phy315109 - physics - assessment report 2013 · 2019. 9. 28. · 2013assessment’report’...

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Physics Course Code: PHY315109 2013 Assessment Report Tasmanian Qualifications Authority Page 1 of 8 The solutions to the 2013 paper are at the end of the report. Once again, they are written on the exam paper by the appropriate marking examiner as there was a lot of positive feedback when they were presented this way last year. The marking examiners saw little evidence that the paper was too long, which is excellent. They also considered the spread of difficulty was appropriate and there appeared to be relatively few questions that were ambiguous. The use of appropriate units and significant figures in the answers was good, with only the weakest candidates falling down in these areas. The only concern with the paper as presented was that the diagram used for Q16 b(ii) was not clear enough and the correct answer needed the detector to be placed right at the top of the page. Since most students misinterpreted the diagram it was decided by the marking panel that the correct answer was to be awarded a bonus mark (this applied to 8 candidates) and the most common answer (arrived at by misinterpreting the diagram) was given full marks. The Assessment Panel set the following cutoffs, with each /40: Criterion A B C 5 32 23 12 6 32 22 12 7 32 22 12 8 33 26 13 Following is a discussion of the exam paper question by question. PHYSICS EXAMINERS COMMENTS 2013 Question 1 a) Many candidates neglected to find the net force and simply used the resistance to determine the acceleration. Of those who did take into account both the tension and the resistance, quite a few did not do a correct vector addition, so used an incorrect net force. Quite a few students misread 2.5 on the horizontal scale of the graph as being half way between 2 and 4 m s 1 . b) Satisfactory. c) i) Those who realised or derived P = Fv had no problems. Many tried to calculate the ship’s kinetic energy and divide by some arbitrary time interval (usually one second). These answers scored zero.

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Page 1: PHY315109 - Physics - Assessment Report 2013 · 2019. 9. 28. · 2013Assessment’Report’ Page3’of’8’ Question4(’’ a)’ Moststudentscalculatedtheverysimpleanswercorrectlythoughafewdidnotconvertgramto

Physics Course Code: PHY315109

2013 Assessment Report

Tasmanian  Qualifications  Authority   Page  1  of  8  

The  solutions  to  the  2013  paper  are  at  the  end  of  the  report.  Once  again,  they  are  written  on  the  exam  paper  by  the  appropriate  marking  examiner  as  there  was  a  lot  of  positive  feedback  when  they  were  presented  this  way  last  year.      The  marking  examiners  saw  little  evidence  that  the  paper  was  too  long,  which  is  excellent.  They  also  considered  the  spread  of  difficulty  was  appropriate  and  there  appeared  to  be  relatively  few  questions  that  were  ambiguous.  The  use  of  appropriate  units  and  significant  figures  in  the  answers  was  good,  with  only  the  weakest  candidates  falling  down  in  these  areas.      The  only  concern  with  the  paper  as  presented  was  that  the  diagram  used  for  Q16  b(ii)  was  not  clear  enough  and  the  correct  answer  needed  the  detector  to  be  placed  right  at  the  top  of  the  page.  Since  most  students  mis-­‐interpreted  the  diagram  it  was  decided  by  the  marking  panel  that  the  correct  answer  was  to  be  awarded  a  bonus  mark  (this  applied  to  8  candidates)  and  the  most  common  answer  (arrived  at  by  misinterpreting  the  diagram)  was  given  full  marks.    The  Assessment  Panel  set  the  following  cut-­‐offs,  with  each  /40:  

Criterion   A   B   C  

5   32   23   12  

6   32   22   12  

7   32   22   12  

8   33   26   13    Following  is  a  discussion  of  the  exam  paper  question  by  question.      PHYSICS  EXAMINERS  COMMENTS  2013    Question  1      a)           Many  candidates  neglected  to  find  the  net  force  and  simply  used  the  resistance  to  determine  the  

acceleration.  Of  those  who  did  take  into  account  both  the  tension  and  the  resistance,  quite  a  few  did  not  do  a  correct  vector  addition,  so  used  an  incorrect  net  force.  Quite  a  few  students  misread  2.5  on  the  horizontal  scale  of  the  graph  as  being  half  way  between  2  and  4  m  s-­‐1.  

 b)   Satisfactory.    c)   i)         Those  who  realised  or  derived  P  =  Fv  had  no  problems.  Many  tried  to  calculate  the  ship’s  

    kinetic  energy  and  divide  by  some  arbitrary  time  interval  (usually  one  second).  These         answers  scored  zero.  

