qs utilization & distribution of power system

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Qs utilization & distribution of power system 1 - What are basic things in planning of an electrical distribution system?& types of loads ? In the planning of an electrical distribution system, as in any other enterprise, it is necessary to know three basic things: 1. The quantity of the product or service desired (per unit of time) 2. The quality of the product or service desired 3 . The location of the market and the individual consumers Logically, then, it would be well to begin with the basic  building  blocks, the individual consumers, and then determine efficient means of supplying their wants, individually and collectively . 2 - Define the next expressions : max. demand , demand factor , load factor , diversity factor , coincidence factor , utilization factor ,power factor Maximum Demand The actual load in use by a consumer creates a demand for  electric energy that varies from hour to hour over a period of time but reaches its greatest value at some point. This may be call ed the consumer’s instanta ne ous ma xi mum de ma nd; in  practice, however, the maximum demand is taken as that which is sustained over a more definite period of time, usually 15, 30, or 60 min. These are referred to as 15-, 30-, or 60-min integrated demands, respectively. Demand Factor The ratio of the maximum demand to the total connected load is

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Qs utilization & distribution of power

system

1-What are basic things in planning of anelectrical distribution system?& types of loads?

In the planning of an electrical distribution system, as in

any other enterprise, it is necessary to know three basic

things:

1. The quantity of the product or service desired (per unit

of time)

2. The quality of the product or service desired3.The location of the market and the individual

consumersLogically, then, it would be well to begin with the basic

 building

 blocks, the individual consumers, and then determine

efficient means of 

supplying their wants, individually and collectively.

2-Define the next expressions : max. demand ,

demand factor , load factor , diversity factor ,

coincidence factor , utilization factor ,power

factorMaximum Demand

The actual load in use by a consumer creates a demand for electric energy that varies from hour to hour over a period of 

time but reaches its greatest value at some point. This may be

called the consumer’s instantaneous maximum demand; in

 practice, however, the maximum demand is taken as that which

is sustained over a more definite period of time, usually 15, 30,

or 60 min. These are referred to as 15-, 30-, or 60-min integrated

demands, respectively.

Demand FactorThe ratio of the maximum demand to the total connected load is

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called the demand factor. It is a convenient form for expressing

the relationship between connected load and demand. For 

example, a consumer may have ten 10-hp motors installed; at

any one time, some will not be in use and others will not be

fully loaded, so that the actual demand may be only 50 hp; the

demand factor is 50 divided by 100, or 50 percent.

The demand factor differs for different types of loads, and by

averaging a large number of loads of each type, typical demand

factors can be obtained. These values are important in

determining the size of facilities to be installed for a particular 

service; they are extremely useful in making estimates in

  planning new distribution systems or in expanding existing

ones.Load Factor

The load factor is a characteristic related to the demand factor,

expressing the ratio of the average load or demand for a period

of time (say a day) to the maximum demand (say 60 min) during

that period.

For example, a consumer household may have a maximum

demand of 2kW during the evening when many of its lights, the

TV, the dishwasher, and other appliances are in use. During the24-h period, the energy consumed may be 12 kWh; thus the

average demand or load is 12 kWh divided by 24 h, or 0.5 kW,

and the load factor in this case is 0.5 kW divided by 2 kW, or 25

  percent. This provides a means of estimating particular 

consumers’ maximum demand if both their consumption and

a typical load factor for their kind of load are known.

Diversity

Consumer load diversity describes the variation in the time of use, or of maximum use, of two or more connected loads. Load

diversity is the difference between the sum of the maximum

demands of two or more individual consumers’ loads and the

maximum demand of the combined loads (also called the

maximum diversified demand or maximum coincident demand).

For example, one consumer’s maximum demand may occur in

the morning, while another’s may occur in the afternoon, and

still another’s in the early morning hours, as shown in

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Figure 3-1.

Diversity

Consumer load diversity describes the variation in the time of 

use, or of maximum use, of two or more connected loads. Load

diversity is the difference between the sum of the maximum

demands of two or more individual consumers’ loads and the

maximum demand of the combined loads (also called themaximum diversified demand or maximum coincident demand).

For example, one consumer’s maximum demand may occur in

the morning, while another’s may occur in the afternoon, and

still another’s in the early morning hours, as shown in

Figure 3-1.

