properties of solutions
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Properties of Solutions. Chapter 13 BLB 11 th. Expectations:. g ↔ mol (using molar mass) g ↔ mL (using density) Other conversions: temp., pressure, etc. Solve for any variable in a formula. Distinguish between molecular and ionic compounds. - PowerPoint PPT PresentationTRANSCRIPT
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Properties of SolutionsChapter 13 BLB 11th
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Expectations: g ↔ mol (using molar mass) g ↔ mL (using density) Other conversions: temp., pressure, etc. Solve for any variable in a formula. Distinguish between molecular and ionic
compounds. Convert between different concentration
units. Describe the properties of solutions.
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13.1 The Solution Process Solution – homogeneous mixture
Solute – present in smaller quantity Solvent – present in larger quantity
Intermolecular forces are rearranged when a solute and solvent are mixed.
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Making a Solution1. Solute molecules separate (endothermic)2. Solvent molecules separate (endothermic)3. Formation of solute-solvent interactions
(exothermic)ΔHsoln = total energy
ΔHsoln – enthalpy change for the formation of a solution; exothermic – usually favorable; endothermic – usually unfavorable
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Will a solution form? Solute-solvent interaction must be stronger or
comparable to the separation of solute and solvent particles.
Intermolecular forces play a key role. Entropy (disorder) is also a factor.
Disorder is favorable. (2nd law of thermodynamics) Solution formation increases entropy.
Dissolve vs. react (p. 533-4)
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Entropy in Solution Formation
Ionic compoundvery ordered
As the ionic compound dissolves, itbecomes more disordered.
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13.2 Saturated Solutions and Solubility Saturated solution – solution is in equilibrium
with undissolved solute.
Solute + solvent ⇌ solution
Unsaturated – less solute than saturated Supersaturated – more solute than saturated
dissolution
crystallization
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A Saturated Solution
A dynamic equilibrium – ions continually exchange between the solid and solution form.
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13.3 Factors Affecting Solubility1. Like dissolves like, i.e. same polarity.
Polar solutes are soluble in polar solvents. Nonpolar solutes are soluble in nonpolar solvents. If two liquids: miscible or immiscible
Examples:✔ water + alcohol, NaCl + water, hexane + pentane✘ water + hexane, NaCl + benzene, oil + water
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Fat- and Water-Soluble Vitamins
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13.3 Factors Affecting Solubility2. Pressure Effects (for gases in any liquid
solvent) Solubility increases as the partial pressure above the
solution increases. Henry’s Law: Sg = kPg
Sg – solubility of gask – Henry’s Law constant; conc./pressure unitsPg – partial pressure of gas above solution
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The partial pressure of O2 in your lungs varies from 25 to 40 torr. What molarity of O2 can dissolve in water at each pressure? The Henry’s Law constant for O2 is 6.02 x 10-5 M/torr.
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13.3 Factors Affecting Solubility3. Temperature Effects
For solids: Solubility ↑ as temperature ↑ - usually. If ΔHsoln > 0 (endothermic) If ΔHsoln < 0 (exothermic)
For gases: Solubility ↓ as temperature ↑ - always. Kinetic energy plays a primary role. Entropy is also a factor.
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Ioniccompounds
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Gases(In liquids)
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13.4 Ways of Expressing Concentration Mass %, volume %, and ppm
610solutiongsolutegppm
100%solutionmLsolutemL%volume
100%solutiongsoluteg%mass
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13.4 Ways of Expressing Concentration, cont. Mole fraction, molarity, and molality
solventkgsolutemol
solutionLsolutemolsolutionmolsolutemol
m
M
X
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44. A solution contains 80.5 g ascorbic acid (C6H8O6) in 210 g water and has a density of 1.22 g/mL at 55°C.Calculate mass %, X, m, and M.
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51. Commercial aqueous nitric acid has a density of 1.42 g/mL and is 16 M. Calculate mass % of HNO3.
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43. A sulfuric acid solution containing 571.6 g of H2SO4 per liter of solution has a density of 1.329 g/cm3. Calculate the mass %, mole fraction, molality, and molarity.
