potential energy surface molecular mechanics forcefield

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Rev-01 Jahan B Ghasemi Drug Design in Silico Lab. Chem Faculty, K N Toosi Univ of Tech Tehran, Iran May 1 2014 Knowledge is antidote to fear Ralph Waldo Emerson Knowledge is power Hakim Abolghasem Ferdoosi Slide 1 of 101

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An Introduction to PES and MM and ForceField

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Page 1: Potential Energy Surface Molecular Mechanics ForceField

Rev-01Jahan B Ghasemi

Drug Design in Silico Lab.

Chem Faculty, K N Toosi Univ of Tech

Tehran, Iran

May 1 2014

Knowledge is antidote to fear –Ralph Waldo Emerson

Knowledge is power – Hakim Abolghasem Ferdoosi

Slide 1 of 101

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Slide 2 of 101

• Example :

• Familiar conformation of the Butane

7

6

5

4

3

2

1

0

0 60 120 180 240 300 360

0.3

0.25

0.2

0.15

0.10

0.1

0.05

0

C

B

D

E

F

Pote

ntial energ

y

Dihedral angle

Pro

bability

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Slide 3 of 101

ENERGY AS A FUNCTION OF GEOMETRY• POLYATOMIC MOLECULE:

• N-DEGREES OF FREEDOM

• N-DIMENSIONAL POTENTIAL ENERGY SURFACE

http://www.chem.wayne.edu/~hbs/chm6440/PES.html

Page 4: Potential Energy Surface Molecular Mechanics ForceField

A PES is the relationship – mathematical or graphical – between

the energy of a molecule (or a collection of molecules) and its geometry.

The Born–Oppenheimer approximation says that in a molecule the nuclei

are essentially stationary compared to the electrons.

It makes:

1- The concept of molecular shape (geometry) meaningful,

2- Makes possible the concept of a PES, and

3- Simplifies the application of the Schrödinger equation to molecules by

allowing us to focus on the electronic energy and add in the nuclear

repulsion energy laterSlide 4 of 101

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The graph of potential energy against bond length is

an example of a potential energy surface. A line is a

one-dimensional “surface”.

The potential energy surface for a

diatomic molecule. The potential energy

increases if the bond length q is stretched

or compressed away from its equilibrium

value qe. The potential energy at qe (zero

distortion of the bond length) has been

chosen here as the zero of energy.

Slide 5 of 101

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1.They vibrate incessantly(continuously) about the equilibrium bond

length, so that they always possess kinetic energy (T) and/or

potential energy (V): as the bond length passes through the

equilibrium length, V = 0, while at the limit of the vibrational

amplitude, T = 0; at all other positions both T and V are nonzero.

The fact that a molecule is never actually stationary with zero

kinetic energy (it always has zero point energy) is usually shown

on potential energy/bond length diagrams by drawing a series of

lines above the bottom of the curve to indicate the possible

amounts of vibrational energy the molecule can have (the

vibrational levels it can occupy

Real molecules behave similarly to, but differ from our macroscopic model in two

relevant ways:

Slide 6 of 101

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Actual molecules do not sit still at the bottom of the potential energy

curve, but instead occupy vibrational levels. Also, only near qe, the

equilibrium bond length, does the quadratic curve approximate the true

potential energy curve

A molecule never sits at the bottom of

the curve, but rather occupies one of

the vibrational levels, and in a

collection of molecules the levels are

populated according to their spacing

and the temperature. We will usually

ignore the vibrational levels and

consider molecules to rest on the actual

potential energy curves or (see below)

surfaces.

Slide 7 of 101

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2- Near the equilibrium bond length qe the potential

energy/bond length curve for a macroscopic balls-and-

spring model or a real molecule is described fairly well

by a quadratic equation, that of the simple harmonic

oscillator E=(½)K(q-qe)2, where k is the force constant

of the spring).

However, the potential energy deviates from the

quadratic (q2) curve as we move away from qe.

Slide 8 of 101

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A two dimensional PES (a normal surface is a 2-D object) in the three-dimensional graph; we could make

an actual 3-D model of this drawing of a 3-D graph of E versus q1 and q2.

The H2O potential energy surface. The point Pmin corresponds to the minimum-energy geometry for the three atoms, i.e.

to the equilibrium geometry of the water molecule

Slide 9 of 101

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The HOF PES is a 3-D

“surface” of more than two

dimensions in 4-D space:

- It is a hypersurface, and

potential energy surfaces

are sometimes called

potential energy

hypersurfaces.

- -We can define the

equation E = f(q1, q2, q3)

as the potential energy

surface for HOF, where f is

the function that describes

how E varies with the q’s,

and treat the hypersurface

mathematically.

