooth side of a chalk board in 5 s. The spring scaleread 80 grams as he pulled it evenly 25 centimeters. HowMuch work did Trevor do?
WORK = FORCE X DISTANCE
= 80 grams x 25 cm
= 2000 joulesPOWER =
WORK
TIME
2000 joules
Now, let’s try a problem!Now, let’s try a problem!
Trevor pulled a 100 gram weight using a spring scale up the smooth side of a chalk board in 5 s. The spring scaleread 80 grams as he pulled it evenly 25 centimeters. HowMuch work did Trevor do?
WORK = FORCE X DISTANCE
= 80 grams x 25 cm
= 2000 joulesPOWER =
WORK
TIME
2000 joules
5 seconds
Now, let’s try a problem!Now, let’s try a problem!
Trevor pulled a 100 gram weight using a spring scale up the smooth side of a chalk board in 5 s. The spring scaleread 80 grams as he pulled it evenly 25 centimeters. HowMuch work did Trevor do?
WORK = FORCE X DISTANCE
= 80 grams x 25 cm
= 2000 joulesPOWER =
WORK
TIME
2000 joules
5 seconds400 watts
VelocityVelocity
VelocityVelocity
VELOCITY
VelocityVelocity
VELOCITY =
VelocityVelocity
VELOCITY = DISTANCE
VelocityVelocity
VELOCITY = DISTANCE
VelocityVelocity
VELOCITY = DISTANCE
TIME
Miles or meters
VelocityVelocity
VELOCITY = DISTANCE
TIME
Miles or meters
Seconds or hours
VelocityVelocity
VELOCITY = DISTANCE
TIME
Miles or meters
Seconds or hoursMiles per hourMeter per second
Let’s now try a problem!Let’s now try a problem!
Ryan ran 600 meter in 50 seconds, what is his Velocity?
Let’s now try a problem!Let’s now try a problem!
Ryan ran 600 meter in 50 seconds, what is his Velocity?
VELOCTIY
Let’s now try a problem!Let’s now try a problem!
Ryan ran 600 meter in 50 seconds, what is his Velocity?
VELOCTIY =
Let’s now try a problem!Let’s now try a problem!
Ryan ran 600 meter in 50 seconds, what is his Velocity?
VELOCTIY = DISTANCE
Let’s now try a problem!Let’s now try a problem!
Ryan ran 600 meter in 50 seconds, what is his Velocity?
VELOCTIY = DISTANCE
Let’s now try a problem!Let’s now try a problem!
Ryan ran 600 meter in 50 seconds, what is his Velocity?
VELOCTIY = DISTANCE
TIME
Let’s now try a problem!Let’s now try a problem!
Ryan ran 600 meter in 50 seconds, what is his Velocity?
VELOCTIY = DISTANCE
TIME
600 meters
Let’s now try a problem!Let’s now try a problem!
Ryan ran 600 meter in 50 seconds, what is his Velocity?
VELOCTIY = DISTANCE
TIME
600 meters
50 seconds
Let’s now try a problem!Let’s now try a problem!
Ryan ran 600 meter in 50 seconds, what is his Velocity?
VELOCTIY = DISTANCE
TIME
600 meters
50 seconds12 meters/second
ACCELERATIONACCELERATION
ACCELERATIONACCELERATION
ACCELERATION
ACCELERATIONACCELERATION
ACCELERATION =
ACCELERATIONACCELERATION
ACCELERATION =
VELOCITY ENDING
ACCELERATIONACCELERATION
ACCELERATION =
VELOCITY ENDING
ACCELERATIONACCELERATION
ACCELERATION =
VELOCITY ENDING
VELOCITYSTARTING
ACCELERATIONACCELERATION
ACCELERATION =
VELOCITY ENDING
VELOCITYSTARTING
TIME
ACCELERATIONACCELERATION
ACCELERATION =
VELOCITY ENDING
VELOCITYSTARTING
TIME
ACCELERATIONACCELERATION
ACCELERATION =
VELOCITY ENDING
VELOCITYSTARTING
TIME
Meters/secondMiles/hour
ACCELERATIONACCELERATION
ACCELERATION =
VELOCITY ENDING
VELOCITYSTARTING
TIME
Meters/secondMiles/hour
ACCELERATIONACCELERATION
ACCELERATION =
VELOCITY ENDING
VELOCITYSTARTING
TIME
Meters/secondMiles/hour
Meters/secondMiles/hour
ACCELERATIONACCELERATION
ACCELERATION =
VELOCITY ENDING
VELOCITYSTARTING
TIME
Meters/secondMiles/hour
Meters/secondMiles/hour
Seconds/hours
ACCELERATIONACCELERATION
ACCELERATION =
VELOCITY ENDING
VELOCITYSTARTING
TIME
Meters/secondMiles/hour
Meters/secondMiles/hour
Seconds/hours
ACCELERATIONACCELERATION
ACCELERATION =
VELOCITY ENDING
VELOCITYSTARTING
TIME
Meters/secondMiles/hour
Meters/secondMiles/hour
Seconds/hours
ACCELERATIONACCELERATION
ACCELERATION =
VELOCITY ENDING
VELOCITYSTARTING
TIME
Meters/secondMiles/hour
Meters/secondMiles/hour
Seconds/hoursMeters/second/secondMiles/hour/hour
OK - Let’s try an acceleration OK - Let’s try an acceleration problemproblem
OK - Let’s try an acceleration OK - Let’s try an acceleration problemproblem
Brandon is traveling in his bike at 3 m/s. He then speeds up Going down hill and at the bottom of the hill he is traveling 7 m/s. 8 seconds was the time he took to bike down the hill. What is his acceleration rate?
