signal processing first - konkukkonkuk.ac.kr/~cyim/dsp/chapter6.pdf · signal processing first...
TRANSCRIPT
![Page 1: Signal Processing First - Konkukkonkuk.ac.kr/~cyim/dsp/Chapter6.pdf · Signal Processing First Chapter 6 Frequency Response of FIR Filters. ... §SINUSOIDALINPUT SIGNAL §DETERMINE](https://reader033.vdocument.in/reader033/viewer/2022051205/5ad06e317f8b9a6c6c8e441c/html5/thumbnails/1.jpg)
5/3/2018 © 2003, JH McClellan & RW Schafer 1
Signal Processing First
Chapter 6Frequency Response
of FIR Filters
![Page 2: Signal Processing First - Konkukkonkuk.ac.kr/~cyim/dsp/Chapter6.pdf · Signal Processing First Chapter 6 Frequency Response of FIR Filters. ... §SINUSOIDALINPUT SIGNAL §DETERMINE](https://reader033.vdocument.in/reader033/viewer/2022051205/5ad06e317f8b9a6c6c8e441c/html5/thumbnails/2.jpg)
5/3/2018 © 2003, JH McClellan & RW Schafer 2
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5/3/2018 © 2003, JH McClellan & RW Schafer 3
Lecture Objectives
Sinusoidal input signal Determine the FIR filter output
Frequency response of FIR Plotting vs. Frequency Magnitude vs. Freq. Phase vs. Freq. )(ˆˆ ˆ
)()( jeHjjj eeHeH
MAG
PHASE
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6-1 Sinusoidal Response ofFIR Systems
Input: x[n] = Sinusoid Output: y[n] will also be a Sinusoid Different Amplitude and Phase
SAME Frequency
Amplitude & Phase change vs. frequency Called the FREQUENCY RESPONSE
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Complex Exponential Input
M
k
M
kk knxkhknxbny
00][][][][
FIR DIFFERENCE EQUATION
neAenx njj ˆ][x[n] is the input signal—a complex exponential
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5/3/2018 © 2003, JH McClellan & RW Schafer 6
Complex Exponential Output
Use the FIR “Difference Equation”
njj eAeH ˆ)ˆ(
M
k
knjjk
M
kk eAebknxbny
0
)(ˆ
0][][
njjM
k
kjk eAeeb ˆ
0
)(ˆ
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Frequency Response
Complex-valued formula Magnitude vs. frequency Phase vs. frequency
Notation:
FREQUENCYRESPONSE
At each frequency, we can DEFINE
)ˆ(of place in )( ˆ HeH j
kjM
kkebH ˆ
0)ˆ(
kjM
kk
j ebeH ˆ
0
ˆ )(
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Example 6.1
Exploitsymmetry
}1,2,1{}{ kb
)ˆcos22()2(
21)(
ˆ
ˆˆˆ
ˆ2ˆˆ
j
jjj
jjj
eeee
eeeH
ˆ)( is Phaseand
)ˆcos22()( is Magnitude0)ˆcos22( Since
ˆ
ˆ
j
j
eH
eH
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PLOT of FREQ RESPONSE
ˆˆ )ˆcos22()( jj eeH RESPONSE at /3
}1,2,1{}{ kb
(radians)
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Example 6.2
y[n]x[n])( jeH
ˆˆ )ˆcos22()( jj eeH
njj
j
eenxeHny
)3/(4/
ˆ
2][ andknown is )( when][ Find
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njj eenxny )3/(4/2][ when][ Find
Example 6.2 (answer)
3/ˆat )( evaluate-Step One ˆ jeH ˆˆ )ˆcos22()( jj eeH
3/ˆ@3)( 3/ˆ jj eeH
njjj eeeny )3/(4/3/ 23][ njj ee )3/(12/6
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6-2 Superposition and theFrequency Response
)cos(2][ andknown is )( when][ Find
43
ˆ
nnxeHny j
ˆˆ )ˆcos22()( jj eeH
y[n]x[n] )( jeH
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Example 6-3: Cosine Input
)cos(2][ when][ Find 43 nnxny
][][][)cos(2
21
)4/3/()4/3/(43
nxnxnxeen njnj
][][][)(][
)(][
21
)4/3/(3/2
)4/3/(3/1
nynynyeeHny
eeHnynjj
njj
UseLinearity
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Ex: Cosine Input (ans-2)
)cos(2][ when][ Find 43 nnxny
)4/3/()3/()4/3/(3/2
)4/3/()3/()4/3/(3/1
3)(][3)(][
njjnjj
njjnjj
eeeeHnyeeeeHny
)cos(6][33][
123
)12/3/()12/3/(
nnyeeny njnj
ˆˆ )ˆcos22()( jj eeH
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Sinusoid Output of FIR
If Multiply the Magnitudes Add the Phases
))(ˆcos()(][
)ˆcos(][11 ˆ
1ˆ
1
jj eHneHAny
nAnx
)()( ˆˆ* jj eHeH
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LTI Systems
LTI: Linear & Time-Invariant
Completely characterized by: FREQUENCY RESPONSE, or IMPULSE RESPONSE h[n]
Sinusoid Input -----> Sinusoid Output At the SAME Frequency
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6-4 Properties of the FrequencyResponse
Get Frequency Response from h[n] Here is the FIR case:
kjM
k
kjM
kk
j ekhebeH ˆ
0
ˆ
0
ˆ ][)(
IMPULSE RESPONSE
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Block Diagrams
Equivalent Representations
y[n]x[n]
