Part 3 Module 7Real-world problems involving distance

Two useful facts

From elementary geometry we have two familiar facts that can be useful if we are trying to calculate a distance.One of these is the Pythagorean Theorem, and the other is the formula for the circumference of a circle.

ABCDrC2 = A 2 + B2Circumference = πD = 2πr

Exercise #1

The GEOMETRIZER www.math.fsu.edu/~wooland/GeoA/Geo15.html

The figure below shows an aerial view of The Hurl-O-Matic, a carnival ride in which the passengers are seated in a car, attached to the end of an arm which rotates rapidly around a central hub.Suppose that the length ( r ) of the arm is 39 feet, and that, at full speed, it takes 4 seconds for the car to complete one revolution. Find the speed of the car.A. 819 miles per hourB. 54 miles per hourC. 90 miles per hourD. 21 miles per hour

E. 42 miles per hour

Hurl-O-Maticr

Solution #1

Suppose that the length ( r ) of the arm is 39 feet, and that, at full speed, it takes 4 seconds to for the car to complete one revolution. Find the speed of the car.

In four seconds, the distance the cars travels is the circumference of a circle whose radius is 39 feet.2π39 = 245.04 feetSince the car travels 245.04 feet in 4 seconds, its speed is245.04/4 = 61.26 feet per second.We must convert 61.26 feet per second to miles per hour.First, multiply by 60 since there are 60 seconds in a minute.61.26 x 60 = 3675.6 The car travels 3675.6 feet in one minute.Multiply again by 60, since there are 60 minutes in an hour.3675.6 x 60 = 220,536 The car travels 220,536 feet in one hour.Finally, divide by 5280, since there are 5280 feet in one mile220,536/5280 = 41.77The car travels 41.77 miles in one hour, so its speed is 41.77 miles per hour.The best choice is E.

Exercise #2

The GEOMETRIZER www.math.fsu.edu/~wooland/GeoA/Geo4.html

Homer and Aristotle are loitering on a street corner when Plato, to whom they owe money, suddenly approaches. Homer begins running northward at 12 miles per hour, and Aristotle begins running eastward at 15 miles per hour. How far apart are Homer and Aristotle after 10 minutes?

A. 1.6 milesB. 4.5 milesC. 3.2 milesD. 32.0 miles

Solution #2

Homer begins running northward at 12 miles per hour, and Aristotle begins running eastward at 15 miles per hour. How far apart are Homer and Aristotle after 10 minutes?We are trying to find the hypotenuse of a right triangle. We will first find the distance (D) between them after one hour, then scale that back to 10 minutes.After one hour, Homer has traveled 12 miles and Aristotle has traveled 15 miles.

DAristotleHomerAfter one hour12 miles15 miles

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D2=122+152D2=144+225D2=369D=369D≈19.02

Since they are 19.02 miles apart after one hour, and 10 minutes is 10/60 of an hour, after ten minutes we haveD = 19.02 x 10/60= 3.2 miles

Exercise #3

The GEOMETRIZER www.math.fsu.edu/~wooland/GeoA/Geo6.html

Archimedes is a traveling salesperson who needs to drive from Podunck to Boonies (see map below). However, Archimedes is too cheap to take the Boonies Expressway (which is a toll road), so instead he takes the Podunck Parkway to Sticks and then takes Sticks Highway to Boonies. The direct distance from Podunck to Boonies is 64 miles, and the distance from Sticks to Boonies is 45 miles. How much gas will Archimedes use, assuming his Yugo gets 5 miles per gallon?

A. 9.1 gallonsB. 391.2 gallonsC. 18.1 gallonsD. 90.5 gallons

PodunckSticksBooniesBoonies ExpresswayPodunckParkwaySticks Highway

Solution #3

To find the number of gallons of gas used, we need to find the number of miles traveled, then divide by 5.The number of miles traveled is x + 45.We use the Pythagorean Theorem to find x.

