section—a / ¸»ÝwÜ>—a
TRANSCRIPT
SECTION—A / Àª›W‹>—A
1.(a) (I) Explain D’Alembert’s principle.
r D¯ÉA§mïð£À vÀvÀéªÀ£ÀÄß «ªÀj¹.
(II) The crank and connecting rod of a vertical petrol engine running at
1800rpm are 60mm and 270mm respectively. The diameter of the
piston is 100mm and the mass of the reciprocating parts is 1.2kg.
During the expansion stroke when the crank has turned 200 from the top
dead centre, the gas pressure is 650kN/m2 . Determine the
(i) Net force on the piston
(ii) Net load on the gudgeon pin
(iii) Thrust on the cylinder walls
(iv) Speed at which the gudgeon pin load is reversed in direction
PÁæAPï ªÀÄvÀÄÛ ®A§vÀ® ¥ÉmÉÆæïï JAf£ï£À ¸ÀA¥ÀQðvÀ ¸ÀgÀ¼ÀÄUÀ¼ÀÄ 1800rpm £À°è PÀæªÀĪÁV 60mm ªÀÄvÀÄÛ 270mm ZÀ°¸ÀÄwÛªÉ. ¦¸ÀÖ£ï£À ªÁå¸ÀªÀÅ 100mm ªÀÄvÀÄÛ »AzÉ ªÀÄÄAzÉ ZÀ°¸ÀĪÀ K¥Áðn£À JAf£ï£À ¨sÁUÀUÀ¼À gÁ²AiÀÄÄ 1.2kg.
«¸ÀÛgÀuÁ ºÉÆqÉvÀzÀ CªÀ¢üAiÀÄ°è PÁæAPï ªÉÄïÁãUÀzÀ ¤±ÉÑÃvÀ£À PÉÃAzÀæ¢AzÀ 200
wgÀÄUÀÄvÀÛzÉ. C¤® MvÀÛqÀªÀÅ 650kN/m2 EzÀÄÝ PɼÀV£ÀªÀÅUÀ¼À£ÀÄß ¤zsÀðj¹.
(i) ¦¸ÀÖ£ï£À ªÉÄð£À ¤ªÀé¼À §®
(ii) wgÀÄUÁt ¦£ï ªÉÄð£À ¤ªÀé¼À ºÉÆgÉ
(iii) ¹°AqÀgï UÉÆÃqÉUÀ¼À ªÉÄð£À zÀÆrPÉ (MvÀÛqÀ)
(iv) wgÀÄUÁt ¦£ï£À ºÉÆgÉAiÀÄÄ vÀ£Àß ¢QÌ£À°è »AZÁ®£ÉAiÀiÁzÀ (ªÀåwjPÀÛ) ªÉÃUÀ
[5+20 Marks]
16/I-Mechanical Engineering 1
1.(b) (I) Briefly explain shrink fit with example.
²æAPï ¦ümï£ÀÄß GzÁºÀgÀuÉAiÉÆA¢UÉ «ªÀj¹.
(II) A thick walled cylindrical pressure vessel has inner radius of 150mm
and outer radius of 185mm. Draw a sketch showing the radial pressure
and hoop stress distribution in the section of the cylinder wall, when an
internal pressure of 10MN/m2 is applied.
zÀ¥Àà£ÉAiÀÄ ©üwÛAiÀÄ ¹°AqÀgï MvÀÛqÀ s̈ÁAqÀªÀÅ DAvÀjPÀ ªÁå¸À 150mm ªÀÄvÀÄÛ ¨ÁºÀå
ªÁå¸À 185mm £ÀÄß ºÉÆA¢zÉ. DAvÀjPÀ MvÀÛqÀ 10MN/m2 £ÀÄß C£Àé¬Ä¹zÁUÀ,
¹°AqÀgï ©üwÛAiÀÄ « s̈ÁUÀzÀ°è£À gÉÃrAiÀįï MvÀÛqÀ ªÀÄvÀÄÛ ¸ÀÄvÀÄÛUÀnÖ£À MvÀÛqÀzÀ«vÀgÀuÉAiÀÄ£ÀÄß vÉÆÃj¸ÀĪÀ avÀæªÀ£ÀÄß gÀa¹. [5+20 Marks]
Time : 3 hours ”‹ ‹·ø· : 3 W‹ÌpÊW‹Ÿ‹·
Maximum Marks : 250
W‹ƒ–‹u AÌP‹W‹Ÿ‹·: 250
2.(a) (I) Explain Gyroscopic effect on Aeroplanes.
KgÉÆÃ¥ÉèãïUÀ¼À ªÉÄð£À eÉÊgÉÆøÉÆÌæPï (¨sÀæªÀÄt zÀ±ÀðQÃAiÀÄ) ¥ÀjuÁªÀĪÀ£ÀÄß«ªÀj¹.
