practice exercise for final exam[1]

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  • 7/24/2019 Practice Exercise for Final Exam[1]

    1/10

    MTS254 Introduction to Management Science

    Solution of Practice Exercise for Final Exam

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    !

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    #

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    %!&%

    &% !%%

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    Max x41

    Subject to

    x41=x

    13+x

    12

    x12+x

    32=x

    23

    x13+x

    23=x

    32+x

    34

    x34 =x41

    x13! 200,x

    12 !150,x

    32 !100,x

    23!100

    x34 !150

    All variables " 0

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    H,'(- )*( -()6%2I ,- D,1F2( .3%'(J K*.) ,/ )*( 92,),9.& 0.)*L

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    H,'(- )*( -()6%2I ,- D,1F2( .3%'(J )*( 92,),9.& 0.)* ,/

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    3 !

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    8" :2%'-++& ;*++&/& -% /*-./ '* (2%& .&, >*1=+'@ 2.A %'2))B C(&0& 20& 2 '*'2+ *)

    53 =+'@ 2.A 93 %'2))B C(& >*%' *) '(& ?2%-> *1%H '(& .=1?&0 *) A&+=I& >*1*1=+'@B C(& ;*++&/& )&&+% '(2' -' 1=%'

    (2%& 2' +&2%' 5 A&+=I& >*1=+'@N -) *1=+'@B O'2)) 1&1?&0% A* )&&+ %*1&,(2' P(-.&% )*0 '(& %'2)) 2% +=%'(2.9*,('(+(-) %5 +.C,+F+ /).55 4(&FC( 9%+0F)(2/

    4A-=F-4(2.9*,('(+(-) %5 )%).& /).55 9%+0F)(2/

    4A+=%'(2.9*,('(+(-) %5 )%).& /).55 9%+0F)(2/

    4R-=F-4(2.9*,('(+(-) %5 3F41()

    4R+=%'(2.9*,('(+(-) %5 3F41()

    It might not be clear but the following is the goals of the problem:

    Goal 1: At least 5 faculty deluxe computers

    Goal 2: At most 20 faculty deluxe computers (as many as 20 so cannot exceed 20)

    Goal 3: Staff deluxe computer is at most 50% of faculty deluxe computerGoal 4: At least total 30 faculty computers. More than 30 is ok but less than 30 is not ok

    Goal 5: At least 10 staff deluxe computers

    Goal 6: At least total 20 staff computers. More than 20 is ok but less than 20 is not ok

    Goal 7: Used at most 100,000 budget. More than 100,000 is not ok but less than 100,000 is ok

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    S,-,+,T( 4!-+4?++4=++4@-+4>-+4A-+4R+

    $F3U(9) )%7 DB+ 4!-- 4!+=> B(&FC( 5.9F&)Q

    DB+4?-- 4?+=?G B(&FC( 5.9F&)Q

    -GN>DB +$B+4=--4=+=G B(&FC( 2.),%

    DB+ DP+4@--4@+==G E%).& 5.9F&)Q$B+4>- -4>+=!G B(&FC( $).55

    $P+ $B+4A--4A+=?G E%).& /).55

    =>GGDB+?GGGDP+?GGG$P+=>GG$B+4R--4R+=!GGGGG 8F41()

    .&& '.2,.3&(/ !G

    5) Consider the following network model. The transportation costs are shown

    above the arcs. The supply capacities are shown in the left of plant nodes and

    the demands are shown on the right of retail nodes. Develop the LP model tofind how to satisfy the demand with minimal cost.

  • 7/24/2019 Practice Exercise for Final Exam[1]

    6/10

    6) Consider the network below. Develop the LP model to find shortest path

    from node 1 to node 6.

  • 7/24/2019 Practice Exercise for Final Exam[1]

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    7) The bank head quarter is trying to locate the minimal number of branches to

    serve all 20 counties below. If a branch is set up at a county, it can serve all

    adjacent counties as well. The list of adjacent counties is shown below. Develop

    LP model to find the minimal number of branches to cover all counties.

  • 7/24/2019 Practice Exercise for Final Exam[1]

    8/10

    8) A company has 3 clients to serve. There are 3 available project leaders tocomplete the projects. The table below shows the completion of the project is

    the particular project leader leads the project. Develop the LP model to find how

    to assign the project leader to client such that the total completion time is

    minimized.

  • 7/24/2019 Practice Exercise for Final Exam[1]

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    9) Consider the project relationship diagram below. The normal time and crash

    time and related crash costs are shown in the table below. Develop the LP

    model to reduce project completion time to 12 weeks.

  • 7/24/2019 Practice Exercise for Final Exam[1]

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    xi = earliest start time of task i (not the same as earlier solution)

    yi= crash time of task i

    Minimize1000ya+2000y

    b+1000y

    c+1000y

    d+1000y

    e+500y

    f + 2000y

    g+3000y

    h

    subject to

    Task A and B no constraint

    xc !x

    a+ (2 "y

    a)

    xd !x

    b+ (3"y

    b)

    xe!x

    c+ (2 "y

    c)

    xf !x

    c+ (2 "y

    c)

    xg !x

    e+ (4 "y

    e)

    xg !x

    d+ (4 "y

    d)

    xh !xg+ (5"yg)

    xh!x

    f + (3"y

    f)

    xh+ (2 "y

    h) #12

    ya #1;y

    b# 2;y

    c#1;y

    d #1;y

    e# 2;y

    f #1;y

    g # 3;y

    h#1;

    All variables! 0