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Kevin Christian Dela Cruz, R.Ph. [email protected] * QC-1: Drug Testing & Assay Review

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Page 1: Qc 1 review

Kevin Christian Dela Cruz, [email protected]

* QC-1: Drug Testing & Assay

Review

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*Analytical Chemistry* Aka. Pharmaceutical Analysis* Branch of chemistry which provides information relative to the composition of matter.

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*2 Divisions of Analytical Chemistry1. Qualitative

oAnswer the question:•What is present in a given sample?

oDetermine the composition of the sample.

2. QuantitativeoAnswer the question:•How much is present in the sample?

oDetermine the proportion of components in a given sample?

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*Classification of Analysis

1.Based on the sample size2.Based on the extent of

determination3.Based on nature of method4.Based on materials used

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* I. Based on the sample

1.Ultra-micro : <1 mg2.Micro : 1 mg – 10 mg3.Semi-micro : 10 mg – 100

mg4.Macro : 100 mg – 1 g

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* II. Based on the extent of determination

1.Proximate – total amount of class / group of active principles in a given sample.

2.Ultimate – amount of a specific compartment / single chemical species present in the sample.

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* III. Based on nature of method1. Classical

oAka. General or ChemicaloEg. Titrimetric, Gravimetric

2. InstrumentationoUsed for more accurate analysisoEg. Spectrophotometer, Polarimeter

3. Miscellaneous / Specific method oInvolves crude drugs and natural products derived from themoEg. Water content determination, Ash content, Acid value

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*IV. Based on materials used

1.ChemicaloUse of chemical reagents

2.PhysicaloUse of instruments & special apparatus

3.BiologicaloUse of microorganisms or animals

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*Basic Principles

1.pH

2.Buffer Capacity

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*I. pH

1. Negative logarithm of molar concentration of Hydrogen ion;.

2. pH = -log[H+] or pH = log 3. Henderson-Hasselbalch

equationopH = pka + log oropH = pka + log • pKa – acid dissociation constant

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*I. pHSample problem:1. Calculate the pH of solution that contains

3.7 x 10 -2 moles of Hac and 4.8 x 10 -2 moles of NaAc in a liter of solution pKa = 9.26.

2. What is the ratio of the salt & acid conc. if the solution has a pH of 4.5 and pKa of 4.76?

Answers: 1.) pH=9.37; 2.) 0.58

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*I. pH4. Properties:oProtolysis – a process whereby a proton

is transferred from one molecule to another.oAutoprotolysis – a process whereby

there is a transfer of a proton from one molecule to another identical molecule.oAmphoteric – property where a

substance can act as either as acid or base.

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*II. Buffer Capacity

1. Ability of buffer solution to resist change in pH upon addition to acid/alkali.

2. BC equation = 3. Van slyke:

Amount in g/L of strong acid or a strong base required to be added to a solution to change it’s pH by 1 unit.

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*Methods used for Official Assay

1.Titrimetry**2.Gravimetric **3. Spectrometric method4. Electrometric method5. Chromatographic method6. Miscellaneous method

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*Assay

An investigative (analytic) procedure in laboratory medicine, pharmacology, environmental biology and molecular biology for qualitatively assessing or quantitatively measuring the presence or amount or the functional activity of a target entity (the analyte).

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*I. Titrimetry**

1. Aka. Volumetric AnalysisoA process of determining volume of standard solution (of known concentration) required to react with a known amount of substance being assayed.

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*I. Titrimetry**2. Definition of terms:o Analyte – aka. sample, active constituent, titrando Standard solution – aka. volumetric solution,

titrant o Indicator – chemicals capable of changing color at

or near end point in w/c equivalent quantities of analyte & std solution have reacted.

o Equivalent point – aka. Theoretical pt. or Stoichiometric pt. is a point where the added substance is chemically equivalent to the analyte or sample.

o End point – experimental approximate of the Eq.Pt. which could be observable.

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*I. Titrimetry**3.Apparatus used:

a.Burets:oMohr’s / baseoGeissler’s / acid

b.Cleaning solutions:oNa2Cr2O7 in H2SO4

o(NH4)2S2O8 in H2SO4

oNa3PO4

oSynthetic detergents

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*I. Titrimetry**4. Indicators

INDICATOR pH range

ACID BASE

Malachite green

0.0-2.0 Yellow Green

Methyl orange 3.2-4.4 Red-Orange

Yellow

Methyl Red 4.2-6.2 Red YellowBromthymol blue

6.0-7.6 Yellow Blue

Phenolphthalein

8-10 Colorless Red

Thymol blue 8-9.2 Yellow Blue

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*I. Titrimetry**5. Types of titration:

a) Based on # of volumetric solutionoDirect titrationoIndirect / Residual titration

b) Based on chemical reactionoNeutralizationoRedOxoReactions involving Combinations of Ions

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*A. Based on # of volumetric solution1.Direct titration

* 1 std. sol’n + Analyte%P = x 100

2.Indirect / Residual titration* 2 std. solution + Analyte* Involves addition of excess std.

solution (primary std) & the excess is back titrated w/ another std. solution (secondary std).

