practice test %2d chapter 5 · 2014. 8. 27. · choose (0, 0) as a test point. since 0 is not...

Solve each inequality. Then graph it on a number line.x 9 < 4

The solution set is {x | x < 5}.

6p 5p 3

The solution set is {p | p 3}.

Drew currently has 31 comic books in his collection. His friend Connor has 58 comic books. How many more comic books does Drew need to add to his collection in order to have a larger collection than Connor?

no more than 21 27 at least 28 more than 30

Let c = the number of comic books Drew needs to add to his collection.

Drew needs to add more than 27, or at least 28, comic books to have a larger collection than Connor.So, the correct choice is C.

Solve each inequality. Graph the solution on a number line.

The solution set is {h | h > 15}.

7w 42

The solution set is {w | w 6}.

The solution set is {t | t 36}.

9m < 36

The solution set is {m | m > 4}.

3c 7 < 11

The solution set is {c | c < 6}.

9

The solution set is {g | g 48}.

2(x 4) > 5x 13


The 8th grade science class is going to the zoo. The class can spend up to $300 on admission.

Write an inequality for this situation. If there are 32 students in the class and 1 adult will attend for every 8 students, can the entire class go to the

a. Let s = the number of students and a = the number of adults.

8s + 10a < 300

b. s = 32 and a = 4.

The $296 cost is less than the $300 limit, so the entire class can go to the zoo.

Solve each compound inequality. Then graph the solution set.y 8 < 3 or y + 5 > 19

The solution set is {y | y < 5 or y > 14}. Notice that the graphs do not intersect. To graph the solution set, graph y < 5 and graph y > 14.

or

11 2h 5 13

First, express 11 2h 5 13 using and. Then solve each inequality.

and

The solution set is {h | h To graph the solution set, graph h 3 and graph h

3z 2 > 5 and 7z + 4 < 17

First, solve each inequality.

and

Next, find the intersection of z > 1 and z < 3.

To find the intersection, graph z > 1 and z < 3.

Notice that the graphs do not intersect.

Define a variable, write an inequality, and solve the problem. Check your solution.The difference of a number and 4 is no more than 8.

Let x = the number.

The solution set is {x | x

Check the endpoint with 12 and the direction with a value less than 12.

So, the solution checks.

Nine times a number decreased by four is at least twenty-three.

Let x = the number.


Check the endpoint with 3 and the direction with a value greater than 3.


Write a compound inequality for the graph shown.

2 x < 3 x 2 or x 3 x < 2 or x 3 2 < x 3

Because there is no intersection in the graph, choices F and J are incorrect. Because the points are both solid, choiceH is incorrect. x 2 or x 3 is the compound inequality for the graph shown. So, the correct choice is G.

Solve each inequality. Then graph the solution set.|p 5| < 3

The solution set is {p | 2 < p < 8}.

Case 1 p 5 is positive. and Case 2 p 5 is negative.

|2f + 7| 21

Case 1 2f + 7 is positive.

or

Case 2 2f + 7 is negative.

The solution set is {f | 14 or 7}.

| 4m + 3| 15

Case 1 4m + 3 is positive.

and

Case 2 4m + 3 is negative.

The solution set is }.

Case 1 is positive

or

Case 2

The solution set is {x | x < 17 or x > 23}.

A sporting goods store is offering a $15 coupon on any pair of shoes. The most and least expensive pairs of shoes are $149.95 and $24.95. What is the range of costs for customers

with coupons? When buying a pair of $109.95 shoes, you can use a coupon or a 15% discount. Which option is best?

a.

The range of prices for customers with coupons is p

b. 109.95 15 = 94.95 109.95 109.95(0.15) = 93.46 The 15% discount is the best option.

and

Graph each inequality.y < 4x 1

y < 4x 1

Because the inequality involves 2x + 5. Then determine which of the ordered pairs in {( 2, 0), ( 1, 5), (2, 3), (7, 3)} are in the solution set.

y > 2x + 5 Because the inequality involves >, graph the boundary using a dashed line. Choose (0, 0) as a test point.

Since 0 is not greater than 5, shade the half-plane that does not contain (0, 0). Plot the points on the graph.

The ordered pairs that are in the solution set are (2, 3) and (7, 3).

Mrs. Jones is buying new books and puzzles for her preschool classroom. Each book costs $6, andeach puzzle costs $4. Write and graph an inequality to determine how many books and puzzles she can buy for $96.

Let x = the number of books and y = the number of puzzles. 6x + 4y Solve for y in terms of x.

Since 0 is less than or equal to 24, shade the half-plane that contains (0, 0).

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Practice Test - Chapter 5



6p 5p 3








7w 42



9m < 36


3c 7 < 11


9


2(x 4) > 5x 13





8s + 10a < 300

b. s = 32 and a = 4.




or

11 2h 5 13


and


3z 2 > 5 and 7z + 4 < 17


and





Let x = the number.





Let x = the number.





2 x < 3 x 2 or x 3 x < 2 or x 3 2 < x 3





|2f + 7| 21


or



| 4m + 3| 15


and



Case 1 is positive

or

Case 2




a.



and


y < 4x 1










practice test %2d chapter 5 · 2014. 8. 27. · choose (0, 0) as a test point. since 0 is not...

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