(II) A rail car has a total mass of 4000kg. The moment of inertia of each
wheel together with it’s gearing is 20kg.m2. The centre distance
between the two wheels on an axle is 1.5m and each wheel is of 400mm
radius, each axle is driven by a motor, the speed ratio between the two
being 1:14. Each motor with it’s gear has a moment of inertia of
15kg.m2 and runs in a direction opposite to that of its axle. The centre
of gravity of the car is 1m above the rails.
Determine the limiting speed for the car when moving on a curve of
250m radius such that no wheel leaves the rails.
MAzÀÄ gÉ樀 PÁgÀÄ MlÄÖ 4000kg AiÀÄ gÁ²AiÀÄ£ÀÄß ºÉÆA¢zÉ. ¥ÀæwAiÉÆAzÀÄ ZÀPÀæzÀ
dqÀvÁ ªÀĺÀvÀÛ÷éªÀÅ CzÀgÀ UÉÃjAUï£ÉÆA¢UÉ MlÄÖ ¸ÉÃj 20kg.m2 EzÉ. DåPÉì̄ ï£À
JgÀqÀÄ ZÀPÀæUÀ¼À PÉÃAzÀæzÀ £ÀqÀÄ«£À CAvÀgÀ 1.5m ªÀÄvÀÄÛ ¥ÀæwAiÉÆAzÀÄ ZÀPÀæªÀÇ
400 mm wædå EzÉ. ¥ÀæwAiÉÆAzÀÄ DåPÉì̄ ï MAzÀÄ ªÉÆÃmÁgï¤AzÀ ZÀ°¸À®àmÁÖUÀ,JgÀqÀgÀ £ÀqÀĪÀt ªÉÃUÀzÀ C£ÀÄ¥ÁvÀªÀÅ 1:14. ¥ÀæwAiÉÆAzÀÄ ªÉÆÃmÁgÀÄ CzÀgÀ
UÉÃgï£ÉÆA¢UÉ 15 kg.m2 £À dqÀvÁ ªÀĺÀvÀÛ÷éªÀ£ÀÄß ºÉÆA¢zÉ ªÀÄvÀÄÛ CzÀÄ CzÀgÀDåPÉì̄ ï£À «gÀÄzÀÞ ¢QÌ£À°è ZÀ°¸ÀÄwÛzÉ. PÁj£À UÀÄgÀÄvÁéPÀµÀðt PÉÃAzÀæªÀÅ gÉÊ°£ÀzÀQÌAvÀ®Æ
1 m ªÉÄð£ÀzÀÄ.
MAzÀÄ wgÀÄ«£À°è 250m wædåzÀ wgÀÄ«£À ªÉÄÃ¯É PÁgÀÄ ZÀ°¸ÀÄwÛzÀÄÝ, CzÀgÀ AiÀiÁªÀÅzÉÃ
ZÀPÀæªÀÇ gÉÊ®ÄUÀ¼À£ÀÄß ©qÀzÀAvÉ, PÁj£À «ÄwAiÀÄ ªÉÃUÀªÀ£ÀÄß ¤zsÀðj¹.[5+20 Marks]
2.(b) State the principle of virtual work? Evaluate external crank shaft torque by
considering slider crank mechanism. [25 Marks]
ªÀ¸ÀÄÛvÀB PÁAiÀÄðzÀ vÀvÀéªÀ£ÀÄß ¤gÀƦ¹. ¸ÉèöÊqÀgï PÁæAPï£À QæAiÀiÁ«£Áå¸ÀªÀ£ÀÄߥÀjUÀtÂ̧ ÀĪÀÅzÀjAzÀ ¨ÁºÀå PÁæAPï µÁ¥sïÖ£À s̈ÁæªÀÄPÀzÀ ªÀiË®åªÀiÁ¥À£À ªÀiÁr.
3.(a) [20 Marks]Describe Single block brake with neat sketch.
KPÀ ¨ÁèPï ¨ÉæÃPï£ÀÄß CAzÀªÁzÀ avÀæzÉÆA¢UÉ «ªÀj¹.
3.(b) A Bicycle and rider of mass 100kg are travelling at the rate of 16 km/hr on a
level road. A brake is applied to the rear wheel which is 0.9mt in a diameter
and this is the only resistance acting. How far will the bicycle travel and
how many turns will it make before it comes to rest? The pressure applied
on the brake is 100N and m=0.5 [30 Marks]
100 kg ®‹≈ ‹¬-√›-Œø· JÌ®‹· ∏ÊÁ‘-P‹«Ö ‹·Ò‹·§ ”‹ ›-√‹√‹· JÌ®‹· ‹·or-”‹ √‹”ʧø· Ê·‡«Ê W‹ÌpÊWÊ
16Q.À·‡. ʇW‹®‹ ®‹√‹-®‹»… a‹»-”‹·-£§-®›™√Ê. 0.9mt ›¬”‹- ‹‚Ÿ‹¤ √ʇ√Ö (◊̪›-W‹-®‹) a‹P‹≈®‹ Ê·‡«Ê
∏Ê≈‡PÖÆ‹·∞ AÆ‹Ã-¿·-”‹-«›-X®Ê ‹·Ò‹·§ C®Ê„̮ʇ √Ê„‡´‹-P‹- ›X ‹£Ï-”‹·-£§-√‹·- ‹‚®‹·. A®‹· ØÕ‹c∆ ‘ߣWÊ
ü√‹· ‹ ‹··Æ‹∞ G–‹·r ®‹„√‹ ∏ÊÁ‘-P‹«Ö a‹»-”‹-ü-∆…®‹·? ‹·Ò‹·§ A®‹· G–‹·r ”‹·Ò›§-W‹-Ÿ‹-Æ‹·∞Ìo· ‹fiv‹·-Ò‹§®Ê?
