national talent search examination (ntse) 2019...

NATIONAL TALENT SEARCH EXAMINATION (NTSE) 2019 STAGE-IMENTAL ABILITY TEST [MAT]

Motion Education Pvt. Ltd., 394-Rajeev Gandhi Nagar, Kota-5

www.motion.ac.in [email protected] 1800-212-1799, 08003899588

TM

SOLUTION - NTSE (Stage-I) 2019

1. (2)

A, D, I, P, Y 1 4 9 16 25

2. (4)YX, UT, QP, ML, IH

25 21 17 13 9

–4 –4 –4 –4

Y U Q M I

24 20 16 12 8

–4 –4 –4 –4

X T P L H

3. (2)ACF, GIL, MOR, SUX

1 7 13 19

+6 +6 +6

A G M S

3 9 15 21

+6 +6 +6

C I O U

6 12 18 24

+6 +6 +6

F L R X

4. (1)YB, WD, UF, SH,QJ

25 23 21 19 17

–2 –2 –2 –2

Y W U S Q

2 4 6 8 10

+2 +2 +2 +2

B D F H J

SOLUTION_MATSOLUTION_MAT2



5. (3)

A, E, I, , U O1 5 9 15 21

+4 +4 +6 +6

B, F, J, , V P2 6 10 16 22

+4 +4 +6 +6

C, G, K, , W Q3 7 11 17 23

+4 +4 +6 +6

6. (3)

ABCD, BDFH, CFIL, , EJOTDHLP1 2 3 4 2 4 6 8 3 6 9 12 4 8 12 16 5101520

7. (2)

4 8 12 16 20

+4 +4 +4 +4

D H L P T

+4

X24

8. (4)ZYAB, VUEF, RQIJ, NMMN, JIQR

Z

V

R

J I

N

Y

U

Q

M M N

A

E

I

Q

B

F

J

R

26

22

18

10

14

25

21

17

9

13 13 14

1

5

9

17

2

6

10

18

–4

–4

–4

–4

–4

–4

–4

–4

+4

+4

+4

+4

+4

+4

+4

+4

9. (1)

1, 2, 6, 15, , 56 31

+1+112 22 32 42 52

+4 +9 +16 +25

10. (4)

100, 50, 1

333

, 25, 20, 216 3

100 1 100 2 100 3 100 4 100 5 100 6

SOLUTION_MATSOLUTION_MAT 3



11. (3)

17, 16, 8, —19, –83

–113

–8 –27 –6423 33 34

12. (3) 6, 24, 60, 120, 210 1x2x3 2x3x4 3x4x5 4x5x6 5x6x7

13. (2)

49, 64, 56, 57, 63, 50, 70, 43

–7 –7 –7

+7 +7 +7

14. (1)

4, 13, 31, 67, 139, 283

×2+5 ×2+5 ×2+5 ×2+5 ×2+5

15. (3)1, 1, 2, 3, 5, 8, 13, 211 + 1 =21 + 2 = 32 + 3 = 53 + 5 = 85 + 8 = 138 + 13 = 21

16. (4)3, 21, 81, 192, 375, 6483 x 13 = 33 x 23 = 243 x 33 = 813 x 43 = 1923 x 53 = 3753 x 63 = 648

17. (4)

18. (4)

19. (4)

20. (3)

F

E

C




21. (3)

B

H

K

22. (2)

U.PA

T.M

23. (2)7 × 4 – 8 × 3 + 39 3= 28 – 24 + 3= 41 – 24= 17

24. (2)A C E = 12 32 52

1 9 25B I G = 22 92 72

4 81 49D O G = 42 (15)2 72

16 225 49

25. (1)S H O U L D E R B O X I N G H O R NT J S N M A G Z R S Y C P H J S Z P

26. (4)

C

D

A

E

L

L

L

L

E

A

D

C

T

R

I

E

G

G

E

I

R

T

N

H

O

T

R

R

T

O

H

N

27. (1)Only Argument I is strong




28. (3)

