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Fitting of second degree and exponential curves. practical. Fitting of second degree curve Prob.-. Fit the second degree curve for the above data. Solution- Let the second degree curve be y=a+bx+cx 2 ---------------------(1) - PowerPoint PPT PresentationTRANSCRIPT
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Fitting of second degree and exponential curves.
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1) Fitting of second degree curveProb.-
Year(X) 1 2 3 4 5
Profit(Y) 24 27 32 38 45
Fit the second degree curve for the above data.
Solution-
Let the second degree curve be y=a+bx+cx2 ---------------------(1) By changing variable x to u=x-x , eq. (1) becomes y=a'+b'u+c'u2 ---------------------(2)
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Claim-To find a' ,b' & c'.The normal eq.s to find a' ,b' & c' are
∑y=na'+b'∑u+c'∑u2 -------------(3) ∑uy= a'∑u+b'∑u2+c'∑u3 -----------(4) ∑u2y= a'∑u2+b'∑u3+c'∑u4 ----------(5)
Obtain the values of ∑y, ∑uy, ∑u2y ,∑u , ∑u2 , ∑u3 & ∑u4 . Use these values in eq. (3),(4) & (5) to get a' ,b' & c'.Put the values of u, a' ,b' & c‘ in eq. (2) , we get the required second degree curve.
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Here x = 3Let u=x-x =x-3
x y u=x-3 u2 u3 u4 uy u2y
∑y= ∑u= ∑u2= ∑u3= ∑u4= ∑uy= ∑u2y=
x y u=x-3 u2 u3 u4 uy u2y
1 24 -2 4 -8 16 -48 96
2 27 -1 1 -1 1 -27 27
3 32 0 0 0 0 0 0
4 38 1 1 1 1 38 38
5 45 2 4 8 16 90 180
∑y=166
∑u=0 ∑u2=1o
∑u3=0
∑u4=34
∑uy=53
∑u2y=341
a‘=31.9143 ,b' =5.3, c' =0.6429
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Prob.-Fit second degree curve.
Year(X)
1989 1990 1991 1992 1993 1994 1995
Profit(Y)
10 12 18 20 15 13 16
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2) Fitting of exponential curve y=a bX Prob.-
Year(X) 1951 1961 1971 1981 1991
Profit(Y) 140 170 200 250 300
Fit the exponential curve y=a bX for the above data.
Solution-
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Let the exponential curve be y=a bX ---------------------(1) Taking log (to the base 10) of both sides. log (y)=log(a)+xlog(b) V=A+BX ,Where log (y)=v, log(a)=A, log(b)=BBy changing variable x to u=(x-x)/10 we get v=A +Bu-----------------------(2)Then eq.(1) becomes y=a bu ---------------------(3) The normal eq.s to find A & B are
∑v=n A+ B ∑u -------------(4) ∑uv= A∑u+B∑u2-----------(5)
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Obtain the values of ∑v, ∑uv, ∑u , ∑u2 .
Use these values in eq. (4),(5) to get A & B.
Taking antilog of A & B we get a & b.
putting u, a & b values in eq. (3) we get required eq.
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x y u=(x-1971)/10
V=logy u2 uv
1951 140
1961 170
1971 200
1981 250
1991 300
∑u= ∑v= ∑u2
=∑uv=
Here x = 1971Let u=(x-x )/10=(x-1971)/10
x y u=(x-1971)/10
V=logy u2 uv
1951 140 -2 2.1461 4 -4.2922
1961 170 -1 2.2304 1 -2.2304
1971 200 0 2.3010 0 0
1981 250 1 2.3979 1 2.3979
1991 300 2 2.4771 4 4.9542
∑u=0 ∑v=11.5525
∑u2
=10∑uv=0.8295
A=2.3105,B=0.08295a=204.41,b=1.2105
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Prob.-Fit the curve y=a bX
Year(X)
1 2 3 4 5 6 7
Sale(Y)
32 47 65 92 132 190 275
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3) Fitting of exponential curve y=a ebx Prob.-
X 1 2 3 4 5 6
Y 1.6 4.5 13.8 40.2 125 300
Fit the exponential curve y=a ebx for the above data.
Solution-
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Let the exponential curve be y=a ebx ---------------------(1) Taking log (to the base 10) of both sides. log (y)=log(a)+bxlog(e) u=A+BX --------------------------(2) Where log (y)=u, log(a)=A, blog(e)=b x 0.4343=BThe normal eq.s to find A & B are
∑u=n A+ B ∑x -------------(3) ∑ux= A∑x+B∑x2-----------(4)
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x y u=log(y) x2 ux
1 1.6
2 4.5
3 13.8
4 40.2
5 125
6 300
∑x= ∑u= ∑x2= ∑ux=
x y u=log(y) x2 ux
1 1.6 0.2410 1 0.2041
2 4.5 0.6532 4 1.3064
3 13.8 1.1399 9 3.4197
4 40.2 1.6042 16 6.4168
5 125 2.0969 25 10.4845
6 300 2.4771 36 14.8626
∑x=21 ∑u=8.1754 ∑x2=91 ∑ux=36.6941
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Use eq. 3 & 4 ,find the values of A & B .
Then
a= antilog (A), b=B/0.4343
Put these values of a & b in eq. 1 we get required curve.
A= -0.25347, B= 0.4617a= 0.5578, b= 1.063
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Prob.-Fit the curve y=a ebx
Year(X)
1989 1990 1991 1992 1993 1994 1995
Profit(Y)
10 12 18 20 15 13 16
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Year(X)
1 2 3 4 5 6 7
Sale(Y)
32 47 65 92 132 190 275
Prob.-Fit second degree & the curve y=a ebx ,y=a bX
Prob.-Fit second degree & the curve y=a bX
Year(X)
1989 1990 1991 1992 1993 1994 1995
Profit(Y)
10 12 18 20 15 13 16
Year(X)
1 2 3 4 5 6 7
Index(Y)
10 12 20 24 25 26 30
Prob.-Fit second degree curve & curve y=a ebx ,y=a bX