∏Ê≈‡PÖÆ‹ Ê·‡«Ê AÆ‹Ã-¿·-”‹-«›®‹ JÒ‹§-v‹- ‹‚ 100N and m=0.5
4.(a) (I) Explain briefly the principal plane and principal stresses.
¥ÀæzsÁ£À ¸ÀªÀÄvÀ® ªÀÄvÀÄÛ ¥ÀæzsÁ£À MvÀÛqÀUÀ¼À£ÀÄß ¸ÀAPÉëÃ¥ÀªÁV «ªÀj¹.
(II) The stresses at point of a machine component are 150 MPa and 50MPa
both tensile. Find the intensities of normal, shear and resultant
stresses on a plane inclined at an angle of 550 with the axis of major
tensile stress. Also find the magnitude of the maximum shear stress in
the component.
MAzÀÄ AiÀÄAvÀæ WÀlPÀzÀ ©AzÀÄ«£À°è£À MvÀÛqÀUÀ¼ÀÄ 150 MPa ªÀÄvÀÄÛ 50 MPa JgÀqÀÆ
PÀµÀðPÀ§®UÀ¼ÀÄ. ¥ÀæzsÁ£À PÀµÀðPÀ MvÀÛqÀzÀ CPÀëzÀ°è£À 550 ¨ÁUÀÄ«PÉAiÀÄ PÉÆãÀzÀ
¸ÀªÀÄvÀ®zÀ ªÉÄð£À ¸ÁªÀiÁ£Àå, wjZÀÄ ªÀÄvÀÄÛ ¥ÀjuÁªÀÄPÀ MvÀÛqÀUÀ¼À wêÀævÉAiÀÄ£ÀÄßPÀAqÀÄ»r¬Äj. WÀlPÀzÀ°è£À UÀjµÀ× wjZÀÄ MvÀÛqÀzÀ ¥ÀæªÀiÁt (§ÈºÀvÀé)ªÀ£ÀÄß ¸ÀºÁPÀAqÀÄ »r¬Äj. [5+20 Marks]
4.(b) (I) Explain briefly the various theories of failure.
ªÉÊ¥sÀ®åzÀ ««zsÀ ¹zÁÞAvÀUÀ¼À£ÀÄß ¸ÀAQë¥ÀÛªÁV «ªÀj¹
(II) A beam of rectangular cross section has a span of 4.8 metres and is
simply supported at its ends. It is required to carry a total load of
4.5 KN, uniformly distributed over the whole span. Find the values of
the breadth (b) and depth (d) of the beam, if maximum bending stress is
not to exceed 7 MPa and maximum deflection is limited to 9.5 mm.
Take modulus of elasticity as 10.5 GPa.
MAzÀÄ DAiÀÄvÁPÁgÀzÀ CqÀغÁ¬ÄPÉ (PÁæ̧ ï ¸ÉPÀë£ï) « s̈ÁUÀzÀ zÀÆ®ªÀÅ 4.8«ÄÃlgïUÀ¼À GzÀݪÀ£ÀÄß ºÉÆA¢zÉ ªÀÄvÀÄÛ CzÀgÀ vÀÄ¢UÀ¼À°è ¸ÀgÀ¼ÀªÁV ¨ÉA§®ªÀ£ÀÄß
¥ÀqÉ¢zÉ. CzÀÄ 4.5 KN UÀ¼À MlÄÖ ºÉÆgÉAiÀÄ£ÀÄß ºÉÆgÀ¨ÉÃPÁVzÀÄÝ CzÀÄ ErÃGzÀÝzÀ ªÉÄÃ¯É ¸ÀªÀiÁ£ÀªÁV ºÀAaPÉAiÀiÁVgÀĪÀAvÉ s̈Àj¸À¯ÁVzÉ. D zÀAqÀzÀ CUÀ®
(b) ªÀÄvÀÄÛ D¼À (d) UÀ¼À ªÀiË®åUÀ¼À£ÀÄß PÀAqÀÄ»r¬Äj. UÀjµÀê ¨ÁUÀÄ«PÉAiÀÄ MvÀÛqÀ
7 MPa AiÀÄ£ÀÄß «ÄÃgÀ¢zÀÝ°è ªÀÄvÀÄÛ «ZÀ®£À/N®ÄªÉAiÀÄ£ÀÄß UÀjµÀÙ 9.5 mm UÉ
«ÄwUÉƽ¹zÀÝ°è, 10.5 GPa AiÀiÁV ¹Üw¸ÁÜ¥ÀPÀvÉAiÀÄ ªÀiÁqÀÄ宸ï£ÀÄß PÀAqÀÄ »r¬Äj.[10+15 Marks]
SECTION—B / Àª›W‹>—B
5.(a) Discuss the criteria used for machinability and methods of measuring tool
life.
