side-angle-side congruence by basic rigid motions a geometric realization of a proof in h. wu’s...
DESCRIPTION
angle In other words, given ABC and A 0 B 0 C 0, A B C A0A0 C0C0 B0B0 A = A 0, |AB| = |A 0 B 0 |, and |AC| = |A 0 C 0 |, we must give a composition of basic rigid motions that maps ABC exactly onto A0B0C0.A0B0C0. side withTRANSCRIPT
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Side-Angle-Side Congruence by basic rigid motions
A geometric realization of a proof in H. Wu’s “Teaching Geometry According
to the Common Core Standards”
![Page 2: Side-Angle-Side Congruence by basic rigid motions A geometric realization of a proof in H. Wu’s “Teaching Geometry According to the Common Core Standards”](https://reader030.vdocument.in/reader030/viewer/2022020301/5a4d1b617f8b9ab0599ad784/html5/thumbnails/2.jpg)
Given two triangles, ABC and A0B0C0.Assume two pairs of equal corresponding sides with the angle between them equal.
We want to prove the triangles are congruent.
AB
C
A0
C0
B0
side
side
angle
angl
eside
side
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angl
e
angle
In other words, given ABC and A0B0C0,
AB
C
A0
C0
B0
A = A0, |AB| = |A0B0|,
and |AC| = |A0C0|,
we must give a composition of basic rigid motions that maps ABC exactly onto A0B0C0.
side
side
side
side
with
![Page 4: Side-Angle-Side Congruence by basic rigid motions A geometric realization of a proof in H. Wu’s “Teaching Geometry According to the Common Core Standards”](https://reader030.vdocument.in/reader030/viewer/2022020301/5a4d1b617f8b9ab0599ad784/html5/thumbnails/4.jpg)
We first move vertex A to A0 by a translation along the vector from A to A0
AB
C
A0
C0
B0
translates all points in the plane. Original positions are shown with dashed lines and new positions in red.
![Page 5: Side-Angle-Side Congruence by basic rigid motions A geometric realization of a proof in H. Wu’s “Teaching Geometry According to the Common Core Standards”](https://reader030.vdocument.in/reader030/viewer/2022020301/5a4d1b617f8b9ab0599ad784/html5/thumbnails/5.jpg)
Then we use a rotation to bring the horizontal side of the red triangle (which is the translated image of AB by ) to A0B0.
AB
C
A0
C0
B0
![Page 6: Side-Angle-Side Congruence by basic rigid motions A geometric realization of a proof in H. Wu’s “Teaching Geometry According to the Common Core Standards”](https://reader030.vdocument.in/reader030/viewer/2022020301/5a4d1b617f8b9ab0599ad784/html5/thumbnails/6.jpg)
AB
C
A0
C0
B0
maps the translated image of AB exactly onto A0B0 because |AB| = |A0B0| and translations preserve length.
![Page 7: Side-Angle-Side Congruence by basic rigid motions A geometric realization of a proof in H. Wu’s “Teaching Geometry According to the Common Core Standards”](https://reader030.vdocument.in/reader030/viewer/2022020301/5a4d1b617f8b9ab0599ad784/html5/thumbnails/7.jpg)
Now we have two of the red triangle’s vertices coinciding with A0 and B0 of A0B0C0.
AB
C
A0
C0
B0
After a reflection of the red triangle across A0B0, the third vertex will exactly coincide with C0.
![Page 8: Side-Angle-Side Congruence by basic rigid motions A geometric realization of a proof in H. Wu’s “Teaching Geometry According to the Common Core Standards”](https://reader030.vdocument.in/reader030/viewer/2022020301/5a4d1b617f8b9ab0599ad784/html5/thumbnails/8.jpg)
Can we be sure this composition of basic rigid motions
AB
C
A0
C0
B0
takes C to C0 — and the red triangle with it?
(the reflection of the rotation of thetranslation of theimage of ABC)
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Yes! The two marked angles at A0 are equal since basic rigid motions preserve degrees of angles,
AB
C
A0
C0
B0and CAB = C0A0B0
is given by hypothesis.
A reflection across A0B0 does take C to C0
— and the red triangle with it!
![Page 10: Side-Angle-Side Congruence by basic rigid motions A geometric realization of a proof in H. Wu’s “Teaching Geometry According to the Common Core Standards”](https://reader030.vdocument.in/reader030/viewer/2022020301/5a4d1b617f8b9ab0599ad784/html5/thumbnails/10.jpg)
AB
C
A0
C0
B0
Since basic rigid motions preserve length and since |AC| = |A0C0|,
by Lemma 8, the red triangle coincides with A0B0C0.
after a reflection across A0B0,
The triangles are congruent. Our proof is complete.
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Given two triangles with two pairs of equal sides and an included equal angle,
maps the image of one triangle onto the other.Therefore, the triangles are congruent.
basic rigid motions
AB
C
A0
C0
B0
A0
C0
B0
a composition of
(translation, rotation, and reflection)