problem of the day (monday)

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roblem of the Day (Monday) Alternate Interior Angles? a. 3 & 6, 4 & 5 b. 1 & 4, 2 & 3, 5 & 8, 7 & 6 c. 1 & 5, 2 & 6, 3 & 7, 4 & 8

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Problem of the Day (Monday). Alternate Interior Angles? 3 & 6, 4 & 5 1 & 4, 2 & 3, 5 & 8, 7 & 6 1 & 5, 2 & 6, 3 & 7, 4 & 8 1 & 8, 2 & 7. Angles Review. Corresponding Angles? 1 & 2, 2 & 4, 3 & 4, 1 & 3 6 & 5, 6 & 8, 7 & 8, 5 & 7 1 & 4, 2 & 3, 5 & 8, 7 & 6 1 & 5, 2 & 6, 3 & 7, 4 & 8 - PowerPoint PPT Presentation

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Page 1: Problem of the Day (Monday)

Problem of the Day (Monday)

Alternate Interior Angles?

a. 3 & 6, 4 & 5

b. 1 & 4, 2 & 3, 5 & 8, 7 & 6

c. 1 & 5, 2 & 6, 3 & 7, 4 & 8

d. 1 & 8, 2 & 7

Page 2: Problem of the Day (Monday)

Angles ReviewCorresponding Angles?

a. 1 & 2, 2 & 4, 3 & 4, 1 & 36 & 5, 6 & 8, 7 & 8, 5 & 7

b. 1 & 4, 2 & 3, 5 & 8, 7 & 6

c. 1 & 5, 2 & 6, 3 & 7, 4 & 8

d. 1 & 8, 2 & 7

1 23 4

7

6

8

5

Page 3: Problem of the Day (Monday)

Supplementary Angles?

a. 1 & 2, 2 & 4, 3 & 4, 1 & 36 & 5, 6 & 8, 7 & 8, 5 & 7

b. 1 & 4, 2 & 3, 5 & 8, 7 & 6

c. 1 & 5, 2 & 6, 3 & 7, 4 & 8

d. 1 & 8, 2 & 7

Page 4: Problem of the Day (Monday)

Alternate Exterior Angles?

a. 1 & 2, 2 & 4, 3 & 4, 1 & 36 & 5, 6 & 8, 7 & 8, 5 & 7

b. 1 & 4, 2 & 3, 5 & 8, 7 & 6

c. 1 & 5, 2 & 6, 3 & 7, 4 & 8

d. 1 & 8, 2 & 7

Page 5: Problem of the Day (Monday)

Vertical Angles?

a. 1 & 2, 2 & 4, 3 & 4, 1 & 36 & 5, 6 & 8, 7 & 8, 5 & 7

b. 1 & 4, 2 & 3, 5 & 8, 7 & 6

c. 1 & 5, 2 & 6, 3 & 7, 4 & 8

d. 1 & 8, 2 & 7

Page 6: Problem of the Day (Monday)

Polygon:

Closed figure

Regular Polygon:

All sides are equal

Page 7: Problem of the Day (Monday)

Triangles Everywhere

Page 8: Problem of the Day (Monday)
Page 9: Problem of the Day (Monday)
Page 10: Problem of the Day (Monday)
Page 11: Problem of the Day (Monday)
Page 12: Problem of the Day (Monday)
Page 13: Problem of the Day (Monday)
Page 14: Problem of the Day (Monday)
Page 15: Problem of the Day (Monday)
Page 16: Problem of the Day (Monday)

Problem of the Day (Tuesday)

What is the measure of angle x?

a. 720°

b. 120°

c. 360°

d. 60°

x

Page 17: Problem of the Day (Monday)

A regular pentagon:

1. What is the sum of the interior angles?

2. What is the measure of each interior angle?

3. What is the sum of the exterior angles?

4. What is the measure of each exterior angle?

Page 18: Problem of the Day (Monday)

An irregular pentagon

What is the measure of the missing angle?

90˚

90˚

130˚

130˚

?

Page 19: Problem of the Day (Monday)

A regular hexagon:

1. What is the sum of the interior angles?

Page 20: Problem of the Day (Monday)
Page 21: Problem of the Day (Monday)

What is the measure of the missing angle?

170˚

90˚ 120˚

100˚

130˚?

Page 22: Problem of the Day (Monday)

A regular octagon:

1. What is the sum of the interior angles?

2. What is the measure of each interior angle?

3. What is the sum of the exterior angles?

4. What is the measure of each exterior angle?

Page 23: Problem of the Day (Monday)

A regular decagon:

1. What is the sum of the interior angles?

2. What is the measure of each interior angle?

3. What is the sum of the exterior angles?

4. What is the measure of each exterior angle?

Page 24: Problem of the Day (Monday)

Missing Angles Challenge

110°

45°

Name__________________

a

bc

d

e

f

*You may only assume that the pentagon and hexagon are regular.

gh

i

jk

lm

n

o p

q

r

s t

u vx

a = _____b = _____c = _____d = _____e = _____f = _____g = _____h = _____i = _____j = _____k = _____l = _____m = _____n = _____o = _____p = _____q = _____r = _____s = _____t = _____u = _____v = _____w = _____x = _____

Page 25: Problem of the Day (Monday)

Learning Target

I can…

Find the exterior angles of any polygon

Page 26: Problem of the Day (Monday)

Exterior Angles of a Polygon

Page 27: Problem of the Day (Monday)
Page 28: Problem of the Day (Monday)
Page 29: Problem of the Day (Monday)
Page 30: Problem of the Day (Monday)

Level Five – Find the missing angles1.

ab

2.