To plot energy against three geometric parameters in a

Cartesian coordinate system we would need four

mutually perpendicular axes. Such a coordinate system

cannot be actually constructed in our three-dimensional

space. However, we can work with such coordinate

systems, and the potential energy surfaces in them,

mathematically.

Slide 10 of 101

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Minimum Potential Energy Geometry at PES

landscape:

- AB is the point at which dE/dq = 0.

- H2O PES the point Pm, at this point dE/dq1 =

dE/dq2 = 0.

- For hypersurfaces cannot be faithfully

rendered pictorially, a computational chemist

use slice of a multidimensional diagram:Slide 11 of 101

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The slice could be made

holding one or the other

of the two geometric

parameters constant, or

it could involve both of

them, giving a diagram

in which the geometry

axis is a composite of

more than one

geometric parameter.

Slide 12 of 101

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A 3-D slice of the hypersurface

for HOF or even a more complex

molecule E versus q1, q2 diagram

to represent the PES.

A 2-D diagram, with q

representing: one, two or all of

the geometric

parameters(composite).

2D and particularly 3D graphs

preserve qualitative and even

quantitative features of the

mathematically rigorous but

unvisualizable E = f(q1, q2, . . .

qn) n-dimensional hypersurface.

1- The angle HOF is constant not optimized Unrelaxed or rigid

PES.

2- The angle HOF is fully optimized this would be a relaxed PESSlide 13 of 101

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Stationary PointsAmong the main tasks of computational chemistry are to determine the

structure and energy of molecules and of the transition states involved in

chemical reactions: our “structures of interest” are molecules and the

transition states linking them.

Consider the reaction

Slide 14 of 101

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E (calculated by the AM1) plotted against:

1- The bond length (assume the two O–O bonds are equivalent)

2- The O–O–O bond angle.

A slice through the reaction coordinate

gives a 1D “surface” in a 2D diagram.Slide 15 of 101

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The slice goes(the curve itself not IRC axis) along the lowest-energy path

connecting ozone, isoozone and the transition state, that is, along the reaction

coordinate.

The horizontal axis (the reaction coordinate) of the 2D diagram is a composite of

O–O bond length and O–O–O angle.

In most discussions this horizontal axis represents the progress of the reaction.

Slide 16 of 101

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Ozone, isoozone, and the transition state are called stationary points.

The Specification of SP:

- A stationary point on a PES is a point at which the surface is flat, i.e.

parallel to the horizontal line corresponding to the one geometric parameter

(or to the plane corresponding to two geometric parameters, or to the

hyperplane corresponding to more than two geometric parameters).

- A marble placed on a stationary point will remain balanced, i.e. stationary

(in principle; for a transition state the balancing would have to be exquisite

indeed).

At any other point on a potential surface the marble will roll toward a

region of lower potential energy.

Slide 17 of 101

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Mathematically, a stationary point is one at which the first derivative of

the potential energy with respect to each geometric parameter is zero:

Slide 18 of 101

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Local Minima, Global Minima:

Stationary points that correspond to actual molecules

with a finite lifetime (in contrast to transition states,

which exist only for an instant), like ozone or isoozone,

are minima, or energy minima:

Each occupies the lowest-energy point in its region of the

PES, and any small change in the geometry increases the

energy, as indicated in Fig.

Ozone is a global minimum, since it is the lowest-energy

minimum on the whole PES,

Isoozone is a relative minimum, a minimum compared

only to nearby points on the surface.Slide 19 of 101

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The lowest-energy pathway

linking the two minima is the

path that would be followed by

a molecule in going from one

minimum to another.

It should acquire just enough

energy to overcome the

activation barrier, pass through

the transition state, and reach

the other minimum.Slide 20 of 101

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The transition state linking the two

minima represents a maximum along

the direction of the IRC, but along all

other directions it is a minimum.

This a saddle-shaped surface, and the

transition state is called a saddle point.(Just like a Saddle while is minimum in one direction, Horse main axis, is

maximum in the other direction, orthogonal to the main Horse axis)

The saddle point lies at the “center” of

the saddle-shaped region and is, like a

minimum, a stationary point,

The PES at that point is parallel to the

plane defined by the geometry parameter

axes: we can see that a marble placed

(precisely) there will balance.

Slide 21 of 101

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Mathematically, minima and

saddle points differ in that

although both are stationary

points but:

1- a minimum is a minimum

in all directions,

2- a saddle point is a

maximum along the reaction

coordinate and a minimum

in all other directions.Slide 22 of 101

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Recalling that minima and maxima can be distinguished by their second

derivatives, we can write:

Slide 23 of 101

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Coordinates for Potential Energy Surfaces

In the absence of fields, a molecule’s potential energy

doesn’t change if it is translated or rotated in space. Thus

the potential energy only depends on a molecule’s internal

coordinates.

