sc network
TRANSCRIPT
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SUPPLY CHAIN MANAGEMENT
Network Design in the Supply Chain (tambahan untuk memahami modul
supply chain network )
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Why Network Planning?
Find the right balance between inventory,transportation and manufacturing costs,Match supply and demand underuncertainty by positioning and managinginventory effectively,Utilize resources effectively by sourcingproducts from the most appropriatemanufacturing facility
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Network Design
Physical configuration and infrastructure ofthe supply chain.
A strategic decision with long-lastingeffects on the firm.Decisions relating to plant and warehouselocation as well as distribution andsourcing
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Key Strategic Decisions
Determining the appropriate number offacilities such as plants and warehouses. Determining the location of each facility. Determining the size of each facility.
Allocating space for products in eachfacility.
Determining sourcing requirements. Determining distribution strategies, i.e., theallocation of customers to warehouse
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Which market is served bywhich plant?Which supply sources areused by a plant?
x ij = Quantity shipped from
plant site i to customer jC ij = cost of producing and
shipping from plant site Ito customer j
D j = annual demand fromcustomer j
K i = capacity of plant i 0
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Demand Allocation Model
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Plant Location with MultipleSourcing
yi = 1 if plant is locatedat site i, 0 otherwisexij = Quantity shippedfrom plant site i tocustomer jf i = annual fixed costof keeping factory i open }1,0{;
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Plant Location with Single Sourcing
yi = 1 if plant is locatedat site i, 0 otherwisexij = 1 if market j is
supplied by factory i, 0otherwiseD j = annual demandfrom customer j
}1,0{
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5-9
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Unit Distribution Costs
Facilitywarehouse
p 1 p 2 c 1 c 2 c 3
w 1 0 4 3 4 5
w 2 5 2 2 1 2
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Heuristic #1:Choose the Cheapest Warehouse to Source
Demand
D = 50,000
D = 100,000
D = 50,000Cap = 60,000
$5 x 140,000
$2 x 60,000
$2 x 50,000
$1 x 100,000
$2 x 50,000
Total Costs = $1,120,000
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The problem we want to solve is:min 0x(p1,w1) + 5x(p1,w2) + 4x(p2,w1)+ 2x(p2,w2) + 3x(w1,c1) + 4x(w1,c2)+ 5x(w1,c3) + 2x(w2,c1) + x(w2,c2) + 2x(w2,c3)
subject to the following constraints:x(p2,w1) + x(p2,w2) 60000
x(p1,w1) + x(p2,w1) = x(w1,c1) + x(w1,c2) + x(w1,c3)x(p1,w2) + x(p2,w2) = x(w2,c1) + x(w2,c2) + x(w2,c3)
x(w1,c1) + x(w2,c1) = 50000x(w1,c2) + x(w2,c2) = 100000x(w1,c3) + x(w2,c3) = 50000
all flows greater than or equal to zero.
The Optimization Model
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Optimal SolutionFacility
warehouse p 1 p 2 c 1 c 2 c 3
w 1 140,000 0 50,000 40,000 50,000
w 2 0 60,000 0 60,000 0
Total cost for the optimal strategy is $740,000