OK - Let’s try an acceleration OK - Let’s try an acceleration problemproblem
Brandon is traveling in his bike at 3 m/s. He then speeds up Going down hill and at the bottom of the hill he is traveling 7 m/s. 8 seconds was the time he took to bike down the hill. What is his acceleration rate?
ACCELERATION = VELOCITY VELOCITYEND START
TIME
OK - Let’s try an acceleration OK - Let’s try an acceleration problemproblem
Brandon is traveling in his bike at 3 m/s. He then speeds up Going down hill and at the bottom of the hill he is traveling 7 m/s. 8 seconds was the time he took to bike down the hill. What is his acceleration rate?
ACCELERATION = VELOCITY VELOCITYEND START
TIME
3 m/s
OK - Let’s try an acceleration OK - Let’s try an acceleration problemproblem
Brandon is traveling in his bike at 3 m/s. He then speeds up Going down hill and at the bottom of the hill he is traveling 7 m/s. 8 seconds was the time he took to bike down the hill. What is his acceleration rate?
ACCELERATION = VELOCITY VELOCITYEND START
TIME
3 m/s7 m/s
OK - Let’s try an acceleration OK - Let’s try an acceleration problemproblem
Brandon is traveling in his bike at 3 m/s. He then speeds up Going down hill and at the bottom of the hill he is traveling 7 m/s. 8 seconds was the time he took to bike down the hill. What is his acceleration rate?
ACCELERATION = VELOCITY VELOCITYEND START
TIME
3 m/s7 m/s
OK - Let’s try an acceleration OK - Let’s try an acceleration problemproblem
Brandon is traveling in his bike at 3 m/s. He then speeds up Going down hill and at the bottom of the hill he is traveling 7 m/s. 8 seconds was the time he took to bike down the hill. What is his acceleration rate?
ACCELERATION = VELOCITY VELOCITYEND START
TIME
3 m/s7 m/s
8 seconds
OK - Let’s try an acceleration OK - Let’s try an acceleration problemproblem
Brandon is traveling in his bike at 3 m/s. He then speeds up Going down hill and at the bottom of the hill he is traveling 7 m/s. 8 seconds was the time he took to bike down the hill. What is his acceleration rate?
ACCELERATION = VELOCITY VELOCITYEND START
TIME
3 m/s = 4m/s7 m/s
8 seconds
OK - Let’s try an acceleration OK - Let’s try an acceleration problemproblem
Brandon is traveling in his bike at 3 m/s. He then speeds up Going down hill and at the bottom of the hill he is traveling 7 m/s. 8 seconds was the time he took to bike down the hill. What is his acceleration rate?
ACCELERATION = VELOCITY VELOCITYEND START
TIME
3 m/s = 4m/s7 m/s
8 seconds4 / 8 = 1/2 meters/sec/sec
OK - Let’s try an acceleration OK - Let’s try an acceleration problemproblem
Brandon is traveling in his bike at 3 m/s. He then speeds up Going down hill and at the bottom of the hill he is traveling 7 m/s. 8 seconds was the time he took to bike down the hill. What is his acceleration rate?
ACCELERATION = VELOCITY VELOCITYEND START
TIME
3 m/s = 4m/s7 m/s
8 seconds4 / 8 = 1/2 meters/sec/sec
1/2 or .5 m/s/s