nucleophilic substitution reactions.pdf

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7/23/2019 Nucleophilic Substitution Reactions.pdf http://slidepdf.com/reader/full/nucleophilic-substitution-reactionspdf 1/13  Dr. Bhanuben Nanavati College of Pharmacy, Mumbai 1 Notes Nucleophilic Substitution Reactions Alkyl halides undergo many reactions in which a nucleophile displaces the halogen atom bonded to the central carbon of the molecule. The displaced halogen atom becomes a halide ion. Some typical nucleophiles are the hydroxy group ( OH), the alkoxy group (RO ), and the cyanide ion ( C N). Reaction of these nucleophiles with an alkyl halide (R&bond;X) gives the following reactions and products:  The halogen ion that is displaced from the carbon atom is called the leaving group , and the overall reaction is called a nucleophilic substitution reaction . Leaving Group For a molecule to act as a nucleus or substrate in a nucleophilic substitution reaction, it must have both a  polar bond  and  good leaving group . For an atom or a group to be a good leaving group, it must be able to exist independently as

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 D r . B h a n u b e n N a n a v a t i C o l l e g e o f P h a r m a c y , M u m b a i 1

Notes

Nucleophilic Substitution Reactions

Alkyl halides undergo many reactions in which a nucleophile displaces the

halogen atom bonded to the central carbon of the molecule. The displaced

halogen atom becomes a halide ion.

Some typical nucleophiles are the hydroxy group (−OH), the alkoxy group (RO−),

and the cyanide ion (−C N). Reaction of these nucleophiles with an alkyl halide

(R&bond;X) gives the following reactions and products:

 The halogen ion that is displaced from the carbon atom is called the leaving

group , 

and the overall reaction is called a nucleophilic substitution reaction . 

Leaving Group

For a molecule to act as a nucleus or substrate in a nucleophilic substitution

reaction, it must have both a polar bond  and a  good leaving group . For an atom

or a group to be a good leaving group, it must be able to exist independently as

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Organic Chemistry-I

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a relatively stable, weakly basic ion or molecule. Groups that act as leaving

groups are always capable of accommodating the negative charge through a

high electronegativity or by delocalization. Because halogen atoms have high

electronegativities and form relatively stable ions, they act as good leaving

groups.

Nucleophilic Substitution Reactions: Mechanisms

Experimental data from nucleophilic substitution reactions on substrates that

have optical activity   (the ability to rotate plane-polarized light) shows that two

general mechanisms exist for these types of reactions. The first type is called

an SN2 mechanism. This mechanism follows second - order kinetics  (the reaction

rate depends on the concentrations of two reactants), and its intermediate

contains both the substrate and the nucleophile and is therefore bimolecular.

 The terminology S N 2  stands for “substitution nucleophilic bimolecular .”

 The second type of mechanism is an S N1 mechanism. This mechanism follows

 first - order kinetics   (the reaction rate depends on the concentration of one

reactant), and its intermediate contains only the substrate molecule and is

therefore unimolecular. The terminology S N 1  stands for “substitution

nucleophilic unimolecular .”

SN2 mechanism

 The alkyl halide substrate contains a polarized carbon halogen bond. The SN2

mechanism begins when an electron pair of the nucleophile attacks the back

lobe of the leaving group. Carbon in the resulting complex is in pentavalent

(trigonal bipyramidal) shape. With the loss of the leaving group, the carbon

atom again regains a tetrahedral (pyramidal) shape; however, its configuration

is inverted.

Figure 1

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 The SN2 mechanism can also be illustrated as shown below.

Figure 2 

Notice that in either picture, the intermediate shows both the nucleophile and

the substrate. Also notice that the nucleophile must always attack from the

side opposite the side that contains the leaving group. This occurs because thenucleophilic attack is always on the back lobe (antibonding orbital) of the

carbon atom acting as the nucleus.