y[n]x[n])( jeH
][nh
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Time & Frequency Domain
FIR DIFFERENCE EQUATION is the TIME-DOMAIN
M
k
M
kk knxkhknxbny
00][][][][
M
k
kjj ekheH0
ˆˆ ][)(
ˆ3ˆ2ˆˆ ]3[]2[]1[]0[)( jjjj ehehehheH
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Unit-Delay System
y[n]x[n] ]1[ n
y[n]x[n] je)( jeH
]1[][for )( and ][ Find ˆ nxnyeHnh j
}1,0{}{ kb
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First Difference System
y[n]x[n] 1 je
y[n]x[n] ]1[][ nn
)( jeH
]1[][][ :Equatione Differencfor the )( and ][ Find ˆ
nxnxnyeHnh j
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Example: Delay by 2 System
y[n]x[n] )( jeH
y[n]x[n] ][nh
]2[][for )( and ][ Find ˆ nxnyeHnh j
]2[][ nnh
}1,0,0{kb
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Delay by 2 System
k = 2 ONLY
y[n]x[n] ]2[ n
]2[][for )( and ][ Find ˆ nxnyeHnh j
M
k
kjj ekeH0
ˆˆ ]2[)(
)( jeHy[n]x[n] 2je
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General Delay Property
Only one non-ZERO termfor k at k = nd
dnjM
k
kjd
j eenkeH ˆ
0
ˆˆ ][)(
][][for )( and ][ Find ˆd
j nnxnyeHnh
][][ dnnnh
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Frequency domain --> Time domain
Start with kj bnheH or find and ][)(
)ˆcos(7)( ˆ2ˆ jj eeH
y[n]x[n] ][nh ?][ nh
y[n]x[n])( jeH
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Euler’s Formula)ˆcos(7)( ˆ2ˆ jj eeH )5.05.0(7 ˆˆˆ2 jjj eee
)5.35.3( ˆ3ˆ jj ee
]3[5.3]1[5.3][ nnnh
}5.3,0,5.3,0{kb
Frequency domain --> Time domain
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6-6 Cascaded LTI Systems
Does the order of S1 & S2 matter? No, LTI systems can be rearranged ! What are the filter coefficients? {bk} What is the overall frequency response?
S1 S2][n ][1 nh ][][ 21 nhnh ][1 nh ][2 nh
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Cascade Equivalent
Multiply the Frequency Responses
y[n]x[n] )( jeH
x[n] )( ˆ1
jeH y[n])( ˆ2
jeH
)()()( ˆ2
ˆ1
ˆ jjj eHeHeH EQUIVALENTSYSTEM
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6-7 Running-Average Filtering
Spectrum of x(t) (Sum of sinusoids) Spectrum of x[n] Is ALIASING a PROBLEM ?
Spectrum y[n] (FIR Gain or Nulls) Output y(t) = Sum of sinusoids
D-to-AA-to-Dx(t) y(t)y[n]x[n] )( jeH
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Frequency Scaling
Time sampling: If NO aliasing: Frequency scaling
D-to-AA-to-Dx(t) y(t)y[n]x[n] )( jeH
sfsT ˆsnTt
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11-point Average Example
D-to-AA-to-Dx(t) y(t)y[n]x[n] )( jeH
?
250 Hz
25 Hz ?))250(2cos())25(2cos()( 2
1 tttx
ˆ5
21
211
ˆ
)ˆsin(11)ˆsin(
)( jj eeH
10
0111 ][][
kknxny
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D-A Frequency Scaling
Reconstruct up to 0.5fs Frequency scaling
D-to-AA-to-Dx(t) y(t)y[n]x[n] )( jeH
Time sampling:
sf ˆ
ss ftnnTt
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Track the Frequencies
D-to-AA-to-Dx(t) y(t)y[n]x[n] )( jeH
Fs = 1000 Hz
0.5
.05
0.5
.05
250 Hz
25 Hz
NO new freqs
250 Hz
25 Hz )(
)(
05.0
5.0
j
j
eH
eH
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11-point Average
NULLS or ZEROS
5.0ˆ 05.0ˆ
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Evaluate Frequency Response
ˆ5
21
211
ˆ
)ˆsin(11)ˆsin(
)( jj eeH
)5.0(5
21
211
ˆ
))5.0(sin(11))5.0(sin(
)(
jj eeH
5.0ˆAt
5.2
)25.0sin(11)75.2sin( je
5.00909.0 je
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Evaluate Frequency Response
fs = 1000MAG SCALE
PHASE CHANGE
)( 1000/)25(2jeH
)( 1000/)250(2jeH
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EFFECTIVE RESPONSE
DIGITAL FILTER
LOW-PASS FILTER
)( jeH
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Filter Types
Low-pass Filter (LPF) Blurring Attenuates high frequencies
High-pass Filter (HPF) Sharpening for images Boots high frequencies Removes DC
Band-pass Filter (BPF)
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Black & White Image
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B&W Image with CosineFILTERED: 11-pt AVG
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Filtered B&W Image
LPF:Blur
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Row of B&W Image
BLACK = 255
WHITE = 0
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Row of Filtered Image
Adjusted Delay by 5 samples