single ended traveling wave based fault location using discrete wavelet transform
TRANSCRIPT
University of Kentucky University of Kentucky
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Theses and Dissertations--Electrical and Computer Engineering Electrical and Computer Engineering
2014
SINGLE ENDED TRAVELING WAVE BASED FAULT LOCATION SINGLE ENDED TRAVELING WAVE BASED FAULT LOCATION
USING DISCRETE WAVELET TRANSFORM USING DISCRETE WAVELET TRANSFORM
Jin Chang University of Kentucky, [email protected]
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Jin Chang, Student
Dr. Yuan Liao, Major Professor
Dr. Caicheng Lu, Director of Graduate Studies
SINGLE ENDED TRAVELING WAVE BASED FAULT LOCATION
USING DISCRETE WAVELET TRANSFORM
THESIS
A thesis submitted in partial fulfillment of the
requirements for the degree of Master of Science in Electrical Engineering
in the College of Engineering
at the University of Kentucky
By
Jin Chang
Lexington, Kentucky
Director: Dr. Yuan Liao, Professor of Electrical and Computer Engineering
Lexington, Kentucky
2014
Copyright © Jin Chang 2014
ABSTRACT OF THESIS
SINGLE ENDED TRAVELING WAVE BASED FAULT LOCATION USING
DISCRETE WAVELET TRANSFORM
In power transmission systems, locating faults is an essential technology. When a fault
occurs on a transmission line, it will affect the whole power system. To find the fault
location accurately and promptly is required to ensure the power supply. In this paper,
the study of traveling wave theory, fault location method, Karrenbauer transform, and
Wavelet transform is presented. This thesis focuses on single ended fault location
method. The signal processing technique and evaluation study are presented. The
MATLAB SimPowerSystem is used to test and simulate fault scenarios for evaluation
studies.
KEYWORDS: Fault Location, Traveling Wave, Single End, Karrenbauer Transform,
Discrete Wavelet Transform.
Jin Chang
Nov 17, 2014
SINGLE ENDED TRAVELING WAVE BASED FAULT LOCATION
USING DISCRETE WAVELET TRANSFORM
By
Jin Chang
Dr. Yuan Liao
Director of Thesis
Dr. Caicheng Lu
Director of Graduate Studies
Nov 17, 2014
Date
iii
ACKNOWLEDGEMENTS
I would like to express my special appreciation and thanks to my advisor Dr.
Yuan Liao, for his tremendous guidance. This thesis would not be finished without his
extensive knowledge and innovative ideas.
I would also like to thank Dr. Yuming Zhang, and Dr. Paul Dolloff, for
serving as my committee members, and for the invaluable comments and feedbacks
they gave.
Last but not least, I would like to express my deepest gratitude to my parents,
my wife and my baby daughter, for their endless love and support.
iv
TABLE OF CONTENTS
ACKNOWLEDGEMENTS ......................................................................................... iii
Table of Contents .......................................................................................................... iv
List of Table .................................................................................................................. vi
List of Figure.............................................................................................................. viii
Chapter 1 Introduction ............................................................................................... 1
1.1 Background of Fault Location ......................................................................... 1
1.2 Fault Location Methods ................................................................................... 2
1.3 Main Problems of Fault Location Method ....................................................... 3
Chapter 2 The Theory of Travelling Wave Fault Location Method .......................... 5
2.1 Process of Transient Traveling Wave on Transmission Line ........................... 5
2.2 Wave Reflection and Refraction ...................................................................... 8
2.3 Traveling Wave Method ................................................................................. 10
2.4 Karrenbauer Transformation .......................................................................... 13
2.4.1 The Module Velocity of Traveling Wave ........................................................... 15
2.4.2 The Classification of Fault Type ........................................................................ 16
2.5 Wavelet Transform ......................................................................................... 20
Chapter 3 single ended Traveling Wave Fault Location method ............................. 25
3.1 System Introduction ....................................................................................... 25
3.2 Signal Processing ........................................................................................... 26
3.3 Testing Wave Velocity and Sample Rate........................................................ 32
3.3.1 The Selection of Sample Rate ............................................................................ 32
v
3.3.2 The Selection of Wave Velocity ......................................................................... 34
Chapter 4 Evaluation study...................................................................................... 42
4.1 Fault Type ...................................................................................................... 42
4.1.1 One Line to Ground Fault .................................................................................. 42
4.1.2 Line to Line Fault............................................................................................... 50
