simple linear regression answers
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7/23/2019 Simple Linear Regression Answers
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1a.
X Y XY X 2
45 55 2 475 2 025
46 54 2 484 2 116
48 57 2 736 2 304
50 65 3 250 2 500
45 57 2 565 2 025
49 58 2 842 2 401
48 60 2 880 2 304
55 67 3 685 3 025
57 57 3 249 3 249
52 62 3 224 2 704
58 70 4 060 3 364
53 64 3 392 2 809
47 59 2 773 2 209
46 46 2 116 2 116
50 65 3 250 2 500
∑ X = 749 ∑ Y = 896 ∑ XY = 44 981 ∑ X 2 = 37 651
Y’ = b X + a
Y’ = 0.96 X + 11.80
b) When X = 43, Y’ = 0.96(43) + 11.80
= 53.08
c)
1
.).2(96.0
749)37651(15
)896)(749()44981(15
)(
2
22
pd
X X n
Y X XY nb
=
−
−=
∑−∑
∑∑−∑=
.).2(80.1115
)749(96.0896 pd
n
X bY a
=−
=
∑−∑=
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X Y Y’ = 0.96 X + 11.80 Y – Y’ (Y – Y’)2
45 55 55.00 0.00 0.00
46 54 55.96 -1.96 3.84
48 57 57.88 -0.88 0.77
50 65 59.80 5.20 27.04
45 57 55.00 2.00 4.00
49 58 58.84 -0.84 0.71
48 60 57.88 2.12 4.49
55 67 64.60 2.40 5.76
57 57 66.52 -9.52 90.63
52 62 61.72 0.28 0.08
58 70 67.48 2.52 6.35
53 64 62.68 1.32 1.74
47 59 56.92 2.08 4.33
46 46 55.96 -9.96 99.20
50 65 59.80 5.20 27.04
∑ (Y – Y’)2= 275.98
d(i)
2
.).2(61.4
215
98.275
2
2
pd
n
)Y' -(Y se
=
−=
−
∑=
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ddoaaeacsscoe, s c s s c o e ,
d(ii)
4446485052545658AdditionalMathematicsscore,X455055606570 P h y s i c s s c o r e , Y RSqLinear =0.456
d(iii)
Coefficients(a)
3
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Model
UnstandardizedCoefficients
StandardizedCoefficients
t Sig. Std. !rror eta
" #Constant$ "".8%0 "4.57% .8"2 .4%2
&dditionalMat'e(aticsscore) *
.+5+ .2+" .675 %.2+8 .006
a ,e-endent aria/le 1'sics score) 3
Y’ = b X + a
Y’ = 0.959 X + 11.830
d(iv)
Model Summary
Model R R Sqare &dsted R
SqareStd. !rror of t'e !sti(ate
" .675#a$ .456 .4"4 4.608
a 1redictors #Constant$) &dditional Mat'e(atics score) *
se = 4.608
e)
Step 1 State the n!"" and a"te#native h$p%the&e&
'% β = 0 (he #e#e&&i%n c%e**icient in the p%p!"ati%n e!a"& e#%)
'1 β ≠ 0 (he #e#e&&i%n c%e**icient in the p%p!"ati%n i& n%t e!a" t% e#%)
#
'% dditi%na" /atheatic& &c%#e i& n%t a &tati&tica""$ &ini*icant p#edict%# %* h$&ic& &c%#e.
'1 dditi%na" /atheatic& &c%#e i& a &tati&tica""$ &ini*icant p#edict%# %* h$&ic& &c%#e.
Step 2 Set the c#ite#i%n *%# #eectin the n!"" h$p%the&i&
eect '% i* p 0.05
Step 3 a##$ %!t the ana"$&i& !&in SSS
Model Summary
4
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Model R R Sqare &dsted R
SqareStd. !rror of t'e !sti(ate
" .675#a$ .456 .4"4 4.608
a 1redictors #Constant$) &dditional Mat'e(atics score) *
Coefficients(a)
Model
UnstandardizedCoefficients
StandardizedCoefficients
t Sig. Std. !rror eta
" #Constant$ "".8%0 "4.57% .8"2 .4%2
&dditionalMat'e(aticsscore) *
.+5+ .2+" .675 %.2+8 .006
a ,e-endent aria/le 1'sics score) 3
Step 4 /ae a deci&i%n b$ app"$in the c#ite#i%n *%# #eectin the n!"" h$p%the&i&
#% the SSS %!tp!t, p = 0.006
(he p#%babi"it$ %* c%ittin a $pe e##%# that i&, the "ie"ih%%d %* #eectin the n!""
