phy 3.1.notebook - wisconsin lutheran high schoolgreschner.wiscoscience.com/worksheets/physics/chpt...
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phy 3.1.notebook
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September 19, 2017
Everything Moves
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Diagrams:
1) Motion (picture)
Motion
timelapsed photo
\
Type Motion?
no reference!
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Diagrams:
1) Motion (picture) diagram
Motion
by inserting lines on thewall in the backgroundyou have a "referencepoint" to comparethe motion of the runner
timelapsed photo
origin re
ference pt.
reference!
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Diagrams:
1) Motion (picture) diagram
Motion
by inserting lines on thewall in the backgroundyou have a "referencepoint" to comparethe motion of the runner
timelapsed photo
origin reference pt.
A = 1 cm B = .9 cm C = .4 cm D = +.2 cm E = +.5 cm
displacement A B C D E
reference values
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2) Particle Model sometimes easier to see what's happening because it reduces the object to a point source and eliminates outside distractions
a
c
What are thefour types ofmotion?
Particle/Point model: when the size of the object is much less than the dist. it moves! when you can ignore the internal motions
How would a graph look?????
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Little Andy rolls a ball along the ground
Andy has arm problem
s!
origin
1) motion along the "x" axis
origin
vector tellssize and direction
scalar tellsize only
distance: 1 m 1 m
displacement: 1 m,+ 1 m
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origin
1) motion along the "x" axis
origin
Andy has arm problem
s!
Little Andy rolls a ball along the ground
dv v
a
using vectors to represent motion !
4.0 m
1 cm = 0.5 mscale
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little Andy drops a rock
Andy still has arm problems!
1) motion along the "y" axis
a) what will the particle diagram look like?
b) what will the vectors look like?
using vectors to represent motion !
." "
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little Andy drops a rock
Andy still has arm problems!
1) motion along the "y" axis
a) what will the particle diagram look like?
b) what will the vectors look like?
using vectors to represent motion !
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little Andy drops a rock
Andy still has arm problems!
1) motion along the "y" axis
a) what will the particle diagram look like?
b) what will the vectors look like?
using vectors to represent motion !
![Page 17: phy 3.1.notebook - Wisconsin Lutheran High Schoolgreschner.wiscoscience.com/worksheets/physics/chpt 3/3.1 notes 20… · phy 3.1.notebook 6 September 19, 2017 2) Particle Modelsometimes](https://reader034.vdocument.in/reader034/viewer/2022043000/5f754928aa2831355211259b/html5/thumbnails/17.jpg)
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little Andy drops a rock
Andy still has arm problems!
v
v
v
v
a
d
a
.
" v " stands for average velocity
1) motion along the "y" axis
a) what will the particle diagram look like?
b) what will the vectors look like?
using vectors to represent motion !
why average velocity in this situation?
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Andy makes the m
ost
of his arm problem
s!
using vectors to represent motion !see Andy putt!
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Andy makes the m
ost
of his arm problem
s! .a a a
v v v vv vv
using vectors to represent motion !see Andy putt!
d
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little Andy drops a rock
Andy doesn't care anymore!
d = 1.88 m
t = 0.63 s
2) Type motion?rest/constant velocity, acceleration
(varying vel,)
3) Formulas that apply?
1) Data/diagrams?given and understoodparticle and/or vector diagram
Here's where we're going!
THE STEPS!!!!!
to come later!
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Motion:
rest Constant velocity varying velocityacceleration
v = Δd/t v = Δdt/t_
v = (v1 + v2)/2_
a = Δv/tthe " " is critical!!!!!!!!!!!!!
_ΔvNote the difference between and v
_ a = (v2 v1)/t
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d = 1.88 m t = 0.63 s
2) Type motion?
3) Formulas that apply?
1) Data?origin
little Andy drops a rock
Andy still has arm problems!
v
v
v
v
a
d
a
.
v2 = ?
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d = 1.88 m t = 0.63 s
2) Type motion?
3) Formulas that apply?