4.1.3 Double Line to Ground Fault ............................................................................. 58
4.1.4 Three Line Fault ................................................................................................. 65
4.2 Fault Resistance ............................................................................................. 69
4.3 Transmission Line Length ............................................................................. 73
Chapter 5 Conclusion .............................................................................................. 75
References .................................................................................................................... 76
VITA ............................................................................................................................ 79
vi
LIST OF TABLE
Table 2.1 : Fault Type Occurrence and Severity .......................................................... 17
Table 2.2: Characteristic of Different Fault Types ....................................................... 20
Table 3.1: Different Sample Rate to Record Voltage Signals and Results of Evaluation
...................................................................................................................................... 33
Table 3.2: Different Sample Rate to Record Current Signals and Results of Evaluation
...................................................................................................................................... 34
Table 3.3: The Fault Location Result with Line-Modal Velocity V1 = 2.9188*105 km/s
...................................................................................................................................... 36
Table 3.4: The Calculation Result of Wave Velocity in Different Fault Locations ...... 39
Table 3.5: The Fault Location Result with Line-Modal Velocity V1 = 2.9050*105 km/s
...................................................................................................................................... 40
Table 4.1: Fault Location Result for One Line to Ground Fault .................................. 49
Table 4.2: Fault Location Result for the L-L Fault by Using the Voltage Signal ........ 56
Table 4.3: Fault Location Result for the L-L Fault by Using the Current Signal ........ 57
Table 4.4: Fault Location Result for Double Line to Ground Fault ............................. 64
Table 4.5: Fault Location Result for Three Line to Ground Fault ............................... 68
Table 4.6: The Result for the AG Fault with Different Resistances............................. 69
Table 4.7: The Result for the L-L Fault with Different Resistances ............................ 70
Table 4.8: The Result for the L-L-G Fault with Different Resistances ........................ 71
vii
Table 4.9: The Result for the Three Line to Ground Fault with Different Resistances72
Table 4.10: Fault Location Estimation for A 200 KM 500 KV Line ........................... 73
Table 4.11: Fault Location Estimation for A 300 KM 500 KV Line ........................... 74
viii
LIST OF FIGURE
Figure 2.1: Superposition Principle [7] .......................................................................... 6
Figure 2.2:Schematic Diagram for Traveling Wave of a Fault on Transmission Line 8
Figure 2.3: Schematic for Wave Reflection and Refraction [8] ..................................... 9
Figure 2.4: Lattice Diagram for One Line to Ground Fault ......................................... 12
Figure 2.5: Simplified Diagram of Different Fault Types............................................ 18
Figure 2.6: Discrete Wavelet Transform Decomposition ............................................. 22
Figure 2.7: The ‘db4’ Mother Wavelet ......................................................................... 23
Figure 3.1: Simulation System for Single Ended Traveling Wave Fault Location
Method ......................................................................................................................... 25
Figure 3.2: The Flow Chart of Signal Processing ........................................................ 27
Figure 3.3: Half Period Window of Voltage and Current Signal ................................. 28
Figure 3.4: Wavelet Transformation for Voltage Modal Signal ................................... 29
Figure 3.5: Wavelet Transformation for Current Modal Signal ................................... 30
Figure 3.6: The Wavelet Modulus Maxima for Voltage Signal ................................... 31
Figure 3.7: The Wavelet Modulus Maxima for Current Signal ................................... 32
Figure 3.8: Voltage Signal for a AG Fault at 35km from bus A .................................. 37
Figure 3.9: The Wavelet Modulus Maxima for Voltage Signal for Fault Location at 35
km ................................................................................................................................ 38
ix
Figure 4.1: Voltage and Current Signal for the AG Fault at 20 km ............................. 43
Figure 4.2: The Modulus Maxima of the Voltage Signal for the AG Fault at 20 km .. 44
Figure 4.3: The Modulus Maxima of the Current Signal for the AG Fault at 20 km .. 45
Figure 4.4: Voltage and Current Signal for the AG Fault at 70 km ............................. 46
Figure 4.5: The Modulus Maxima of the Voltage Signal for the AG Fault at 70 km .. 47
Figure 4.6: The Modulus Maxima of the Current Signal for the AG Fault at 70 km .. 48
Figure 4.7: Voltage and Current Signal for the L-L Fault at 40 km ............................. 50
Figure 4.8: The Modulus Maxima of the Voltage Signal for the L_L Fault at 40 km . 51