SN2 mechanisms always proceed via backward attack of the nucleophile on the

substrate. This process results in the inversion of the relative configuration,

going from starting material to product. This inversion is often called the

Walden inversion, 

Figure 3

Steric hindrance

SN2 reactions require a rearward attack on the carbon bonded to the leaving

group. If a large number of groups are bonded to the same carbon that bears

the leaving group, the nucleophile's attack should be hindered and the rate of

the reaction slowed. This phenomenon is called steric hindrance. The larger or

bulkier the group(s)-greater the steric hindrance and slower the rate of

reaction. Table-1 shows the effect of steric hindrance on the rate of reaction for

a specific, unspecified nucleophile and leaving group. Different nucleophiles

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and leaving groups would result in different numbers but similar patterns of

results.

SN2 reactions give good yields on 1° (primary) alkyl halides, moderate yields on

2°(secondary) alkyl halides, and poor to no yields on 3° (tertiary) alkyl halides.

Solvent effects

For  protic solvents   (solvents capable of forming hydrogen bonds in solution) -

an increase in the solvent's polarity results in a decrease in the rate of SN2

reactions. This decrease occurs because protic solvents solvate the nucleophile,

thus lowering its ground state energy. Because the energy of the activated

complex is a fixed value, the energy of activation becomes greater and,

therefore, the rate of reaction decreases.

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Polar aprotic solvents   (solvents that cannot form hydrogen bonds in solution)

do not solvate the nucleophile but rather surround the accompanying cation,

thereby raising the ground state energy of the nucleophile. Because the energy

of the activated complex is a fixed value, the energy of activation becomes less

and, therefore, the rate of reaction increases.

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Multi-stepreactions haveintermediates anda several transitionstates (TS).

In an SN1 there isloss of the leavinggroup generates anintermediate carbo-cation which isthen undergoes a

rapid reaction withthe nucleophile..

General case  SN1 reaction 

Let's look at how the various components of the reaction influence the reactionpathway:

Alkyl group (R-)

Reactivity order: (CH3)3C- > (CH3)2CH- > CH3CH2- > CH3-

In an SN1 reaction, the rate determining step is the loss of the leaving group to

form the intermediate carbocation. The more stable the carbocation is, the

easier it is to form, and the faster the SN1 reaction will be. Some students fall

into the trap of thinking that the system with the less stable carbocation will

react fastest, but they are forgetting that it is the generation of the carbocation

that is rate determining. Since a carbocation intermediate is formed, there is

the possibility of rearrangements (e.g.  1,2-hydride or 1,2-alkyl shifts) to

generate a more stable carbocation. This is usually indicated by a change in

the position of the substituent or a change in the carbon skeleton of the

product when compared to the starting material.

Leaving Group (LG) 

 The only event in the rate determining step of the SN1 is breaking the C-LG 

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bond. Therefore, there is a very strong dependence on the nature of the leaving

group, the better the leaving, the faster the SN1 reaction will be.

Nucleophile (Nu) 

Since the nucleophile is not involved in the rate determining step, the nature of

the nucleophile is unimportant in an SN1 reaction. However, the more reactive

the nucleophile, the more likely an SN2 reaction becomes.

Stereochemistry 

In an SN1, the nucleophile attacks the planar carbocation.

Since there is an equally probability of attack on each face

there will be a loss of stereochemistry at the reactive center

as both products will be observed.

Solvent 

Since the hydrogen atom in a polar protic solvent is highly positively charged, it can

interact with the anionic nucleophile which would negatively affect an SN2, but it does

not affect an SN1 reaction because the nucleophile is not a part of the rate-determining

step (See SN2 Nucleophile). Polar protic solvents actually speed up the rate of the

unimolecular substitution reaction because the large dipole moment of the solvent

helps to stabilize the transition state. The highly positive and highly negative parts

interact with the substrate to lower the energy of the transition state. Since the

carbocation is unstable, anything that can stabilize this even a little will speed up the

reaction.

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Sometimes in an SN1 reaction the solvent acts as the nucleophile. This is called a

solvolysis reaction (see example below). The polarity and the ability of the solvent to

stabilize the intermediate carbocation is very important as shown by the relative rate

data for the solvolysis (see table below). The dielectric constant of a solvent roughly

provides a measure of the solvent's polarity. A dielectric constant below 15 is usually

considered non-polar. Basically, the dielectric constant can be thought of as the

solvent's ability to reduce the internal charge of the solvent. So for our purposes, the

higher the dielectric constant the more polar the substance and in the case of SN1

reactions, the faster the rate.