1) Data?origin
little Andy drops a rock
Andy still has arm problems!
v
v
v
v
a
d
a
. d = 1.88 m
t = 0.63 s
a (g) = 9.8 m/s2
v1 = 0
v2 = ?
v or, a_
v =
a = Δv/t
v1 + v22
_
v = Δdt/t_
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v
a
_
Δd = 1.88 mΔt = 0.63 s
vv
v1 = 0
v2 = ?v = dt/tt = 1.88 m/0.63 s v = 3.0 m/s_
_
v = (v1 + v2)
v2 = 2v v1v2 = 2(3.0 m/s) 0v2 = 6.0 m/s
_
_
a = Δv/t = (v2 v1)/ta = (6.0 m/s 0)/0.63 sa = 9.5 m/s2
m/ss s
11s
m/ss1
m/s
( ( 1s
s1
m/s
( ( ( ( 1s m/s2= = = =
v1 = 0, v2 = ?
2
where is that?
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v = dt/tt
v = (v1 + v2)/2
a = Δv/t = (v2 v1)/t
_
_
dt = v t t = d/v_ _
v2 = 2v v1_
v1= 2v v2_
v2 = v1 + at
v1 = v2 at
t = (v2 v1)/a
formulas for varying velocity
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0.0998 m
1.175 m
t = 1.68s
1) Data/diagram?
2) Type Motion?
3) Formulas that apply?
A ball starts from rest and rolls down a 4.870 ramp, what velocity does it attain at the bottom?...what is its acceleration?
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0.0998 m
1.175 m
t = 1.68 s
1) Data?
2) Type Motion?
3) Formulas that apply?dll = 1.175 mdh = 0.0998 mt = 1.68 sv1 = 0
v
v
v
a
ad
v = v1 + v22 v = dt
a = vt
.dll means parallel to motion
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0..0998 m
1.175 m
t = 1.68 s
1) Data? 2) Type Motion?
3) Formulas that apply?
dll = 1.175 m
v = dt
1.175 m1.68 s= = 0.699 m/s
v = v1 + v22
v2 = 2v v1 v2 = 2(.699 m/s) 0
v2 = 1.40 m/s
a = vt
v = v1 + v22
v = dt
a = v2 v1 t
a = 1.40 m/s 01.68 s
a = 0.833 m/s2
dll = 1.175 mdh = 0.0998 mt = 1.68 sv1 = 0
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. Little Andy throws a rock. It leaves his hand at 12 m/s and travels for 3.0 seconds. How far does it go?
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.Little Andy throws a rock. It leaves his hand at 12 m/s and travels for 3.0 seconds. How far does it go?
. . . .
.v v v
d
a
v = 12 m/s
t = 3.0 s
d = ?
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.Little Andy throws a rock. It leaves his hand at 12 m/s and travels for 3.0 seconds. How far does it go?
. . . .
.v v v
d
a
v = 12 m/s
t = 3.0 s
d = ?
TM? v constant
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.Little Andy throws a rock. It leaves his hand at 12 m/s and travels for 3.0 seconds. How far does it go?
. . . .
.v v v
d
a
v = 12 m/s
t = 3.0 s
d = ?TM? v constant... v = d/t
d = vt
d = 12 m/s(3.0 s)
d = 36 m
m = m/s (s)
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A 955 kg car slows from 55 mph to 35 mph in1.3 s. What is the deceleration? How fardid he travel during the decelerating?
data?
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v1 = 55 mph
v2 = 35 mph
t = 1.3 s
a = ?
d = ?
A 955 kg car slows from 55 mph to 35 mph in1.3 s. What is the deceleration? How fardid he travel during the decelerating?
particle diagram/vectors?
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v1 = 55 mph
v2 = 35 mph
t = 1.3 s
a = ?
d = ?
d
v v v
a
. . . . .
a
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convertv1 = 55 mphv2 = 35 mpht = 1.3 sa = ?d = ?
55 miles/hr(1 hr/3600s)(1610 m/1mile) = 25 m/s
35 miles/hr(1 hr/3600s)(1610 m/1mile) = 16 m/s
25 m/s
16 m/s
a = Δv/t = (v2 v1)/ta = (16 m/s 25 m/s)/1.3 sa = 6.9 m/s/s = 6.9 m/s2
v = dt/tt dt = v t =
v1 + v2 2
(( t
dt = 25 m/s + 16 m/s 2( (
1.3 s
dt = 27 m
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t = 0.46 s
v1 = 0
v2 = ?
