problem solving: form words to symblos

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PROBLEM SOLVING: FORM WORDS TO SYMBLOS LESSON1.1

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PROBLEM SOLVING: FORM WORDS TO SYMBLOS. LESSON1.1. Keywords that indicate operations used in writing algebraic expressions. Keywords that indicate operations used in writing algebraic expressions. How to represent a word expression by algebraic symbols. - PowerPoint PPT Presentation

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Page 1: PROBLEM SOLVING: FORM WORDS TO SYMBLOS

PROBLEM SOLVING:

FORM WORDS TO SYMBLOS

LESSON1.1

Page 2: PROBLEM SOLVING: FORM WORDS TO SYMBLOS

Keywords that indicate operations used in writing algebraic

expressions.

Operation keywordsADDITION Sum, total, plus,

increased by, more than

SUBTRACTION

Difference, exceeds, less than, less, minus, decreased by, diminished by, subtracted from

Page 3: PROBLEM SOLVING: FORM WORDS TO SYMBLOS

Keywords that indicate operations used in writing algebraic

expressions.

Operation keywords

MULTIPLICATION

product, multiplied by, times, twice, doubled, tripled

DIVISION Quotient, divided by

Page 4: PROBLEM SOLVING: FORM WORDS TO SYMBLOS

How to represent a word expression by algebraic symbols.

First choose a variable to represent the unknowns.

Identify the key word(s) that indicate the operation.

Use algebraic symbols to represent the word expression.

Page 5: PROBLEM SOLVING: FORM WORDS TO SYMBLOS

Example 1. Write an algebraic expression for each word expression.

P29.50 less than the cost of a coat

Solution: Let x = the cost of the coat. P29.50 less than the cost : x – 29.50

Page 6: PROBLEM SOLVING: FORM WORDS TO SYMBLOS

Example 2. Write an algebraic expression for each word expression.

Five more than three times the number of pages

Solution: Let p = the number of pages. Five more than three times the

number :

3p +5

Page 7: PROBLEM SOLVING: FORM WORDS TO SYMBLOS

Many word problems involve more than one unknown .

In these problems, one condition (CONDITION1) tells how the unknowns related.

You can use this condition to represent the unknowns.

A second condition (CONDITION 2) tells what quantities are equal.

You can use this condition to write an equation for the problem.

Page 8: PROBLEM SOLVING: FORM WORDS TO SYMBLOS

Example 3.

In a recent year, the cost of electricity used for lighting a house was P9.00 less than 6 times the cost of operating a color tv set (CONDITION1). The total cost for these two items was P834.50 (CONDITION 2). Find the cost for lighting.

Page 9: PROBLEM SOLVING: FORM WORDS TO SYMBLOS

Solution

Use CONDITION1 to represent the unknowns.

Let c = the cost of operating a color tv set .

Then 6c - 9= the cost for lighting.

Page 10: PROBLEM SOLVING: FORM WORDS TO SYMBLOS

Solution Use CONDITION 2 to write an equation. c + 6c - 9= 834.50 total cost Solve the equation: c + 6c - 9= 834.50 7c -9 = 834.50 7c = 843.50 c = 120.50 6c – 9 = 614.00

Check: CONDITION 1.

Is the cost for lighting P9.00 less than 6 times the cost for the color tv?

614.00 =6(P120 – P9.00?

Yes.

Page 11: PROBLEM SOLVING: FORM WORDS TO SYMBLOS

Solution Use CONDITION 2 to write an equation. c + 6c - 9= 834.50 total cost Solve the equation: c + 6c - 9= 834.50 7c -9 = 834.50 7c = 843.50 c = 120.50 6c – 9 = 614.00

Check:CONDITION 2. Is the total cost P834.50?

P614.00 + P120 = P834.50?

Yes.

Page 12: PROBLEM SOLVING: FORM WORDS TO SYMBLOS

STEPS IN SOLVING WORD PROBLEMS.

Identify CONDITION1.Use this condition to represent the unknowns.

Identify CONDITION2. Use this condition to write an equation for the problem.

Solve the equation. Check in the original conditions of

the problem. Answer the question.