There are 3N total coordinates for a molecule (x, y, z for

each atom), minus three translations and three rotations

which don’t matter (only two rotations for linear

molecules).

The internal coordinates: Stretch, Bend, Torsion

coordinates, or Symmetry-adapted(according to sym.

Elements) Linear Combinations, or Redundant

Coordinates, or Normal Modes Coordinates, etc.

[x,y]=meshgrid(linspace(-4,2,50),linspace(-2,4,50));

z=x.^2+y.^2+3*x.^2-3*y.^2-8;

z=3*x-x.^3-3*x.*y.^2;

surf(x,y,z)

[x,y]=meshgrid(linspace(-4,2,50),linspace(-2,4,50));

z=x.^3+y.^3+3*x.^2-3*y.^2-8;

surf(x,y,z)

[c,h]=contour(x,y,z,-14:4);

clabel(c,h)

grid on

xlabel('x-axis')

ylabel('y-axis')

title('The contour map for z=x^3+y^3+3x^2-3y^2-8.')

Slide 24 of 101

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Characterizing Potential Energy Surfaces

The most interesting points on PES’s are

the stationary points, where the gradients

with respect to all internal coordinates are

zero.

1. Minima: correspond to stable or quasi-

stable species; i.e., reactants, products,

intermediates.

2. Transition states: saddle points which

are minima in all dimensions but one; a

maximum in that dimension.

3. Higher-order saddle points: a minimum

in all dimensions but n, where n > 1;

maximum in the other n dimensions.Slide 25 of 101

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A transition state and A transition structure

A transition state is a thermodynamic concept, the species an ensemble

of which are in a kind of equilibrium with the reactants in Eyring’s

transition-state theory.

Since equilibrium constants are determined by free energy differences,

the transition structure, within the strict use of the term, is a free energy

maximum along the reaction coordinate (in so far as a single species can

be considered representative of the ensemble).

This species is also often also called an activated complex. A transition

structure, in strict usage, is the saddle point on a theoretically (Not

realistic) calculated PES. Slide 26 of 101

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A transition state and A transition structure

Normally PES is drawn through a set of points each of which represents the enthalpy of a molecular species at a certain geometry; recall that free energy differs from enthalpy by temperature times entropy.

The transition structure is thus a saddle point on an enthalpy surface(then this is the difference between T-State and T-Structure.

However, the energy of each of the calculated points does not normally include the vibrational energy, and even at 0 K a molecule has such energy, ZPE.

Slide 27 of 101

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The usual calculated PES is thus a hypothetical, physically unrealistic

surface in that it neglects vibrational energy, but it should qualitatively,

and even semiquantitatively, resemble the vibrationally-corrected one

since in considering relative enthalpies ZPEs at least roughly cancel.

A transition state and A transition structure

In accurate work ZPEs are calculated for stationary points and added to

the “frozen-nuclei” energy of the species at the bottom of the reaction

coordinate curve in an attempt to give improved relative energies which

represent enthalpy differences at 0 K (and thus, at this temperature where

entropy is zero, free energy differences also; Next Slide).

Slide 28 of 101

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A transition state and A transition structure

It is also possible to calculate enthalpy and entropy differences,

and thus free energy differences, at, say, room temperature.

Many chemists do not routinely distinguish between the two

terms, and in this course the commoner term, transition state, is

used.

Unless indicated otherwise, it will mean a calculated geometry,

the saddle point on a hypothetical vibrational-energy-free PES.

Slide 29 of 101

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Slide 30 of 101

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Slide 31 of 101

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The propane PES, provides examples of

a minimum, a transition state and a

hilltop – a second-order saddle point in

this case.

The propane PES as the two HCCC

dihedrals are varied (AM1 calculated).

Bond lengths and angles were not

optimized as the dihedrals were varied,

so this is not a relaxed PES; however,

changes in bond lengths and angles

from one propane conformation to

another are small, and the relaxed PES

should be very similar to this one Slide 32 of 101

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Three stationary points:

The “doubly-eclipsed” conformation (a

in Figure) in which there is eclipsing as

viewed along the C1–C2 and the C3–C2

bonds (the dihedral angles are 0o viewed

along these bonds) is a second order

saddle point because single bonds do

not like to eclipse single bonds and

rotation about the C1–C2 and the C3–

C2 bonds will remove this eclipsing:

There are two possible directions along

the PES which lead, without a barrier, to

lower-energy regions, i.e. changing the

H–C1/C2–C3 dihedral and changing the

H–C3/C2–C1 dihedral.Slide 33 of 101

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PES Scan

The geometry of propane depends on more than just two

dihedral angles, of course; there are several bond lengths

and bond angles and the potential energy will vary with

changes in all of them. In PES Scan we have to change all

of them simultaneously.

