rhic physics and ads/cft
DESCRIPTION
RHIC physics and AdS/CFT. Amos Yarom, Munich. together with: S. Gubser and S. Pufu. TexPoint fonts used in EMF. Read the TexPoint manual before you delete this box.: A A A A A A A A A A A. g YM. 1. ~ 170 MeV. Energy. Overview. The quark gluon plasma. ?. AdS/CFT. J. Maldacena. - PowerPoint PPT PresentationTRANSCRIPT
RHIC physics and AdS/CFT
Amos Yarom, Munich
together with: S. Gubser and S. Pufu
Overview
• The quark gluon plasma
Energy
gYM
1
~170 MeV
?
Overview
• The quark gluon plasma
• N=4 SYM plasma via AdS/CFT
AdS/CFT
J. Maldacena
Overview
• The quark gluon plasma
• N=4 SYM plasma via AdS/CFT
?
Overview
• The quark gluon plasma
• N=4 SYM plasma via AdS/CFT
• Energy loss of a moving quark
Overview
• The quark gluon plasma
• N=4 SYM plasma via AdS/CFT
• Energy loss of a moving quark
Overview
• The quark gluon plasma
• N=4 SYM plasma via AdS/CFT
• Energy loss of a moving quark
• Summary
The quark gluon plasma at RHICRELATIVISTIC
HEAVY
ION
COLLIDER
Jet quenching
197 ×
pT
RAA =Hadron yield in Au-Au
(rescaled) Hadron yield in p-pRAA (pT ) =
Hadron yield in Au-Au(pT )(rescaled) Hadron yield in p-p(pT )
Jet quenching(Phenix, 2005)
Friction coefficient for QCD plasma
_p= ¡ ´p+F
0:3f m=c< ´ < 8f m=c
N=4 SYM plasma via AdS/CFT
AdS/CFT
J. Maldacena
AdS5 CFT
Empty AdS5Vacuum
L4/’2 gYM2 N
L3/2 G5 N2
J. Maldacena hep-th/9711200
T>0
N=4 SYM plasma via AdS/CFT
AdS5 CFT
AdS5 BH Thermal state
L4/’2 gYM2 N
L3/2 G5N2
E. Witten hep-th/9802150
Horizon radius Temperature
Empty AdS5Vacuum
J. Maldacena hep-th/9711200
AdS Black holes
ds2 = L2=z2¡¡ g(z)dt2+dx2i +dz
2=g(z)¢
g(z) = 1¡µzz0
¶4
z0
z
0x1xi, t
AdS5 CFT
AdS5 BH Thermal state
L4/’2 gYM2 N
L3/2 G5N2
E. Witten hep-th/9802150
Horizon radius Temperature
z01/ T
AdS/CFT
J. Maldacena
Friction coefficient
AdS5 CFT
J. Maldacena hep-th/9803002
Massive parton
Endpoints of an open
string
z0
z
0
S =12¼®0
Z(G@X@X )1=2d2¾
±S±X
= 0X jb= (t;0;0;0;0)X jh =no outgoing
?
(Gubser 2006, Holzhey, Karch, Kovtun, Kozcaz, Yaffe, 2006, Teaney Cassalderrey-Solana, 2006)
Friction coefficient
AdS5 CFT
J. Maldacena hep-th/9803002
Massive parton
Endpoints of an open
string
z0
z
0
S =12¼®0
Z(G@X@X )1=2d2¾
±S±X
= 0X jb= (t;vt;0;0;0)X jh =no outgoing
?