Figure 4.9: The Modulus Maxima of the Current Signal for the L_L Fault at 40 km . 52
Figure 4.10: Voltage and Current Signal for the L-L Fault at 60 km ........................... 53
Figure 4.11: The Modulus Maxima of the Voltage Signal for the L_L Fault at 60 km 54
Figure 4.12: The Modulus Maxima of the Current Signal for the L_L Fault at 60 km55
Figure 4.13: Voltage and Current Signal for the L-L-G Fault at 15 km ...................... 58
Figure 4.14: The Modulus Maxima of the Voltage Signal for the L-L-G Fault at 15 km
...................................................................................................................................... 59
Figure 4.15: The Modulus Maxima of the Current Signal for the L_L Fault at 15 km60
Figure 4.16: Voltage and Current Signal for the L-L-G Fault at 90 km ...................... 61
Figure 4.17: The Modulus Maxima of the Voltage Signal for the L-L-G Fault at 90 km
...................................................................................................................................... 62
Figure 4.18: The Modulus Maxima of the Current Signal for the L_L Fault at 15 km63
x
Figure 4.19: Voltage and Current Signal for the L-L-L-G Fault at 55 km ................... 65
Figure 4.20: The Modulus Maxima of the Voltage Signal for the LLL-G Fault at 55 km
...................................................................................................................................... 66
Figure 4.21: The Modulus Maxima of the Current Signal for the LLL-G Fault at 55 km
...................................................................................................................................... 67
CHAPTER 1 INTRODUCTION
1.1 Background of Fault Location
The power industry is an essential part of a country. Typically, there are three
parts of a power system: generation, transmission, and distribution. All of them are
indispensable for the entire power system. In recent years, the power system is
increasingly sophisticated. The transmission lines are longer and longer. The voltage
level on transmission line is also higher and higher. However, the faults of the
transmission lines are difficult to avoid. Those faults endanger the safety and the
reliability of the power system. The longer the power outages, the greater the damage
caused. Therefore, quickly pinpointing the fault location and restoring power supply
is required by all utilities. In order to fix the fault rapidly, finding the accurate location
of fault point is the key. Thus, the subject of fault location estimation for the
transmission line is especially interesting to electric engineers and utilities.
With the development of power system, the fault of the transmission line has been
more complex. In general, there are four different types of faults that occur on
transmission lines, such as single-phase to ground fault, line-to-line fault, double-line
to ground fault, and three-line fault. Generally, faults on transmission lines are caused
by lightning, storms, freezing rain, snow, insulation breakdown. In addition, external
objects such as tree branches and birds are factors that can cause short circuits [1]. In
the past, utilities had to send staff to seek the transmission line, which might need
2
several hours to find the location. Especially flashover transient faults are more
difficult to find. Thence, how to find the fault location promptly and accurately has
been a popular subject in the power industry for many years.
1.2 Fault Location Methods
Nowadays, fault location methods are developed in many different ways. The
keys of fault location methods are accuracy and reliability. Methods of locating faults
on a transmission line can be classified into two fundamental categories: techniques
based on power-frequency components, and the other utilizing the higher-frequency
components of the transient fault signals. The former one is using voltage and current
measured and necessary system parameters to calculate fault location. The fault
location methods with voltage and current measurements are proposed in [2] and [3].
Methods are based on impedance matrix that can establish the equations to govern the
relationship of the measurements and fault location are proposed in [4], [5] and [6].
The latter one is the traveling wave method. In this paper, the traveling wave method
is mainly discussed.
As a fast and accurate method, travelling wave method has been reported since
1931. According to the superposition principle, the forward and backward wave will
generate at the fault point after the fault occurs. The essential idea of traveling wave
method is based on the correlation between those forward and backward traveling
3
waves. The advantage of using the traveling wave method is that the power frequency
phenomena such as power swings and current transformer (CT) saturation, and
insensitivity to fault type, fault resistance, fault-inception angle, and source
parameters of the system can be avoided [1].
1.3 Main Problems of Fault Location Method
Using the impedance calculation method is much easier to implement than
traveling wave method. It is also much cheaper than the traveling wave method since
its hardware investment is low. Nevertheless, the accuracy of power-frequency
method can be affected by many factors such as transition resistance, nonlinear
voltage transformers, and asymmetrical transmission lines. The traveling wave
method uses transient signal, which is less affected by those factors. Thus, the error of
traveling wave method is much lower than impedance calculation method.