h$p%the&i& hen it i& t#!e i& 0.006)
he#e*%#e, #eect '% beca!&e p 0.05
Step 5 /ae a c%nc"!&i%n in the c%nte:t %* the p#%b"e
dditi%na" /atheatic& &c%#e i& a &tati&tica""$ &ini*icant p#edict%# %* h$&ic& &c%#e,
t (14) = 3.298, p .05
(hat i&, n%"ede %* dditi%na" /atheatic& &c%#e& enhance& the p#edicti%n %* h$&ic&
&c%#e&)
he #e#e&&i%n e!ati%n i& a& *%""%&
Y’ = 0.959 X + 11.830
Predicted Physics score = 0.959 ( Additional Mathematics score) + 11.830
r 2 = 0.456
45.6; %* the va#iance in h$&ic& &c%#e& can be a&&%ciated ith (e:p"ained b$) the va#iance in
dditi%na" /atheatic& &c%#e&.
2a.
5
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X Y XY X 2
2.2 2.6 5.72 4.84
1.0 1.5 1.50 1.00
2.3 2.7 6.21 5.29
3.6 4.0 14.40 12.96
0.9 1.0 0.90 0.81
1.6 2.0 3.20 2.56
3.3 3.5 11.55 10.89
3.4 3.0 10.20 11.56
4.0 2.5 10.00 16.00
2.6 2.8 7.28 6.76
∑ X = 24.9 ∑ Y = 25.6 ∑ XY = 70.96 ∑ X 2 = 72.67
Y’ = b X + a
Y’ = 0.68 X + 0.87
b) When X = 3.5, Y’ = 0.68 (3.5) + 0.87
= 3.25
c.
X Y Y’ = 0.68 X + 0.87 Y – Y’ (Y – Y’)2
2.2 2.6 2.37 0.23 0.05
1.0 1.5 1.55 -0.05 0.00
6
.).2(68.09.24)67.72(10
)6.25)(9.24()96.70(10
)(
2
22
pd
X X n
Y X XY nb
=−
−=
∑−∑
∑∑−∑=
.).2(87.010
)9.24(68.06.25
pd
n
X bY a
=
−
=
∑−∑=
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2.3 2.7 2.43 0.27 0.07
3.6 4.0 3.32 0.68 0.46
0.9 1.0 1.48 -0.48 0.23
1.6 2.0 1.96 0.04 0.00
3.3 3.5 3.11 0.39 0.15
3.4 3.0 3.18 -0.18 0.03
4.0 2.5 3.59 -1.09 1.19
2.6 2.8 2.64 0.16 0.03
∑ (Y – Y’)2= 2.21
d(i)
7
.).2(53.0
210
21.2
2
pd
n
)Y' -(Y s
2
e
=
−=
−
∑=
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".02.0%.04.0Number of hour sspentstudyingdaily,X".0".52.02.5%.0%.54.0 C P A , Y
d(ii)
".. . .,"."......
, Linr.
d(iii)
8
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Coefficients(a)
Model
UnstandardizedCoefficients
StandardizedCoefficients
t Sig. Std. !rror eta
" #Constant$ .876 .4%5 2.0"% .07+
(/er of'ors s-entstding dail)*
.676 ."6" .82+ 4."+" .00%
a ,e-endent aria/le C1&) 3
Y’ = b X + a
Y’ = 0.676 X + 0.876
d(iv)
Model Summary
Model R R Sqare &dsted R
SqareStd. !rror of t'e !sti(ate
" .82+#a$ .687 .648 .5272
a 1redictors #Constant$) (/er of 'ors s-ent stding dail) *
se = 0.5272
e)
Step 1 State the n!"" and a"te#native h$p%the&e&
'% β = 0 (he #e#e&&i%n c%e**icient in the p%p!"ati%n e!a"& e#%)
'1 β ≠ 0 (he #e#e&&i%n c%e**icient in the p%p!"ati%n i& n%t e!a" t% e#%)
#
'% <!be# %* h%!#& &pent &t!d$in dai"$ i& n%t a &tati&tica""$ &ini*icant p#edict%# %* .
'1 <!be# %* h%!#& &pent &t!d$in dai"$ i& a &tati&tica""$ &ini*icant p#edict%# %* .