A tool life of 100 minutes is obtained at 25 m/min and 6 minutes at
70 m/min. Calculate tool life index (n). What is the cutting speed for 1
minute life and 60 minute life? [25 Marks]
ªÉĶ£ï©°n ªÀÄvÀÄÛ ¸À®PÀgÀuÉAiÀÄ fëvÀªÀ£Àß¼ÉAiÀÄĪÀ «zsÁ£ÀUÀ½UÉ §¼À¸À¯ÁUÀĪÀªÀiÁ£ÀzÀAqÀªÀ£ÀÄß ZÀað¹. MAzÀÄ ¸À®PÀgÀuÉAiÀÄ 100 ¤«ÄµÀUÀ¼À fëvÀªÀ£ÀÄß
25 m/¤«ÄµÀUÀ¼À°è ¥ÀqÉAiÀįÁVzÉ ªÀÄvÀÄÛ 6 ¤«ÄµÀUÀ¼À fëvÀªÀ£ÀÄß 70 m/¤«ÄµÀUÀ¼À°è
¥ÀqÉAiÀįÁVzÉ. ¸À®PÀgÀuÉAiÀÄ fëvÀ ¸ÀÆZÀåAPÀªÀ£ÀÄß (n) ¯ÉQ̹. 1 ¤«ÄµÀ fëvÀ ªÀÄvÀÄÛ 60 ¤«ÄµÀ fëvÀPÁÌV PÀvÀÛj¸ÀĪÀ ªÉÃUÀªÀÅ JµÀÄÖ?
5.(b) Explain clearly the factors considered in designing a work station. Draw a
work station layout for a cylindrical grinding machine showing space
requirements. [25 Marks]
MAzÀÄ PÁAiÀÄð PÉÃAzÀæzÀ «£Áå¸ÀPÁÌV ¥ÀjUÀtÂ̧ ÀĪÀ CA±ÀUÀ¼À£ÀÄß ¸ÀàµÀÖªÁV «ªÀj¹.¹°AræPÀ¯ï UÉæöÊArAUï AiÀÄAvÀæPÁÌV ¸ÀܼÁªÀPÁ±ÀªÀ£ÀÄß vÉÆÃj¸ÀĪÀAvÉ PÁAiÀÄð PÉÃAzÀæ «£Áå¸À gÀZÀ£ÉAiÀÄ£ÀÄß awæ¹.
6. With neat setup line diagram explain the working principle of Ultrasonic
Machining and explain the different components of Ultrasonic Machining
system. With simple graphs explain the important process parameters of
Ultrasonic Machining process. [50 Marks]
CAzÀªÁzÀ ªÀåªÀ¸ÉÜAiÀÄ gÉÃR£À gÉÃSÁavÀæzÉÆA¢UÉ ±ÀæªÀuÁwÃvÀ ªÉĶ¤AUï£À PÁAiÀÄð vÀvÀéªÀÄvÀÄÛ ±ÀæªÀuÁwÃvÀ ªÉĶ¤AUï ªÀåªÀ¸ÉÜAiÀÄ «©ü£Àß WÀlPÀUÀ¼À£ÀÄß «ªÀj¹. ¸ÀgÀ¼À £ÀPÉëUÀ¼ÉÆA¢UɱÀæªÀuÁwÃvÀ ªÉĶ¤AUï ¥ÀæQæAiÉÄAiÀÄ ¥ÀæªÀÄÄR ¥ÀæQæAiÀiÁ ¥ÀæZÀÄgÀUÀ¼À£ÀÄß «ªÀj¹.
7.(a) What do you mean by Vee and conical locators in Jig design? With simple
sketches explain any two types of locators in each category. With neat
sketches explain Channel and Leaf (Lath) jigs. [25 Marks]
fUï «£Áå¸ÀzÀ°è£À «Ã ªÀÄvÀÄÛ ±ÀAPÁéPÀÈwAiÀÄ £É¯É ¤zÉÃð±ÀPÀUÀ¼ÉAzÀgÉãÀÄ? ¥ÀæwAiÉÆAzÀÄ¥ÀæªÀUÀðzÀ°è£À JgÀqÀÄ «zsÀUÀ¼À £É¯É ¤zÉÃð±ÀPÀUÀ¼À£ÀÄß ¸ÀgÀ¼À avÀæUÀ¼ÉÆA¢UÉ «ªÀj¹. ZÁ£É¯ï ªÀÄvÀÄÛ °Ã¥sï (®vï) fUïUÀ¼À£ÀÄß CAzÀªÁzÀ avÀæUÀ¼ÉÆA¢UÉ «ªÀj¹.
7.(b) (i) What are the various uses of predetermined motion time standard
(PMTS)?