Since it is unaffected by fault resistance, transmission line types, and two-end
systems, traveling wave method is more reliable and accurate than impedance
calculation method. The main factors to the accuracy of travelling wave fault location
method are the propagation time and the velocity of the fault travelling wave. There
still are some problems for the traveling wave method. The first, to distinguish
between the traveling waves reflected from the fault point and from the remote end of
the line is a problem. The second, the uncertainty of the traveling wave can affect the
4
accuracy, such as the randomness of fault types and fault transition time. The third,
the velocity of traveling wave is affected by the different climates and environments.
The fourth, the sample rate of recording signals is also a significant factor which can
affect the accuracy of traveling wave method.
5
CHAPTER 2 THE THEORY OF TRAVELLING WAVE FAULT
LOCATION METHOD
The principle of the traveling wave method is based on the traveling high
frequency signals of voltage and current, which are recorded at end bus. In particular,
using arrived time difference between the initial and few subsequent wave peaks at
end bus and the velocity of the traveling wave calculates the distance of fault point.
2.1 Process of Transient Traveling Wave on Transmission Line
Assume there is a fault that occurs on a single phase transmission line of a two
end bus system. According to superimposed theory, there are two equal amplitude and
opposite direction voltage sources superimposed at fault point. The amplitude of those
two voltage sources is equal to the amplitude of the pre-fault voltage at fault point F.
The post fault network of a single phase transmission line power system can be regard
as a superimposed circuit of a pre-fault normal operation network and an additional
fault component network.
6
Figure 2.1: Superposition Principle [7]
(a): two end power system with a fault on single-phase transmission line (b): equivalent
circuit (c): pre-fault normal operation network (d): additional fault component network
Figure 2.1 presents the superposition principle. The figure 2.1 (a) is a one line
diagram of a two end bus power system with a fault on transmission line at the point F.
The figure 2.1 (b) is the equivalent circuit of figure 2.1 (a), the ef is equal to pre-fault
voltage at the fault point F. The figure 2.1 (c) is the pre-fault normal operation network.
The ef is equal to pre-fault voltage of point F. The figure 2.1(d) is the fault component
network. The –ef is equal in amplitude and opposite in direction of pre-fault voltage of
the fault point F. This figure only appears after fault.
When a fault occurs on the transmission line, the voltage and current transients will
travel towards end buses. According to the principle of reflection and refraction of the
traveling wave, these transient signals will continue to bounce back and forth between
the fault point and end buses [1]. The following equations are from Jan Izykowski,
A B
Ea E
b
F
A B
Ea
F
Eb
ef
-ef
A B
Ea
F
ef
Eb
A B
Za
F
-ef Z
b
(a)
(b)
(c)
(d)
7
Murari Mohan Saha and Rosolowski, Eugeniuszs’ book [1]. In single-phase lossless
transmission line, the voltage u and current i of the traveling wave at point x and time
t obey the partial differential equations:
t
iL
x
u (2-1)
t
uC
x
i
(2-2)
In equation (2-1) and (2-2): L and C are the inductance and capacitance of the line per
unit length.
The equation (2-1) and (2-2) can be deformed from partial differential by x and t:
t
uLC
x 2
2
2
2u
(2-3)
t
iCL
x
i2
2
2
2
(2-4)
Resistance is assumed to be negligible. The solutions of equation (2-3) and (2-4) are:
)(u)(t)u(x, vtxvtxu rf (2-5)
)(1
)(1
),( vtxuZ
vtxuZ
txi r
c
f
c
(2-6)
In equation (2-6): 𝑍𝑐 = √𝐿
𝐶 is the characteristic impedance of the transmission line,
v = √1
𝐿𝐶 is the velocity of propagation.
8
Figure 2.2:Schematic Diagram for Traveling Wave of a Fault on Transmission Line
Figure 2.2 represents the forward and the reverse waves, which leave the fault
point F and travel in opposite direction on transmission line toward to the end bus. In
equation (2-6), uf(x-vt) is the forward voltage traveling wave, and ur(x+vt) is the
reverse voltage traveling wave. The current traveling wave is similar to the voltage
traveling wave.