X = (t;vt+»(z);0;0;z)
»(z) =vz04
µln1¡ z=z01+z=z0
+2arctanzz0
¶
(Gubser 2006, Holzhey, Karch, Kovtun, Kozcaz, Yaffe, 2006, Teaney Cassalderrey-Solana, 2006)
Friction coefficient
z0
z
0
X = (t;vt+»(z);0;0;z)
»(z) =vz04
µln1¡ z=z01+z=z0
+2arctanzz0
¶
F =¼pg2Y M NT
2p2m
F F
_p= ¡¼pg2Y M NT
2
2mp
´b » 0:5f m=c
´c » 1:2f m=c
(Gubser 2006, Holzhey, Karch, Kovtun, Kozcaz, Yaffe, 2006, Teaney Cassalderrey-Solana, 2006)
Friction coefficient
´b » 0:5f m=c
´c » 1:2f m=c
AdS/CFT
J. Maldacena
0:3f m=c< ´ < 8f m=c
(Gubser 2006, Holzhey, Karch, Kovtun, Kozcaz, Yaffe, 2006, Teaney Cassalderrey-Solana, 2006)
Measurables which have been compared
Friction coefficient
Energy density Shear viscosity Jet quenching parameter
0:3f m=c< ´ < 8f m=c
² » 0:8²SB
1< 4¼́ v=s < 2
5GeV2=f m< q? <15GeV2=f m
(Policastro, Son, Starinets, 2001)
(Liu, Rajagopal, Wiedemann, 2006)
(Gubser 2006, Holzhey, Karch, Kovtun, Kozcaz, Yaffe, 2006, Teaney Cassalderrey-Solana, 2006)
(Gubser, Klebanov, Peet, 1996)
Measuring jets
Measuring jets
Measuring di-jets
Measuring di-jets(STAR, 0701069)
Measuring di-jets(STAR, 0701069)
=
Measuring di-jets(STAR, 0701069)
»
Creation of sound waves(Casalderrey-Solana, Shuryak, Teaney, 2004, 2006)
Creation of sound waves(Casalderrey-Solana, Shuryak, Teaney, 2004, 2006)
Mach cones and di-jets(Casalderrey-Solana, Shuryak, Teaney, 2004, 2006)
»
Mach cones in N=4 SYM
AdS5 CFT
» hTrF 2i©jb
hTmn iGmn jb
z0
z
0
The energy momentum tensor
AdS5 CFT
» hTrF 2i©jbhTmn iGmn jb
hTmn i / Qmn
Gmn =G(0)mn +hmn
AdS black hole Metric fluctuationshmn = :::+Qmnz4+:::
S = SN G +SE H
SN G =12¼®0
Z(G@X@X )1=2d2¾
SE H =1
16¼G5
µR +
12L2
¶G1=2d5x
±S±X
= 0±S±G= 0
z0
z
0
Gmnz,k)
The energy momentum tensor
z0
z
0
S = SN G +SE H
SN G =12¼®0
Z(G@X@X )1=2d2¾
±S±X
= 0±S±G= 0D¹ º½¾h½¾= J ¹ º
Gmn =G(0)mn +hmn
SE H =1
16¼G5
µR +
12L2
¶G1=2d5x
X = (t;vt+»(z);0;0;z)
»(z) =vz04
µln1¡ z=z01+z=z0
+2arctanzz0
¶
The energy momentum tensor
D¹ º½¾h½¾= J ¹ º
hmn =
0
BBBB@
h00 h01 h02 h03 h04h10 h11 h12 h13 h14h20 h21 h22 h23 h24h30 h31 h32 h33 h34h40 h41 h42 h43 h44
1
CCCCA
hmn =
0
BBBB@
h00 h01 h02 h03 0h10 h11 h12 h13 0h20 h21 h22 h23 0h30 h31 h32 h33 00 0 0 0 0
1
CCCCA
hmn =
0
BBBB@
h00 h01 h02 0 0h10 h11 h12 0 0h20 h21 h22 0 00 0 0 h33 00 0 0 0 0
1
CCCCA
Gauge choiceCylindrical symmetry
µz3@zz¡ 3g(z)@z ¡
µk2 ¡
v2k21g(z)
¶¶©T = ze¡ ik1»(z)
©T =12v2
Ã
¡ h11+2µk1k?
¶2h22+
µkk?