¥ÀƪÀð ¤zsÁðjvÀ ZÀ®£À ¸ÀªÀÄAiÀÄ ²µÀÖ£À (PMTS) £À ««zsÀ G¥ÀAiÉÆÃUÀUÀ¼ÁªÀŪÀÅ?
(ii) List and explain four kinds of values in value engineering.
›¬∆„¬ GÌi-Ø-ø·-ƒÌWÖ-Æ‹»… ›¬∆„¬-W‹-Ÿ‹-»…Æ‹ 4 Ø´‹-W‹-Ÿ‹Æ‹·∞ ±‹qr- ‹fiw ‹·Ò‹·§ À ‹-ƒ-‘.
(iii) Design of workplace is an important aspect of man-machine system,
discuss its importance.
PÁAiÀÄð¸ÀܼÀzÀ «£Áå¸ÀªÀÅ ªÀiÁ£ÀªÀ-AiÀÄAvÀæ ªÀåªÀ¸ÉÜAiÀÄ ¥ÀæªÀÄÄR CA±ÀªÁVzÉ. CzÀgÀªÀĺÀvÀéªÀ£ÀÄß «ªÀj¹. [25 Marks]
8. Explain the importance of Transportation model and show that it can be
considered as Lpp. Solve the following transportation problem in which cell
entries represent unit costs. [50 Marks]
¸ÁUÀuÉ ªÀiÁzÀjAiÀÄ ¥ÁæªÀÄÄRåªÀ£ÀÄß «ªÀj¹ ªÀÄvÀÄÛ CzÀ£ÀÄß Lpp AiÀiÁV¥ÀjUÀtÂ̧ À§ºÀÄzÉA§ÄzÀ£ÀÄß vÉÆÃj¹. PÉÆñÀ £ÀªÀÄÆzÀÄUÀ¼ÀÄ WÀlPÀ ªÉZÀÑUÀ¼À£ÀÄß ¥Àæw¤¢ü¸ÀĪÀ°èPɼÀV£À ¸ÁUÀuÁ ¸ÀªÀĸÉåAiÀÄ£ÀÄß ©r¹.
To UÉ Available ® s̈Àå
From EAzÀ
2 7 4 5
3 3 1 8
5 4 7 7
1 6 2 14
Required
CUÀvÀå«gÀĪÀÅzÀÄ
7 9 18 34
SECTION—A / Àª›W‹>—A
1.(a) A reversible heat engine is supplied with heat from two constant
temperature sources at 900 K and 600 K and rejects heat to a constant
temperature sink at 300 K. The engine develops work equivalent to
90KJ/Sec. and rejects heat at rate of 56 KJ/Sec. Calculate heat supplied by
each source. [25 Marks]
jªÀ¹ð§¯ï («¥ÀAiÀÄðAiÀÄPÀ) GµÀÚ JAf£ïUÉ JgÀqÀÄ ¹ÜgÀ vÁ¥À DPÀgÀUÀ½AzÀ 900 K
ªÀÄvÀÄÛ 600 K UÀ¼À°è ±ÁR/vÁ¥ÀªÀ£ÀÄß ¥ÀÆgÉʸÀ¯ÁVzÉ ªÀÄvÀÄÛ MAzÀÄ ¹ÜgÀ GµÀÚvÁ ±ÁR
ZÉÆõÀuÉAiÀÄÄ 300 K AiÀÄ°è vÁ¥ÀªÀ£ÀÄß wgÀ¸ÀÌj¸ÀÄvÀÛzÉ. JAf£ï, 90 KJ/¸ÉPÉAqïUÉ
¸ÀªÀiÁ£ÀªÁUÀĪÀAvÉ PÁAiÀÄð ¨É¼ÀªÀtÂUÉAiÀÄ£ÀÄß GAlÄ ªÀiÁqÀÄvÀÛzÉ ªÀÄvÀÄÛ 56 KJ/¸ÉPÉAqïzÀgÀzÀ°è GµÀÚªÀ£ÀÄß wgÀ¸ÀÌj¸ÀÄvÀÛzÉ. ¥ÀæwAiÉÆAzÀÄ DPÀgÀ¢AzÀ ¥ÀÆgÉʸÀ¯ÁzÀ GµÀÚvÉAiÀÄ£ÀÄ߯ÉPÁÌZÁgÀ ªÀiÁr.
16/II-Mechanical Engineering 2
1.(b) Using Rayleigh’s method find an expression for the drag force on smooth
sphere of diameter ‘D’, moving with a velocity ‘V’ in a fluid of density ‘r’and
dynamic viscosity ‘m’. [25 Marks]
gÉðUïì£À «zsÁ£ÀªÀ£ÀÄߥÀAiÉÆÃV¹, ªÁå¸À ‘D’G¼Àî, ªÉÃUÀ ‘V’AiÉÆA¢UÉ ‘r’ ¸ÁAzÀævÉAiÀÄ
zÀæªÀzÀ°è ZÀ°¸ÀÄwÛgÀĪÀ ªÀÄvÀÄÛ QæAiÀiÁvÀäPÀ ¹ßUÀÞvÉ ‘m’DVgÀĪÀ £ÀAiÀÄ UÉÆüÀzÀ ªÉÄÃ¯É dUÀÄÎ
(J¼É) §®PÁÌV C©üªÀåQÛAiÀÄ£ÀÄß PÀAqÀÄ»r¬Äj.