 

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  ii)           A  substantial  number  of  candidates  incorrectly  said  that  doubling  the  power  would         double  the  force,  and  then  either  read  the  corresponding  speed  off  the  graph,  or  said         that  this  would  double  the  speed.  In  neither  case  did  they  acknowledge  that  the  product       of  their  two  values  gave  nothing  like  the  approximate  value  of  780  kW  required.  A  large         number  of  candidates  simply  ignored  the  graph.  Perhaps  2%  of  candidates  did  this         question  correctly.  

   Question  2    Even  in  Year  12  Physics,  people  are  mixing  up  vertical  and  horizontal  components,  as  well  as  the  hypotenuse,  in  projectile  motion.  Some  students  are  simply  performing  arithmetic  without  quoting  the  equations  or  relationships  they  are  using.  Others  are  quoting  the  equations  but  then  showing  a  final  answer  without  showing  what  numbers  they  substituted  into  the  equations.    a)   i)         Generally  satisfactory,  although  some  students  tried  to  do  a  trigonometric  calculation    

    based  on  an  initial  velocity  that  was  not  given.    a)   ii)  &  b)    Satisfactory    c)           Again,  satisfactorily  answered.  Some  students  lost  up  to  a  mark  if  there  was  no  indication  (here  

or  in  previous  parts)  of  how  they  arrived  at  the  required  horizontal  velocity  before  substituting  it  into  the  appropriate  equation  of  motion.  

 d)           Those  who  got  this  far  generally  had  no  problems  in  this  section.  Perhaps  half  of  those  who  did  

this  part  took  a  fairly  inefficient  approach,  namely  dividing  the  problem  up  into  sections  and  considering  the  trajectory  from  the  zenith  onwards  as  a  horizontal  projectile  motion  problem,  and  then  subtracting  their  answer  from  15  m.    The  question  can  be  done  more  quickly  by  simply  substituting  the  flight  time  and  vertical  initial  velocity  into  s  =  ut  +  ½  at2.  

     Question  3    a)   Most  students  recognised  that  only  two  forces  existed  at  the  beginning  of  the  rocket’s  motion  –  

namely  weight  and  the  thrust  of  the  engines.  These  were  given  strange  names  at  times.      b)   Few  students  mentioned  that  Newton’s  Second  Law  was  relevant.  Far  too  many  students  simply  

used  F  =  ma  =  2.6  x  106  x  2.2  as  their  calculation,  ignoring  weight  altogether.      c)   This  was  poorly  done,  with  few  students  correctly  identifying  the  necessary  force  as  the  thrust  

and  then  realising  mass  per  second  =  thrust/velocity  of  the  gas.      d)   Poorly  done  with  most  students  not  including  weight  and  many  not  converting  tonnes  to  kg.            

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Question  4      a)   Most  students  calculated  the  very  simple  answer  correctly  though  a  few  did  not  convert  gram  to  

kilogram.  Few  put  in  direction.      b)   i)   Extremely  poorly  done.  Students  had  enormous  difficulties  with  the  directions  and    

    subsequent  momentum  diagram.  The  fact  that  the  first  ball  rebounded  made  the         direction  of  the  larger  ball  difficult  to  envisage.  Many  students  failed  to  add  the  two  final       momenta  to  get  the  original,  but  added  the  final  of  the  smaller  to  its  original  to  give         entirely  the  wrong  momentum  for  the  other  ball.    

    ii)   In  lieu  of  the  poor  diagrams,  this  section  was  understandably  badly  done.  The  biggest    

    disappointment  was  the  number  of  students  who  used  1D  solutions  rather  than  some         form  of  2D  solution.  The  marker  was  generous.    

