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    Transformer Excitation

    Current Test Procedures

    Doble Engineering DiagnosticsToolbox

    89 Years of Diagnostic Instrumentation and Services for the Electric Power Industry 2

    Abnormal core grounds Winding faults: shorts, open

    circuits

    LTC problems

    Manufacturing defects

    The Doble Excitation Current Test has beeneffective in finding:

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    89 Years of Diagnostic Instrumentation and Services for the Electric Power Industry 3

    1) When an AC Voltage Source, such as a Doble Test Set, is placed on a

    transformer, a small current will flow.

    2) This small current is the Magnetizing Current: the current required to

    magnetize the Transformer core with the Magnetic Fluxmag. ThisMagnetizing Current is the Excitation Current we measure and record.3) This Magnetic Flux will induce a voltage across the secondary

    windings: V2

    Iexcitation =Imag

    V1

    mag

    +

    -V2

    +

    -

    89 Years of Diagnostic Instrumentation and Services for the Electric Power Industry 4

    1) When a Load is placed on the secondary windings a current will flow

    I2=V2/R2 [ Ohms Law ]

    2) The Current I2

    will in-turn create an Opposing Magnetic Flux2.

    3) The Generator, which regulates voltage at a set level, will provide more

    current to maintain the core magnetized equal to the opposing flux

    Iexcitation =Imag+I2

    I22

    V2

    +

    -

    V1

    Iexcitation =Imag+I2

    +

    -

    mag+2

    R2

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    89 Years of Diagnostic Instrumentation and Services for the Electric Power Industry 5

    E1

    mag+fault

    Ifault

    X0

    X1UST

    fault

    +

    -

    Imag+IfHV

    LV

    H0

    H1

    1) If a fault develops in the secondary windings, this fault will act as aload across the faulted windings drawing a current Ifault

    2) As a result, the Excitation Current will go up due to the opposing flux

    created by the fault [fault]

    Result: A Fault will cause Excitation Current to Increase

    89 Years of Diagnostic Instrumentation and Services for the Electric Power Industry 6

    Iexcitation=Imag+Ifault

    1) If the secondary winding has a grounded neutral and one of the windingsdevelops a fault to ground, grounded windings will draw a fault current

    2) As a result, the Excitation Current will go up due to the opposing flux createdby the fault [fault]

    Result: A grounded winding on a transformer with a grounded

    neutral will cause the Excitation Current to go up.

    H0

    H1

    fault

    X1

    Ifault

    mag+fault

    XoNeutral Ground

    Ground Fault

    HV

    LV

    UST

    +

    -

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    89 Years of Diagnostic Instrumentation and Services for the Electric Power Industry 7

    When an autotransformer is connected across two taps it acts as aload and the primary current goes up.

    Result: When a LTC transitioning device such as a Preventive

    Autotransformer is in the bridging position the

    excitation current goes up.

    Iexcitation=Imag+IAT

    H0

    H1

    AT

    X1mag+AT

    Xo

    HV

    LV

    UST

    +

    -

    IA

    89 Years of Diagnostic Instrumentation and Services for the Electric Power Industry 8

    Excitation Current test results present patterns:

    Three Phase Transformers: Between phases

    (Two Similar Highs and One Low)* Within each Phase

    (When Tap Changers are present)**

    Single Phase Transformers

    Reverse measurement for confirmation

    * There are exceptions** Pattern will depend on Tap Changer type and Manufacture

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    89 Years of Diagnostic Instrumentation and Services for the Electric Power Industry 9

    =

    (b) Reluctance Circuit(a) Ferrous Core

    89 Years of Diagnostic Instrumentation and Services for the Electric Power Industry 10

    For simplicity assume that each section has a reluctance of 1

    1

    1

    1 1

    1 1 A B C

    In this example we have a three Phase three legged core

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    89 Years of Diagnostic Instrumentation and Services for the Electric Power Industry 11