¶2h33
!Tensor modesVector modes
µ©V1©V2
¶=
0
@12v
³h01 ¡ k1
k?h02´
12v2
³¡ h11+
³k1k?¡ k?
k1
´h12+h22
´
1
A
(x1;t) ! x1 ¡ vtZh½¾eikx
d3k(2¼)3
The energy momentum tensor
µz3@zz¡ 3g(z)@z ¡
µk2 ¡
v2k21g
¶¶©T = ze¡ ik1»(z)
¡@2z +K V@z +VV
¢µ©V1©V2
¶= ~SV
zge¡ ik1»
©T =12v2
Ã
¡ h11+2µk1k?
¶2h22+
µkk?
¶2h33
!
VV =k2
g
á g gv2
¡ k1k
¢2
¡ 1 v2¡ k1k
¢2
!
K V =
á 3z 00 ¡ 3z +
g0
g
!~SV =
µ11
¶
Tensor modes
Vector modesµ©V1©V2
¶=
0
@12v
³h01 ¡ k1
k?h02´
12v2
³¡ h11+
³k1k?¡ k?k¡
´h12+h22
´
1
A
+ first order constraint
The energy momentum tensor
µz3@zz¡ 3g(z)@z ¡
µk2 ¡
v2k2¡g
¶¶©T = ze¡ ik¡ »(z)
¡@2z +K V@z +VV
¢µ©V1©V2
¶= ~SV
zge¡ ik¡ »¡
@2z +K S@z +VS¢
0
BB@
©S1©S2©S3©S4
1
CCA =
~SSzge¡ ik¡ »
Tensor modes
Vector modes
+ first order constraint
Scalar modes
+ 3 first order constraints
D¹ º½¾h½¾= J ¹ º
Energy density for v=3/4
Over energy
Under energy
v=0.75 v=0.58
v=0.25
Small momentum approximations
E = ¡3iK 1v(1+v2)
2¼(K 2? +K21(1¡ 3v2))
+O(K 0)
D¹ º½¾h½¾= J ¹ º
h½¾=X
n
K nh(n)½¾ Zh½¾eiK X
d3K(2¼)3
(x1;t) ! x1 ¡ vt
1-3v2 > 0 (subsonic)
Small momentum approximations
E = ¡3iK 1v(1+v2)
2¼(K 2? +K21(1¡ 3v2))
+O(K 0)
1-3v2 > 0 (subsonic)
Re(K1)
Im(K1)
§iK ?p1¡ 3v2
v decreasesv increases
ZEeiK 1X 1 dK 1
2¼
X1 > 0
X1 < 0
Small momentum approximations
E = ¡3iK 1v(1+v2)
2¼(K 2? +K21(1¡ 3v2))
+O(K 0)
1-3v2 < 0 (supersonic)
Re(K1)
Im(K1)
ZEeiK 1X 1 dK 1
2¼
1-3v2 = 0
v increases
??
X1 > 0
X1 < 0X1
Small momentum approximations
E = ¡3iK 1v(1+v2)
2¼(K 2? +K21(1¡ 3v2))
+O(K 0)
1-3v2 < 0 (supersonic)
E(X ) =
(3v(1+v2 )4¼2
X 1(X 2
1+(1¡ 3v2)X 2
? )3=2 inside theMach cone.
0 outside theMach cone.
1-3v2 > 0 (subsonic)
E(X ) =3v(1+v2)8¼2
X 1(X 21 +(1¡ 3v2)X
2? )3=2
Small momentum approximations
E =
¡3K 21v
2(K 2? (2+v2) +2K 21(1+v
2)2¼(K 2? +K
21(1¡ 3v2))2
¡3iK 1v(1+v2)
2¼(K 2? +K21(1¡ 3v2))
+O(K 1)
E =¡3iK 1v(1+v2) +O(K 2)
2¼(K 2? +K21(1¡ 3v2) ¡ ivK 2K 1)
+O(K 1)
Small momentum approximations
E =¡3iK 1v(1+v2) +O(K 2)
2¼(K 2? +K21(1¡ 3v2) ¡ ivK 2K 1)
+O(K 1)
Re(K1)
Im(K1)
¡@2t +@
2x(c
2s +¡ s@t)
¢E = sources
cs2=1/3
s=1/3
Multi-scale analysis
Large distances – linear hydrodynamic
picture valid
Intermediate distances – nonlinear
hydrodynamics
Short momenta – Strong dissipative
effects
Energy density for v=3/4
0
v=0.75 v=0.58
v=0.25
Large momentum approximations
E =v2(1¡ v2)K 21 ¡ (2+v
2)(K 21(1¡ v2) +K 2? )
24pK 21(1¡ v2) +K
2?