 c)   The  question  was  slightly  ambiguous.  It  could  be  read  that  each  ball  individually  had  to  have  the  

percentage  loss  calculated,  rather  than  the  system.  Many  students  calculated  the  loss  but  did  not  move  on  to  calculate  the  percentage  as  requested.  

 d)   This  answer  depended  on  whether  students  knew  the  term  ‘inelastic’.  Some  didn’t.        Question  5      Overall  this  question  was  made  more  difficult  by  the  use  of  many  units  rather  than  standard  SI  value,  km  mixed  with  metres,  minutes  rather  than  seconds.            a)   The  first  section  was  intended  to  be  a  straightforward  use  of  a  calculator,  but  many  students  

used  the  wrong  radius  (that  of  the  planet)  or  added  radii,  or  didn’t  convert  or….  But  still  somehow  got  the  right  answer!  Amazing.    

 b)   Poorly  done,  with  students  not  really  reading  the  question  and  sitting  back  to  understand  the  

problem.  Many  students  leapt  to  a  formula  and  played  with  it  incorrectly,  interpreting  the  mass  as  that  of  the  satellite  rather  than  the  planet.    

 c)   Reasonably  done  but  many  students  reverted  to  not  using  their  own  value  of  mass.        Question  6    a)   i)     Field  lines  should  start  at  the  positive  plate  and  end  at  the  negative.  Enough  lines  should  

    be  drawn  to  show  the  field  is  uniform.       ii)     Well  done,  except  for  the  conversion  from  cm  to  metres.    

iii)     Also  well  done,  except  the  conversion  from  g  to  kg  was  often  omitted.    

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b)     A  range  of  answers  was  accepted,  with  credit  given  for  good  understanding.  Many  students  inferred  incorrectly  that  the  force  up  had  to  be  greater  than  force  down  in  order  for  the  sphere  to  move  up.  Alternative  acceptable  answers  were:-­‐  

  To  move  upwards  at  constant  speed  implies  Fnet  =  0.  Since  no  magnitude  of  speed  was  mentioned,  just  a  momentary  increase  in  voltage  would  be  enough  to  get  the  sphere  moving  up  from  rest  and,  if  it  were  moving  up  slowly,  it  would  continue  to  move  up  if  V  =  15  kV.  

   Or    To  move  up  with  the  same  speed  as  it  falls,  with  V  =  0,  would  require  a  PD  of  30  kV.  

   Question  7    a)     Straight  forward,  but  incorrect  in  about  a  third  of  the  papers.    b)     Good  understanding.  Some  students  did  not  include  the  50  turns.    c)   A  commutator  is  needed  to  reverse  the  current  each  half  turn  so  that  the  force  is  always  acting  

to  turn  the  coil  in  the  same  direction.    d)   i  &  ii)  Well  done,  except  for  some  students  ignoring  the  commutator  and  some  thinking  that  V  

should  be  constant  if  the  rate  of  rotation  is  constant.    

iii)   The  only  problem  was  the  emf  was  for  a  single  wire,  not  50  turns  of  the  wire.  Also  units         are  volts.  

   Question  8    a)     Magnetic  field  lines  around  the  magnet  should  not  meet  or  cross.  More  care  needed  in  

sketching.    b)     Most  students  deduced  that  a  south  pole  needed  to  be  induced  on  the  magnet  side  of  the  coil  

but  many  then  had  the  current  in  the  wrong  direction.    c)     The  current  needs  to  increase  as  the  magnet  approaches  the  coil,  then  go  to  zero  then  reverse  

direction  as  the  magnet  moves  away  to  the  right.  Symmetry  was  expected.          Question  9    This  was  a  fairly  straightforward  question  but  many  students  had  difficulty  completing  it  successfully.    a)         Forgetting  to  square  ‘v’  and  only  calculating  Ek  were  the  most  common            mistakes.    b)     Many  attempted  to  use  E  =  V/d,  which  is  not  correct.      

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c)       Often  well  done,  with  excessive  early  rounding  resulting  in  lost  marks.  Many  students  used  the  vertical  distance  of  2  cm  instead  of  1  cm  to  incorrectly  test  if  the  electron  emerged.  

