pure maths exam c4 edexcel specimen paper - a-level maths tutor
DESCRIPTION
Mark scheme for exam C4(6666), an A2 level paper.This is a specimen paper for A-level mathematics from Edexcel.The exam will cover the following: Algebra and functions; coordinate geometry in the (x, y) plane; sequences and series;differentiation; integration; vectors.TRANSCRIPT
EDEXCEL PURE MATHEMATICS C4 (6666) SPECIMEN PAPER MARK SCHEME
54
Questionnumber Scheme Marks
1. 21
)34(�
� x = 21
4� 2
1
431
�
��
���
�� x
= 21 � �� �� � � �� �� �� �
��
�
�
��
�
��
�����
����� .....
62831
343
25
23
212
43
23
21 xx
x B1 M1
= 21 + x
163 , + 2
25627 x , + 3
2048135 x ……. A1, A1, A1
(5 marks)
2. 26x + 26yy´ ; � 10xy´ – 10y = 0 M1A1; M1A1
y´(26y – 10x) = 10y – 26x
y´ = xyxy
10262610
�
�
= xyxy
513135�
�
M1 A1
(6 marks)
3. x = tan ��d
dx = sec2 � � I = ��
� dsecsec
4
2
��
� M1 A1
Limits 4� and 0 B1
I = ��
��� dcos2 = �
� d2
12cos��� �
M1 A1
= 4
0242sin
�
��
��
���
�� M1 A1
= 84
1 �
� (*) A1 cao
(8 marks)
EDEXCEL PURE MATHEMATICS C4 (6666) SPECIMEN PAPER MARK SCHEME
55
Questionnumber Scheme Marks
4. (a) tx
dd = sec2 t
ty
dd = 2 cos 2t, �
xy
dd =
tt
2sec2cos2
M1 A1, � M1
When t = 3� gradient is
41
� B1 (4)
(b) y � 23 =
m1
� (x – �3) P has coordinates (�3, 23 ) B1
y � 23 = 4 (x – �3) M1
y = 4x � 327
A1 (3)
(c)xy
dd = 0 � gradient of tan = 0, gradient of normal undefined M1
� x = tan 4� , i.e: x = 1 A1 (2)
(9 marks)
5. (a) 5 + � = 2 � 3�; 3 � 2� = �11 � 4� B1 B1
�� + 3� + 3 = 0
2� � 4� � 14 = 0
2� + 6� + 6 = 0
10� + 20 = 0 � � = �2 � � = 3 M1 A1
� point is (8, �3, 4) A1 (5)
(b) � a � 10 = 4 � a = 14 M1 A1 (2)
(c) cos � = 252591083�
���
M1 A1
= 253
15�
= 2
1
Angle = 45� M1 A1 (4)
(11 marks)
EDEXCEL PURE MATHEMATICS C4 (6666) SPECIMEN PAPER MARK SCHEME
56
Questionnumber Scheme Marks
6. (a) 11x � 1 � A(2 + 3x) + B(1 � x)(2 + 3x) + C(1 � x)2
Putting x = 1 � A = 2 B1
Putting x = 32
� � 325
� = C925
� C = � 3 B1
cf x2 0 = �3B + C � B = �1 M1A1 (4)
(b)� ��
�
�
�
21
021
2x
� )1(
1x�
� )32(
3x�
dx
= ��
���
�����
�xx
x32ln1ln
12 M1 A1ft A1ft
A1ft
= [4 + ln 21 � ln 3 2
1 � (2 � ln 2)] M1
= 2 + ln 21
21
32�
M1
= 2 + ln 72 A1 (7)
(11 marks)
7. (a) xu
dd = 2
1 � 21 cos 4x; = 2
1 � 21 (1 � 2 sin2 2x) = sin2 2x M1 A1; M1 A1
(4)
(b) V = � � x sin2 2x dx M1
= �4
0
d4sin81
24sin
81
2
�
��
���
��� �
�
��
� xxxxxx M1 A1 A1
= � 4
0
22
4cos321
44sin
82
�
��
���
����
�
� �� xxxxx M1 A1
= � ��
���
���
�
321
321
64
2 = � �
�
���
��
�
161
64
2
M1 A1 (8)
(12 marks)
EDEXCEL PURE MATHEMATICS C4 (6666) SPECIMEN PAPER MARK SCHEME
57
Questionnumber Scheme Marks
8. (a)tr
dd = 2r
kB1
A = �r2 �rA
dd = 2�r M1A1
� tA
dd = 2�r 2r
k = � �rk�2 ; = � �
21
2
��
���
�
�
�
A
k = A
k23
2�M1; M1
� tA
dd �
A1 (*) A1 (6)
(b) � S dS = � 2e2t dt M1
23
32 S = e2t + C M1A1
t = 0, S = 9 � C = 17 B1
� 23
32 S = e2t + 17 and use S = 16 M1
��
���
��17
3128 = e2t � t =
21 ln ��
���
�
377
M1
= 1.6 A1 (7)
(13 marks)