nanoscale investigation-x ray diffraction
TRANSCRIPT
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Investigation in nanoscale
X-RAY DIFFRACTION
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X-ray generation
Wavelength range:0.5-2.5
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Bremsstruhlung radiation-B re m sstra h lu n g p ro d u ce d b y ra p id d e ce le ra tio n o f a h ig h
.e n e rg y e le ctro n in th e e le ctric fie ld o f a n a to m ic n u cle u s
:// . . / /h ttp e n w ikip e d ia o rg w iki B re m sstra hlu n g
impactbeforjustelectronofvelocityv,
masselectronm,volts30,000oforderin theeV,
2
1 2mveVKE ==
T h e d e ce le ra te d e le ctro n e m its e n e rg y
( - ).x ray
http://upload.wikimedia.org/wikipedia/commons/1/1e/Bremsstrahlung.svg -
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( , ) W h ite p o ly ch ro m a tic co n tin u o u sra d ia tio n
-C o n tin u o u s X ra yspe ctrum of m olbd en um
( )Mo as of a function of
.a p p lie d v o lta g e
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W h e n a p p lie d v o lta g e e xc e ss a critica l v a lu e C h a ra cte ristic
.R a d ia tio n o ccu rs
C h a ra cte ristic e m issio n s su p e rim p o se o n co n tin u o u s sp e ctru m a n d. -th e y a re n a rro w a n d in te n se T h e y a re u sed fo r x R a y d iffra ctio n
.b eca u se o f th ey are ap p roxim a te m o n och ro m atic
Characteristics radiation
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2p str ns t o n
Characteristic radiation lines, , , .,fall into several sets K L M
in the order of increasing.wavelength Only K line is used
- .in x ray diffraction
3p s1tr ns t on
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K doublet
E le ctro n S p in sta te2 P /3 2
E le ctro n S p in sta te
2 P / 2
K istwice asstrong as K 2
U n re solve d K lineistaken
as w eig h ted av erag e ofw ave len g th of K and K 2
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X-Ray and Braggs law
A crystal is viewed as a planecontaining several lattice point. AtBraggs angle the reflective beamsare in phase and reinforced beamis obtained.
http://upload.wikimedia.org/wikipedia/commons/0/0a/Bragg_diffraction.pnghttp://upload.wikimedia.org/wikipedia/commons/0/0a/Bragg_diffraction.png -
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X-RAY spectroscopy
A crystal with planes of known spacing or a grating ofknow spacing can be set at particular angle , thus,the incident wavelength of the radiation can be
determined. Intensity of diffraction at that particular angle is
recorded. Repeat this test for various diffraction angle , a
wavelength-x-ray intensity curve can be plotted.Te st sa m p le -generates xR a y
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X-Ray diffractometerCrystal structure analysis: With known x-Ray irradiation, a crystals
lattice spacing can be determined by thediffraction pattern.
Three methods :
method Laue Variable
(polychromatic)Fixed
Rotating-crystal Fixed
(monochromatic)
Variable in part
powder Fixed(monochromatic)
variable
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Laue method
First x-ray diffraction ever used A white x-ray irradiation falls on a crystal Each set of planes in the crystal, selects and
diffracts a particular wavelength thatsatisfies Braggs law.
S p o ts lyin g o n o n ecu rv e a re tra n sm itte d
d iffra ctio n s fro mp lan es b elon g s to on e
.z o n e
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Rotating crystal method Uses the characteristic x-ray
irradiations The crystal is mounted with one
of its axes or importantcrystallographic direction,
normal to the incident x-ray. The crystal axis or
crystallographic directioncoincides with the axis of the
cylindrical film. The crystal rotates, a particular
set of lattice plane will satisfiesBraggs law at a particularangle and at that instant adiffraction pattern will be
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Powder method
Sample is reduced to very fine powder.Each microscopic grain is a crystal.
Same principle as rotating crystal
method. Only that in powder form,each tiny crystal is orientated atrandom angle with respect to incidentbeam. The mass of powder in fact is
equivalent to a single crystal rotatedat all possible axes. Therefore, alllattice planes are capable ofdiffraction.
