THE PATH OF A PROJECTILE

Christine Chang Ruth LeeZach Rice

Alton Zheng

PHYSICS BASICS

+ Vertical velocity= vi sin Ѳ

+ Horizontal velocity= vi cos Ѳ

DISPLACEMENT EQUATIONS

y= (vy)(t) + 0.5gt2

x= (vx)(t)

COMBINE THEM

PLUG IN

EQUATION OF PROJECTILE MOTION

REAL WORLD APPLICATION

+ Video of our example

INITIAL

AFTER 1 SECOND

VALUE OF VARIABLES

Ѳ = 45⁰h = 6 ftVx = 12 ft/sg = 32.174 ft/s^2

Solve for vi :vi cos 45= 12 ft/s

vi = 17.0 ft/s

+ To find the y position of the ball at any point x, plug values into the equation above.

+ For example, at x = 6+ Y = 6(tan 45) – [(32.174)(62)(sec2 (45))]/[2(172)]

+ 6+ Y= 7.992 ft

+ h