p roperties of similar triangles

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Properties of similar triangles

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P roperties of similar triangles. Warm Up Solve each proportion. 1. 2. 3. 4. AB = 16. QR = 10.5. x = 21. y = 8. Objectives. Use properties of similar triangles to find segment lengths. Apply proportionality and triangle angle bisector theorems. - PowerPoint PPT Presentation

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Page 1: P roperties of similar triangles

Properties of similar triangles

Page 2: P roperties of similar triangles

Warm UpSolve each proportion.

1. 2.

3. 4.

AB = 16 QR = 10.5

x = 21 y = 8

Page 3: P roperties of similar triangles

Use properties of similar triangles to find segment lengths.Apply proportionality and triangle angle bisector theorems.

Objectives

Page 4: P roperties of similar triangles

Artists use mathematical techniques to make two-dimensional paintings appear three-dimensional. The invention of perspective was based on the observation that far away objects look smaller andcloser objects look larger.

Mathematical theorems like the Triangle Proportionality Theorem are important in making perspective drawings.

Page 5: P roperties of similar triangles
Page 6: P roperties of similar triangles

Example 1: Finding the Length of a Segment

Find US.

Substitute 14 for RU, 4 for VT, and 10 for RV.

Cross Products Prop.US(10) = 56

Divide both sides by 10.

It is given that , so by

the Triangle Proportionality Theorem.

Page 7: P roperties of similar triangles

Check It Out! Example 1

Find PN.

Substitute in the given values.

Cross Products Prop.2PN = 15

PN = 7.5 Divide both sides by 2.

Use the Triangle Proportionality Theorem.

Page 8: P roperties of similar triangles
Page 9: P roperties of similar triangles

Example 2: Verifying Segments are Parallel

Verify that .

Since , by the Converse of the

Triangle Proportionality Theorem.

Page 10: P roperties of similar triangles

Check It Out! Example 2

AC = 36 cm, and BC = 27 cm.

Verify that .

Since , by the Converse of the

Triangle Proportionality Theorem.

Page 11: P roperties of similar triangles
Page 12: P roperties of similar triangles

Example 3: Art Application

Suppose that an artist decided to make a larger sketch of the trees. In the figure, if AB = 4.5 in., BC = 2.6 in., CD = 4.1 in., and KL = 4.9 in., find LM and MN to the nearest tenth of an inch.

Page 13: P roperties of similar triangles

Example 3 Continued

Given

2-Trans. Proportionality Corollary

Substitute 4.9 for KL, 4.5 for AB, and 2.6 for BC.

Cross Products Prop.4.5(LM) = 4.9(2.6)

Divide both sides by 4.5.LM 2.8 in.

Page 14: P roperties of similar triangles

Example 3 Continued

2-Trans. Proportionality Corollary

Substitute 4.9 for KL, 4.5 for AB, and 4.1 for CD.

Cross Products Prop.4.5(MN) = 4.9(4.1)

Divide both sides by 4.5.MN 4.5 in.

Page 15: P roperties of similar triangles

Check It Out! Example 3

Use the diagram to find LM and MN to the nearest tenth.

Page 16: P roperties of similar triangles

Given

Check It Out! Example 3 Continued

2-Trans. Proportionality Corollary

Substitute 2.6 for KL, 2.4 for AB, and 1.4 for BC.

Cross Products Prop.2.4(LM) = 1.4(2.6)

Divide both sides by 2.4.LM 1.5 cm

Page 17: P roperties of similar triangles

Check It Out! Example 3 Continued

2-Trans. Proportionality Corollary

Substitute 2.6 for KL, 2.4 for AB, and 2.2 for CD.

Cross Products Prop.2.4(MN) = 2.2(2.6)

Divide both sides by 2.4.MN 2.4 cm

Page 18: P roperties of similar triangles

The previous theorems and corollary lead to the following conclusion.

Page 19: P roperties of similar triangles

Example 4: Using the Triangle Angle Bisector Theorem

Find PS and SR.

Substitute the given values.

Cross Products Property

Distributive Property

by the ∆ Bisector Theorem.

40(x – 2) = 32(x + 5)

40x – 80 = 32x + 160

Page 20: P roperties of similar triangles

Example 4 Continued

Simplify.

Divide both sides by 8.

Substitute 30 for x.

40x – 80 = 32x + 160

8x = 240

x = 30

PS = x – 2 SR = x + 5

= 30 – 2 = 28 = 30 + 5 = 35

Page 21: P roperties of similar triangles

Check It Out! Example 4

Find AC and DC.

Substitute in given values.

Cross Products Theorem

So DC = 9 and AC = 16.

Simplify.

by the ∆ Bisector Theorem.

4y = 4.5y – 9

–0.5y = –9

Divide both sides by –0.5. y = 18

Page 22: P roperties of similar triangles

Find the length of each segment.

1. 2.

Lesson Quiz: Part I

SR = 25, ST = 15

Page 23: P roperties of similar triangles

Lesson Quiz: Part II

3. Verify that BE and CD are parallel.

Since , by the

Converse of the ∆ Proportionality Thm.