section 11.5 partial fraction decomposition 2 2 write the partial fraction decomposition of 12 x xx...
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Section 11.5
Partial Fraction Decomposition
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2
7 1Write the partial fraction decomposition of 6
xx x
+
+ −( 3)( 2)x x+ −
2
7 16 3 2
x A Bx x x x
+= +
+ − + −
( )2
( 3)( 2) ( 3)( 2) ( 37 1 )(6
23 2
)x x x x x xx A Bx x x x
+ − + −+=
+
+ −+
+ − −
7 1 ( 2) ( 3)x A x B x+ = − + +
( 3)B x +
( ) ( )2 3A B x A B= + + − +
Equate coefficients of like powers of x to get: 71 2 3
A BA B
= +⎧⎨= − +⎩
4 3A B= =
2
7 1 4 36 3 2
xx x x x
+= +
+ − + −
( )( )
2
22Write the partial fraction decomposition of
1 2x
x x+
− +
( )( ) ( )
2
2 22
1 21 2 2x A B C
x xx x x+
= + +− +− + +
( )( )2Clear of fractions by multiplying all terms by 1 2x x− +
( ) ( )( ) ( )22 2 2 1 2 1x A x B x x C x+ = + + − + + −
2 2 22 4 4 2x Ax Ax A Bx Bx B Cx C+ = + + + + − + −
( ) ( ) ( )2 22 4 4 2x A B x A B C x A B C+ = + + + + + − −
10 42 4 2
A BA B CA B C
= += + += − −
1 2, , 23 3
A B C= = = −
( )2
1 223 3
1 2 2x x x−
= + +− + +
( )
2
23
4Write the partial fraction decomposition of 1
xx x
−
−
( ) ( )
2
2 22 33
411 1
x A B C D Ex x x xx x x
−= + + + +
−− −
( ) ( ) ( ) ( )2 2 22 2 3 34 1 1 1 1x Ax x Bx x C x Dx x Ex− = − + − + − + − +
( )2Let 0: 4 0 1x C= − = − 4C = − ( )32Let 1: 1 4 1x E= − = 3E = −
( ) ( ) ( ) ( )2 2 22 3 2 34 4 1 3 1 1 1x x x Ax x Bx x Dx x− + − + = − + − + −
( ) ( ) ( ) ( )( )23 8 ( 1) 1 1 1x x x x x Ax x B x Dx+ − = − − + − +
( ) ( ) 23 8 1 1x Ax x B x Dx+ = − + − + ( )Let 0 :8 0 1x B= = − 8B = −
( )2Let 1:3(1) 8 1x D= + = 11D =
( ) ( ) 23 8 1 8 1 11x Ax x x x+ = − − − +
( ) ( )( ) ( ) ( )2Let 2 :3 2 8 2 2 1 8 2 1 11 2x A= + = − − − + 11A = −
( ) ( )
2
2 22 33
4 11 8 4 11 311 1
xx x x xx x x
− − − − −= + + + +
−− −
( )( )2
1Write the partial fraction decomposition of 1 4x x+ +
( )( ) 22
11 41 4A Bx Cx xx x
+= +
+ ++ +
( ) ( )( )21 4 1A x Bx C x= + + + +
2 21 4Ax A Bx Bx Cx C= + + + + +
( ) ( ) ( )21 4A B x B C x A C= + + + + +
001 4
A BB CA C
= += += +
151515
A
B
C
=
= −
=
2
1 1 15 5 51 4
x
x x
− += +
+ +
( )
2
22
1Write the partial fraction decomposition of 4
x
x
+
+
( ) ( )
2
2 222 2
144 4
x Ax B Cx Dxx x
+ + += +
++ +
( )( )2 21 4x Ax B x Cx D+ = + + + +
2 3 21 4 4x Ax Bx Ax B Cx D+ = + + + + +
( ) ( )2 3 21 4 4x Ax Bx A C x B D+ = + + + + +
010 41 4
ABA CB D
=== += +
0103
ABCD
==== −
( )22 2
1 34 4x x
−= +
+ +