Slide 34 of 101

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Is Geometry of a Molecules Meaningful with or without BOA?

Yes and No respectively.

Chemistry is essentially the study of the stationary points on

potential energy surfaces: in studying more or less stable

molecules we focus on minima, and in investigating chemical

reactions we study the passage of a molecule from a minimum

through a transition state to another minimum.

Slide 35 of 101

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Is Geometry of a Molecules Meaningful with or without BOA? No and Yes respectively.

There are four known forces in nature: 1-the gravitational force, 2- the strong and 3- the weak nuclear forces, and 4- the electromagnetic force.

Celestial mechanics studies the motion of stars and planets under the influence of the gravitational force and nuclear physics studies the behaviour of subatomic particles subject to the nuclear forces.

Slide 36 of 101

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Is Geometry of a Molecules Meaningful with or without BOA? Yes

and No respectively.

Chemistry is concerned with aggregates of nuclei and electrons (with

molecules) held together by the electromagnetic force, and with the

shuffling of nuclei, followed by their obedient retinue of electrons,

around a potential energy surface under the influence of this force

(with chemical reactions).

The potential energy surface for a chemical reaction has just been

presented as a saddle-shaped region holding a transition state which

connects wells containing reactant(s) and products(s) (which species

we call the reactant and which the product is inconsequential here).Slide 37 of 101

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Slide 38 of 101

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The Born–Oppenheimer Approximation

A PES is a plot of the energy of a collection of nuclei and electrons against the

geometric coordinates of the nuclei.

Essentially a plot of molecular energy versus molecular geometry (or it may be

regarded as the mathematical equation that gives the energy as a function of the

nuclear coordinates).

The nature (minimum, saddle point or neither) of each point was discussed in terms

of the response of the energy (first and second derivatives) to changes in nuclear

coordinates.

But if a molecule is a collection of nuclei and electrons why plot energy versus

nuclear coordinates – why not against electron coordinates? In other words, why are

nuclear coordinates the parameters that define molecular geometry?

The answer to this question lies in the Born–Oppenheimer

approximation.

Slide 39 of 101

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Born and Oppenheimer showed in 1927 that to a very good approximation the

nuclei in a molecule are stationary with respect to the electrons.

One consequence of this is that all (!) we have to do to calculate the energy of a

molecule is to solve the electronic Schrödinger equation and then add the electronic

energy to the internuclear repulsion (this latter quantity is trivial to calculate) to get

the total internal energy.

Mathematically, the approximation states that the Schrödinger equation for a

molecule may be separated into an electronic and a nuclear equation.

Slide 40 of 101

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The nuclei see the electrons as a cloud of negative charge which binds them in fixed relative positions and which defines the surface of the molecule.

Because of the rapid motion of the electrons compared to the nuclei the “permanent” geometric parameters of the molecule are the nuclear coordinates.

The energy (and the other properties) of a molecule is a function of the electron coordinates (E= Ψ(x, y, z of each electron), but depends only parametrically on the nuclear coordinates, i.e. for each geometry 1, 2, . . . there is a particular energy: E1= Ψ1(x, y, z. . .), E1= Ψ2(x, y, z. . .); cf. xn, which is a function of x but depends only parametrically on the particular n.

Slide 41 of 101

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The nuclei in a molecule see a time-averaged electron cloud.

The nuclei vibrate about equilibrium points which define the molecular geometry;

as the nuclear Cartesian coordinates, or as bond lengths and angles r and a here) and

dihedrals, i.e. as internal coordinates.

The experimentally determined van der Waals surface encloses about 98% of the

electron density of a molecule Slide 42 of 101

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Geometry Optimization

The characterization (the “location” or “locating”) of a stationary point(minimum, a transition state or a higher order saddle point) on a PES, that is, demonstrating that the point in question exists and calculating its geometry and energy, is a geometry optimization.

Locating a minimum is often called an energy minimization or simply a minimization, and locating a transition state is often referred to specifically as a transition state optimization.

Slide 43 of 101

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Geometry optimizations are done by starting with an input structure that is believed to resemble (the closer the better) the desired stationary point and submitting this plausible structure to a computer algorithm that systematically changes the geometry until it has found a stationary point.

The curvature of the PES at the stationary point, i.e. the second derivatives of energy with respect to the geometric parameters may then be determined to characterize the structure as a minimum or as some kind of saddle point.

Geometry Optimization

Slide 44 of 101

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Acetone ionized then neutralization of the radical cation, then were frozen in an inert matrix and studied by IR spectroscopy.

