section 13.5 chain rule

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Section 13.5 Chain Rule Calculus III November 16, 2009 Berkley High School [email protected]

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Section 13.5 Chain Rule. Calculus III November 16, 2009 Berkley High School [email protected]. Remembering Single Variable. Total Differential. On To Multi-Variable. Even more complicated…. Implicit Differentiation. F. y. x. x. x. Implicit Differentiation. Assignment. - PowerPoint PPT Presentation

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Page 1: Section 13.5 Chain Rule

Section 13.5Chain Rule

Calculus IIINovember 16, 2009Berkley High [email protected]

Page 2: Section 13.5 Chain Rule

2

Remembering Single Variable

If

Then

h x f g x

h x f g x g x

If

and

Then

y f x x g t

dy dy dx

dt dx dt

Page 3: Section 13.5 Chain Rule

3

Total Differential

If

,

Then

z f x y

z zdz dx dy

x y

Page 4: Section 13.5 Chain Rule

4

On To Multi-Variable

If

, and and

Then

z f x y x g t y h t

dz z dx z dy

dt x dt y dt

z

x y

tt

z

x

z

y

dy

dt

dx

dt

Page 5: Section 13.5 Chain Rule

5

2 2

2

2 2

0 2 0 0

, where sin and .

Find when 0.

2 , cos , 2 ,

2 cos 2 2sin cos sin 2

at 0, 2 sin 0 cos 0 sin 0 2 2

t

t

t t t t

w x y y x t y e

dwt

dtdw w dx w dy

dt x dt y dt

w dx w dyxy t x y e

x dt y dt

dwxy t x y e t e t t e e

dtdw

t e e edt

w

x y

tt

w

x

w

y

dy

dt

dx

dt

Page 6: Section 13.5 Chain Rule

6

Even more complicated…

,

,

,

z f x y

x g s t

y h s t

z z x z y

s x s y s

z z x z y

t x t y t

Page 7: Section 13.5 Chain Rule

7

2 2

2 2 22 2

2 , where and .

Find

12 , 2 , 2 ,

1 1 4 2 62 2 2 2 2 2 2 2

sz xy x s t y

tz

sz z x z y

s x s y s

z x z yy s x

x s y s t

z s s s sy s x s s t t t

s t t t t t t

z

x y

t

z

x

z

y

x

t

x

s

s t

y

t

y

s

s

Page 8: Section 13.5 Chain Rule

8

2 2

2

2 22 2

3 3

2 2

2 , where and .

Find

2 , 2 , 2 ,

2 2 2 4 2

2 24 2 2

sz xy x s t y

tz

tz z x z y

t x t y t

z x z y sy t x

x t y t t

w s s sy t x t s t

t t t t

s ss s s

t t

z

x y

t

z

x

z

y

x

t

x

s

s t

y

t

y

s

s

Page 9: Section 13.5 Chain Rule

9

Implicit Differentiation

( , ), , 0

( , ) 0

0

F x y F x f x

d dF x y

dx dxF dx F dy

x dx y dx

F dy F

y dx x

x

y

FFdy x

Fdx Fy

F

x y

xx

F

x

F

y

dy

dx

dx

dx

Page 10: Section 13.5 Chain Rule

10

3 2 2

3 2 2

2

2 2

5 4 0

Let ( , ) 5 4

2

3 2 5

2 2

3 2 5 3 2 5

x

y

x

y

y y y x

F x y y y y x

F x

F y y

Fdy x x

dx F y y y y

Page 11: Section 13.5 Chain Rule

11

Implicit Differentiation

( , , ), , , , 0

, yx

z z

F x y z F x y f x y

FFz z

x F y F

Page 12: Section 13.5 Chain Rule

12

Assignment

13.5, 1-9 odd, 15-37 odd