quadratic function. brainstorm stylin’ both are quadratics (parabolas) not one-to-one (not...
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Quadratic Function
Brainstorm Stylin’ Both are quadratics (parabolas) Not one-to-one (not invertible) Parent function is x^2 Both are positive Both are continuous One goes through the origin Polynomial Both go through at least two quadrants Passes vertical line test and fails the
horizontal line test
Advanced Algebra 2 – Unit 210/20/2011 AGENDADO NOW: Quadratic or
NO?Look to the right of the
boardAgenda: Portfolio Recap
More Quadratic VOCABThink Pair Share
FOILING Quadratics
We will: Analyze the value and
consequence of “a” coefficients
Determine the role does “b” play
Determine the vertex – MAX/MIN
Calculate SOLUTIONS, roots, intercepts & zeros
Quadratic Function(y = ax2 + bx + c) a, b, and c are called
the coefficients. The graph will form
a parabola. Each graph will have
either a maximum or minimum point.
There is a line of symmetry which will divide the graph into two halves.
y = x2
a = 1, b = 0, c = 0
Minimum point (0,0)
Axis of symmetry x=0
y=x2
What happen if we change the value of a and c ?
y=3x2
y=-3x2
y=4x2+3
y=-4x2-2
Recap(y = ax2+bx+c)
When a is positive,
When a is negative,
When c is positive When c is negative
the graph concaves UPWARD. happy
the graph concaves downward. sad.
the graph moves up c units.
the graph moves down c units.
Quadratic Function(y = ax2 + bx + c) a, b, and c are called
the coefficients. The graph will form
a parabola. Each graph will have
either a maximum or minimum point.
There is a line of symmetry which will divide the graph into two halves.
Let’s investigate MAX and MIN
y=x2-4 y=x2+2x-15
y=-x2+5 y=-x2-1
What do you notice about max/min and line of symmetry? Think pair share (2min)
y=x2-4 y=x2+2x-15
y=-x2+5 y=-x2-1
VERTEX: –b/2a, f(-b/2a)
y=x2-4
y=x2+2x-15
y=-x2+2x -15
y=-2x2-x +4
Work with a friend – be ready to present!
? Explore
http://www.explorelearning.com/index.cfm?method=cResource.dspView&ResourceID=154
Describe the changes in your own words.
Solving Quadratic Functions(ax2 + bx + c = 0)
Since y = ax2 + bx +c , by setting y=0 we set up a quadratic equation.
To find the solutions means we need to find the x-intercept(s).
X-intercepts are also called ROOTS To make your life more complicated,
they are also called ZEROS
What are x intercepts also called?
Solving Quadratic Functions(ax2 + bx + c = 0)
We know what a parabola looks like, so how many solutions or roots or zeros or x-intercepts can there be??
Think Pair and share out (3 minutes)
Find the Solutions
y=x2-4 y=x2+2x-15
y=-x2+5 y=-x2-1
Find the solutions
y=x2+2x+1
y=-x2+4x-1
Observations
Sometimes there are two solutions. Sometimes there is only one solution.
Sometimes there is no solution at all…well…there are imaginary solutions…you are going to love them
To solve quadratic equations(graphing method) X2 - 2x = 0 We could put y = x2-x into a
calculator or sketch it to find x intercepts.
This one has two solutions, x=0 and x=2.
y=x2-2x
Another Method to find ROOTS?
By factoring…let’s get it started
Other Methods
By factoring…let’s get it started
By using the quadratic formula
2 4
2
b b acx
a
The End