oxidation and reduction
DESCRIPTION
Chapter 14. Oxidation and Reduction. Oxidation and Reduction. Oxidation - addition of Oxygen. Reduction - removal of Oxygen. In terms of electrons Oxidation is the loss of electrons. ( OILRIG) Reduction is the gain of electrons. - PowerPoint PPT PresentationTRANSCRIPT
Chapter 14
Oxidation and Reduction
Oxidation - addition of Oxygen.Reduction - removal of Oxygen.
In terms of electrons Oxidation is the loss of electrons.
(OILRIG)
Reduction is the gain of electrons
Oxidising and reducing agents
An oxidising agent causes another substance to become oxidised and, in the process, the oxidising agent is reduced. Common oxidising agents include O2, Cl2, ClO-, KMnO4 and H2O2
A reducing agent causes another substance to become reduced and, in the process, the reducing agent is oxidised. Common reducing agents include CO, SO2, SO3
2-
Oxidising agents are useful in Sterilising and Bleaching.
Experiments: (a) Halogens as Oxidising agents
(b) Displacement
reactions of Metals. (See Book Pages 184-186)
Oxidation Numbers
The oxidation number of an atom is the charge that the atom has or appears to have when electrons are distributed according to certain rule.
Rules
The ON of an element is 0.
The ON of an ion is the charge that it has.
The ON of F is always -1.
The ON of O IS -2 except OF2 (+2) and H2O2 (-1).
The ON of H is +1 except with metal hydrides (-1)
Oxidation and reduction in terms of Oxidation numbers
Oxidation is an increase in Oxidation number.
Reduction is a decrease in Oxidation number.
Balancing Redox reactions (See Book Page 187-188) + HANDOUT
2.6.2Balancing equations using
Oxidation Numbers
Chemical reactions are all about the movement of electrons
When an equation is balanced the electron movements must balance
Sometimes it is possible to balance an equation in more than one way
It is therefore possible to make the numbers of atoms balance but not the electron movement
Using oxidation numbers prevents this
Sequence of events
Write out the formulae of all reactants and products
Assign oxidation numbers to all atoms Pick out the atoms whose oxidation numbers
change Write down the electron movements Balance the electron movements Enter the numbers from balanced electron
movement into the overall equation Balance equation by inspection - [do H last]
MnO4- + Fe2+ + H+ = Mn2+ + Fe3+ + H2O
+7 -2 +2 +1 +2 +3 +1 -2+7 +2+2 +3
OxidationReduction
Mn = Mn2+
+7 +2
Fe2+ = Fe3+
+2 +3
5 5
55 48
+ 5 e- - 1 e- 5
1. Assign oxidation numbers2. Select those which change
3. (a) Assign Oxidation – increase in Ox. No
(b) Assign Reduction – decrease in Ox. No
5. Write electron gains and losses
6. Balance electron transfers
7. Put numbers up into the equation8. Balance equation by inspection - leave H+ till last
Sequence of events
Write down reactants and products Assign oxidation numbers Identify oxidation and reduction Write down changes and electrons
involves Balance e- change Put changes into equation Balance equation by inspection [H
last]
C2H5OH + Cr2O72-+ H+ = CH3COOH + Cr3++ H2O
-2 +1-2+1 +6 -2 +1 0 +1 0 -2-2+1 +3 +1-2
-2
0+6 +3
OxidationReduction
C2 = C2
-2 0Cr2O7
2- = Cr3+
+6 +3
2
33 42
- 2 e-
+ 3 e-
0
3 3 4
6 2
12
12
x3
x24
11 16
1. Assign oxidation numbers2. Select those which change
3. (a) Assign Oxidation – increase in Ox. No
(b) Assign Reduction – decrease in Ox. No
5. Write electron gains and losses
6. Balance electron transfers
7. Put numbers up into the equation8. Balance equation by inspection - leave H+ till last :- O 3+(2*7) =
(3*2) + x x=11 H 3(6*1) + X = (3*4) +
11(2*1) x= 16
Examples
1. C2H5OH + MnO41- + H+ = CH3CHO + Mn2+ + H2O
2. C2H5OH + MnO41- + H+ = CH3COOH + Mn2+ + H2O
3. Cr2O72- + Fe2+ + H+ = Cr3+ + Fe3+ + H2O
4. MnO41- + C2O4
2- + H+ = CO2 + Mn2+ + H2O
5. Fe2+ + Cl2 = Fe3+ + Cl-
6. MnO41- + H2O2 + H+ = Mn2+ + O2 +H2O
7. Cr2O72- + CH3OH + H+ = Cr3+ + HCHO + H2O
8. Cr2O72- + CH3CHO + H+ = Cr3+ + CH3COOH + H2O
Answers
1. 5C2H5OH + 2MnO41- + 6H+ = 5CH3CHO + 2Mn2+ +
8H2O
2. 5C2H5OH + 4MnO41- + 12H+ = 5CH3COOH + 4Mn2+
+ 11H2O
3. Cr2O72- + 6Fe2+ + 14H+ = 2Cr3+ + 6Fe3+ + 7H2O
4. 2MnO41- + 5C2O4
2- + 16H+ = 10CO2 + 2Mn2+ + 8H2O
5. 2Fe2+ + Cl2 = 2Fe3+ + 2Cl-
6. 2MnO41- + 5H2O2 + 8H+ = 2Mn2+ + 5O2 +8H2O
7. Cr2O72- + CH3OH + H+ = Cr3+ + HCHO + H2O
8. Cr2O72- + CH3CHO + H+ = Cr3+ + CH3COOH + H2O