2.2 Wave Reflection and Refraction
When a fault occurs on the transmission line, there will be a forward and a backward
traveling wave towards two sides of transmission line. During this time, at the point of
wave impedance change, the traveling wave will reflect and transmit.
A B
F
uf ur
9
Figure 2.3: Schematic for Wave Reflection and Refraction [8]
In figure 2.3, η1 and η2 are wave impedance, e, r, t representing Incident, reflected,
and transmitted wave.
The following equations are from Yaozhong Ge’s book [9].
At point A:
ret
ret
iii
uuu
(2-7)
Meanwhile:
1
1
2
ee
rr
tt
iu
iu
iu
(2-8)
Solution of two formulas above:
2
Incident wave (e) Transmitted wave (t)
Reflected wave (r)
η1 A
η2
1
10
er
et
uu
uu
21
12
21
22
(2-9)
R is the reflection coefficient, T is the transmission coefficient, and 1 + R = T.
21
12R
(2-10)
21
22
T (2-11)
The relation between current reflection coefficient 𝑅𝑖 and voltage reflection
coefficient 𝑅𝑢 is:
Ri = -Ru (2-12)
2.3 Traveling Wave Method
Traveling wave method is divided into three modes [1]:
Single-ended mode: using traveling wave transients that produced by fault
point.
Double-ended mode: using traveling wave transients that produced by fault
point.
Single-ended mode: using pulse signal by devices after fault.
11
Single-ended mode uses traveling waves generated by fault, according to the first
two traveling waves which are recorded at end bus to determine the fault location.
Devices of this mode are only installed at one end of the line, and the communication
system is not required on the other buses. The single-ended mode demands simpler
devices than double-ended; however, this mode is subjected from transmitted wave
generated at the fault point and reflection waves from the other buses.
There are various methods to identify the reflected wave either from the fault
point or the remote end. One is based on wave polarity. The first reflected wave from
remote end has an opposite polarity of the first reflected wave from fault point. Thus,
the polarities of first and second reflected waves can be used to identify if the fault
point is located in first half or the second half of the transmission line. The other one
is based on impedance method. Single ended impedance method is used to estimate a
location in order to get a small range of fault location. Then, the range is used to
indicate if the reflected wave is from the fault point or from the remote end.
12
Figure 2.4: Lattice Diagram for One Line to Ground Fault
Figure 2.4 (a) shows a two bus transmission line system, which has a fault point
F1 on the first half of the line AB, and the second arrived wave is the reflected wave
from fault point. A traveling wave detector is placed at bus A. For the fault F1, the
time difference between the first two wave peaks will record as t2 – t1. Figure 2.4 (b)
A
B
F1
t1 t
2
(a)
A
B
F2
t1’ t
2’
(b)
13
shows the line with the fault F2, which occurs on the second half of the line AB, and
the second arrived wave is the reflected wave from remote end. A traveling wave
detector is still placed at bus A. For the fault F2, the time difference between the first
two wave peaks is t2’- t1’.
When the second arrived wave is the reflected wave from fault point, calculating
the distance ‘X’ between bus A and F1 uses the formula:
)(2
112 ttvX (2-13)
In equation (2-13): v is the wave velocity, which is close to velocity of light.
When the second arrived wave is the reflected wave from remote end, calculating
the distance ‘X’ between bus A and F2 uses the formula:
)''(2
112 ttvLX (2-14)
In equation (2-14): L is the length of transmission line.
2.4 Karrenbauer Transformation
Detailed description of the Karrenbauer transformation theory can be referred to
Yaozhong Ge’s book [8]. The equations in this section are from Ge’s book. In the three
phase lossless transmission line, the voltage and current equations:
14
t
it
it
i
LLL
LLL
LLL
x
ux
ux
u
c
b
a
smm
msm
mms
c
b
a
(2-15)
t
ut
ut
u
KKK
KKK
KKK
x
ix
ix
i
c
b
a
smm
msm
mms
c
b
a
(2-16)
In equation (2-15) and (2-16), Ls is the self-inductance, Lm is the mutual inductance,
Cs is the self-capacitance, Cm is the mutual capacitance, Ks=Cs+2Cm, Km=-Cm.
Because of electromagnetic coupling, the matrixes of L and C are not diagonal
matrixes. In addition, the LC and CL are also not diagonal matrixes. Thus, it is not
easy to calculate the traveling wave equations. In order to decouple the three phase
system, the phase domain signals need to be transformed into modal components.
mSUpU (2-17)
mp QII (2-18)
In equation (2-17) and (2-18), S and Q are modules transformation matrixes, Up and Ip
are phase values, Um and Im are modal values.
