project - ans.docx

7/28/2019 Project - Ans.docx

1/7

PART B

a)

b) Price Index, 1000

1 P

PI

Brand AI= 125

P0 = RM 2.20

10020.2

125 1 RM

P

P1 = RM 2.75

2 Dozen of Brand A = 2 x (RM 2.75 x 12)

2 Dozen of Brand A = RM 66.00

Brand BI= 80

P0 = RM 1.20

10020.1

80 1 RM

P

P1 = RM 0.96

2 Dozen of Brand B = 2 x (RM 0.96 x 12)2 Dozen of Brand B = RM 23.04

Brands Volume Price (RM)

A Anlene: Low Fat Milk 125 ml RM 2.20

B Milo 180 ml RM 1.20

C Nescafe Milk Coffee Drink 200 ml RM 2.00D Yeos Chrysanthemum Tea 250 ml RM 1.50

E Dutch Lady Strawberry 1000 ml RM 4.99


2/7

Brand C

I= 110

P0 = RM 2.00

100

00.2

110 1 RM

P

P1 = RM 2.20

2 Dozen of Brand C = 2 x (RM 2.20 x 12)

2 Dozen of Brand C = RM 52.80

Brand DI= 150

P0 = RM 1.50

10050.1

150 1 RM

P

P1 = RM 2.25

2 Dozen of Brand D = 2 x (RM 2.25 x 12)

2 Dozen of Brand D = RM 54.00

Brand EI= 100

P0 = RM 4.99

10099.4

100 1 RM

P

P1 = RM 4.99

2 Dozen of Brand E = 2 x (RM 4.99 x 12)

2 Dozen of Brand E = RM 99.80

TOTAL AMOUNT OF 2 DOZEN FROM EACH BRAND= RM 66.00 + RM 23.04 + RM 52.80 + RM 54.00 + RM 99.80

= RM 295.64


3/7

c)

Angle of C + D = 360o90

o60

o42

o= 168

o

Assume that the angles of C and D is x

Based on the question, sales of C is twice the sales of D

Therefore, 2x + x = 168o

3x = 168o

x = 56

o

Angle of C = 112o

Angle of D = 56o

Composite Index,i

ii

w

wII

Brand Price Index Weightage

A 125 90

B 80 60

C 110 112

D 150 56

E 100 42

Composite Index,42561126090

)42(100)56(150)112(110)60(80)90(125

I

Composite Index,360

40970I

Composite Index, 8.113I


4/7

PART C

a) ConjectureThe bigger the size of packet drink, the smaller the value of

V

Aratio.

Measurement of 5 Packet Drinks

Calculation

Brand AArea of Cross-section

= 2(8.5 cm x 4.5 cm) + 2(4.5 cm x 3.0 cm) + 2(8.5 cm x 3.0 cm)

= 154.500 cm2

Volume

= 8.5 cm x 4.5 cm x 3.0 cm

= 114.750 cm3

Ratio ofV

A

=750.114

500.154

= 1.346 cm-1

Brands Volume Dimension( h x l x w) [cm]

A Anlene: Low Fat Milk 125 ml 8.5 x 4.5 x 3.0

B Milo 180 ml 9.0 x 4.8 x 4.0

C Nescafe Milk Coffee Drink 200 ml 11.5 x 4.8 x 3.8

D Yeos Chrysanthemum Tea 250 ml 13.0 x 5.3 x 3.6

E Dutch Lady Strawberry 1000 ml 19.5 x 9.0 x 5.6


5/7

Brand B

Area of Cross-section


= 196.800 cm2

Volume= 9.0 cm x 4.8 cm x 4.0 cm= 172.800 cm

3

Ratio ofV

A

=800.172

800.196

= 1.139 cm-1

Brand C

Area of Cross-section= 2(11.5 cm x 4.8 cm) + 2(4.8 cm x 3.8 cm) + 2(11.5 cm x 3.8 cm)= 234.280 cm

2

Volume= 11.5 cm x 4.8 cm x 3.8 cm

= 209.760 cm3

Ratio ofV

A

= 760.209

280.234

= 1.117 cm-1

Brand D

Area of Cross-section= 2(13.0 cm x 5.3cm) + 2(5.3 cm x 3.6 cm) + 2(13.0 cm x 3.6 cm)

= 269.560 cm2

Volume= 13.0 cm x 5.3 cm x 3.6 cm

= 248.040 cm3

Ratio ofV

A

=040.248

560.269

= 1.087 cm-1


6/7

Brand E

Area of Cross-section


= 670.200 cm2

Volume= 19.5 cm x 9.0 cm x 5.6 cm= 982.800 cm

3

Ratio ofV

A

=800.982

200.670

= 0.682 cm-1

b)

Mean, N

xx

5

cm1.346cm1.139cm1.117cm1.087cm0.682 -1-1-1-1-1 x

074.1x

Median = valuethN

2

1

TheV

Aratio in ascending order

0.682 cm-1, 1.087 cm-1, 1.117 cm-1, 1.139 cm-1, 1.346 cm-1

Median = valueth2

15

Median = valuerd3

Median = 1.117 cm-1

Interquartile range = Q3Q1

Q3 =2

346.1139.1

Q3 = 1.243 cm-1

Q1 =2

087.1682.0

Q1 = 0.885 cm-1


7/7

Therefore, the interquartile range

= 1.2430.885

= 0.358 cm-1

Standard deviation, =

22

N

x

N

x

Standard deviation, = 2

22222

074.15

1.3461.1391.1171.0870.682

Standard deviation, = 0.216

project - ans.docx

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