problems on lcm and hcf

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Read Basics of LCM and HCF Here, Before starting Practice 1. Find the least number which when increased by 4 is exactly divisible by 8, 16, 24, 30 and 32 ? a) 480 b) 484 c) 476 d) 472 e) None of these 2. What is the greatest number of five digits which when 3769 is added to it will be exactly divisible by 5, 6 , 10, 12, 15 and 18 ? a) 4309 b) 99459 c) 100539 d) 99911 e) None of These 3. Find the minimum number of square tiles required to pave the floor of a room of 2m 50cm long and 1m 50cm broad ? a) 50 b) 750 c) 45

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Problems on LCM and HCF

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  • ReadBasicsofLCMandHCFHere,BeforestartingPractice

    1.Findtheleastnumberwhichwhenincreasedby4isexactlydivisibleby8,16,24,30and32?a)480b)484c)476d)472e)Noneofthese

    2.Whatisthegreatestnumberoffivedigitswhichwhen3769isaddedtoitwillbeexactlydivisibleby5,6,10,12,15and18?a)4309b)99459c)100539d)99911e)NoneofThese

    3.Findtheminimumnumberofsquaretilesrequiredtopavethefloorofaroomof2m50cmlongand1m50cmbroad?a)50b)750c)45

  • d)15e)Noneofthese

    4.Fivebellstolltogetherattheintervalsof5,6,8,12and20secondsrespectively.Findthenumberoftimestheytolltogetherinonehour'stime(Inclusiveofthetollatthebeginning)a)120b)31c)30d)5e)NoneofThese

    5.Amilkmanhasthreedifferentkindsofmilk493liters,551litersand435liters.Findtheminimumnumberofequalsizecontainersrequiredtostoreallthemilkwithoutmixing.a)29b)51c)58d)49e)Noneofthese

    6.Thecircumferenceofthefrontandbackwheelsofavehicleare63/14mand81/18mrespectively.Atanygivenmoment,achalkmarkisputonthepointofcontactofeachwheelwiththeground.Findthedistancetraveledbythevehiclesothatboththechalkmarksareagainonthegroundatthesametimea)217.5mb)435m

  • c)412md)419me)Noneofthese

    7.TheLCMoftwonumbersis28timesoftheirHCF.ThesumoftheirLCMandHCFis1740.Ifoneofthenumbersis420,theothernumberisa)150b)225c)180d)240e)Noneofthese

    8.TwopersonsAandBwalkaroundacirculartrackwhoseradiusis1.4km.Awalksataspeedof176metersperminutewhileBwalksataspeedof110metersperminute.iftheybothstartatthesametime,fromthesamepointandwalkinthesamedirection,atwhatintervaloftimewouldtheybothbeatthesamestartingpointagain?(inHours)a)62/3b)21/3c)51/4d)32/3e)Noneofthese

    9.Findtheleastnumberwhichwhendividedby8,9,15,24,32and36leavesremainders3,4,10,19,27and31respectively?a)2880b)2885

  • c)2974d)2875e)Noneofthese

    10.Findthegreatestnumberwhichwhendivide357,192and252leavessameremainderineachcasea)45b)1c)15d)Cantbedetermindee)Noneofthese

    Solutions:

    1.LCMof8,16,24,30and32is480So,Requirednumberis4804=476

    2.LCMof5,6,10,12and18is540Ondividing(99999+3769)by540,theremainderis88So,therequirednumberis9999988=99911

    3.HCFof250cmand150cmis50cm,whichisthesideofthetile

  • So,therequirednumberoftiles=(250X150)/(50X50)=15

    4.TimeafterwhichallthebellstoltogetheristheLCMof5,6,8,12and20.i.e.,120seconds=20minutesThenumberoftimestheytolltogetherinonehour=60/2=30+1(beginningtone)So,theansweris31

    5.Asminimumnumberofcontainersarerequired,thesizeofthecontainershouldbemaximumandthesizeisalsoequal.sosizeofthecontainerwillbeHCFof493,551and435i.e.,29So,requirednumberofcontainersis=(493+551+435)/29=51

    6.TherequireddistanceistheLCMof63/14and81/18LCMof63/14and81/18=LCM(87/14,145/18)=>LCM(87,145)/HCF(14,18)=435/2=217.5m7.LCM=28HCFLCM+HCF=1740=>28HCF+HCF=1740HCF=1740/29=60andLCM=28X60ifaandbaretwonumbers,thenLCMof(a&b)XHCFof(a&b)=aXb28X60X60=xX420=>x=240So,theothernumberis240

  • 8.Circumferenceofthetrackis2r=2X(22/7)X1400m=8800m

    TimetakenbyAtocompleteoneround=(8800m)/(176m/min)=(8800X60)/(176)=3000sec

    TimetakenbyBtocompleteoneround=(8800)/(110m/min)=(8800X60)/(110)=4800sec

    TimetheymeettogetheratthestartingpointisLCMof3000and4800seci.e.,24000sec=62/3hoursSo,theymeetatthestartingpointafter62/3hours

    9.Wecanobservethatthedifferencebetweenthenumbersandtheirremaindersissamei.e.,83=94=1510=2419=3227=3631=5

    So,requiredanswerisLCM(8,9,15,24,32,36)5=>28805=2875

    10.RequiredanswerisHCF(357192,192252,357252)=>HCF(165,60,105)=15