2.(a) Show by dimensional analysis that data for forced convection may be
correlated by an equation of the form: Nu= F (Re,Pr) [25 Marks]
¤§ðA¢üvÀ ¸ÀAªÀºÀ£ÀzÀ ªÀiÁ»wAiÀÄ£ÀÄß Nu= F (Re,Pr) ¸À«ÄÃPÀgÀtzÀ gÀÆ¥ÀzÉÆA¢UɸÀA§A¢ü¹, DAiÀiÁ«Äà «±ÉèõÀuɬÄAzÀ ¸Á¢ü¹..
Time : 3 hours ”‹ ‹·ø· : 3 W‹ÌpÊW‹Ÿ‹·
Maximum Marks : 250
W‹ƒ–‹u AÌP‹W‹Ÿ‹·: 250
2.(b) A 12mm diameter mild steel sphere (k=42.5W/mK) is exposed to cooling
airflow at 270C resulting in convective coefficient h=114W/m2K. Determine.
MAzÀÄ 12mm ªÁå¸ÀzÀ ªÀÄÈzÀÄ GPÀÄÌ UÉÆüÀ (k=42.5W/mK) ªÀ£ÀÄß 270C AiÀÄ°è
vÀA¥ÀÄPÁgÀPÀ UÁ½ºÀj«UÉ MqÀدÁVzÀÄÝ EzÀÄ ¸ÀAªÁºÀPÀ ¸ÀºÀUÀÄuÁAPÀ h=114W/m2K £À
¥sÀ°vÁA±ÀªÀ£ÀÄß GAlÄ ªÀiÁqÀÄvÀÛzÉ. EªÀÅUÀ¼À£ÀÄß ¤zsÀðj¹.
(i) Time required to cool the sphere from 5400C to 950C
5400C ¤AzÀ 95
0C UÉ UÉÆüÀªÀ£ÀÄß vÀA¥ÁV¸À®Ä ¨ÉÃPÁVgÀĪÀ ¸ÀªÀÄAiÀÄ
(ii) Instantaneous heat transfer rate 2 minutes after the start of cooling
and
vÀA¥ÀÄUÉƽ¸ÀÄ«PÉAiÀÄ DgÀA s̈ÀªÁzÀ 2 ¤«ÄµÀUÀ¼À £ÀAvÀgÀ vÁvÀÌ÷ëtÂÃAiÀÄ ±ÁRªÀUÁðªÀuÉ zÀgÀ.
(iii) Total energy transferred from the sphere the first 2 minutes.
ªÉÆzÀ® 2 ¤«ÄµÀUÀ¼À°è UÉÆüÀ¢AzÀ ªÀUÁðªÀuÉAiÀiÁzÀ MlÄÖ ±ÀQÛAiÀÄ£ÀÄß ¤zsÀðj¹.
The relevant properties of mild steel are:
Density ‘r’=7850kg/m3 , specific heat c=475 J/kg K and Thermal diffusivity
a= 0.043 m2/hr.
ªÀÄÈzÀÄ GQÌ£À ¸ÀĸÀAUÀvÀ ®PÀëtUÀ¼ÉAzÀgÉ ¸ÁAzÀævÉ ‘r’=7850kg/m3, ¤¢ðµÀÖ GµÀÚvÉ
c=475 J/kg K ªÀÄvÀÄÛ xÀªÀÄð¯ï «¸ÀgÀtvÉ a= 0.043 m2/hr. [25 Marks]
3.(a) The frictional torque T of disc of diameter D rotating at a speed N in a fluid of viscosity m and density r in a turbulent flow is given by
[25 Marks]
D ªÁå¸ÀªÀ£ÀÄß¼Àî ©¯ÉèAiÀÄ (r¸ïÌ) WÀµÀðuÁ s̈ÁæªÀÄPÀ T AiÀÄÄ N ªÉÃUÀzÀ°è m ¹ßUÀÞvÁ
zÀæªÀzÀ°è wgÀÄUÀÄwÛzÉ ªÀÄvÀÄÛ ¸ÁAzÀævÉ r ¥ÀæPÀëÄ§Þ ºÀj«£À°è T = D N5 2 AiÀÄ£ÀÄß
¤ÃqÀĪÀÅzÀÄ. EzÀ£ÀÄß §QAUï ºÁåA£À p-¹zÁÞAvÀ¢AzÀ ¸Á¢ü¹.
