section p.2
DESCRIPTION
Group C. Section P.2. How to Sketch the Graph of an Equation. Graph of Equation: The set of all solution points of an equation Rewrite the equation so that one of the variables is isolated on one side Make a table of several solution points Plot these points in the C artesian plane - PowerPoint PPT PresentationTRANSCRIPT
SECTION P.2Group C
How to Sketch the Graph of an Equation Graph of Equation: The set of
all solution points of an equation
1. Rewrite the equation so that one of the variables is isolated on one side
2. Make a table of several solution points
3. Plot these points in the Cartesian plane
4. Connect the points with a smooth curve
Example 1
x -2 -1 0 1 2 3
y=x2-2 2 -1 -2 -1 2 7
First, make a table of values by choosing values of x and calculating the values of y
Now plot the corresponding points
x
y
Using a Graphing Utility
1. Rewrite the equation so y is isolated
2. Enter the equation into the utility
3. Determine a viewing window that shows all important features of the graph
4. Graph equation
Example 2: Sketching a Circle Using a Graphing Utility
The graph of x2 + y2 = 9 is a circle whose center is at the origin and radius is 3. To graph the equation, solve for y.
x2 + y2 = 9 y2 = 9 - x2
y = √9 - x2
The graph of y = √9 - x2 is the top half The graph of y = -√9 - x2 is the bottom
half
x2 + y2 = 9
x
yEnter both equations into the calculator and generate the graph. If you use the standard viewing window the graph may not appear to be a circle, by changing the viewing window to a square setting you can overcome this.
Example 3: Real life
A runner runs a constant rate of 4.9 mph. (Distance = Rate x Time)
d = 4.9t
a) Determine how far a runner can run in 3.1 hours
b) How long will it take to run a 26.2 mile marathon?
Example 3: Real life
a) Substitute 3.1 hours for td = 4.9(3.1)d = 15.2 milesIn 3.1 hours the runner could run 15.2 miles
b) d = Rtd/R = t26.2m / 4.9mph = tt = 5.3 hours
It would take about 5.3 hours to run a 26.2 mile marathon