A little girl drops a rock from rest and it hits the ground 0.46 s later. What velocity does it hit the ground at?
vectors?
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t = 0.46 s
v1 = 0
v2 = ?
d
v
v
v
a
a
.
anything else known?
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t = 0.46 s
v1 = 0
v2 = ?
a = 9.8 m/s2
TM?
a, vv
... v =
a = Δv/t
v1 + v22
_
v = Δdt/t_
a = Δv/t
v2 = v1 + at v2 = 0 + 9.8 m/s2 (.46 s)v2 = 4.5 m/s2
you have "a" and "t" and want v2...
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What distance did it fall?from last page
t = 0.46 s
v1 = 0
v2 = ?
What's known?
(4.5 m/s)
a = 9.8 m/s2
d?equation???
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What distance did it fall?from last page
v = (v1 + v2)/2
v = [0 +(4.5 m/s)]/2
v = 2.3 m/s _
_
_
v = dt/tt d = vtd = v (.46s)
_
_
_
d = vtd = 2.3 m/s (.46s) = 1.1 m
_
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d
v
v
v
a
a
d2 = 1.5 m
t2 = 0.55 s
v1 = 0
v2 = ?
a = ?This time a little girl drops a rock from rest from a height of 1.5 m. a) What velocity does it hit the ground at?b) What acceleration did it experience?
a)
b)
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d2 = 1.5 m
t2 = 0.55 s
v1 = 0
v2 = ?
a = ?
a = vt
v = v1 + v22
v = dt
v = Δdt/t = 1.5 m/.55 s = 2.7 m/sv1 + v22
_v = v2 = 2v v1
v2 = 2(2.7 m/s) 0v2 = 5.4 m/s
a = Δv/t = v2 v1/ta = 5.4 m/s 0/.55 sa = 9.8 m/s2
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v =
a = Δv/t
v1 + v22
_
v = Δdt/t_
v2 = 2v v1
Δdt = v t
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d
v
v
v
a
a
A ball is dropped from a cliff and it takes 3.0 s to hit the ground. What velocity does it hit at?
v1 = 0
t = 3.0 s
v2 = ?
.
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vector directions gravity is down so youlist the value as ""
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September 19, 2017
d
v
v
v
a
a
. v
Bad Billy throws a rock upward at 16 m/s. How long does it take to get to the top of it path?v1 = 16 m/s
v2 = 0
t = ?
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ball thrown upward at 16 m/s
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d
v
v
v
a
a
This time bad Billy throws the rock downward at 15 m/s (from a new cliff) and it takes 3.0 s to hit the ground. a) What velocity does it hit the ground at? b) How high was the cliff?
v1 = 15 m/s
a = 9.8 m/s2
t = 3.0 s
v2 = ?
dy = ?
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You pull back a bow 37 cm and let it go. The arrow reaches a speed of 120 m/s as it leaves the bow wow! How long did it take?
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You pull back a bow 37 cm and let it go. The arrow reaches a speed of 120 m/s as it leaves the bow wow! How long did it take?
dp = .37 mv1p = 0v2p = 120 m/st = ?
TM? ... accel,
Δdt = v tt = Δd/vt = .37 m/60 m/st = .0062 s
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You pull back a bow 37 cm and let it go. The arrow reaches a speed of 120 m/s wow! How long did it take? How far does it go in 0.55 s?
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You pull back a bow 37 cm and let it go. The arrow reaches a speed of 120 m/s wow! How long did it take? How far does it go (after it leaves the bow) in 0.55 s?
d = ?
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You pull back a bow 37 cm and let it go. The arrow reaches a speed of 120 m/s wow! How long did it take? How far does it go in 0.55 s? The arrow stops in 4.0 cm?
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duck in air: v1 = 345 ft/sv2 = 0t = ?da = ?
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1200 ft
v2 = ?
t = 3.06 s
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1200 ft
v1 = 345 ft/s
d = 1200 ft
366 m
105 m/s
g = 9.81 m/s2
v2 = ?
t = 3.06 s
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1200 ft
v1 = 345 ft/s
d = 1200 ft
366 m
105 m/s
g = 9.81 m/s2
v2 = ?
a = ∆v/tv2 = v1 + atv2 = (105 m/s) + [(9.81 m/s2)3.06 s]
v2 = 135 m/s
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duck
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