net and total change sect. 6-b. remember rate of change = derivative f(b) – f(a) is the change in...

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NET AND TOTAL CHANGE Sect. 6-B

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Page 1: NET AND TOTAL CHANGE Sect. 6-B. Remember Rate of change = derivative f(b) – f(a) is the change in y from a to b This is the net change Net Change Net

NET AND TOTAL CHANGESect. 6-B

Page 2: NET AND TOTAL CHANGE Sect. 6-B. Remember Rate of change = derivative f(b) – f(a) is the change in y from a to b This is the net change Net Change Net

Remember• Rate of change = derivative• f(b) – f(a) is the change in y from a to b

• This is the net change

Net Change

Net or Total Change = integral of rate of change

b

a

b

a

dxxfafbfafbfdxxf )(')()( that followsit )()()(' since

Page 3: NET AND TOTAL CHANGE Sect. 6-B. Remember Rate of change = derivative f(b) – f(a) is the change in y from a to b This is the net change Net Change Net

•If V(t) is the volume of water in a reservoir at time t, then its derivative V’(t) is the rate at which water flows into the reservoir. So the integral of V’(t) is the change in the amount of water in the reservoir between an initial time and final time

Examples

b

a

aVbVdxxV )()()('

Page 4: NET AND TOTAL CHANGE Sect. 6-B. Remember Rate of change = derivative f(b) – f(a) is the change in y from a to b This is the net change Net Change Net

•If C(t) is the concentration of a chemical reaction at time t, then the rate of the reaction is the derivative C’(t). Such that the integral of C’(t) is the change in concentration of C from an initial time and final time

Examples

b

a

aCbCdxxC )()()('

Page 5: NET AND TOTAL CHANGE Sect. 6-B. Remember Rate of change = derivative f(b) – f(a) is the change in y from a to b This is the net change Net Change Net

•If an object moves along a straight line with a position x(t), then its velocity is such that the integral of v(t) is the net change of position, or DIPLACEMENT of the particle during the same time period. Distance is the integral of

Examples

b

a

b

a

axbxtxdxtv )()()(')( nt displaceme

)(')( txtv

)(tv

Page 6: NET AND TOTAL CHANGE Sect. 6-B. Remember Rate of change = derivative f(b) – f(a) is the change in y from a to b This is the net change Net Change Net

1.) If

find )2(f

4)0( and 33)(' 2 fxxf

Page 7: NET AND TOTAL CHANGE Sect. 6-B. Remember Rate of change = derivative f(b) – f(a) is the change in y from a to b This is the net change Net Change Net

2.) If

find )4(f

3)2( and )('2

fxx

xxf

Page 8: NET AND TOTAL CHANGE Sect. 6-B. Remember Rate of change = derivative f(b) – f(a) is the change in y from a to b This is the net change Net Change Net

3.) The rate at which water is dripping into a tub of water

is given by (gal/hour). Find how much water

entered the tub from t = 1 to t = 3 hours?1

2)(

t

ttr

Page 9: NET AND TOTAL CHANGE Sect. 6-B. Remember Rate of change = derivative f(b) – f(a) is the change in y from a to b This is the net change Net Change Net

4) The birth rate for a population of animals is given by

and the death rate is given by

a) About how many total births occurred in the years t = 0 to t = 6?

b) What was the net change in the population from t = 0 to t = 10?

3

cos1545)(

ttd

45

6

cos30)(

t

tb

Page 10: NET AND TOTAL CHANGE Sect. 6-B. Remember Rate of change = derivative f(b) – f(a) is the change in y from a to b This is the net change Net Change Net

a) About how many total births occurred in the years t = 0 to t = 6?

dttb6

0

)( Birth Total 456

cos30)(

t

tb

Page 11: NET AND TOTAL CHANGE Sect. 6-B. Remember Rate of change = derivative f(b) – f(a) is the change in y from a to b This is the net change Net Change Net

b) What was the net change in the population from t = 0 to t = 10?

10

0

)()(changeNet tdtb

dttt

10

0 3

cos154545

6

cos30

The population is 62 members less after ten years, than when it began

Page 12: NET AND TOTAL CHANGE Sect. 6-B. Remember Rate of change = derivative f(b) – f(a) is the change in y from a to b This is the net change Net Change Net

5) A tank contains 30 gallons of water. Water is pumped into the tank at the rate of 8 gal/min. Water leaks out of the tank at a rate of gallons per minute for

minutes.

Figure 6.21

1t1200 t

a) How many gallons of water leak out of the tank from time t = 0 to t = 3 minutes?

Page 13: NET AND TOTAL CHANGE Sect. 6-B. Remember Rate of change = derivative f(b) – f(a) is the change in y from a to b This is the net change Net Change Net

3) A tank contains 30 gallons of water. Water is pumped into the tank at the rate of 8 gal/min. Water leaks out of the tank at a rate of gallons per minute for

minutes.

Figure 6.21

1t1200 t

b) How many gallons of water are in the tank at time t = 3 minutes?

Page 14: NET AND TOTAL CHANGE Sect. 6-B. Remember Rate of change = derivative f(b) – f(a) is the change in y from a to b This is the net change Net Change Net

5) A tank contains 30 gallons of water. Water is pumped into the tank at the rate of 8 gal/min. Water leaks out of the tank at a rate of gallons per minute for

minutes.

Figure 6.21

1t1200 t

c) Write an expression for A(t), the total amount (number of gallons) in the tank at time t.

Page 15: NET AND TOTAL CHANGE Sect. 6-B. Remember Rate of change = derivative f(b) – f(a) is the change in y from a to b This is the net change Net Change Net

5) A tank contains 30 gallons of water. Water is pumped into the tank at the rate of 8 gal/min. Water leaks out of the tank at a rate of gallons per minute for

minutes.

Figure 6.21

1t1200 t

d) At what time t is the amount of water in the tank a maximum?

Page 16: NET AND TOTAL CHANGE Sect. 6-B. Remember Rate of change = derivative f(b) – f(a) is the change in y from a to b This is the net change Net Change Net

Assignment

Workshete 6-B: Net Change