related rates finding the rates of change of two or more related variables that are changing with...
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Related Rates
Finding the rates of change
of two or more related variables that are changing with respect to time.
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For example, when water is drained out of a conical tank, the volume V, the radius r, and the height h, of the water level are all functions of time t. These variables are related by the following equation:
hrV 2
3
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Differentiating Implicitly with respect to t gives the following related rates equation.
hrV 2
3
dt
drrh
dt
dhr
dt
dV2
32
The rate of change of V is related to the rates of change of both r and h.
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Solving a Related Rate Problem•Step 1:
Identify the changing quantities, possibly with the aid of a sketch.
•Step 2:
Write down an equation that relates the changing quantities
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• Step 3: Differentiate both sides of the
equation with respect to t.
•Step 4: Go through the whole problem and restate it in terms of the quantities and their rates of change. Rephrase all
statements regarding changing quantities using the phrase "the rate of change of . . . ."
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•Last Step:
Substitute the given values in the derived equation you obtained above, and solve for the required quantity.
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LADDER PROBLEMJ oey is perched precariously onthe top of a 10- foot ladder leaning against the back wall of an apartment building (spying on an enemy of his) when it starts to slide down the wall at a rate of 4 ft per minute. J oey's accomplice, Lou, is standing on the ground 6 ft. away from the wall. How fast is the base of the ladder moving when it hits Lou?
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The changing quantities are
and x y
An equation relating these quantities is:
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Differentiating both sides with respect to t gives
022 dt
dyy
dt
dxx
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Restating the problem in terms of
rates of change gives the following:
dt
dxFind
Given that 4dt
dy
At the instant when x = 6
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Substitute the given values into the equation
Use the PythagoreanTheorem to determine that when x = 6 andthe ladder = 10, theny = 8
022 dt
dyy
dt
dxx
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min/
)()(
ftdt
dxdt
dxdt
dx
3
16
12
64
6412
048262
022 dt
dyy
dt
dxx
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Conclusion
The base of the ladder is moving
at a rate of:
min/ft3
16
At the instant when it hits Lou!