reactions in aqueous solution chapter 4 – part 3

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Reactions in Aqueous Solution Chapter 4 – Part 3

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Page 1: Reactions in Aqueous Solution Chapter 4 – Part 3

Reactions in Aqueous Solution

Chapter 4 – Part 3

Page 2: Reactions in Aqueous Solution Chapter 4 – Part 3

Acid Base Reactions

Proton Transfer ReactionsAKA - Neutralization

Page 3: Reactions in Aqueous Solution Chapter 4 – Part 3

Acids: Substances that

increase the concentration of H+ when dissolved in water (Arrhenius).

Proton donors (Brønsted–Lowry).

Page 4: Reactions in Aqueous Solution Chapter 4 – Part 3

AcidsThere are only seven strong acids:

Page 5: Reactions in Aqueous Solution Chapter 4 – Part 3

Monoprotic acids

HCl H+ + Cl-

HNO3 H+ + NO3-

CH3COOH H+ + CH3COO-

Strong electrolyte, strong acid

Strong electrolyte, strong acid

Weak electrolyte, weak acid

4.3

Page 6: Reactions in Aqueous Solution Chapter 4 – Part 3

Diprotic acidsH2SO4 H+ + HSO4

-

HSO4- H+ + SO4

2-

Strong electrolyte, strong acid

Weak electrolyte, weak acid

Triprotic acidsH3PO4 H+ + H2PO4

-

H2PO4- H+ + HPO4

2-

HPO42- H+ + PO4

3-

Weak electrolyte, weak acid

Weak electrolyte, weak acid

Weak electrolyte, weak acid

4.3

Page 7: Reactions in Aqueous Solution Chapter 4 – Part 3

Bases: Substances that

increase the concentration of OH− when dissolved in water (Arrhenius).

Proton acceptors (Brønsted–Lowry).

Page 8: Reactions in Aqueous Solution Chapter 4 – Part 3

Bases

The strong bases are the soluble salts of hydroxide ion:

Page 9: Reactions in Aqueous Solution Chapter 4 – Part 3

Neutralization ReactionsGenerally, when solutions of an acid and a base are combined, the products are a salt and water.

HCl (aq) + NaOH (aq) NaCl (aq) + H2O (l)

Salts are less reactive than acids and bases.

Why do they do that?

Page 10: Reactions in Aqueous Solution Chapter 4 – Part 3

Neutralization ReactionsWhen a strong acid reacts with a

strong base, the net ionic equation is…

HCl (aq) + NaOH (aq) NaCl (aq) + H2O (l)

Page 11: Reactions in Aqueous Solution Chapter 4 – Part 3

Gas-Forming Reactions Sometimes the expected product predicted

by just switching the ion partners decomposes to give a gaseous product (CO2 or SO2).

CaCO3 (s) + HCl(aq) CaCl2(aq) + CO2(g) + H2O (l)

NaHCO3(aq) + HBr(aq) NaBr(aq) + CO2(g) + H2O(l)

SrSO3(s) + 2 HI(aq) SrI2(aq) + SO2(g) + H2O(l)

Why do they do that?

Page 12: Reactions in Aqueous Solution Chapter 4 – Part 3

Gas-Forming Reactions This reaction gives the predicted

product, but you had better carry it out in the hood, or you will be very unpopular!

Just as in the previous examples, a gas is formed as a product of this reaction:

Na2S (aq) + H2SO4 (aq) Na2SO4 (aq) + H2S (g)

Page 13: Reactions in Aqueous Solution Chapter 4 – Part 3

Solution Stoichiometry

Count with Volume!

Page 14: Reactions in Aqueous Solution Chapter 4 – Part 3

Molarity Two solutions can contain the

same compounds but be quite different because the proportions of those compounds are different.

Molarity is one way to measure the concentration of a solution.

moles of solute

volume of solution in litersMolarity (M) =

Page 15: Reactions in Aqueous Solution Chapter 4 – Part 3

4.5

Page 16: Reactions in Aqueous Solution Chapter 4 – Part 3

Making Solutions

M = molarity =moles of solute

liters of solution

What mass of KI is required to make 500. mL ofa 2.80 M KI solution?

4.5

Page 17: Reactions in Aqueous Solution Chapter 4 – Part 3

Dilution is the procedure for preparing a less concentrated solution from a more concentrated solution.

Dilution

Add Solvent

Moles of solutebefore dilution (i)

Moles of soluteafter dilution (f)=

MiVi MfVf=4.5

Page 18: Reactions in Aqueous Solution Chapter 4 – Part 3

How would you prepare 60.0 mL of 0.200 MHNO3 from a stock solution of 4.00 M HNO3?

4.5

Page 19: Reactions in Aqueous Solution Chapter 4 – Part 3

Using Molarities inStoichiometric Calculations

Page 20: Reactions in Aqueous Solution Chapter 4 – Part 3

Titration

The analytical technique in which one can calculate the concentration of a solute in a solution.

Page 21: Reactions in Aqueous Solution Chapter 4 – Part 3

4.7

What volume of a 1.420 M NaOH solution isRequired to titrate 25.00 mL of a 4.50 M H2SO4 solution?