nature of the solutions
DESCRIPTION
Nature of the SolutionsTRANSCRIPT
Nature of the Solutions
Nature of the Solutions
Value of the discriminant Type and number of Solutions Example of graph
Positive Discriminant
b 4ac > 0 Two Real Solutions
If the discriminant is a perect square the roots are rational. Otherwise, they are irrational.
Discriminant is Zero
b 4ac = 0 One Real Solution
Negative Discriminant
b 4ac < 0 No Real Solutions Two Imaginary Solutions
Example 1 Quadratic Equation: y = x + 2x + 1 a = 1
b = 2
c = 1
The discriminant for this equation is
2 - 41 1= 4 4 = 0
Since the discriminant is zero, there should be 1 real solution to this equation. Below is a picture representing the graph and one solution of this quadratic equation
Graph of y = x + 2x + 1
Calculate the discriminant to determine the number and nature of the solutions of the following quadratic equation:
y = x 2x + 1
Answer
In this quadratic equation,
y = x 2x + 1
a =1
b = 2
c = 1
Using our general formula, the discriminant is (-2) 41 1 = 4 4 = 0 Since the discriminant is zero, we should expect 1 real solution which you can see pictured in the graph below.
Use the discriminant to find out the nature and number of solutions:
y = x x 2
Answer
In this quadratic equation,
y = x x 2 and its solution
a =1
b = 1
c = 2
Discriminant: b 4(a)(c) = (-1) 4(1)(-2) 1 -8 = 1 + 8 = 9
Since the discriminant is positive, there should be 2 real solutions to this equation.
Calculate the discriminant to determine the nature and number of solutions:
y = x 1
Answer
In this quadratic equation,
y = x 1
a = 1
b = 0
c = 1
Discriminant: b 4(a)(c) = (0) 4(1)(-1) -4 = 4
Since the discriminant is positive, we have two real solutions. The exact solutions are show below.
Calculate the discriminant to determine the nature and number of solutions:
y = x + 4x + 5
Answer
In this quadratic equation,
y = x + 4x + 5
a =1
b = 4
c = 5
the discriminant = b 4(a)(c) = 4 4(1)(5) 16 20 = - 4
Since the discriminant is negative , there are noreal solutions to this quadratic equation. The only solutions are imaginary.
Below is a picture of this quadratic's graph
Find the discriminant to determine the nature and number of solutions:
y = x + 4
Answer
y = x + 4
a =1
b = 0
c = 4
the discriminant = b 4(a)(c) = 0 4(1)(4) 16
Since the discriminant is negative , there are two imaginary solutions to this quadratic equation.
The solutions are 2i and -2i Below is a a picture of this equations graph Find the discriminant to determine the nature and number of solutions:
y = x + 25
Answer
y = x + 25
a =1
b = 0
c = 25
the discriminant = b 4(a)(c) = 0 4(1)(25) 100 = 100
Since the discriminant is negative , there are two imaginary solutions to this quadratic equation.
The solutions are 5i and -5i