A well-known Karrenbauer phase-to-modal transformation matrix S is given:
211
121
111
S Q ,
101
011
111
3
1S 11- Q (2-19)
15
Using Karrenbauer transformation changes phase value to modals value:
c
b
a
u
u
u
u
u
u
101
011
111
3
1
(2-20)
c
b
a
i
i
i
i
i
i
101
011
111
3
1
(2-21)
Therefore,
u
u
u
U m
0
,
i
i
i
I m
0
(2-22)
In equation (2-22), the uα and the iα are α modal; the uβ and the iβ are β modal; the
uo and the i0 are 0 modal.
The α modal and the β modal are called “line-modal”, since the α modal
represents the “line-modal” between phase A and phase B, and the β modal represents
the “line-modal” between phase A and phase C. The 0 modal is called “zero-modal”.
2.4.1 The Module Velocity of Traveling Wave
The wave velocity is a significant component for traveling wave fault location
method. The accuracy of fault location is affected by the wave velocity. In commons,
the wave velocity is approximate the light speed, and it is smaller than the light speed.
16
Since the voltage and current signals are transformed from phase value to modal value,
the modal velocity should be used for calculating the fault locations.
The modal voltage and modal current equations [8] are:
t
ULCSS
x
U mm
2
21
2
2
(2-23)
t
ILCQQ
x
I mm
2
21
2
2
(2-24)
11
11
00
11
00
00
00
CL
CL
CL
LCQQLCSS (2-25)
Thus, the modal α and β have the same velocity V1, and zero modal velocity V0:
11
1
1
CLV (2-26)
00
0
1
CLV (2-27)
2.4.2 The Classification of Fault Type
In general, there are four types of fault commonly occurs on the transmission line.
The occurrence and the severity for each fault type are different. The table 2.1 is from
the paper [10].
17
Table 2.1 : Fault Type Occurrence and Severity
Type of Fault Symbol Occurrence (%) Severity
Line to Ground L – G 75-80 much less severe
Line to Line L – L 10 - 15 less severe
Double Line to
Ground 2L - G 5 - 10 severe
Three Line
(Ground) 3 - ϕ 2 - 5 very severe
Table2.1 shows the one line to ground fault is the most common fault type occurs
on the transmission line. The four fifths faults are one line to ground fault. The
occurrence of the three phase fault is small, but it is the most severe fault type.
Using the Karrenbauer transform can identify the fault types. The following
materials of this section are from Xinzhou, Dong’s paper [11]. The matrix of
Karrenbauer transform is a full-order matrix. In the matrix, the α-modal is the
line-modal between phase A and phase B; the β-modal is the line-modal between
phase A and phase C. For representing the line-modal between phase B and phase C,
the γ-modal is constructed in the matrix. Thus, the new Karrenbauer Transformation
matrix is:
18
c
b
a
110
101
011
111
3
1
0
(2-28)
Figure 2.5: Simplified Diagram of Different Fault Types
(a): one line to ground fault; (b): ling to line fault;
(c): double line to ground fault; (d): three line to ground fault.
1) One line to Ground Fault: The simplified diagram is shown in figure (a).
Assuming the grounding resistance is zero, the instantaneous boundary conditions
are:
0
0
A
CB
u
ii
(2-29)
Then the instantaneous modal components are:
A
B
C
(a)
A
B
C
(b)
A
B
C
(c)
A
B
C
(d)
19
0
3
1
0
A
A
A
i
i
i
i
i
i
i
(2-30)
2) Line to Line Fault: The simplified diagram (phase B to phase C) is shown in
figure (b). Assuming the grounding resistance is zero, the instantaneous boundary
conditions are:
CB
CB
A
uu
ii
i
0
(2-31)
Then the instantaneous modal components are:
B
B
B
i
i
i
i
i
i
i
2
0
3
1
0
(2-32)
3) Double Line Grounding Fault: The simplified diagram (phase B to phase C
grounding) is shown in figure (c). Assuming the grounding resistance is zero, the
instantaneous boundary conditions are:
0
0
CB
A
uu
i (2-33)
Then the instantaneous modal components are:
CB
C
B
CB
ii
i
i
ii
i
i
i
i
3
1
0
(2-34)
4) Three ling Grounding Fault: The simplified diagram is shown in figure (d).
