noise n. libatique ece 293 2 nd semester 2008-09
TRANSCRIPT
http://universe-review.ca
Optical Detection: Optical Detection: Biomolecular Biomolecular SignalingSignaling
11-cis-retinal trans-retinal rodopsin changes shape makes opsin sticky to transducin GDP from transducin falls off and replaced by GTP activated opsin binds to phosphodiesterasewhich aqcuires the ability to cut cGMP lower cGMP conc. causes ion channels to close lowering Na concentration in cell and lowers cell potential current transmitted down optic nerve to brain
Optical DetectionOptical Detection Opto-electronic Detection vs. Others Opto-electronic Detection vs. Others
(Biomolecular Signalling) (Biomolecular Signalling) Limits of communication, bit error Limits of communication, bit error
raterate
Shot NoiseShot Noise
Shot Noise, Johnson Noise, 1/f NoiseShot Noise, Johnson Noise, 1/f Noise Shot Noise ~ Poisson ProcessShot Noise ~ Poisson Process
very small
P(0,) + P(1,) = 1 P(1,) = a(); a = rate constant No arrivals over + ; P(0, + ) P(0, + ) = P(0,) P(0,) What is P(0, )? In a pulse of width what is the
probability of it containing N photons? P(N)
What is the detection limit?
A perfect quantum detector is used to receive an optical pulse train of marks and spaces. If even one photon arrives, it will be detected and counted as a mark. The absence of light over a clock period is a space. Every pulse will have a random number of photons. On average, how many photons should be sent per pulse, if it is desired that only 1 ppb be misinterpreted as a space when in fact it is a mark?
Poisson
dP(0,)/d = - a P(0, ) P(0, ) = e- a ; What about P(N)? N photons at a
time? It can be shown that this is a Poisson
process P(N) = (Nm)N e –N
m / N!
Poisson DistributionPoisson Distribution
P(N) = (Nm)N e –Nm / N!Variation is fundamental
N = 6; Only 16% of pulses have 16 photons; e-6 probability of having no photons
Optical Shot Noise
Other Sources
Aside from photon shot noise Background radiation: blackbodies Johnson Noise: thermal motion of
electrons 1/f Noise: conductivity fluctuations Amplifier Noise
Background Radiation
Ptotal = Psignal + Pbackground
MeanSquareCurrentshot proportional to Ptotal
I(W/cm2) = (T/645)4 (T in K) 4.7x10-2 W/cm2 at 300 K Human Body 2 m2 1 kW
Spectrally distributed
http://en.wikipedia.org/wiki/Black_body
1,000 oC
3 K
Bit Error Rates Analog Signals: SNR ratio Digital Signals: BER Telco Links = 10-9
Datacomms and Backplanes = 10-12
Quality Factor Power required to
achieve Q and BER? 0.1 dB significant as fiber losses are low…
http://zone.ni.com/devzone/cda/tut/p/id/3299
Probability Distribution Function
Decision Level
s(0) = expectation current value
s(1) = expectation current value21
20
Id
Output Current
Probability
A10
A01
• Signal + Noise results inbit errors…• Noise statistics of signal, detector, amplifier determine PDF
Probability of Error
p(0) = probability that a space is transmitted
p(1) = probability that a mark is transmitted
A01 = probability that space is seen as mark
A10 = probability that mark is seen as space
P(E) = p(0) A01 + p(1) A10
Assume Gaussian statistics P(E) = Integral[Exp[-x2/2],{x,Q,Infinity}]/Sqrt[2 ]
Design Assume a perfect quantum detector.
Amplifier input impedance is 50 Ohms. Shunt Capacitance 2 pF. Design a 100 Mbps link at 1.5 m. Design for a BER 10-12.
Assume the effective bandwidth required would be 200 MHz (Nyquist Criterion).
Optimize the detector. Minimize the power required to achieve BER. reducing the BW via changing RC, reduce ckt noise, etc……