simple method of acid base balance interpretation

5/21/2018 Simple Method of Acid Base Balance Interpretation

1

, ABG. I

3 .

,

2

3

1. .

< 7.35 7.357.45 > 7.45

A

CA

2. 2 .

2

< 35 35 45 > 45

C

H

H

C

C H

H

3. .

' :


2

H H L H

H C2 L C2 H C2 L C2

I 2 , .o

H > 7.4 .

o H < 7.4 .

ABG .

.

( "" "BACK" )

.

4. 03

3 2226

:

, ,

:o

,

,

o ,

.

"C" 3 H

2.

H 2 3()

L 2 3().

1


3

7.39 1 H

2 40 2

C2

I

(

;

H ,

,

.)

2

7.2 1

L

2 50 2

H

2

I

3

7.49 1H


4

2 30 2

L 2

(

H)

I

4

7.23 1L

2 31 3

L 2

,

. L

H.

I

5

7.48 1H

2 47 3H 02

H


5

.

H.

I

6

7.43 1

7.4,

.

2 33 3

L 2

I

ABG , ABG .

1


6

. 35 , .

ED . .

2 . H 102.2, 110/76,

108, 32, . B ,

. C .

ABG :

o H= 7.44

o C2= 28

o HC3= 24

o 2= 54

:

C2 .

H , . A, 2 ,

( ).

:

. AD .

. .

, C2. I 2

H.

H F2 , ,

EE, BA 2. (C BA

.)

E , .

C

.

2

. 52 . H . H ED

. H

. H ; . EKG . H

. H . H

. ABG :


7

ABG :

o H= 7.48

o C2= 28

o HC3= 22

o 2= 85

:

H ,

C2

.

:

I ,

. H C2. C2 .

* C2 ,

CD . , C2

.

3

. , 24 DKA () ED. . I

780. H

.

.

ABG :

o H= 7.33

o C2= 25

o HC3=12

o

2= 89

:

H ,

C2 25 () .

.

, , .


8/

:

I, ,

.

I , H

. *

* L G , ,HD

ABG.

E .

.

I . L :

A ABG , , .

.

.

1. F, H. ( = 7.357.45)

2. I H < ( ) 7.35; .

3. I H > ( ) 7.45; .

(: H 7.40. , , H

7.357.39 . I H 7.417.45

.)

.

, .

1. L H .

2. I 7.357.45 () .

3. I H 7.45 .

.


9

,

.

( A:

. A

.)

1. F C2 HC3.

(: C2 = 3545. HC3 = 2226)

2. .

3. I C2 45 .

4. I HC3 26 .

.

1. H HC3 " " .2. B C2 " "H .

:

3. D H D HC3 = .

4. I H I HC3 = .

5. D H I C2 = .

6. I H D C2 = .

.

A. ABG :

H = 7.60 C2 = 30 HC3 = 22

1. ?(H H >7.45 .)

2. ?

(H H 7.357.45 .)

3. ?

(H C2


1

4. .

B. H = 7.31 C2 = 50 HC3 = 25

1. ?(H H 45 HC3 .)

5. .

C. H = 7.55 C2 = 40 HC3 = 30

1. ?

(H H >7.45 .)

2. ?

(H H .)

3. ?(H C2 HC3 >26 .)

4. .

D. H = 7.35 C2 = 45 HC3 = 21

1. ?

(H H


1

4.

simple method of acid base balance interpretation

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