+i¼vK 12v2(1¡ v2)K 21 +(5¡ 11v
2)(K 21(1¡ v2) +K 2? )
18(K 21(1¡ v2) +K2? )2
+O(K ¡ 3)
D¹ º½¾h½¾= T ¹ º
h½¾=X
n
K ¡ nh(n)½¾ Zh½¾eiK X
d3K(2¼)3
(x1;t) ! x1 ¡ vt
+O(X 0)
E(X ) =
¡ vX 1(5¡ 11v2)X 21 +(1¡ v
2)(5¡ 8v2)X 2?
72(1¡ v2)5=2³X 21
1¡ v2 +X2?
´5=2
X 21 +(1+v2)X 2?
12¼2p1¡ v2
³X 21
1¡ v2 +X2?
´3
Large momentum approximations
E =v2(1¡ v2)K 21 ¡ (2+v
2)(K 21(1¡ v2) +K 2? )
24pK 21(1¡ v2) +K
2?
+i¼vK 12v2(1¡ v2)K 21 +(5¡ 11v
2)(K 21(1¡ v2) +K 2? )
18(K 21(1¡ v2) +K2? )2
+O(K ¡ 3)
+O(X 0)
E(X ) =
¡ vX 1(5¡ 11v2)X 21 +(1¡ v
2)(5¡ 8v2)X 2?
72(1¡ v2)5=2³X 21
1¡ v2 +X2?
´5=2
X 21 +(1+v2)X 2?
12¼2p1¡ v2
³X 21
1¡ v2 +X2?
´3
Large momentum approximations
E(X ) = ¡ vX 1(5¡ 11v2)X 21 +(1¡ v
2)(5¡ 8v2)X 2?
72(1¡ v2)5=2³X 21
1¡ v2 +X2?
´5=2
Large momentum approximations
E(X ) = ¡ vX 1(5¡ 11v2)X 21 +(1¡ v
2)(5¡ 8v2)X 2?
72(1¡ v2)5=2³X 21
1¡ v2 +X2?
´5=2
Large momentum approximationsc2s =
515
Wakes
Mach cones, wakes and di-jets(Casalderrey-Solana, Shuryak, Teaney, 2004, 2006)
Mach cones, wakes and di-jets(Casalderrey-Solana, Shuryak, Teaney, 2004, 2006)
(STAR, 0701069)
The Poynting vector
z0
z
0
D¹ º½¾h½¾= J ¹ º
The Poynting vector
V=0.25
S1 S?
V=0.58
V=0.75
(Gubser, Pufu, AY, 2007)
Re(K1)
Im(K1)
Small momentum asymptotics
Sound Waves ?
S1 = ¡ iK 1(1+v2)
2¼(K 2 ¡ 3K 21v2)+ i
12¼K 1
+O(K 0)
K 21v2¼(K 2 ¡ 3K 21v2)2
+3K 41v
2(1+v2)2¼(K 2 ¡ 3K 21v2)2
+K 2
8¼K 21v¡
18¼v
S1 = ¡ iK 1(1+v2) +O(K 2)
2¼(K 2 ¡ 3K 21v2 ¡ iK 2K 1v)+
4v+O(K )2¼(K 2 ¡ 4iK 1v)
(Gubser, Pufu, AY, 2007)
X1
Small momentum asymptotics
S1 = ¡ iK 1(1+v2) +O(K 2)
2¼(K 2 ¡ 3K 21v2 ¡ iK 2K 1v)+
4v+O(K )2¼(K 2 ¡ 4iK 1v)
Z4v
2¼(K 2 ¡ 4iK 1v)eiK X
d3K(2¼)3
= ¡X 18¼2X 3
e¡ 2v(X 1+X )
X 1X 3e¡ 2v(X 1+X ) »
8<
:
X 1X 3 e¡ 4vX 1 jX j À 1; X 1 > 0
X 1X 3 e
¡ vX 2?X 1 jX j À 1; X 1 <0
(Gubser, Pufu, AY, 2007)
The poynting vector
V=0.25
S1 S?