The spectrum of the mixture suggested the presence of the enol isomer of propanone, 1-propen-2-ol:

Slide 45 of 101

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To confirm (or refute) this

the IR spectrum of the enol

might be calculated. But

which conformer should one

choose for the calculation?

Rotation about the C–O and

C–C bonds creates six

plausible stationary points

and a PES scan indicated

that there are indeed 6 such

species:The arrows represent one-step (rotation about one bond)

conversion of one species into another Slide 46 of 101

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The plausible stationary points

on the propenol potential energy

surface. From PES scan:

1 is the global minimum

4 is a relative minimum,

2 and 3 are transition states

5 and 6 are hilltops.

AM1 gave relative energies:

1, 2, 3 and 4 of 0, 0.6, 14 and 6.5

kJ mol-1,

(5 and 6 were not optimized).

Left part is the Inset of the

right part to show details of

the 1 and 2 as GM and TSSlide 47 of 101

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Slide 48 of 101

Examination of this PES shows that the global minimum isstructure 1 and that there is a relative minimumcorresponding to structure 4.

Geometry optimization starting from an input structureresembling 1 gave a minimum corresponding to 1,while optimization starting from a structureresembling 4 gave another, higher energy minimum,resembling 4.

Transition-state optimizations starting fromappropriate structures yielded the transition states 2and 3. These stationary points were all characterized asminima or transition states by second-derivativecalculations (the species 5 and 6 were not located).

The calculated IR spectrum of 1 (using the ab initio HF/6–31G* method was in excellent agreement with the observedspectrum of the putative propenol.

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This illustrates a general principle: the optimized structure one obtains is that closest in geometry on the PES to the input structure.

To be sure we have found a global minimum we must search a potential energy surface

There are algorithms that will do this and locate the various minima:

Geometry optimization to a minimum gives the

minimum closest to the input structure.

The input structure A’ is moved toward the

minimum A, and B’ toward B.

To locate a transition state a special algorithm is usually used: this moves

the initial structure A’ toward the transition state

TS.

Optimization to each of the stationary points

would probably actually require several steps

Slide 49 of 101

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Optimization to each of the stationary points

would probably actually require several steps:

An efficient optimization

algorithm knows:

1- In Which Direction to Move

2- How far to step, in an attempt to

reach the optimized structure

Slide 50 of 101

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On the one-dimensional PES of a diatomic molecule:

geometry optimization requires a simple algorithm

On any other surface, efficient geometry

optimization requires a sophisticated

algorithm

Slide 51 of 101

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Slide 52 of 101

Geometry Optimization

Algorithm

1- It is not possible, in general, to go from

the input structure to the proximate

minimum in just one step.

2- Modern geometry optimization

algorithms commonly reach the minimum

within about ten steps, given a

reasonable input geometry.

3- The most widely-used algorithms for

geometry optimization use the

first and second derivatives of the

energy with respect to the geometric parameters. To

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• The input structure at point Pi(Ei, qi)

• The proximate minimum at the point Po(Eo, qo). Example

Slide 53 of 101

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1- Before the optimization has been carried out the values of Eo and qo are of course unknown.

2- If we assume that near a minimum the potential energy is a quadratic function of q, which is a fairly good approximation, then:

Initial qi is a vector and of the geometry of the

molecules at starting point and qo is new geometry

of the molecule. This is Newton-Raphson Slide 54 of 101

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Equation shows that if we know:

(dE/dq)i, the slope or gradient of the PES at the

point of the initial structure.

(d2E/dq2), the curvature of the PES (which for a

quadratic curve E(q) is independent of q).

qi, the initial geometry, we can calculate qo, the optimized geometry:

Very Useful Hint:

The second derivative of potential energy with respect to geometric displacement is the force constant for motion along that geometric coordinate; this is an

important concept in connection with calculating vibrational spectra.

Slide 55 of 101

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Slide 56 of 101

In the illustration of an optimization algorithm using a diatomic molecule, Equation:

Referred to the calculation of first and second derivatives with

respect to bond length, which latter is an internal coordinate

(inside the molecule).

But optimizations are actually commonly done using Cartesian

coordinates x, y, z. Amazing Point!

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Slide 57 of 101

Optimization HOF in a Cartesian

coordinate system.

Each of the three atoms has an x, y and

z coordinate.

Nine geometric parameters, q1, q2, .

. . , q9.

The PES would be a nine-dimensional

hypersurface on a 10D graph.

We need the first and second

derivatives of E with respect to each of

the nine q’s,

Derivatives are manipulated as

matrices.

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The first-derivative matrix, the gradient matrix, for the input structure can be

written as a column matrix:

The second-derivative matrix, the force constant

matrix, is:

The force constant matrix is Called the Hessian.

