rsm-gp-s

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  • 8/18/2019 RSM-GP-S

    1/6

    General PhysicsSubjective Problems

    LEVEL-I

    2. 60 ×  12 = 720 days

    3. Density =3

    872.2g= 3.5g/cc

    25cm

    4. V =34 r 

    3

    π  ⇒  2dv 4

    rh

    dr 3

    = π

    2

    3

    dv 4 r dr 3dr  

    4V r r 

    3

    π= =

    π

    v 3 r 

    V r 

    ∆ ∆=

    % = 3 × 3×0.1

    ×100 = 5.7%5.3

    5. = 6 2 ! "

    r r − +

    = #$2−2 

    Dimensi&ns &' ! = #$8−2

    Dimensi&n &' " = #$4−2

    "hatnagar (()*/+# !cademy. ,)5- ama +ar-ttamnagar- e Dehi

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    LEVEL - II

    2. = $ #(

    ω

    = #$2

    −2

     $ = #$−2$ = #$2−1 

    = −1 

    ( = #$2ω = −1

    21 #$ = ω

    ∴ # = −3 

    # = −4.

    3. =V

    ( &g = &gV −&g(

    V (

    V (

    ∆ ∆ ∆= +

    = 8V

    (= Ω

    V ( 0.1 1 0.8 1 1.8 = =

    V ( 2.5 20 20 20 20

    ∆ ∆+ =

    ∆ =1.8

    8 = 0.7220

    ×

    = 8 ± 0.72 Ω 

    4. = 2π$

    g

    &g = &g2π  ( )1 1

    &g$ &g g2 2

    g 1 $ 1

    2 $ 2 g∆∆ ∆± = ± ±

    g 2 $

    g $

    ∆ ± ∆ ∆± = ±

    ( )g

    2× yg

     ∆= ÷

     

    FIITJEE Ltd., ICES House, Sarvapriya Vihar (Near Hauz Khas Bus Term.), New Delhi - 16, Ph : 26515949 , 26865182, 26569493, Fax : 26513942

    RSM79PH-P1-GP(S))2

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    5. = 9am:ac 

    9 =2 2 2

    1 3 2

    2 2

    m #$ $# $

    g #

    −− −

    −= =

    = #)a$3a)2a#:$c 

    a =1

    2− ; 3a c = 0

    −a : = 0

    a = : =1

    2−

    =3 / 2a

    9#

    = λ

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    !bjective Problems

    LEVEL - I

    1. y = > !?tress >?train !

    = =∆ ∆l

    l l l

    =

    2

    1 2

    2

    #$ $#$

    $ $

    − −   =

     

    2.   η => 1

     ! dv d@=

    2

    1 1

    2 1

    #$ $#$

    $ $

    − −

      =

    4.

    3@ 1 

    2 2 2 2

    1 2

    #$ d$ $

    #$

    −−− + −

    − −

    °     = = = ÷    

    hAs- @ =

    1

    2−

    6. ! = πr 2

    ⇒   ( ) ! r 

    2 2 1% 2% ! r 

    ∆ ∆= = =

    8. g =2

    24

    π

    l

    g 2

    g

    ∆ ∆ ∆  = + ÷  

    l

    l

    g 2 2 1= 4%g

    ∆ = ×

    B. ∝  l% 1

    % 2

    ∆ ∆=

      lQ

    l

    12=1%

    2

    ∆= ×

    12. ,&ACe = '&rce × CerCendicAar distance

    = #$

    −2

    × $ = #$2

    −2

    13. @ =2

    3

    a:

    c

    @ a 2: 3 c

    @ a : c

    ∆ ∆ ∆∴ = + +

    @1% 6% 6% =13%

    @

    ∆=

    FIITJEE Ltd., ICES House, Sarvapriya Vihar (Near Hauz Khas Bus Term.), New Delhi - 16, Ph : 26515949 , 26865182, 26569493, Fax : 26513942

    RSM79PH-P1-GP(S))"

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    15. !verage vaAe =7.15 7.2 5 6.7

    = 7.0*3

    17.   τ  i have dimensi&n &' time- dimensi&n &' η = #$−1−1

    ∴  1 1m #

    6 r  #$ $− −∴ =πη   ×  =

    20. =V

    (-

    ( V1% 2% = 3%

    ( V

    ∆ ∆ ∆= + =

    LEVEL - II

    4.

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    21 1

    + 11 1

    1At at

    s 12v A att t 2

    += = +   ( ) ( )

    17 6 10m / s

    2= + =

    LEVEL - III

    4. 6Geat Cr&dAced G is given :y

    2( tG

    *=

    ∴ G t *

    2G t *

    ∆ ∆ ∆ ∆ ∆= + + −

     I 

     I 

    G t *100 2 100 100 100 100

    G t *

    ∆ ∆ ∆ ∆ ∆  × = × + × + × − × ÷  

     I 

     I 

    >&r ma@imAm Cercentage err&r-G *

    100 2 100 100 100 100G *

    ∆ ∆ ∆ ∆ ∆× = × + × + × + ×

     I t 

     I t 

    = 2 × 2% 1% 1% 0% = 6%.

    5. 5

    eative density =a

    a

    H

    H H−&r    a

    W

    wρ =

    Hhere ρ is reative density- Ha eight in air and is &ss in eight.

    a

    a

    W   w

    W w

    ∆∆ρ ∆= −

    ρ>&r ma@imAm err&rI

    a

    a

    W   w

    W w

    ∆∆ρ ∆= +

    ρ>&r ma@imAm Cercentage err&rI

    a

    a

    H   100 100 100

    H

    ∆∆ρ ∆× = × + ×

    ρ

    9ivenI aW 0.1 gmf  ∆ =   and Ha = 10.0 gm' = 10.0 J 5.0 = 5.0 gm'

    a 0.1 0.1 0.2 gm'  ∆ = ∆ + ∆ = + =

    ∴  0.1 0.2

    100 100 100 1 4 5%10.0 5.0

    ∆ρ    × = × + × = + = ÷ ÷ρ    

    FIITJEE Ltd., ICES House, Sarvapriya Vihar (Near Hauz Khas Bus Term.), New Delhi - 16, Ph : 26515949 , 26865182, 26569493, Fax : 26513942

    RSM79PH-P1-GP(S))$