3.(b) Derive an expression for total emissive power of a black body as stated
according to Stefan-Boltzman’s law to get value of constant being
computated. [25 Marks]
¹ÖÃ¥sÀ£ï-¨ÉÆïïÖ÷ÓªÀÄ£ï£À ¤AiÀĪÀÄzÀ ªÉÄÃgÉUÉ ¤gÀƦ¹gÀĪÀAvÉ ¯ÉQ̸À¯ÁzÀ ¹ÜgÁAPÀzÀªÀiË®åªÀ£ÀÄß ¥ÀqÉAiÀÄ®Ä MAzÀÄ PÀ¥ÀÄà PÁAiÀÄzÀ MlÄÖ GvÀìdð£Á ¸ÁªÀÄxÀåðzÀ C©üªÀåQÛAiÀÄ£ÀÄß ¤µÀàwÛ¹.
∅ .Prove this by using Buekingham’s –theorem .
∅
4. (I) Explain the following terms as applied to heat exchangers
GµÀÚ «¤ªÀÄAiÀÄPÁjUÀ½UÉ C£Àé¬Ä¹ PɼÀV£À ¥ÀzÀUÀ¼À£ÀÄß «ªÀj¹.
¸ÁªÀÄxÀåð C£ÀÄ¥ÁvÀ(i) Capacity ratio
(ii) Heat exchanger effectiveness
(iii) Number of Transfer Units
GµÀÚ «¤ªÀÄAiÀÄ ¥ÀjuÁªÀÄPÁjvÀé
ªÀUÁðªÀuÉ WÀlPÀUÀ¼À ¸ÀASÉå
(II) Obtain an expression for effectiveness of a parallel flow and counter flow
heat exchanger in terms of NTU and Capacity ratio.
NTU ¥ÀzÀUÀ¼À°è ªÀÄvÀÄÛ zsÁgÀt±ÀQÛ (¸ÁªÀÄxÀåð) C£ÀÄ¥ÁvÀzÀ°è MAzÀÄ ¸ÀªÀiÁAvÀgÀ ºÀjªÀŪÀÄvÀÄÛ ¥Àæw ºÀjªÀÅ (PËAlgï) «¤ªÀÄAiÀÄPÁjAiÀÄ ¥ÀjuÁªÀÄPÁjvÀézÀ C©üªÀåQÛAiÀÄ£ÀÄߥÀqɬÄj. [50 Marks]
SECTION—B / Àª›W‹>—B
5.(a) What are the differences between compression ignition (CI) and spark
ignition (SI) system? [25 Marks]
¸ÀA¦ÃqÀ£À d鮣À (CI) ªÀÄvÀÄÛ Qr d鮣À (SI) ªÀåªÀ¸ÉÜUÀ¼À £ÀqÀĪÀt ªÀåvÁå¸ÀUÀ¼ÉãÀÄ?
5.(b) With a neat sketch discuss the ideal reverse Brayton cycle. Compare the
actual reverse Brayton cycle with the ideal Brayton cycle using a T-S
diagram (Temperature-Entropy diagram). Derive expressions for network
output and the turbine and compressor efficiencies. [25 Marks]
DzÀ±Àð «¥ÀAiÀÄðAiÀÄ ¨ÉæÃl£ï ZÀPÀæªÀ£ÀÄß CAzÀªÁzÀ avÀæzÉÆA¢UÉ ZÀað¹. MAzÀÄ T-S
gÉÃSÁavÀæªÀ£ÀÄß (vÁ¥À-JAmÁæ¦ (C®¨sÀå ¥ÀæªÀiÁt) gÉÃSÁavÀæ) §¼À¹ ªÁ¸ÀÛªÀ »ªÉÆäUÀ¨ÉæÃl£ï ZÀPÀæzÉÆA¢UÉ DzÀ±Àð ¨ÉæÃl£ï ZÀPÀæªÀ£ÀÄß ºÉÆð¹. eÁ®PÁAiÀÄð GvÀà£Àß ªÀÄvÀÄÛl¨ÉÊð£ï ªÀÄvÀÄÛ ¸ÀA¦ÃqÀPÀ zÀPÀëvÁ ¸ÁªÀÄxÀåðUÀ¼À C©üªÀåQÛUÀ¼À£ÀÄß ¤µÀàwÛ¹.
An air refrigerator working on the principle of reverse Brayton cycle. The
air into the compressor is at 1 atm at -100C. It is compressed to 10 atm and
cooled to 400C at the same pressure. It is then expanded to 1 atm and
discharged to take cooling load. The air circulation is 1 kg/s.
»ªÉÆäUÀ ¨ÉæÃl£ï ZÀPÀæzÀ vÀvÀézÀ ªÉÄÃ¯É MAzÀÄ ªÁAiÀÄÄ gɦüædgÉÃlgï PÁAiÀÄð
¤ªÀð»¸ÀÄwÛzÉ. ¸ÀA¦ÃqÀPÀzÀ M¼ÀUÀqÉUÉ UÁ½AiÀÄÄ 1 atm £À°è -10 0C £À°èzÉ. CzÀÄ 10
atm UÉ ¸ÀAPÉÆÃZÀ£ÀUÉƼÀÄîvÀÛzÉ ªÀÄvÀÄÛ CzÉà MvÀÛqÀzÀ°è 400C UÉ vÀA¥ÁUÀÄvÀÛzÉ. £ÀAvÀgÀ
CzÀÄ 1 atm UÉ «PÀ¹¸ÀÄvÀÛzÉ ªÀÄvÀÄÛ vÀA¦PÉ ºÉÆgÉAiÀÄ£ÀÄß vÉUÉzÀÄPÉƼÀî®Ä
©qÀÄUÀqÉAiÀiÁUÀÄvÀÛzÉ. UÁ½AiÀÄ ¥Àæ̧ ÀgÀt 1 kg/¸É.