Slide 58 of 101

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More About Hessian Matrix:

The Hessian is particularly important:

For geometry optimization, For the

characterization of stationary points

as:

Minima Transition

states Hilltops

For the calculation of

IR spectra.

In the Hessian:

∂2E/∂q1q2 = ∂2E/∂q2q1, as is true

for:

All well-behaved

functions,

But this systematic notation is preferable

The first subscript refers to the row and the second to the

column.Slide 59 of 101

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The geometry coordinate matrices for the initial and optimized structures are:

Slide 60 of 101

For n atoms we have 3n

Cartesians;

qo, qi and gi

are 3n×1 column matrices

H is a 3n×3n square matrix

Hint:

Multiplication by the H-1 rather than

division by H is used because matrix

division is not defined.

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For an efficient geometry optimization we need:

An initial structure (for qi)

From a model-building program

followed by molecular mechanics

Initial gradients (for gi)

Calculated analytically (from the

derivatives of the molecular

orbitals and the derivatives of certain

integrals

Second derivatives (for H).

An approximate initial Hessian is often calculated from molecular

mechanics

Slide 61 of 101

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Optimization is not a Single Step Process. Why?

Since the PES is not really exactly quadratic

The first step does not take us all the way to the optimized geometry, qo.

Rather, we arrive at q1, the first calculated geometry.

Using q1 a g1 and a new H1 are calculated (g1calculated analytically and H1updated using the changes in g1).

Using q1 g1 and H1 matrices a new approximate geometry matrix q2 is calculated.

The process is continued until the geometry and/or the gradients (or with some

programs possibly the energy) have ceased to change appreciably.

Slide 62 of 101

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Stationary Points and Normal-Mode Vibrations

Once a stationary point has been found by geometry optimization, it is

usually desirable to check whether it is a minimum, a transition state, or a

hilltop.

This is done by calculating the vibrational frequencies. Such a calculation

involves finding the normal-mode frequencies; these are the simplest

vibrations of the molecule, which, in combination, can be considered to

result in the actual, complex vibrations that a real molecule undergoes.

Slide 63 of 101

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Consider a diatomic molecule A–B; the normal-mode frequency (there is

only one for a diatomic, of course) is given by:

The symbols have their ordinary meanings.

The force constant k of a vibrational mode is a measure of the “stiffness”

of the molecule toward that vibrational mode – the harder it is to stretch

or bend the molecule in the manner of that mode, the bigger is that force

constant.

Frequency of a vibrational mode is related to the force constant for the

mode:

Suggests that it might be possible to calculate the normal-mode

frequencies of a molecule, that is, the directions and frequencies of the

atomic motions, from its force constant matrix (its Hessian).Slide 64 of 101

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This is indeed possible: matrix diagonalization of the Hessian gives the

directional characteristics (eigenvectors, which way the atoms are

moving), and the force constants themselves(eigenvalues), for the

vibrations.

Matrix diagonalization : MATLAB Command:

A=[1 2 3; 3 2 1; 2 1 3] [P lambda]=eig(A); D=inv(P)*A*P

Square matrix A decomposed to 3 square matrices:

D= 6 0 00 −1.4142 00 0 1.4142

P, D and P-1:

A=PDP-1

D is a diagonal matrix as with k in following eq all its off-diagonal

elements are zero. P is eigenvectors and P-1 is inverse of P. Slide 65 of 101

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When matrix algebra is applied to

physical problems, the diagonal row

elements of D are the magnitudes of

some physical quantity, and each

column of P is a set of coordinates

which give a direction associated

with that physical quantity.

* These ideas are made more

concrete in the discussion

accompanying Eq. which shows the

diagonalization of the Hessian

matrix for a triatomic molecule, e.g.

H2O:

Slide 66 of 101

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Equation is of the form A = PDP-1.

The 9 ×9 Hessian for a triatomic molecule:

Is decomposed by diagonalization into a P matrix:

-whose columns are “direction vectors” for the vibrations

-whose force constants are given by the k matrix.

Actually, columns 1, 2 and 3 of P and the corresponding k1, k2 and k3 of

k refer to translational motion of the molecule; these three “force

constants” are nearly zero.

Columns 4, 5 and 6 of P and the corresponding k4, k5 and k6 of k refer to

rotational motion about the three principal axes of rotation and are also

nearly zero.

Columns 7, 8 and 9 of P and corresponding k7, k8 and k9 of k(diagonal

matrix) are the direction vectors and force constants respectively. Slide 67 of 101

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For the normal-mode vibrations: k7, k8 and k9 refer to vibrational modes

1, 2 and 3, while the 7th, 8th, and 9th columns of P are composed of the

x, y and z components of vectors for motion of the three atoms in

mode 1 (column 7), mode 2 (column 8), and mode 3 (column 9).