Coincidence Factor

The coincidence factor is the ratio of the maximum coincident

total demand of a group of consumers to the sum of themaximum demands of each of the consumers.

Utilization Factor

The ratio of the maximum demand of a system to the rated

capacity of the system is known as the utilization factor. Both

the maximum demand and the rated capacity are expressed in

the same units. The factor indicates the degree to which a

system is being loaded during the load peak with respect to its

capacity. The rated capacity of a system is usually determined by its thermal capacity, but may also be determined by voltage

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drop limitations, the smaller of the two determining the

capacity.

Power Factor

The ratio of power (in watts) to the product of the voltage and

current (in volt-amperes) is called the power factor. It is a

measure of the relation between current and voltage out of phase

with each other brought about by reactance in the circuit

(including the device served).Since facilities must be designed

to carry the current and provide for losses which vary as the

square of the current, and for voltage drops which are

approximately proportional to the current, it is necessary that

current values be known. The power factor enables loads and

losses designated in watts to be converted to amperes.Transformer sizes, wire and cable sizes, fuses, switch ratings,

etc., are all based on values of current they must carry safely and

economically.

3-What advantages for conversion from delta to

wye in power system distribution?

The principal advantages to such conversions from deltato wye systems are:

1. The wye system affords greater feeder capacity and

usually improved voltage regulation.

2. Existing transformers, insulators, and other material

can be used; in most cases, spacing between conductors

is left unchanged.

3. Single-phase branches need not have any work doneon them.

4. Existing secondary neutral conductors can be used as

the fourth and neutral conductor in establishing the wye

circuit. Where a new neutral conductor is required, it can be installed safely and readily in the secondary position

on the pole with no conflict with the higher-voltage

energized conductors

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5. The entire circuit need not be converted to the higher 

voltage at

one time, but can be converted piecemeal over a period

of time; a portion of the three-phase delta circuit can be maintained

from a

relatively small step-down transformer (pole-mounted)

connected

to the new supply three-phase wye circuit.

6. Transformers and other equipment at the substation

can be rearrangedand reutilized, like those on distribution lines.

7. Where the neutral is grounded at the substation and at

many points along the feeder, the voltage stresses on the

insulation of 

the lines, transformers, and other devices are limited to

the lowest

 possible value; should an accidental ground occur on any

 phase, it

will be cleared as the circuit breaker opens.

8. Important savings can be realized in the equipment

installed on

wye systems: transformers need only one high-voltage

 bushing;

only one cutout and lightning arrester are required (if acompletely

self-protected transformer is used the cutout can be

eliminated);

and the single high-voltage line conductor may be

mounted on one

 pin at the top of the pole, eliminating the need for a cross

arm (and

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contributing to a neater appearance of the line.(

 4-What principals features of the required

additional protections in the case of parallelingof systems?

1. Automatic synchronizing of the generator output with

the utility.

2. Relaying to prevent the closing of the circuit breaker 

to the utility

system until the cogenerator’s generator is open, for 

 protection of that generator.

3. Relaying to open the circuit breaker to the utilitysystem on loss of 

 power in the utility system.

4. Relaying to open the circuit breaker to the utility

system on a

ground fault on the utility system.5. Relaying to control the cogenerator’s generator circuit

 breaker to

 provide generator overcurrent protection, phase current

 balance

 protection, reverse power protection, under- and over-frequency

 protection, and under- and overvoltage protection.

6. Control of engine governor equipment for speed,

generator phase

match, and generator load.

5-What are the requirements which the design

distribution system must meet?

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6-What are the distribution system problems? Distribution System Problems

Where distribution feeders are deliberately designed to

accommodatesuch lowering of voltage below normal values, it may benecessary

to reinforce or provide for some consumers, usually at

the ends of primary

circuits. These may have a sufficiently low normal

voltage that the

additional drop may cause damage to some of their connected loads. In

most cases, provision involves the shortening of 

secondary mains and

the more closely spaced installation of transformers; also,taps may be set

for a lower (or the lowest) ratio of transformation.

Sometimes, the installationof a booster transformer in those farthest sections of the

 primary

circuit will accomplish the purpose. In any event, this

feature requires

investigation and the taking of necessary measures

 preferably before the

need for such voltage reduction to shed load is placed in

effect.Where the need for voltage reduction stems only from

some deficiency

in the distribution system, that deficiency should be

identified

and removed as quickly as possible; such a need might

occur in the

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case of overloads in an outgoing underground cable

supplying a feeder 

where the cable carries too great a load under normal

conditions, or under contingency conditions where it may be called

upon to carry the

load of an additional circuit or circuits, or parts of them.