71

3

2

456

1, 2, 3, 4, 12, 34, 13, 24, 1234= 9 rectangles

29. (3)

1 2 3

4 5 6

1, 2, 3, 4, 5 ,6, 12, 23, 123, 45, 56, 456, 14, 25, 36, 1245, 2356, 12345618 Parallelograms

30. (2)

31. (2)

32. (3)

QUALITY

33. (4)

247596

34. (4)

FAMILY




35. (1)

NhRqSy

36. (4)

37. (2)

38. (1,3)

39. (4)By observation



42. (3)

43. (3)

44. (1)




45. (4)

46. (1)

47. (1)












56. (4)

Man

Son

3Sons 3Sons 3Sons 3Sons

SonSon Son

Total = 17 malesDirection: Q. 57 to 60

CB FSister Brother

D

A E

SonSon

Daughter

57. (1)Cousin

58. (3)Niece

59. (3)

60. (1)Brother/Sister

61. (1)

A

D

C

B

EastWest

North

South

62. (3)N

NE

E

SE

S

SW

W

NW




63. (2)

F

D

Male

64. (4)G

65. (2)Uneducated, Unemployed and rural women.

66. (4)E

67. (3)E, F

68. (1)4, 24, 40, 44, 48, 64, 84

69. (3)

5 1 4 7 3 9 8 5 7 2 6 3 1 5 8 6 3 8 5 2 2 4 6 4 9 6

70. (3)Let number is x3 < x < 8 and 6 < x < 106 < x < 8So number is ‘7’(x = 7)

71. (4)Position from last = 49 + 1 – 18 = 32

72. (2)

17 Dec 2002 6 2 0 6 17 31

7 7

3 Remainder = Tuesday + 4 = Saturday

22 Dec 2004 6 4 1 6 22 39

7 7

= 4 Remainder

Wednesday + 4 = Sunday




73. (3)Two month will have the some calender if the period between them is divisible by 7 Now(1) June + July + Aug + Sep = 30 + 31 + 31 + 30 = 122 (not divisible by 7)(2) Apr + May + June + JUly + Aug + Sep + Oct = 30 + 31 + 30 + 31 + 31 + 30 + 31 = 217 (notdivisible by 7)(3) Apr + May + June = 30 + 31 + 30 = 91 (divisible by 7)(4) October + November = 31 + 30 = 61 (Not divisible by 7)

74. (3)25th August is a ThursdaySo 22nd August is a mondaySo Monday fall on 1st, 8th, 15th and 22nd and 29th of AugustThus there are five modays

75. (2)26 × 72 4 – 5 + 2= 26 × 18 – 5 + 2= 468 – 5 + 2= 470 – 5= 465

76. (4)A + B > C + D B > C + D – A ....(1)D + A < B + C D + A – C < B ....(2)By (1) & (2)B > D

77. (1)AEDBC

78. (3)ACEBD

79. (2)n = 512 (n – 2) = 12 (5 – 2) = 12 × 3 = 36

80. (1)n = 3(n – 2)3 = (3 – 2)3 = 13 = 1

81. (2)

2–15– 63– 4




82. (3)

6 –32–51– 4

83. (3)

28,58,68,88,78,1882,85,86,–,87,81

84. (3)

85. (3)(36 – 4) 8 – 44 x 8 – 2 x 16 + 1

86. (2)A is 6th from leftB is 10th from rightAfter exchanging their positionsB is 6th from leftA is 10th from right8 persons are between them. SoA is 15th from leftTotal = 15 + 10 – 1 = 25 – 1 = 24

87. (4)

88. (1)

89. (4)

90. (4)

91. (4)

92. (3)

93. (2)

94. (2)By Observation






97. (3)All except Pea are root vegitables.

98. (1)All except 105 are divisible by 13.

99. (3)All except TTA consist 2 vowels

100. (2)All except carrom are outdoor games.

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