Assuming the grounding resistance is zero, the instantaneous boundary conditions
are:
0
0
CBA
CBA
uuu
iii (2-35)
Then the instantaneous modal components are:
20
CB
CA
BA
ii
ii
ii
i
i
i
i 0
3
1
0
(2-36)
Table 2.2: Characteristic of Different Fault Types
0-modal α-modal β-modal γ-modal
AG iA iA iA 0
BG iB - iB 0 iB
CG iC 0 -iC -iC
AB 0 2 iA iA - iA
BC 0 - iB iB 2 iB
CA 0 -iC -2 iC -iC
ABG iA + iB iA - iB iA iB
BCG iB + iC - iB -iC iB - iC
CAG iA + iC iA iA – iC -iC
ABC(G) 0 iA - iB iA – iC iB – iC
*All modals shown above are multiplied by 3.
Table 3.2 represents the characteristics of various fault types in different situations.
2.5 Wavelet Transform
Wavelet transform is an effective mathematical method for transient traveling
wave. It has been widely used in faulted phase identification, traveling wave fault
location, and transformer protection [12]. By using Fourier transform, a sinusoid wave
21
is broken up into sine waves of various frequencies. Analogously, Wavelet transform
can break up a signal into shifted and scaled versions of the mother wavelet. However,
different from the Fourier transform, the wavelet transform allows time localization of
different frequency components of a signal. In other words, wavelets can adjust their
time-widths to their frequency. For example, the time-widths of the higher frequency
wavelets will be narrow, and the time-widths of the lower frequency wavelets will be
broader [13]. Since it applies to irregular, asymmetric, and oscillatory waveforms, the
wavelet transform is used in this paper as a mathematical tool for analyzing the
transient voltage and current traveling wave.
In the recent years, discrete wavelet transform (DWT) has been an attractive
signal processing tool. When a discrete signal is translated by discrete dyadic wavelet
transform, it will be decomposed into the approximation coefficients (A) and the
detail coefficients (D). In addition, the original signal also can be reconstructed by its
discrete wavelet approximations and discrete wavelet details as well [14]. By using
the discrete wavelet transform, the approximation coefficients are obtained by
convolving the original signal with the low-pass filter; the detail coefficients are
obtained by convolving the original signal with the high-pass filter.
The wavelet transform of sampled waveforms can be obtained by implementing
the discrete time wavelet transform. The equation of the discrete wavelet transform is
from [13].
22
m
m
m a
nakg
akm
0
0
n0
nx 1
),(DWT (2-37)
In equation (2-37), g [] is the mother wavelet; the ma0
represents scaling factors and
the ma0n represents time shifting factors.
Figure 2.6: Discrete Wavelet Transform Decomposition
In figure 2.6, S is the original signal; F is the output signal of the low-pass filter; G is
the output signal of the high-pass filter; the block after those two filters is down
sampling. This operation is keeping the even indexed elements.
There are many different types of mother wavelets, such as Harr, Daubichies (db),
Coiflet (coif) and Symmlet (sym) wavelets. To choose which type of mother wavelet
is significant for detecting and localizing different types of fault transients. The choice
also depends on a particular application. For short and fast transient disturbances, db4
High-pass filter
Low-pass filter 2
2
Approximation
Coefficients
(A1)
Detail
Coefficients
(D1)
S
F
G
23
and db6 are better [15]. Since the traveling wave is short and fast fault transient, the
db4 mother wavelet is used in this paper.
Figure 2.7: The ‘db4’ Mother Wavelet
Figure 2.7 shows the db4 mother wavelet. The figure is made by the display wavelets
of wavelet tool box of the MATLAB.
Based on the wavelet coefficients, the modulus maxima of a wavelet transform
contain the singularity information of a signal. The position where the modulus
maxima appear is the exact position where the peak of traveling wave occurs.
According to this principle, finding the traveling wave peaks converts into finding the
wavelet modulus maxima. In this paper, the DWT ‘db4’ is chosen as wavelet
24
transform. After the transformation, the wavelet modulus maxima of the detail
coefficient are found. Those modulus maxima are used as the peaks of the traveling
wave.
25
CHAPTER 3 SINGLE ENDED TRAVELING WAVE FAULT L
OCATION METHOD
3.1 System Introduction
In this paper, MATLAB® is chosen as the simulation programs. The following
system was constructed in SimPowerSystem™.