Below is the same reaction conducted in two different solvents and the relative rate that corresponds

with it.

The figure below shows the mechanism of an SN1 reaction of an alkyl halide with water. Since water is

also the solvent, this is an example of a solvolysis reaction.

Summary 

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 This pathway is most common for systems with good leaving groups, stable

carbocations and weaker nucleophiles. A typical example is the reaction of HBr

with a tertiary alcohol.

SN1 Mechanism for Reaction of Alcohols with HBr 

Step 1: 

An acid/base reaction. Protonation of

the alcoholic oxygen to make a better

leaving group. This step is very fast and

reversible. The lone pairs on the oxygen

make it a Lewis base.

Step 2: 

Cleavage of the C-O bond allows the loss

of the good leaving group , a neutral

water molecule, to give a carbocation

intermediate. This is the rate

determining step (bond breaking is

endothermic)

Step 3: 

Attack of the nucleophilic bromide ion

on the electrophilic carbocation creates

the alkyl bromide.

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SN1 MECHANISM FOR REACTION OF ALKYL HALIDES WITH H2O 

Step 1: 

Cleavage of the already polar C-Br bond allows the loss of

the good leaving group , a halide ion, to give a carbocation

intermediate. This is the rate determining step (bondbreaking is endothermic)

Step 2: 

Attack of the nucleophile, the lone pairs on the O atom of

the water molecule, on the electrophilic carbocation creates

an oxonium species.

Step 3: 

Deprotonation by a base yields the alcohol as the product.

Note that this is the reverse of the reaction of an alcohol

with HBr.

In principle, the nucleophile here, H2O, could be replaced

with any nucleophile, in which case the final deprotonation

may not always be necessary.

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SN1 vs  SN2 Reactions

Whether an alkyl halide will undergo an SN1 or an SN2 reaction depends upon

a number of factors. Some of the more common factors include the natures of

the carbon skeleton, the solvent, the leaving group, and the nature of the

nucleophile.

Nature of the carbon skeleton

Only those molecules that form extremely stable cations undergo S N1

mechanisms. Normally, only compounds that yield 3° (tertiary) carbonications

(or resonance-stabilized carbocations) undergo S N1 mechanisms rather than S

N2 mechanisms. Carbocations of tertiary alkyl halides not only exhibit stability

due to the inductive effect, but the original molecules exhibit steric hindrance

of the rear lobe of the bonding orbital, which inhibits S N2 mechanisms from

occurring. Primary alkyl halides, which have little inductive stability of their

cations and exhibit no steric hindrance of the rear lobe of the bonding orbital,

generally undergo S N2 mechanisms. Figure 1 illustrates the tendencies of alkyl

halides toward the two types of substitution mechanisms.

Polar protic solvents such as water favor S N1 reactions, which produce both a

cation and an anion during reaction. These solvents are capable of stabilizing

the charges on the ions formed during solvation. Because S N2 reactions occur

via a concerted mechanism   (a mechanism which takes place in one step, with

bonds breaking and forming at the same time) and no ions form, polar protic

solvents would have little effect upon them. Solvents with low dielectric

constants tend not to stabilize ions and thus favor S N2 reactions. Conversely,solvents of high dielectric constants stabilize ions, favoring S N1 reactions.

In general, good leaving groups are those capable of forming stable ions or

molecules upon displacement from the original molecule. Conversely, poor

leaving groups form ions of poor to moderate stability. Strong bases, such as

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OH −, NH 2 −, and RO −, make poor leaving groups. Water, which is less basic

than a hydroxide ion, is a better leaving group. Poor bases usually make good

leaving groups. A poor base is an ion or group in which the electrons are tightly

bound to the molecule due to high electronegativity or resonance. Some good

leaving groups are the sulfate ion and the p-toluenesulfonate (tosylate ion).

 The following list ranks atoms and molecules in order of their stability asleaving groups, from most to least stable.