The isentropic efficiency of the compressor = 80%
¸ÀA¦ÃqÀPÀzÀ L¸É£ïmÉÆææPï zÀPÀëvÉAiÀÄÄ = 80%
The isentropic efficiency of the expander = 90%
«PÀ¸À£ÀzÀ L¸É£ïmÉÆææPï zÀPÀëvÉAiÀÄÄ = 90%
Find the following:
PɼÀV£ÀªÀÅUÀ¼À£ÀÄß PÀAqÀÄ»r¬Äj
(i) Refrigeration capacity of the system ªÀåªÀ¸ÉÜAiÀÄ gɦüædgÉõÀ£ï ¸ÁªÀÄxÀåð.
(ii) C.O.P. of the system ªÀåªÀ¸ÉÜAiÀÄ C.O.P
Take g = 1.4, Cp= 1.00 kJ / kg0C
g = 1.4, Cp= 1.00 kJ / kg0C JAzÀÄ vÉUÉzÀÄPÉƽî.
6. (I) Compare the advantages of MHD (magneto hydrodynamic) power
generation over the other Conventional Methods of Generation.
MHD (ªÀiÁåUÉßmÉÆ ºÉÊqÉÆæqÉÊ£À«ÄPï ¥ÀªÀgï d£ÀgÉõÀ£ï) AiÀÄ C£ÀÄPÀÆ®UÀ¼À£ÀÄßGvÁàzÀ£ÉAiÀÄ EvÀgÉ ¸ÁA¥ÀæzÁ¬ÄPÀ «zsÁ£ÀUÀ¼ÉÆA¢UÉ ºÉÆð¹.
(II) Explain the utilization of Solar Energy?
¸ËgÀ±ÀQÛAiÀÄ G¥ÀAiÀÄÄPÀÛvÉAiÀÄ£ÀÄß «ªÀj¹. [50 Marks]
7.(a) Describe the features of High-pressure Boilers? and List the advantages of
High-pressure Boilers? [25 Marks]
C¢üPÀ MvÀÛqÀzÀ ¨ÁAiÀÄègïUÀ¼À ®PÀëtUÀ¼À£ÀÄß «ªÀj¹ ªÀÄvÀÄÛ C¢üPÀ MvÀÛqÀ ¨ÁAiÀÄègïUÀ¼ÀC£ÀÄPÀÆ®UÀ¼À£ÀÄß ¥ÀnÖ ªÀiÁr.
7.(b) Explain the working principal of vapour compression cycle refrigeration,
with neat sketch. List its merits and demerits over Air Refrigeration
System. [25 Marks]
s̈ÁµÀà ¸ÀA¦ÃqÀ£À ZÀPÀæ gɦüædgÉÃlgïUÀ¼À PÁAiÀÄðvÀvÀéªÀ£ÀÄß CAzÀªÁzÀ avÀæzÉÆA¢UÉ «ªÀj¹. ªÁAiÀÄÄ gɦüædgÉõÀ£ï ªÀåªÀ¸ÉÜVAvÀ®Æ EzÀÄ ºÉÆA¢gÀĪÀ C£ÀÄPÀÆ®UÀ¼ÀÄ ªÀÄvÀÄÛC£Á£ÀÄPÀÆ®UÀ¼À£ÀÄß ¥ÀnÖ ªÀiÁr.
8.(a) Classify hydraulic turbines. Name and explain the performance
characteristics of turbines. [25 Marks]
÷ÊÁv›≈-»PÖ o∏ÊÁÏ-Æ‹·-W‹-Ÿ‹Æ‹·∞ ‹X‡Ï-P‹-ƒ‘. ÷Ê”‹-ƒ‘ ‹·Ò‹·§ o∏ÊÁÏ-Æ‹·-W‹Ÿ‹ Ø ‹Ï-÷‹O› W‹·|-∆-P‹“-|-W‹-Ÿ‹Æ‹·∞
À ‹-ƒ-‘.
8.(b) List and explain the desirable properties of a Ideal Refrigerant by
considering suitable examples.. [25 Marks]
DzÀ±Àð gɦüædgÉAmï£À (±ÉÊvÀåPÁj) C¥ÉÃPÀëtÂÃAiÀÄ ®PÀëtUÀ¼À£ÀÄß ¸ÀÆPÀÛ GzÁºÀgÀuÉUÀ¼À£ÀÄߥÀjUÀt¸ÀĪÀÅzÀjAzÀ ¥ÀnÖ ªÀiÁr ªÀÄvÀÄÛ «ªÀj¹.