   Question  10    Few  students  received  full  marks  for  all  sections.  Part  (d)  was  essentially  a  maths  question  that  examined  a  student’s  maths  skills;  partial  attempts  were  given  partial  marks.  The  use  of  the  term  ‘null  point’  in  the  question  caused  confusion  and  appeared  to  be  a  new  term  for  many  students  which  most  interpreted  to  refer  to  the  point  “X”.    a)       Crossing  field  lines  and  lack  of  merged  field  lines  were  common  errors.    b)       The  wrong  ‘k’  was  often  used.    c)       Few  students  answered  the  question  as  the  examiner  intended.      Question  11    a)   Well  answered  by  the  majority  of  students,  but  some  just  copied  a  inappropriate  diagram  

directly  from  the  formula  sheet  and  therefore  got  no  marks.    b)   Well  done  by  most  candidates.    c)   Some  found  the  length  for  the  incorrect  lower  frequency,  858  Hz      Question  12    a)   Poorly  answered.  Only  a  minority  of  students  could  calculate  the  tension  in  the  rope.      b)   Less  than  half  the  students  recognised  that  the  tension  decreased  on  descending  the  rope.    c)   Descriptions  were  good  but  explanations  were  lacking.    d)   Most  students  focused  on  change  to  line  density  or  tension  but  did  not  take  both  into  account.      Question  13    a)   Polarisation  was  not  well  understood.  Most  answers  were  vague,  describing  light  making  an  

angle  to  the  polariser.    b)   There  was  considerable  confusion  about  the  orientation  of  the  polarising  filter  and  the  partial  

polarisation  of  the  reflected  light.    c)   This  question  was  quite  novel  and  led  to  a  great  variety  of  guesses.    

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Question  14    a)   Surprisingly  poorly  answered;  far  too  many  students  believed  the  frequency  had  to  change!    b)   i)           Well  done.       ii)         Very  poorly  answered.  A  common  error  was  to  confuse  diffraction  with  refraction.    

    Huygens  principle  as  applied  to  refraction  was  very  poorly  understood.    c)   This  was  a  novel  question  that  was  surprisingly  well  answered.      Question  15    All  sections  of  this  question  were  well  answered,  apart  from  the  diagram  showing  the  path  of  the  light.  Angles  of  incidence  and  refraction  seemed  poorly  understood,  as  did  how  to  decide  if  total  internal  reflection  took  place.      Question  16    a)  &     b)  i)  Well  done.      b)   ii)         In    placing  the  detector,  candidates  failed  to  realise  that  a  path  difference  of  2.5  λ  meant  

    the  detector  had  to  be  on  the  3rd  nodal  line  above  the  central  maximum.  (In  this  case         right  at  the  top  of  the  page.)    

 c)   Part  (i)  was  good  but  in  Part  (ii)  very  few  candidates  realised  halving  d  would  double  W  and  so  

there  needed  to  be  half  as  many  fringes  shown  in  graph  2  as  in  graph  1.              Question  17      a)         Most  students  named  X  as  ‘stopping  voltage’,  but  the  explanation,  in  general,  was  poor.  A  

significant  minority  of  students  incorrectly  thought  the  filter  was  relevant.    b)         Nearly  all  students  recognised  the  gradient  was  h  but  a  significant  minority  were  unable  to  

correctly  calculate  that  gradient.    c)         The  threshold  frequency  was  poorly  identified.    d)         Poorly  answered,  with  many  students  stating  conclusions  that  were  irrelevant  to  the  PE  

experiment.  Any  conclusion  relevant  to  the  PE  experiment  was  accepted  regardless  of  whether  it  was  Einstein  or  not.  

     

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Question  18    a)         Both  minimum  excitation  and  ionisation  energies  were  accepted  as  answers;  done  well.    b)   i)         Correctly  answered  by  nearly  all  students,  although  many  thought  their  answer  in  metres  

    was  incorrect  because  they  were  looking  for  an  answer  of  30.    

ii)         Answered  correctly  by  just  about  everyone.  (Both  UV  and  X-­‐ray  was  accepted)    c)   i)           Only  half  the  students  answered  this  correctly  with  many  students  giving  the  Ek  of  the    

    electron  after  the  excitation  as  the  answer.  Most  students  overlooked  the  n3  to  n2         transition.  

    ii)     Just  about  all  students  answered  this  correctly.  Mentioning  the  original  photon  was  not    

    mandatory  in  the  answer  as  long  as  it  was  made  clear  that  the  entire  50  eV  energy  had  to       be  transferred.  

