p 100 % p+1 10 %
DESCRIPTION
Compound 1. P 100 % P+1 10 %. 148/13 = 11.38; .38*13 =5 C 11 H 18. Compound 1. Compound 1. C 11 H 18 C 10 H 14 O. Area : 5:2:2:3. m/e 120 m/e 105 m/e 77. +. m/e 120. m/e 105. Compound 2. P 100 % P+1: 7.1% P+2 : 33 %. 126-35 = 91 91/13 = 7.0 C 7 H 7 Cl. Compound 2. - PowerPoint PPT PresentationTRANSCRIPT
P 100 %
P+1 10 %
Compound 1
148/13 = 11.38; .38*13 =5C11H18
Compound 1
Compound 1
C11H18
C10H14O
Area : 5:2:2:3
m/e 105
+.
m/e 120
m/e 120m/e 105m/e 77
Compound 2
P 100 %
P+1: 7.1%
P+2 : 33 %
126-35 = 9191/13 = 7.0C7H7Cl
Compound 2
Area: 5:2
Compound 3
m/e 114114/13 = 8.769; 0.769*13 = 10C8H18
Compound 3
Compound 3
C8H18
C7H14OC6H10O2
m/e 99 P-15m/e 86 P-28m/e 69 P-45m/e 41
m/e 86
m/e 69m/e 41
Compound 4
m/e 184184-79 = 105105/13 = 8.077; 0.077*13 = 1C8H9Br
Compound 4
Compound 4
Area 5:2:2
Compound 5
C8H18O3 mw 162
m/e 75C2H3O3
+
C3H7O2+
m/e 73C2HO3
+
C3H5O2+
C4H9O+
m/e 147 = P - 15m/e 130 = P - 32 CH4Om/e 115 = P – 47 CH3O2; C2H7O
Compound 6
Compound 7
Compound 7
A comparison of two EIMS spectra obtained from different instruments and different samples
m/e 136136/13 = 10.460.46*13 = 6C10H16
Compound 7
C10H16
Compound 7
C10H16
Empirical Rules for Dienes (π → π*)Homoannular(cisoid) Heteroannular (transoid)
Parent λ = 253 nm λ = 214 nmIncrements for:
double bond extension 30 30alkyl subst or ring 5 5exocyclic double bond 5 5
Alkenesethylene λ = 175 nm
λ = 253 +10 + 10 = 273 nm
Compound 8
m/e 108108/13 = 8.30770.3077*13 = 4C8H12
Compound 8
Compound 8
d
d t
Compound 8
area = 2:2:4:4 left to right
P : m/e 108
m/e 80 = P-28
1H NMR: no signal13C NMR: 4 vinyl carbons
282/13 = 21.692; 0.692*13= 9C21H30
C18H31ClC15H32Cl2
C12H33Cl3
C9H34Cl4
C6H35Cl5
C6Cl6
35Cl = 0.7637Cl = 0.24
1 1 1 n = 11 2 1 n = 2
1 3 3 1 n = 31 4 6 4 1 n = 4
1 5 10 10 5 1 n = 51 6 15 20 15 6 1 n = 6
n = 5 (0.76)5 = 0.254; 5(0.76)4(0.24)= 0.40 100% 157%n = 6 (0.76)6 = 0.193; 6(0.76)5(0.24) = 0.365
100% 189%
146/13 = 11.23; 0.23 *13 =3C11H14
Compound 9
P-28
C11H14 C10H10O
Compound 9
2 1
C10H10O C9H6O2
Compound 9
160.63 S 153.99 S143.48 D131.79 D127.95 D124.43 D118.81 S116.70 D116.56 D
C9H6O2
Compound 9
136/13 = 10.462; 0.462*13 = 6C10H16
Compound 10
Compound 10
Neat liquid
Compound 10
C10H16
C9H12O
CCl4 solution
Compound 10
Area: 1:2:2:3C9H12OC8H8O2
190.70 D164.63 S131.93 D 129.97 S114.33 D 55.53 Q
C8H8O2
Compound 11
112/13 = 8.615; 0.615*13 = 8C8H16
Compound 11
C8H16
Degrees of unsaturation: 1
Area: 3:2:3C8H16
147.28 S126.63 D123.24 D 122.62 D23.25 T 16.03 Q
C8H16
C7H12OC6H8O2
Exact mass: 112.0347Exact mass of C6H8O2: 112.0524