3.

4. 34˚

ba

Page 31: Problem of the Day (Monday)
Page 32: Problem of the Day (Monday)

Missing Angles

The lines m and n are parallel

What is the measure angle b?

What is the measure of angle a?

What is the measure of angle g?

What is the measure of angle f?

98°ab c

de

fg

m n

Page 33: Problem of the Day (Monday)

Create your own puzzleRules:1. You must use at least 2 regular

polygons2. Angle measures must be close (they do

not have to be perfectly drawn to scale)3. You must use a ruler4. You must include 3 of the following:

complementary angles, supplementary angles, interior angles, exterior angles, corresponding angles, vertical angles

Page 34: Problem of the Day (Monday)

Problem of the Day (Tuesday)

What is the measure of angle x?

a. 720°

b. 120°

c. 360°

d. 60°

x

Page 35: Problem of the Day (Monday)

A regular pentagon:

1. What is the sum of the interior angles?

2. What is the measure of each interior angle?

3. What is the sum of the exterior angles?

4. What is the measure of each exterior angle?

Page 36: Problem of the Day (Monday)

Congruent Triangles• All sides are congruent and all angles are

congruent

G

H

I

J

K

L

Page 37: Problem of the Day (Monday)

Congruent Triangles

Page 38: Problem of the Day (Monday)

SSS

A

B

C D

E

F

Page 39: Problem of the Day (Monday)

SAS

G

H

I

J

K

L

Page 40: Problem of the Day (Monday)

ASA

Page 41: Problem of the Day (Monday)

AAS

Page 42: Problem of the Day (Monday)

SQ VT Side Q E Angle

QP EY Side

Q Y Angle

Congruent PolygonsCongruent Polygons

Show that each pair of triangles is congruent.

QPR EYT by ASA. SQR VTU by SAS.

b.a.

Q T Angle

QR TU Side

Page 43: Problem of the Day (Monday)
Page 44: Problem of the Day (Monday)
Page 45: Problem of the Day (Monday)

Does AAA guarantee that two triangles are congruent? Why or

why not?

No

Same angles, different sizes

Example:

50° 50°

80°

50° 50°

80°

Page 46: Problem of the Day (Monday)
Page 47: Problem of the Day (Monday)
Page 48: Problem of the Day (Monday)
Page 49: Problem of the Day (Monday)

Congruent PolygonsCongruent Polygons

A surveyor drew the diagram below to find the distance from

J to I across the canyon. Show that GHI KJI. Then find JK.

J H Both are right angles.

JI HI Both measure 48 ft.

KIJ GIH They are vertical angles.

So ∆GHI ∆ JI by ASA

Corresponding parts of congruent triangles are congruent.JK corresponds to HG, so JK is 36 ft.

Page 50: Problem of the Day (Monday)

Congruent PolygonsCongruent Polygons

Use ABC and XYZ to answer the questions.

1.Suppose AC= XZ, AB = XY, and BC = YZ. Write a congruence statement for the figures.

2.Suppose ABC and XYZ are congruent. If AB = 5 cm, BC = 8 cm, and AC = 10 cm, find XZ.

3. Suppose B Y, A X, and AB XY. Why is ABC XYZ?

∆ABC ∆XYZ

10 cm

ASA

Page 51: Problem of the Day (Monday)

Congruent PolygonsCongruent Polygons

4. Let AB = XY = 9 inches; BC = YZ = 24 inches; and m B = 85°, m Z = 35°, and m Y = 85°. Prove that the triangles are congruent and find m C.

∆ABC ∆XYZ by SAS; m C =35°

Page 52: Problem of the Day (Monday)

Problem of the Day (Wednesday)

Are the two triangles congruent? Why?

a. Yes, because of SAS

b. Yes, because of ASA

c. Yes, because of SSS

d. No, because two side are congruent, no angles

Page 53: Problem of the Day (Monday)

aa ABC is congruent to DCB because of SAS

aa ABC is congruent to DCB because of SAS

aa ABC is congruent to BCD because of AAS

d. The triangles are not congruent because they only have a side and angle that are congruent

A

B

C

D

Page 54: Problem of the Day (Monday)

Are the two triangles congruent? Why or why not?

a. Yes, because of SAS

b. Yes, because of ASA

c. Yes, because of SSA

d. No, because SSA is not a congruent triangle rule

Page 55: Problem of the Day (Monday)

Review

Are the two triangles congruent? Why?