PSBx6445

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642=452+x2642−452=x24096−2025=x22071=x2x=2071≈45.5The number of miles traveled is 45.5 + 45 = 90.5

The number of gallons of gas used is90.5/5 = 18.1

Exercise from Part 3 Module 6

From The Big UNIT-izerwww.math.fsu.edu/~wooland/unitizer.html

How many square yards are in 11664 square feet?A. 34992B. 104976C. 1296D. 3888

SolutionHow many square yards are in 11664 square feet?A. 34992 B. 104976 C. 1296 D. 3888

To find the correct conversion factor between square yards and square feet, we need to use the fact that 1 yard = 3 feet, along with the meaning of the word “square.”

“1 square yard” means “1 yard x 1 yard”

1 sq. yard = 1 yd. x 1 yd.= 3 feet x 3 feet= 9 square feet

We have figured out that 1 square yard = 9 square feet.To convert 11,664 square feet to square yards, we divide by 9.

11,664/9 = 1296 The correct choice is C.

Exercise #4

The GEOMETRIZER www.math.fsu.edu/~wooland/GeoA/Geo8.html

Study the race track shown below. If Gomer runs 32 laps around the track, how many miles will he have run?

A. 675.3 milesB. 26.6 milesC. 16.6 miles

D. 637.4 miles

782 feet374 feet

Solution #4

We need to find the perimeter of the figure, the multiply by 32 (since he runs 32 laps), then divide by 5280 (to convert from feet by miles.To find the perimeter ( P ) of the figure, we will assume that the figure consists of a rectangle with exactly half a circle joined to each end.

782 feet782 feetC1C2374 feetP = 782 + 782 + C1 + C2where C1 + C2 is the circumefrence of a circle whose diameter is 374 feet.374π = 1175 feetSo P = 782 + 782 + 1175= 2739 feet

In one lap he runs 2739 feet, so in 32 laps he runs 32 x 2739 = 87,648 feet87648/5280 = 16.6 miles

Exercise #5The GEOMETRIZER www.math.fsu.edu/~wooland/GeoA/Geo13.html

According to classical mythology, Sisyphus was condemned to spend eternity rolling a large rock up a hill. Upon reaching the top of the hill, the rock would roll down the other side, whereupon Sisyphus would repeat the process.Suppose the figure below (definitely not drawn to scale -- note the cosmic size of the hill) shows his situation. Suppose also that the rock is roughly circular with a diameter of 3.6 feet, and that on average it takes him 10 months to roll the rock one complete revolution.How long will it take him to roll the rock to the top of the hill?A. 9624452 yearsB. 1042649 yearsC. 255297 yearsD. 1604075 yearsE. 802038 years

Solution #5Suppose the figure below (definitely not drawn to scale -- note the cosmic size of the hill) shows his situation. Suppose also that the rock is roughly circular with a diameter of 3.6 feet, and that on average it takes him 10 months to roll the rock one complete revolution.How long will it take him to roll the rock to the top of the hill?The amount of time required to get to the top of the hill is determined by the number of revolutions of the rock needed to get to the top.The number of revolutions of the rock depends upon the length of the hillside and the distance the rock travels in one revolution.The distance the rock travels in one revolution is the circumference ( C ) of the rock.C = 3.6π = 11.31 feet Each time the rock turns one complete revolution, it has traveled 11.31 feet.The length ( L ) of the hillside is the hypotenuse of a right triangle whose legs measure 500 miles and 2000 miles, respectively.

The length of the hillside is 2061.6 miles.Convert this to feet, so that it is comparable to the circumference of the rock.2061.6 x 5280 = 10,885,248 feet

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L2 = 20002 + 5002

L2 = 4000000 + 250000

L2 = 4250000

L = 4250000

L ≈ 2061.6

Solution #5, page 2Each time the rock turns one complete revolution, it has traveled 11.31 feet ( C ), and the length of the hillside ( L ) is 10,885,248 feet.

Divide L by C to get the number of revolutions of the rock needed to get from the bottom to the top of the hill.

Number of revolutions = L/C = 10885248 /11.31 = 962444.56

The rock will turn 962,444.56 revolutions, and each revolution takes 10 months, sonumber of months = 962444.56 x 10 = 962445.6

Finally, convert from months to years by dividing by 12:9624445.6/12 = 802037.1 years.

The best choice is E (802038 years). Of course, our answer isn’t an exact match, due to the fact that we rounded our results during several of the preliminary steps.