oxidation and reduction

14
Chapter 14

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Chapter 14. Oxidation and Reduction. Oxidation and Reduction. Oxidation - addition of Oxygen. Reduction - removal of Oxygen. In terms of electrons Oxidation is the loss of electrons. ( OILRIG) Reduction is the gain of electrons. - PowerPoint PPT Presentation

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Page 1: Oxidation and Reduction

Chapter 14

Page 2: Oxidation and Reduction

Oxidation and Reduction

Oxidation - addition of Oxygen.Reduction - removal of Oxygen.

In terms of electrons Oxidation is the loss of electrons.

(OILRIG)

Reduction is the gain of electrons

Page 3: Oxidation and Reduction

Oxidising and reducing agents

An oxidising agent causes another substance to become oxidised and, in the process, the oxidising agent is reduced. Common oxidising agents include O2, Cl2, ClO-, KMnO4 and H2O2

A reducing agent causes another substance to become reduced and, in the process, the reducing agent is oxidised. Common reducing agents include CO, SO2, SO3

2-

Oxidising agents are useful in Sterilising and Bleaching.

Page 4: Oxidation and Reduction

Experiments: (a) Halogens as Oxidising agents

(b) Displacement

reactions of Metals. (See Book Pages 184-186)

Page 5: Oxidation and Reduction

Oxidation Numbers

The oxidation number of an atom is the charge that the atom has or appears to have when electrons are distributed according to certain rule.

Rules

The ON of an element is 0.

The ON of an ion is the charge that it has.

The ON of F is always -1.

The ON of O IS -2 except OF2 (+2) and H2O2 (-1).

The ON of H is +1 except with metal hydrides (-1)

Page 6: Oxidation and Reduction

Oxidation and reduction in terms of Oxidation numbers

Oxidation is an increase in Oxidation number.

Reduction is a decrease in Oxidation number.

Balancing Redox reactions (See Book Page 187-188) + HANDOUT

Page 7: Oxidation and Reduction

2.6.2Balancing equations using

Oxidation Numbers

Page 8: Oxidation and Reduction

Chemical reactions are all about the movement of electrons

When an equation is balanced the electron movements must balance

Sometimes it is possible to balance an equation in more than one way

It is therefore possible to make the numbers of atoms balance but not the electron movement

Using oxidation numbers prevents this

Page 9: Oxidation and Reduction

Sequence of events

Write out the formulae of all reactants and products

Assign oxidation numbers to all atoms Pick out the atoms whose oxidation numbers

change Write down the electron movements Balance the electron movements Enter the numbers from balanced electron

movement into the overall equation Balance equation by inspection - [do H last]

Page 10: Oxidation and Reduction

MnO4- + Fe2+ + H+ = Mn2+ + Fe3+ + H2O

+7 -2 +2 +1 +2 +3 +1 -2+7 +2+2 +3

OxidationReduction

Mn = Mn2+

+7 +2

Fe2+ = Fe3+

+2 +3

5 5

55 48

+ 5 e- - 1 e- 5

1. Assign oxidation numbers2. Select those which change

3. (a) Assign Oxidation – increase in Ox. No

(b) Assign Reduction – decrease in Ox. No

5. Write electron gains and losses

6. Balance electron transfers

7. Put numbers up into the equation8. Balance equation by inspection - leave H+ till last

Page 11: Oxidation and Reduction

Sequence of events

Write down reactants and products Assign oxidation numbers Identify oxidation and reduction Write down changes and electrons

involves Balance e- change Put changes into equation Balance equation by inspection [H

last]

Page 12: Oxidation and Reduction

C2H5OH + Cr2O72-+ H+ = CH3COOH + Cr3++ H2O

-2 +1-2+1 +6 -2 +1 0 +1 0 -2-2+1 +3 +1-2

-2

0+6 +3

OxidationReduction

C2 = C2

-2 0Cr2O7

2- = Cr3+

+6 +3

2

33 42

- 2 e-

+ 3 e-

0

3 3 4

6 2

12

12

x3

x24

11 16

1. Assign oxidation numbers2. Select those which change

3. (a) Assign Oxidation – increase in Ox. No

(b) Assign Reduction – decrease in Ox. No

5. Write electron gains and losses

6. Balance electron transfers

7. Put numbers up into the equation8. Balance equation by inspection - leave H+ till last :- O 3+(2*7) =

(3*2) + x x=11 H 3(6*1) + X = (3*4) +

11(2*1) x= 16

Page 13: Oxidation and Reduction

Examples

1. C2H5OH + MnO41- + H+ = CH3CHO + Mn2+ + H2O

2. C2H5OH + MnO41- + H+ = CH3COOH + Mn2+ + H2O

3. Cr2O72- + Fe2+ + H+ = Cr3+ + Fe3+ + H2O

4. MnO41- + C2O4

2- + H+ = CO2 + Mn2+ + H2O

5. Fe2+ + Cl2 = Fe3+ + Cl-

6. MnO41- + H2O2 + H+ = Mn2+ + O2 +H2O

7. Cr2O72- + CH3OH + H+ = Cr3+ + HCHO + H2O

8. Cr2O72- + CH3CHO + H+ = Cr3+ + CH3COOH + H2O

Page 14: Oxidation and Reduction

Answers

1. 5C2H5OH + 2MnO41- + 6H+ = 5CH3CHO + 2Mn2+ +

8H2O

2. 5C2H5OH + 4MnO41- + 12H+ = 5CH3COOH + 4Mn2+

+ 11H2O

3. Cr2O72- + 6Fe2+ + 14H+ = 2Cr3+ + 6Fe3+ + 7H2O

4. 2MnO41- + 5C2O4

2- + 16H+ = 10CO2 + 2Mn2+ + 8H2O

5. 2Fe2+ + Cl2 = 2Fe3+ + 2Cl-

6. 2MnO41- + 5H2O2 + 8H+ = 2Mn2+ + 5O2 +8H2O

7. Cr2O72- + CH3OH + H+ = Cr3+ + HCHO + H2O

8. Cr2O72- + CH3CHO + H+ = Cr3+ + CH3COOH + H2O