Physics 1A, Section 7

October 15, 2007

Reminders

• Homework #2 due Wednesday 4 PM

• Quiz #1 due Thursday noon, box outside 110 E. Bridge

OM Chapter 4

OM Chapter 4

OM Chapter 4

Circular Motion

• a = v2/r(At least two ways to show that.)

• v = r

Quiz Problem 19

Quiz Problem 19

• Answer:a) t = 2 (tan - tan) cos2 v0

2 / g

Quiz Problem 26

Quiz Problem 26

• Answer:a) 10.3 m

b) 2.04 s

c) 4.97 m/s2

d) ball, by 7.2 m/s

e) 2.27 sec

OM, Problem 4-55

OM, Problem 4-55

OM, Problem 4-55

• Answer: maximum height = R + R/2[Rg/u2 + u2/Rg]

(for u2 ≥ Rg)

specific case: u = 30 km/h, R = 0.80 m, g = 9.80 m/s2 4.39 m

Thursday, October 18:

• Quiz Problem 36, part (a)

• OM, Chapter 5, Problem 55

• Quiz Problem 37

• Optional to work on these in advance.

Quiz Problem 34

Quiz Problem 34

• Answer:a) vi = -sqrt[2gL/(1-e2)]

b) ti = sqrt[2L(1+e)/(g(1-e))]

c) h = Le2/(1-e2)