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Concentration Problems Practice! See Figure 13.19, p. 545, for conversion map. Several examples on pp. 544-6.
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13.5 Colligative Properties The addition of a solute to a pure solvent:
1. Lowers the vapor pressure2. Lowers the freezing point3. Raises the boiling point4. Causes movement through a semipermeable
membrane (osmosis) Depends on the number of solute particles (moles),
not the identity; more particles the greater the effect Ionic compounds cause an even greater effect.
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1. Lowering the vapor pressure Addition of solute blocks the solvent from
evaporation. More solute, less vapor, lower vapor pressure Raoult’s Law (for a nonvolatile solute):
PA = XAPA° PA – solvent v. p. over solution(PA < PA°) PA° – pure solvent v. p.
XA – mole fraction of solvent
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1. Lowering the vapor pressure, cont. When a volatile solute is added, both the
solvent and solute contribute to the vapor pressure.
“Expanded” Raoult’s Law: Ptotal = PA + PB = XAPA° + XBPB°
If a solution obeys Raoult’s Law, it is an ideal solution.
Nonideal solutions have strong intermolecular interactions which lower the vapor pressure of the solution even further.
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Vapor Pressure Lowering
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62a. Calculate the vapor pressure above a solution of 32.5 g C3H8O3 (glycerin-nonvolatile) in 125 g water at 343 K. The vapor pressure of water at 343 K is 233.7 torr.
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63. A solution is made from equal masses of water and ethanol (C2H5OH). Calculate the vapor pressure above the solution at 63.5°C. The vapor pressures of water and ethanol are 175 and 400. torr, respectively, at 63.5°C.
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2. Boiling point elevation3. Freezing point depression
Since a solution has a lower vapor pressure: A higher temperature is needed to boil solution A lower temperature is needed to freeze solution.
To calculate effect:b.p. ↑ ΔTb = Kb·m solution − solventf.p. ↓ ΔTf = Kf·m solvent − solution ΔT – difference between boiling or freezing points of the pure
solvent and solution K – boiling or freezing pt. dep. constant (specific to solvent) m – molality
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69a. Calculate the freezing and boiling points of a solution that is 0.40 m glucose in ethanol.For ethanol: f.p. -114.6°C, b.p. 78.4°C, Kf = 1.99 °C/m, Kb = 1.22 °C/m
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72. Calculate the molar mass of lauryl alcohol when 5.00 g of lauryl alcohol is dissolved in 0.100 kg benzene (C6H6). The freezing point of the solution is 4.1°C. For benzene: f.p. 5.5°C, Kf = 5.12 °C/m
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4. OsmosisOsmosis – movement of solvent molecules through
a semipermeable membrane from a region of lower solute concentration to a region of higher solute concentration
Driving force – to dilute the higher concentration Continues until:
Equilibrium is reached between two solutions, or External pressure prevents further movement.
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Osmosis in red blood cells
Hypertonic solution Hypotonic solution
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4. Osmosis, cont.Osmotic pressure
P = M R T P – osmotic pressure (atm)M – molarityR – 0.08206
L∙atom/mol∙KT – temperature (K)
Good technique for measuring molar mass of large molecules like proteins
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4. Osmosis, cont. Applications:
Kidney dialysis Intercellular transport
Reverse osmosis – apply external pressure to reverse the flow of solvent molecules Water purification – alternative to salt ion exchange Desalination – purification of salt water
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78. A dilute aqueous solution of an organic compound is formed by dissolving 2.35 g in water to form 0.250 L of solution. The resulting solution has an osmotic pressure of 0.605 atm at 25°C. Calculate the molar mass of the compound.
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13.6 Colloids Colloid or colloidal dispersion
Intermediate between a solution and a suspension Dispersing medium – analogous to solvent Dispersing phase – analogous to solute; typically
large molecules with high molar masses Does not settle Tyndall effect – particles scatter light
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Tyndall Effect
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Types of Colloids
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Surfactants Change the surface properties so that two
things that would not normally mix do Emulsifying agent Soap Detergent
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Hydrophobic – water-fearing (nonpolar)Hydrophilic – water-loving (polar)
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Action of soap on oil