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( )a T h e d iffra cte d ra ys fro m a sin g le cry sta l p o in t to d iscre te d ire ctio n s
. ( )e a ch co rre sp o n d in g to a fa m ily o f d iffra ctio n p la n e s S p o t p a tte rn
( ) ( )b The diffractionpattern from a polycrystalline powder sample formsa se rie s d iffra ctio n co n e s if la rg e n u m b e r o f cry sta ls o rie n te d ra n d o m ly in
- .th e spa ce a re cov e re d b y th e in cid e n t x ra y b e a m E a ch d iffra ctio n con eco rre sp o n d s to th e d iffra ctio n fro m th e sa m e fa m ily o f cry sta llin e p la n e s
. ( )in a ll th e p a rticip a tin g g ra in s R in g p a tte rn
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,Jo h n H a rt,n a n o m a n u fa ctu rin g
U n iv e rsity o f M ich ig a n
,T h e co m p o sitio n size a n dd e g re e o f cry sta llin e o f th esam p le m a te ria l ca n b e
e x tra cte d fro m th e rin gp o sitio n s a n d ra d ia l w id th s o f
.th e se rin g s
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S ch e m a ticd ra w in g o f a X
R a yD iffra cto m e te r
: -S X R a y so u rce:H ro ta tio n ta b le, : -A B X R a y o p tics:F re ce iv in g slit o f
the detector
,D iffra ctio n p a tte r a b o u t-on e h alf of th e e n tire ran g e
.o f 21
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O n ly cry sta llin em a te ria l g iv e s
.na rrow pe aksFro m th e
lo ca tio n s o f th e se
( ),p ea ks rin g sla ttice sp a cin gca n b e
.ca lcu la te d
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Calculation of DiffractionIntensity
Lattice is considered as gratings for thedetermination of diffraction direction(Braggs law)
In real X-Ray irradiation, lattice cannotbe considered a not a grating. For thecalculation of diffraction intensity, X-ray is considered as photons of highenergies and the intensity is the result
of photon-electron, photon-nucleusinteraction. The emission of diffractedbeams is a result of interference ofscattered X-Rays, but not the incidentX-Ray,
Eff t d d b th
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Effects produced by thepassage of X-ray through
matter
C on trib u te to
ba ckgrou n dn o ise
Form s
D iffractio np a tte rn
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Factors of intensitycalculation
Structure factor Multiplicity factor
Absorption factor Temperature
factor
D ete rm in e dby the
stru ctu re o fthe crystal
A ccou n t for sam p le-a b sorp tio n o f x ra ya n d th e re su lta n t
.te m p e ra tu re rise
( ) MeApFI 22
2
2
cossin
2cos1
+=
Me
2( )A
F
p
,I relative integrated
intensity
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Example of intensitycalculation
, -C op p er face cen tered cub e
T h e in te n sity a n a lysisg iv e s m o re d e ta ils o n
the a tom arran ge m e nt.o f th e u n it ce ll
To g e th e r w ith th e
la ttice sp a cin ge x tra cte d fro m th e
,d iffra ctio n a n g le th estru ctu re o f th e cry sta l
.ca n b e p re d icte d
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Intensity in x-ray scattering Scattering factors is proportional to the atomic number. The
scattering factor of atoms of similar atomic numbers areclose, therefore it is difficult to identify similar atoms.
Problem materials: compound containing N andO(polymers) aluminosilicates, Al, Si.
the peak of maximum is taken as 100 and all the otherpeaks are scaled accordingly. A set of peaks and theirheights are adequate for phase identification. Sometimesaccurate measurement of peak positions is required.
If preferred orientation exist for a material, it is likely thatonly those orientations will be manifested.
Sample preparation affects the scattering intensity. It is
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Broadening of diffractionpeak
, -B fu ll p e a k w id th a t h a lfm ax im u m
21=B
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http://prism.mit.edu/xray
Particle size and Peakwidth
P. Scherrer, Bestimmung der Grsse und der inneren Struktur vonKolloidteilchen mittels Rntgenstrahlen, Nachr. Ges. Wiss.Gttingen26 (1918) pp 98-100.
J.I. Langford and A.J.C. Wilson, Scherrer after Sixty Years: A Survey
and Some New Results in the Determination of Crystallite Size,J.Appl. Cryst.11 (1978) pp 102-113.
BB
t
cos9.0=
( )eak width B is inversely ( )roportional to crystallite size t
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http://prism.mit.edu/xray
Particle size is not the onlyattribution to peak boardening
66 67 68 69 70 7 72 73 742 ( .)eg These diffraction patterns were produced from the xact same sample , ,Two different diffractometers with different optical configurations were use h e a p p a r e n t p e a k b r o a d e n i n g i s du e s o l el y t o t h e i n s t ru m e n t at i o n
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http://prism.mit.edu/xray
The Laue Equations describe the intensity of adiffracted peak from a single parallelopipeden
crystal
N1, N2, and N3 are the number of unit cells along the a1, a2, and a3directions
When N is small, the diffraction peaks become broader
The peak area remains constant independent of N
( ) ( )( ) ( )
( ) ( )( ) ( )
( )( )( ) ( ) 3
2
33
2
2
2
22
2
1
2
11
2
2
/sin/sin
/sin/sin
/sin/sin
assaNss
assaNss
assaNssFII
O
O
O
O
O
O
e
=
0
500
1000
1500
2000
2500
3000
3500
4000
4500
5000
2.4 2.9 3.4
N=99
N=20
N=10
N=5
N=2
0
50
100
150
200
250
300
350
400
2.4 2.9 3.4
N=20
N=10
N=5
N=2
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Stress measurement
U n ifo rm e d stra inre su lt in sh ift in 1 B ,
w ith n o a ffe ct on
.p ro file o f th e p e a kU sed fo r
m ea surem en t of.m a cro stre ss
-N o n u n ifo rm e dm icro stra in d istu rb s
th e g rain sha p e b u t
n o d isto rtio n to th ee n tire v o lu m e o f th e.sam p le T h e re sults
is n o t sh ift in 1B ,b u t th e p ro file o f th e
p e a k w ill b e a lte re d
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XRD Strain measurement
( )
2
22
2
11
2211
2
sincosstressbiaxial
sin1
+=
++
=
EEd
dd
o
o
,In re a lte st w illb e ch a n g e d sev e ra ltim e sa n d d11 .recorded
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Definition of
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Stress measurementExample
C o m p re sse d th in g o ld film