    HV

    -

    P1

    P2

    A B C

    When you energize Phase A the equivalent reluctance circuit becomes:

    HV

    -

    P1

    P2

    3.75

    The same holds true when you energize Phase C

    89 Years of Diagnostic Instrumentation and Services for the Electric Power Industry 12

    B

    For Phase B the equivalent reluctance circuit becomes:

    HV

    -

    P1

    P2

    2.5

    P1

    P2

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    89 Years of Diagnostic Instrumentation and Services for the Electric Power Industry 13

    89 Years of Diagnostic Instrumentation and Services for the Electric Power Industry 14

    Benchmark or Base Measurement:

    LTC only: all positions NLTC only: all positions LTC and NLTC combination:

    all LTC positions with NLTC in

    center position; then all positions

    in NLTC with LTC in neutral

    On a Routine Basis:

    NLTC only: as found or positionregularly tapped

    LTC only: one full range plus neutraland one position in opposite range

    NLTC and LTC combination:NLTC in regularly tapped position or as

    found testing the LTC one full range

    plus neutral and one position in opposite

    range

    When Tap Changers are present, test as follows:

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    Perform tests at the highest Voltage possible

    Test each Phase at the same Voltage

    Perform subsequent tests at the same Voltage forcomparison

    If a Preventive Autotransformer is included in thetransformer, it might not be possible to excite thatposition of the LTC. In this event, testing might bepossible with the Preventive Autotransformer bypassedor at a lower voltage

    If the test set trips, choose a lower Voltage and repeat

    all three phases Never allow test voltage to exceed rated L-L for Delta

    and L-G for Wye

    89 Years of Diagnostic Instrumentation and Services for the Electric Power Industry 16

    Be aware of test equipment limitations Have consistent procedures Document special conditions, be specific If the Test set trips, choose a lower Voltage and repeat

    all three phases

    Example

    M4K is rated for 300 mA at 10 kV

    10 kV 300 mA

    9 kV 333 mA

    8 kV 375 mA7 kV 429 mA

    6 kV 500 mA

    5 kV 600 mA

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    =

    (b) Reluctance Circuit(a) Ferrous Core

    Remember this:

    Because test must comply with:

    Test at the highest Voltage possible Test each Phase at the same Voltage

    Phase demanding the highest current should be tested first

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    H1

    H2H3

    HV

    USTI1-2 I1-3

    Test Measure

    1 H1-H2

    2 H2-H3

    3 H3-H1

    When Low Voltage side is Wye configuration, remember to

    ground the Neutral

    LV

    89 Years of Diagnostic Instrumentation and Services for the Electric Power Industry 20

    H1

    H0

    H2 H3

    HV

    LV

    UST I1-0Test Measure

    1 H1-H0

    2 H2-H0

    3 H3-H0

    When Low Voltage side is Wye configuration, remember to

    ground the Neutral

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    89 Years of Diagnostic Instrumentation and Services for the Electric Power Industry 21

    Remember that the Excitation Current test is the only test where

    the short circuit jumpers are taken off the bushings

    H1

    H0

    HV

    LV

    USTI1-0

    89 Years of Diagnostic Instrumentation and Services for the Electric Power Industry 22

    Check the pattern: two similar high readings and onelow reading is normal (though there are exceptions)

    When Tap Changers are present, consider the patternwithin the phase

    For three-phase units, compare both high readings withthe following criterion: Readings 50 mA, differences should not exceed 5%

    For single phase units both readings should becompared using the same above criterion

    Compare Normal test to alternate tests; results shouldbe similar for a winding in good condition

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    Compare Normal test to alternate tests; results shouldbe similar for a winding in good condition

    Compare readings to previous results. Ensure that thesame voltage was used for both tests for consistentnumerical comparison

    If the core is magnetized an irregular pattern (high,medium, low readings) will be present and you will beunable to compare results effectively. A true problemcould be masked, therefore core should be

    demagnetized and test should be repeated If unusual results are obtained, consider performing an

    alternate test to further investigate