resultant of non concurrent force system

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RESULTANT OF NON CONCURRENT FORCE SYSTEM Problem 260 The effect of a certain non- concurrent force system is defined by the following data: ΣF x = +90 kN, ΣF y = -60 kN, and ΣM O = 360 kN·m counterclockwise. Determine the p oint at which the resultant intersects the x-axis. Solution 260 The x-intercept is at 6 m to the left of the origin. answer  Problem 261 In a certain non- concurrent force system it is found that ΣF x = -80 lb, ΣF y  = +160 lb, and ΣM O = 480 lb·ft in a counterclockwise sense. Determine the point at which the resultant intersects the y- axis. Solution 261 

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7/27/2019 Resultant of Non Concurrent Force System

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RESULTANT OF NON CONCURRENT FORCE SYSTEM

Problem 260 

The effect of a certain non-concurrent force system is defined by the following data: ΣFx = +90kN, ΣFy = -60 kN, and ΣMO = 360 kN·m counterclockwise. Determine the point at which the

resultant intersects the x-axis.

Solution 260 

The x-intercept is at 6 m to the left of the origin. answer  

Problem 261 In a certain non-concurrent force system it is found that ΣFx = -80 lb, ΣFy = +160 lb, and ΣMO =

480 lb·ft in a counterclockwise sense. Determine the point at which the resultant intersects the y-

axis.

Solution 261 

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The y-intercept of the resultant is 6 ft above the origin. answer  

Problem 262 Determine completely the resultant of the forces acting on the step pulley shown in Fig. P-262. 

Solution 262 

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Thus, R = 1254.89 lb downward to the right at θx = 44.21° and passes through the axle.

Problem 263 Determine the resultant of the force system shown in Fig. P-263 and its x and y intercepts.

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Solution 263

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Thus, R = 161.314 lb upward to the right at θx = 21.69° and intercepts at (1.668, 0) and (0, -

0.671).

Problem 264 Completely determine the resultant with respect to point O of the force system shown in Fig. P-

264.

Solution 264 

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Thus, R = 544.68 N upward to the right at θx = 28.25°. The intercepts of R are (-4.57, 0) and (0,2.46).

Problem 265 Compute the resultant of the three forces shown in Fig. P-265. Locate its intersection with X and

Y axes.

Solution 265 

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Thus, R = 957.97 lb downward to the right at θx = 32.19°. The x-intercept is at 2.90 ft to the right

of O and the y-intercept is 1.83 ft above point O.

Problem 266 Determine the resultant of the three forces acting on the dam shown in Fig. P-266 and locate its

intersection with the base AB. For good design, this intersection should occur within the middle

third of the base. Does it?

Solution 266 

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Righting moment

Overturning moment

Moment at the toe (downstream side - point B)

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Location of R y as measured from the toe

(within the middle third)

Thus, R = 27 424.02 lb downward to the right at θx = 79.91° and passes through the base at 8.44

ft to the left of B which is within the middle third.

Problem 267 The Howe roof truss shown in Fig. P-267 carries the given loads. The wind loads are

 perpendicular to the inclined members. Determine the magnitude of the resultant, its inclinationwith the horizontal, and where it intersects AB.

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Solution 267 

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Thus, R = 10 778.16 N downward to the right at θx = 68.2° passing 4.46 m to the right of A.

Problem 268 The resultant of four forces, of which three are shown in Fig.P-268, is a couple of 480 lb·ft clockwise in sense. If each

square is 1 ft on a side, determine the fourth force completely.

Solution 268 

Let F4 = the fourth force and for couple resultant, R is zero.

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Thus,

Assuming F4 is above point O

d is positive, thus, the assumption is correct that F4 is above point O.

Therefore, the fourth force is 200 lb acting horizontally to the left at 5.8 ft above point O.

answer  

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Problem 269 Repeat Prob. 268 if the resultant is 390 lb directed down to the right at a slope of 5 to 12 passing

through point A. Also determine the x and y intercepts of the missing force F.

Solution 269 Let F4 = the fourth force

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Resolve F4 into components at the x-axis

Resolve F4 into components at the y-axis

Thus, F4 = 219.32 lb downward to the right at θx = 43.15° with x-intercept ix = 3.27 to the right

of O, and y-intercept iy = 3.06 ft above point O.

Problem 270 The three forces shown in Fig. P-270 are required to cause a horizontal resultant acting through

 point A. If F = 316 lb, determine the values of P and T. Hint: Apply MR  = ΣMB to determine R,then MR  = ΣMC to find P, and finally MR  = ΣMD or R y = ΣY to compute T. 

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Solution 270 For horizontal resultant, R y = 0 and R x = R 

answer  

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  answer  

Problem 271 The three forces in Fig. P-270 create a vertical resultant acting through point A. If T is known to

 be 361 lb, compute the values of F and P.

Solution 271 For vertical resultant, R x = 0 and R y = R 

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answer  

answer