 Question  19    a)         Most  students  made  reference  to  the  high  energy  involved,  but  few  referenced  1%.  A  lot  of  

students  mentioned  that  the  forces  in  tungsten  must  be  strong  in  an  irrelevant  explanation  as  to  why  the  melting  point  was  high.  

 b)   i)         Poorly  answered  as  most  students  had  only  a  vague  idea.    

ii)       Many  students  used  the  name  –    brehmstrahlung  or  braking  (both  words  in  a  variety  of         spellings)  –  but  not  many  gave  correct  explanations  of  what  that  was.  

 iii)     Even  more  poorly  answered  than  (ii)!  The  majority  of  students  used  the  reference         ‘threshold  frequency’,  revealing  confusion  with  the  photo-­‐electric  effect.  

 c)   i)         Quite  a  large  minority  of  students  correctly  stated  the  spikes  would  remain  at  the    

    frequencies  indicated,  although  many  then  sketched  the  spikes  in  different  positions.  Not       many  students  indicated  the  intensities  increased  (again  many  stated  it  would  increase         but  failed  to  show  this  on  their  sketch.)  Few  students  recognised  that  fmax  would  increase.  

 ii)         Quite  a  large  minority  of  students  correctly  stated  the  spikes  would  change  from  the         frequencies  indicated,  although  many  of  those  students  then  sketched  the  spikes  in  same       position.  

   Question  20    a)   Generally  well  done,  with  many  students  getting  full  marks.  Common  sources  for  error  were  

including  the  beta  particle  as  an  incoming  particle,  rather  than  one  that  was  ejected,  and  failing  to  outline  all  three  steps  as  asked.  

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2013  Assessment  Report  

Page  8  of  8  

b)   i)   Generally  well  done.  Most  students  recognised  that  they  had  to  find  the  mass  defect,  and     common  errors  were  calculation  mistakes,  rounding  off  the  masses,  and  failing  to  include     two  neutrons  as  products.  

ii)   Well  done.      c)   i)   Well  done.  Common  errors  were  using  a  mass  of  238.03  (from  the  table),  rather  than  233  

    for  uranium,  when  working  out  the  number  of  atoms,  and  students  trying  to  use  E=mc2.         Some  students  used  mole  calculations  successfully.  

ii)   Adequately  done.  Many  students  left  out  the  30%  efficiency  factor,  or  applied  it  wrongly.      Question  21    a)   i)   Generally  well  done.  Most  candidates  recognised  the  formula  to  use,  but  some  did  not    

    realise  that  the  mass  and  years  could  be  used  directly.  Determining  the  number  of  atoms       was  a  common,  but  superfluous,  approach.  

ii)   Poorly  done.  Many  students  did  not  realise  that  the  mass  from  the  previous  question  had       to  be  subtracted  from  the  total  mass,  or  forgot  to  find  the  fraction  required.  

 b)   Generally  well  done.  Common  errors  were  mixing  the  time  units  of  the  decay  constant  and  the  

decay  equation,  and  in  solving  the  decay  equation.  

 

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TASMANIAN QUALIFICATIONS AUTHORITY

ASSESSMENT PANEL REPORT

PHY315109 Physics

18% (50) 21% (59) 21% (59) 40% (110) 278

23% (56) 22% (54) 15% (37) 40% (100) 247

11 % 19 % 39 % 31 %

20 % 23 % 29 % 28 %

11 % 19 % 39 % 30 %

80% (223) 20% (55) 1% (3) 99% (275)

79% (196) 21% (51) 0% (1) 100% (245)

78% 22% 1% 99%

This year

Last year

Previous 5 years

EA HA CA SA Total

Previous 5 years (all examined subjects)

Last year (all examined subjects)

Award Distribution

Student Distribution (SA or better)

This year

Last year

Previous 5 years

Male Female Year 11 Year 12

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