Report copyright - j3. - 國立臺灣大學cheng/teaching/calculus/ch06.pdf · IBC I = y tan 30° =.J16 - x2 /.j3. Thus the cross-sectional area is A(x) =~.J16 - x2 • ~.J16 - x2 f 4 f4 16 - x2 V
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