a. Yes, because of SAS

b. Yes, because of ASA

c. Yes, because of SSS

d. No, because two side are congruent, no angles

Page 56: Problem of the Day (Monday)

Are the two triangles congruent? Why?

a. Yes, because of SAS

b. Yes, because of ASA

c. Yes, because of SSS

d. No, because two side are congruent, no angles

Page 57: Problem of the Day (Monday)

Are the two triangles congruent? Why?

a. Yes, because of AAS

b. Yes, because of ASA

c. Yes, because of SSS

d. No, because two sides are congruent, no angles

Page 58: Problem of the Day (Monday)

Is ? Why?

a. Yes, because of SAS

b. Yes, because of ASA

c. Yes, because of SSS

d. No, because two side are congruent, no angles

Page 59: Problem of the Day (Monday)

Corresponding parts

If two polygons are congruent, then their corresponding parts are congruent.

For example:

Since QRS = HGJ

That means

Page 60: Problem of the Day (Monday)

Similar TrianglesTriangles are similar if:

1. All angles are congruent

2. Corresponding sides are proportional

Symbol: ABC ~ DEF

Example:

50° 50°

80°

50° 50°

80°2 62 6

5

15

A

B

C

D

E

F

Page 61: Problem of the Day (Monday)

Corresponding Sides

• Sides that match

ABC ~ XBY

AC corresponds to ____

AB corresponds to _____

BY corresponds to _____ A

B

C

X Y

Page 62: Problem of the Day (Monday)

Are the triangles similar?

No, ¾ is not proportional to ½

2

1

3 4

A

B

CD

E

F

Page 63: Problem of the Day (Monday)

Are the triangles similar? Why or why not?

1.5

2

Page 64: Problem of the Day (Monday)

If ABC ~ DEF, find x

9

11

40.5

A

B

CD

E

Fx

Page 65: Problem of the Day (Monday)
Page 66: Problem of the Day (Monday)
Page 67: Problem of the Day (Monday)

Other Polygons Can Be Similar Too*They still must have congruent angles and sides must be proportional

A

B C

DE

FG

H

If the two figures are similar, what is the measure of side EH?

16

5 2

Page 68: Problem of the Day (Monday)

You try!

Page 69: Problem of the Day (Monday)

Which polygons are always similar?

(hint: they always have congruent angles and they will always have proportional sides)

a. Rhombuses

b. Squares

c. Triangles

d. Pentagons

Page 70: Problem of the Day (Monday)

CPS Learning Series Questions!

Page 71: Problem of the Day (Monday)

Problem of the Day (Thursday)If the two figures are similar, what is the

value of x?

852

71.5

x

a.11

b.5.81

c.464.75

d.14

Page 72: Problem of the Day (Monday)

Right Triangles

hypotenuse

leg

leg

Page 73: Problem of the Day (Monday)

Pythagorean Theorem

1. Use when you know 2 sides of a right triangle and you need to figure out the 3rd

2. a² + b² = c²3. a and b are lengths of sides and c is

the length of the hypotenuse

Page 74: Problem of the Day (Monday)

Example

a²+ b² = c²a = 3, b = 43² + 4² = c²9 + 16 = c²25 = c²5 = c

3

4

x

Page 75: Problem of the Day (Monday)

You try

Find the measure of

the hypotenuse x

5

12

x

Page 76: Problem of the Day (Monday)

You try again!

Page 77: Problem of the Day (Monday)

You also can find the length of a side

Find the missing length

a² + b² = c²8² + x² = 10²64 + x² = 100 -64

x² = 36 x = 6

x

810

Page 78: Problem of the Day (Monday)

You try!

Page 79: Problem of the Day (Monday)
Page 80: Problem of the Day (Monday)

Pam is making a new sail for her sailboat pictured below. What is the height of the

sail?

a² + b² = c²

a² + 10² = 26²

a² + 100 = 676

-100

a² = 576

a = 24

Page 81: Problem of the Day (Monday)

A ladder, placed 4 ft from a wall, touches the wall 11.3 ft

above the ground. What is the approximate length of the ladder?

c2 = 42 + 11.32 Substitute.

The length of the ladder is about 12 ft.

c2 = 143.69

c2 = 16 + 127.69 Square 4 and 11.3.

Add.

Use a calculator.

Take the square root of each side.

c = 11.98708

c2 = 143.69

Draw a diagram to illustrate the problem.

c2 = a2 + b2 Use the Pythagorean Theorem.

Use the Pythagorean Theorem.

The Pythagorean Theorem

Page 82: Problem of the Day (Monday)

a² + b² = c²6² + 8² = 9² ?36 + 64 = 81?100 = 81?No, she cannot use these boards

Page 83: Problem of the Day (Monday)

Problem of the Day (Friday)

Page 84: Problem of the Day (Monday)
Page 85: Problem of the Day (Monday)

You Try!

Page 86: Problem of the Day (Monday)

Draw a picture!

Page 87: Problem of the Day (Monday)
Page 88: Problem of the Day (Monday)
Page 89: Problem of the Day (Monday)