Slide 68 of 101

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The Basic Principles of Molecular MechanicsDeveloping a Forcefield

k=1500

r0=1.1

r=.7:0.01:1.5

E=(k/2).*(r-r0).^2

Plot(E)

Slide 69 of 101

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The potential energy of a

molecule can be written

Slide 70 of 101

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Forcefield and are energy contributions

from:

Bond stretching

Angle bending

Torsional motion

(rotation) around single

bonds

Interactions between atoms or groups which are nonbonded (not directly bonded

together).

The sums are over all the

bonds, all the angles defined by three atoms

A–B–C,

All the dihedral angles defined by four atoms

A–B–C–D

All pairs of significant nonbondedinteractions.

The mathematical form of these terms and the parameters in them constitute a particular

forcefield. Slide 71 of 101

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The Bond Stretching Term:

The increase in the energy of a spring when it is stretched is

approximately proportional to the square of the extension:

Changes in bond lengths or in bond

angles result in changes in the energy of

a molecule. Such changes are handled

by the Estretch and Ebend terms in the

molecular mechanics forcefield.

kstretch = the proportionality constant the bigger kstretch, the

stiffer the bond/spring – the more it resists being stretched.

l = length of the bond when stretched.

leq = equilibrium length of the bond, its “natural” length.

Slide 72 of 101

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If we take the energy corresponding to the equilibrium length leq as the

zero of energy, we can replace DEstretch by Estretch:

Slide 73 of 101

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The Angle Bending Term:

kbend = a proportionality constant

a = size of the angle when distorted

aeq = equilibrium size of the angle, its “natural” value.

Slide 74 of 101

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The Torsional Term:

Dihedral angles (torsional angles) affect molecular geometries and energies. The energy is a periodic function (cosine or combination of cosines) of dihedral angle.

Slide 75 of 101

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The Nonbonded Interactions Term:

This represents the change in potential energy with distance apart of

atoms A and B that are not directly bonded:

1- these atoms, separated by at least two atoms (A–X–Y–B) or even

2- in different molecules, are said to be nonbonded (with respect to

each other).

Slide 76 of 101

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The Nonbonded Interactions Term:

Note:

A-B case is accounted for by the bond stretching term Estretch,

A–X–B term by the angle bending term Ebend,

nonbonded term Enonbond is, for the A–X–Y–B case, superimposed upon

the torsional term Etorsion:

we can think of Etorsion as representing some factor inherent to resistance

to rotation about a (usually single) bond X–Y, while for certain atoms

attached to X and Y there may also be nonbonded interactions.

Slide 77 of 101

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The potential energy curve for two

nonpolar nonbonded atoms has the

general form:

Variation of the energy of a molecule with

separation of nonbonded atoms or groups.

Atoms/ groups A and B may be in the same

molecule (as indicated here) or the interaction

may be intermolecular.

The minimum energy occurs at van der Waals

contact. For small nonpolar atoms or groups the

minimum energy point represents a drop of a

few kJ mol-1 (Emin=-1.2 kJ mol-1 for CH4/CH4),

but short distances can make nonbonded

interactions destabilize a molecule by many kJ

mol-1 Slide 78 of 101

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A simple way to approximate this is by the so-called Lennard-Jones 12–6

potential:

r = the distance between the centers of the nonbonded atoms or groups.

The function reproduces

1-The small attractive dip in the curve (represented by the negative term)

as the atoms or groups approach one another, then

2-The very steep rise in potential energy (represented by the positive,

repulsive term raised to a large power) as they are pushed together closer

than their van der Waals radii. Slide 79 of 101

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Setting dE/dr = 0:

the energy minimum in the curve the corresponding value of:

r is rmin = 21/6s and s=2-1/6rmin

Slide 80 of 101

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If we assume that this minimum corresponds to van der Waals contact of

the nonbonded groups, then:

rmin = (RA + RB),

the sum of the van der Waals radii of the groups A and B.

So:

21/6s = RA + RB

and so s =2-1/6(RA + RB)= 0.89 (RA + RB)

Thus s can be calculated from rmin or estimated from the van der Waals radii.

Slide 81 of 101

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Setting E = 0, we find that for this point on the

curve r = s:

s= r(E=0)

If we set r = rmin=21/6 s we find:

i.e.

knb = -4E(r=rmin) So knb can be calculated from the depth of

the energy minimum. Slide 82 of 101

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Parameterizing a Forcefield

We can now consider putting actual numbers, kstretch, leq, kbend, etc., into

corresponding Eqs. to give expressions that we can actually use.

The process of finding these numbers is called parameterizing (or

parametrizing) the forcefield.