 7-What are the economic choice of conductor

size in power system utilization & distribution?

8-Why ACSR preferred as conductor material

in distribution networks? Aluminum Conductor, Steel-Reinforced (ACSR)

 From the viewpoint of mechanical strength, plain

aluminum conductorscannot be hardened and, hence, cannot compare with

mediumand 

hard-drawn copper conductors. It is sometimes alloyed,

however,

with other materials to increase its strength slightly, but 

more often, its

deficiency in strength is overcome by having steel reinforce the aluminum.

This is accomplished by having strands of aluminum

wire wrapped 

around a central core of one or more strands of high-

 strength steel wire.

The breaking strength of this type of conductor, 2 or 

more times that of 

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 plain aluminum, is considerably greater than even that 

of a hard-drawn

copper conductor of the same conductivity.

9-Discus the desirable properties of insulators in

over head distribution system?

10-how can we make a line drop compensation

in network of distribution system?

 Line-drop CompensatorsWhere it is desired to regulate or maintain the voltageband at some

distance from the source of the distribution feeder (e.g.,

at the first consumer 

or at some other point farther out on the feeder), a line-

drop compensator 

is used with the contact-making voltmeter. The line-dropcompensator 

is an electrical miniature of the line to the point where

the regulation

is desired. See Figure 4-4. Resistance and reactancevalues of the line are

calculated and a resistance and reactance proportional 

to these values are set on the compensator; the linecurrent, through a current transformer, flows through

the compensator, producing a voltage drop proportional 

to that current.

This drop is subtracted from the line voltage

at the regulator terminals, thus applying at the contact-

making voltmeter a voltage (varying with the load)

representing the voltage at the point of compensation onthe feeder. Refer to

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 Figure 4-32.

The point of compensation should be selected so that the

consumer 

 farthest from the regulator will have at least the lowest  permissible voltage

under the heaviest load while the consumer nearest the

regulator 

will have the highest permissible voltage under light-load conditions.

 

11- What are the advantages & disadvantages of 

AC & DC distribution systems ?

EXAMPLE 4-2

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The diversified maximum demand for 20consumers at 2.25 kW demand

each and a load factor of 0.67 is 30 kW.

Assume the loads are at or near unity

power factor.

The load can be served from one 25-kVAtransformer, if the period of overload

is not excessive; the next larger standard-size transformer is 50 kVA. From

manufacturer’s specifications (typical), theno-load loss for the 25-kVA transformer

is 0.5 percent of the full load; for 50 kVA, it is0.4 percent. Resistance as a

percentage of full load for 25 kVA is 1.4percent; for 50 kVA, it is 1.25 percent.

0.5

No load loss (25 kVA) = ———     25,000 = 125W or 0.125 kW

100

0.125 kW     2937 equiv h = 367 kWh

At 5 cents per kilowatt-hour that equals$18.35 a year.

0.4

No load loss (50 kVA) = ——     50,000 = 200 Wor 0.200 kW

100

0.200 kW     2937 equiv h = 587.4 kWh

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At 5 cents a kilowatt-hour that comes to$29.37 a year.

Annual carrying charges: Assume a cost of $8

per kVA for 25 kVA and $6 per

kVA for 50 kVA (typical) plus a $100installation cost. For 25 kVA,

25     $8 + $100 = $300

The carrying charge of 20 percent comes to$60.00. For 50 kVA,

50     $6 + $100 = $400

The carrying charge of 20 percent amountsto $80.00. The total annual carrying

charges are:

25 kVA: $18.35 + $60.00 = $ 78.35

50 kVA: $29.37 + $80.00 = $109.37

Load loss: Resistance as a percentage of fullload is the same as the loss at

full load. For 25 kVA:

1.4

——     25,000 = 350 W or 0.350 kW

100

Adjust for a 30-kW load:

30

25

2 × 350 = 504 W or 0.504 kW

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probably should be preferred. As an exercise,different secondary-transformer

combinations might be investigated—say,

two secondary circuits with two 15-

kVA or two 25-kVA transformers, or threesecondary circuits with three 15-kVA

units.