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Here we do not know the direction of travel but we know the magnitude of travel= 4 m. The body will move along the F net F net = -3i+[ - 4sin50 i -4cos50j ]+[10cos35 i + 10sin35 j] = 2.13 i + 3.16j IFI = √ 2.13 2 + 3.16 2 = 3.81 So, work done=Fd= 3.81*4=15.24 Work done is +ve , so kinetic energy will increase.

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Page 1: Problem 14

Here we do not know the direction of travel but we know the magnitude of travel= 4 m.

The body will move along the Fnet

Fnet = -3i+[ - 4sin50 i -4cos50j ]+[10cos35 i + 10sin35 j]

= 2.13 i + 3.16j

IFI = √2.132+3.162= 3.81

So, work done=Fd= 3.81*4=15.24

Work done is +ve , so kinetic energy will increase.

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