Training Set

The set of molecules used for parameterization, perhaps 100 for a good

forcefield, is called the training set. Slide 83 of 101

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Parameterizing the Bond Stretching TermA forcefield can be parameterized by reference to:

1- experiment (empirical parameterization) or by

2- getting the numbers from high-level ab initio or density functional

calculations, or by

3- a combination of both approaches.

For the bond stretching term of Eq. we need kstretch and leq.

Experimentally, kstretch could be obtained from IR spectra, as the

stretching frequency of a bond depends on the force constant.

leq could be derived from X-ray diffraction, electron diffraction, or

microwave spectroscopySlide 84 of 101

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Lets find kstretch for the C/C bond of ethane by ab initio calculations.

Normally high-level ab initio calculations would be used to parameterize

a forcefield.

But for illustrative purposes we can use the low-level but fast STO-3G

method.

Eq shows that a plot of Estretch against (l–leq)2 should be linear with a

slope of kstretch.

Slide 85 of 101

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Change in energy as the C–C bond in

CH3–CH3 is stretched away from its

equilibrium length. The calculations

are ab initio (STO-3G). Bond lengths

are in Å

Energy vs. the square of the

extension of the C–C bond in

CH3–CH3. The data in the left

Table were usedSlide 86 of 101

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The equilibrium bond length has been taken as the STO-3G length:

Similarly, the CH bond of methane was stretched using ab initio STO-3G

calculations; the results are:

Slide 87 of 101

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Parameterizing the Angle Bending Term

From Eq., a plot of Ebend against (a–aeq)2 should be linear with a slope of

kbend.

From STO-3G calculations on bending the H–C–C angle in ethane we

get:

Calculations on staggered butane gave for the C–C–C angle

Slide 88 of 101

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Parameterizing the Torsional TermFor the ethane case, the equation for energy

as a function of dihedral angle can be

deduced fairly simply by adjusting the

basic equation:

E=cos q

to give:

E= ½ Emax [1 + cos3(q +60)]

Slide 89 of 101

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Variation of the energy of butane with

dihedral angle. The curve can be

represented by a sum of cosine functions

For butane, using Eq. and

experimenting with a curve-fitting

program shows that a reasonably

accurate torsional potential energy

function can be created with five

parameters, k0 and k1–k4: See the

next slide(a kind of FT to find

cosine basis functions).

Slide 90 of 101

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Slide 91 of 101

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Parameterizing the Nonbonded Interactions Term

To parameterize Eq. we might perform ab initio calculations in which

the separation of two atoms or groups in different molecules (to avoid

the complication of concomitant changes in bond lengths and angles)

is varied, and fit Eq. to the energy vs. distance results.

For nonpolar groups this would require quite high-level calculations, as

van der Waals or dispersion forces are involved. We shall approximate

the nonbonded interactions of methyl groups by the interactions of

methane molecules, using experimental values of knb and s, derived

from studies of the viscosity or the compressibility of methane:

Slide 92 of 101

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Slide 93 of 101

Summary of the Parameterization of the Forcefield Terms The four terms

of Eq. were parameterized to give:

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A Calculation Using Our ForcefieldLet us apply the naive forcefield developed here to comparing the energies of two

2,2,3,3-tetramethylbutane ((CH3)3CC(CH3)3, i.e. t-Bu-Bu-t) geometries.

We compare the energy of structure 1 with all the bond lengths and angles at our

“natural” or standard values (i.e. at the STO-3G values we took as the equilibrium

bond lengths and angles) with that of structure 2, where the central C-C bond has

been stretched from 1.538Å to 1.600Å , but all other bond lengths, as well as the

bond angles and dihedral angles, are unchanged Left Figure shows the nonbonded

distances we need, which would

be calculated by the program

from bond lengths, angles and

dihedrals. Using Eq.:

Slide 94 of 101

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Slide 95 of 101

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Actually, nonbonding interactions are already included in the torsional

term (as gauche–butane interactions); we might have used an ethane-type

torsional function and accounted for CH3/CH3 interactions entirely with

nonbonded terms. However, in comparing calculated relative energies the

torsional term will cancel out.

Slide 96 of 101

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For structure 2

Slide 97 of 101

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The stretching and bending terms for structure 2 are the same as for

structure 1, except for the contribution of the central C-C bond;

strictly speaking, the torsional term should be smaller, since the opposing

C(CH3) groups have been moved apart.

Slide 98 of 101

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This crude method predicts that stretching the central C/C bond of

2,2,3,3-tetramethylbutane from the approximately normal sp3–C–sp3–C

length of 1.583 Å (structure 1) to the quite “unnatural” length of 1.600 Å

(structure 2) will lower the potential energy by 67 kJ mol1, and indicates

that the drop in energy is due very largely to the relief of nonbonded

interactions.

Slide 99 of 101