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*Indirect titration* Used when:

1. Sample is insoluble or forms a ppt.2. Sample is volatile3. Slow reaction4. Reaction does not have sharp end point

*End point1. Visual end point - use of indicators2. Electrometric end point – use of

instruments in ampherometry, conductivity or HF titration

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*Indirect titration* Formula• %P = x100

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*Blank Determination* Performing the entire titration

process without the analyte- Rationale: 1. to enhance end point reliability

2. to account for correction* Formula• %P = x 100

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*Sample problem* A 0.3 g sample of Sod. bicarbonate

(MW=84 g/mol) requires 4 mL of 0.9 N HCL. What is its % purity?

* If sample magnesia magma weighing 5 g when dissolved in 25 mL 1 N H2SO4 required 10 mL of 1 N NaOH to titrate the excess acid, what is the % purity of magnesia magma? (Mg = 24; O = 16; H=1)

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*B. Based on chemical reaction1.Neutralization

* Acid-base reaction* Alkalimetry & Acidimetry

2.RedOx* Chemical reaction involves a change in the

balance number of reacting substance3.Reactions involving Combinations of Ions* Volumetric precipitation* Complexation / Chelometry reaction

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*I. NeutralizationA.Acidimetry1.Direct• Sample: NaHCO3, Na2CO3, NaOH• Vs: HCl, H2SO4

2. Indirect • Sample: ZnO, Methenamine• 1* std: HCl, H2SO4• 2* std: NaOH

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*I. NeutralizationB.Alkalimetry1.Direct• Sample: H3PO4, H3BO3, HCl• Vs: NaOH

2. Indirect • Sample: Aspirin• 1* std: NaOH• 2* std: K biphthalate

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*II. Reduction-oxidation

1.Permanganometry2.Iodimeetry3.Iodometry4.Cerimetry

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*II. Reduction-oxidation1.Permanganometry* Direct• Sample: H2O2• Vs: KMnO4* Indirect • Sample: Malic Acid, TiO2• 1* std: KMnO4• 2* std: Na2C2O4

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*II. Reduction-oxidation2. Iodimetry* Assay of reducing agents* Involves iodine* Direct• Sample: Ascorbic acid; Tartar

emetic• Vs: I2

* Indirect • Sample: Calomel, antipyrine• 1* std: I2

• 2* std: As2O3

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*II. Reduction-oxidation3. Iodometry* Assay of oxidizing agents* Involves iodide* Direct• Sample: CuSO4, NaOCl• Vs: Na2S2O3

* Indirect • Sample: Phenol, Resorcinol, PbO• 1* std: Na2S2O3• 2* std: K2Cr2O7

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*II. Reduction-oxidation

Indicators:1. Starch TS:* Iodimetry : colorless* Iodometry : blue

2. Chloroform, CCl4

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*II. Reduction-oxidation

4.Cerimetry• Sample: Vit. K (Menadione);

FeSO4• Vs: Ce(SO4)2• Indicator: Orthophenantroline TS

(Red to Blue)

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*III. Reaction involving combination of ions1. Volumetric precipitation

a) Volhard - Formation of insoluble colored complex. Ex. Aminophlline

b)Mohr – Formation of 2nd precipitate. Ex. SLS

c) Gay-Lussac – Cessation of precipitation. Ex. NaCl

d)Liebig – Appearance of turbidity Ex. Organic Nitrogen compounds

e) Fajans – Change in color of precipitate Ex. Pheyleprine HCl; Tubocurarine HCl

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*III. Reaction involving combination of ions2. Complexation / Chelometry reaction

* Sample: CaCO3, ZnO, Mg (direct)Bi & Al cmpds (residual)

VS: EDTA – ethelynediaminetetraacetic acidIndicator: hydronaphtol blue* Masking – metal detection in presence of

another metal.Masking agent Element masked

Triethanolamine Al, Fe, MnThioglycol Hg, Cu, BiCyanide Zn, Co, Ni, CuFluoride Ca, Mg, Al

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II.Gravimetry**

1. Analysis where in constituents of a sample are separated & the product is weighed

2. Determining the weight of the substance in a sample from the weight of chemically equivalent amount of some other substances

3. Examples: MgO in Mg citrate sol’n.;Na2SO4 in SLS

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II.Gravimetry**

Formula:%P = x 100 or;%P =

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II.Gravimetry**

Sample Problem:If a 0.5 g sample KI yielded 0.8 g

of AgI ppt by gravimetric assay. What would be the % purity of KI? (MW of KI = 166 g/mol; MW of AgI = 235 g/mol)

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