Step 2 Set the c#ite#i%n *%# #eectin the n!"" h$p%the&i&
eect '% i* p 0.01
Step 3 a##$ %!t the ana"$&i& !&in SSS
Model Summary
9
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Model R R Sqare &dsted R
SqareStd. !rror of t'e !sti(ate
" .82+#a$ .687 .648 .5272
a 1redictors #Constant$) (/er of 'ors s-ent stding dail) *
Coefficients(a)
Model
UnstandardizedCoefficients
StandardizedCoefficients
t Sig. Std. !rror eta
" #Constant$ .876 .4%5 2.0"% .07+
(/er of'ors s-entstding dail)*
.676 ."6" .82+ 4."+" .00%
a ,e-endent aria/le C1&) 3
Step 4 /ae a deci&i%n b$ app"$in the c#ite#i%n *%# #eectin the n!"" h$p%the&i&
#% the SSS %!tp!t, p = 0.003
(he p#%babi"it$ %* c%ittin a $pe e##%# that i&, the "ie"ih%%d %* #eectin the n!""
h$p%the&i& hen it i& t#!e i& 0.003)
he#e*%#e, #eect '% beca!&e p 0.01
Step 5 /ae a c%nc"!&i%n in the c%nte:t %* the p#%b"e
<!be# %* h%!#& &pent &t!d$in dai"$ i& a &tati&tica""$ &ini*icant p#edict%# %* ,
t (9) = 4.191, p .01
(hat i&, n%"ede %* n!be# %* h%!#& &pent &t!d$in dai"$ enhance& the p#edicti%n %*
.)
he #e#e&&i%n e!ati%n i& a& *%""%&
Y’ = 0.676 X + 0.876
Predicted CGPA = 0.676 ( Number of hours spent studying daily) + 0.876
r 2 = 0.687
68.7; %* the va#iance in can be a&&%ciated ith (e:p"ained b$) the va#iance in n!be#
%* h%!#& &pent &t!d$in dai"$.
3a)
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Coefficients(a)
Model
UnstandardizedCoefficients
StandardizedCoefficients
t Sig. Std. !rror eta
" #Constant$ 27.8%" .724 %8.42+ .000
&ge of a car#ear$) *
2.2+2 ."%8 .+86 "6.65+ .000
a ,e-endent aria/le 1rice of a car) 3
Y’ = b X + a
Y’ = -2.292 X + 27.831
When X = 3, Y’ = -2.292 (3) + 27.831
= 20.955 th%!&and init /a"a$&ia
b)
Step 1 State the n!"" and a"te#native h$p%the&e&
'% β = 0 (he #e#e&&i%n c%e**icient in the p%p!"ati%n e!a"& e#%)
'1 β ≠ 0 (he #e#e&&i%n c%e**icient in the p%p!"ati%n i& n%t e!a" t% e#%)
#
'% e %* a ca# i& n%t a &tati&tica""$ &ini*icant p#edict%# %* the p#ice %* a ca#.
'1 e %* a ca# i& a &tati&tica""$ &ini*icant p#edict%# %* the p#ice %* a ca#.
Step 2 Set the c#ite#i%n *%# #eectin the n!"" h$p%the&i&
eect '% i* p 0.05
Step 3 a##$ %!t the ana"$&i& !&in SSS
Model Summary
Model R R Sqare
&dsted R
Sqare
Std. !rror of
t'e !sti(ate" .+86#a$ .+72 .+68 .5657
11
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a 1redictors #Constant$) &ge of a car #ear$) *
Coefficients(a)
Model
Unstandardized
Coefficients
Standardized
Coefficients
t Sig. Std. !rror eta
" #Constant$ 27.8%" .724 %8.42+ .000
&ge of a car#ear$) *
2.2+2 ."%8 .+86 "6.65+ .000
a ,e-endent aria/le 1rice of a car) 3
Step 4 /ae a deci&i%n b$ app"$in the c#ite#i%n *%# #eectin the n!"" h$p%the&i&
#% the SSS %!tp!t, p = 0.000
(he p#%babi"it$ %* c%ittin a $pe e##%# that i&, the "ie"ih%%d %* #eectin the n!""
h$p%the&i& hen it i& t#!e i& 0.000)
he#e*%#e, #eect '% beca!&e p 0.05
Step 5 /ae a c%nc"!&i%n in the c%nte:t %* the p#%b"e
e %* a ca# i& a &tati&tica""$ &ini*icant p#edict%# %* the p#ice %* a ca#,
t (9) = -16.659, p .05
(hat i&, n%"ede %* the ae %* a ca# enhance& the p#edicti%n %* the p#ice %* a ca#.)
he #e#e&&i%n e!ati%n i& a& *%""%&
Y’ = -2.292 X + 27.831
Predicted price of a car = -2.292 ( Age of a car ) + 27.831
r2
= 0.972
97.2; %* the va#iance in the p#ice %* a ca# can be a&&%ciated ith (e:p"ained b$) the va#iance
in the ae %* a ca#.
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