V=0.58
V=0.75
(Gubser, Pufu, AY, 2007)
Energy analysis
S2 = ¡ iK 2(1+v2) +O(K 2)
2¼(K 2 ¡ 3K 21v2 ¡ iK 2K 1v)+
O(K )2¼(K 2 ¡ 4iK 1v)
S3 = ¡ iK 3(1+v2) +O(K 2)
2¼(K 2 ¡ 3K 21v2 ¡ iK 2K 1v)+
O(K )2¼(K 2 ¡ 4iK 1v)
S1 = ¡ iK 1(1+v2) +O(K 2)
2¼(K 2 ¡ 3K 21v2 ¡ iK 2K 1v)+
4v+O(K )2¼(K 2 ¡ 4iK 1v)
² = ¡3iK 1v(1+v2) +O(K 2)
2¼(K 2 ¡ 3K 21v2+iK 2K 1v)
_² +@iSi = ¡@E@t
Zd3x
limK ! 0
(¡ iK 1v² + iK iSi ) = F 0drag
= F 0drag±(~X ¡ ~vT)
(Friess, Gubser, Michalogiorgakis, Pufu, 2006 Gubser, Pufu, AY, 2007)
_² +@iSi = ¡@E@t
Z
d3x
limK ! 0
(¡ iK 1v² + iK iSi ) = F 0drag
= F 0drag±(~X ¡ ~vT)
Energy analysis(Friess, Gubser, Michalogiorgakis, Pufu, 2006 Gubser, Pufu, AY, 2007)
z0
z
0 F
?
Just been calculated
limK ! 0
(¡ iK 1v² + iK iSi ) = F 0draglimK ! 0
(¡ iK 1v² + iK iSi )¯¯wake+ lim
K ! 0(¡ iK 1v² + iK iSi )
¯¯sound
= F 0jwake+F 0jsound
F 0jwake : F 0jsound = ¡ 1 : 1+v2
Energy analysis(Friess, Gubser, Michalogiorgakis, Pufu, 2006, Gubser, Pufu, AY, 2007)
_² +@iSi = ¡@E@t
Z
d3x = F 0drag±(~X ¡ ~vT)
F 0jwake : F 0jsound = ¡ 1 : 1+v2
Energy analysis(Friess, Gubser, Michalogiorgakis, Pufu, 2006, Gubser, Pufu, AY, 2007)
=
Universality(Gubser, AY,2007)
SN G =12¼®0
Z(g@X@X )1=2q(ÁI )d2¾
SE H =1
16¼G5
Zg12Rd5x
SÁ =1
16¼G5
Zg12¡ I J @ÁI@ÁJ +V(ÁI )d5x
¢
z0
z
0
ds2 =®(z)2¡¡ h(z)dt2+d~x2+dz2=h(z)
¢
®! L=z
h ! 1
h ! 0
Universality(Gubser, AY, 2007)
SN G =12¼®0
Z(g@X@X )1=2q(ÁI )d2¾
SE H =1
16¼G5
Zg12Rd5x
SÁ =1
16¼G5
Zg12¡ I J @ÁI@ÁJ +V(ÁI )d5x
¢
z0
ds2 =®(z)2¡¡ h(z)dt2+d~x2+dz2=h(z)
¢
0
zD¹ º½¾h½¾+D¹ ºI Á
I = J ¹ ºF 0jwake : F 0jdrag = ¡ 1: v2
Summary
N=4 SYM plasma exhibits a Mach cone and a wake at large distances, where the hydrodynamic approximation is valid.
The laminar wake behind the quark is a universal feature of theories with string duals, and the ratio of energy carried by the wake to the drag force is 1:v2.
This wake is difficult to reconcile with current experimental data.