Figure 3.1: Simulation System for Single Ended Traveling Wave Fault Location
Method
26
System Parameters:
System Base Voltage: 500 KV
System Base Power: 100 MVA
System Frequency: 60 Hz
Source P Voltage: 500 KV
Source Q Voltage: 500 KV
Source P Positive Sequence Impedance: 17.177+j45.5285 Ω
Source P Zero Sequence Impedance: 2.5904+14.7328 Ω
Source Q Positive Sequence Impedance: 15.31+j45.9245 Ω
Source Q Zero Sequence Impedance: 0.7229+15.1288 Ω
Positive Sequence Line Resistance: 0.15573Ω/km
Zero Sequence Line Resistance: 0.37650625Ω/km
Positive Sequence Line Inductance: 9.7066e-4 H/km
Zero Sequence Line Inductance: 0.003 H/km
Positive Sequence Line Capacitance: 1.2093e-8F/km
Zero Sequence Line Capacitance: 7.4949e-9 F/km
Line Length: 100 km
3.2 Signal Processing
The voltage and current signal data are recorded by the simulation system. Those
data are phase values. In order to change the phase values to modal values, the
Karrenbauer Transformation is used. From the Karrenbauer Transformation, the 0, α,
and β modal values are calculated. Then, using the DWT, which is with the db4 mother
wave, translates those modal values into the approximation coefficients and detail
coefficients. Then, the points where the modulus maxima of detail coefficients appear
27
are the exact wave peak positions, so that the sample number of wave peaks are the
point positions of modulus maxima.
Figure 3.2: The Flow Chart of Signal Processing
Figure 3.2 shows all the steps of the signal processing of the single ended traveling
wave fault location method. Figure3.2 also presents the order and the function of each
step.
Assume there is one line to the ground fault that occurs at 30 km from bus A; the
fault transition time is from 0.041 s to 1 s; the fault and ground resistances are
negligible. From the simulation system, the three phase voltage and current signal are
recorded.
Recorded Voltage &Current Signals
Half Period Sample Window from Fault Point
DWT with db4
Karrenbauer Transformation
Sample Number for First and Second Peak
Calculation
Distance of Fault Location
28
Figure 3.3: Half Period Window of Voltage and Current Signal
Figure 3.3 represents the half period three phase voltage and current traveling
wave signals. The initial point is the point when the fault occurs. This figure shows
the results of the first and the second steps of the signal processing.
The third step of the signal processing is using Karrenbauer transformation to
translate the phase value to modal value. The fourth step is using the ‘db4’ DWT to
decompose the modal value into approximation coefficients and detail coefficients.
0 1000 2000 3000 4000 5000 6000 7000 8000 9000-2
-1
0
1
2
Points
Voltage (
pu)
0 1000 2000 3000 4000 5000 6000 7000 8000 9000-6
-4
-2
0
2
Points
Corr
ent
(pu)
29
Figure 3.4: Wavelet Transformation for Voltage Modal Signal
Figure 3.4 represents the signal processing of the voltage signal. The first plot
shows the α-modal signal for the voltage signal; the second plot shows the
approximation coefficients at level 1 from the wavelet transformation; the last plot
shows the detail coefficients at level 1 from the wavelet transformation. This figure
shows the results of the third and the fourth step of the signal processing.
0 1000 2000 3000 4000 5000 6000 7000 8000 9000-0.5
0
0.5
Points
V-m
ode
0 1000 2000 3000 4000 5000 6000 7000 8000 9000-0.5
0
0.5
Points
A1
0 1000 2000 3000 4000 5000 6000 7000 8000 9000-0.05
0
0.05
Points
D1
30
Figure 3.5: Wavelet Transformation for Current Modal Signal
Figure 3.5 represents the signal processing of the current signal. The first plot
shows the α-modal signal for the current signal; the second plot shows the
approximation coefficients at level 1 from the wavelet transformation; the last plot
shows the detail coefficients at level 1 from the wavelet transformation. This figure
shows the results of the third and the fourth step of the signal processing.
0 1000 2000 3000 4000 5000 6000 7000 8000 9000-2
0
2
Points
I-m
ode
0 1000 2000 3000 4000 5000 6000 7000 8000 9000-2
0
2
Points
A1
0 1000 2000 3000 4000 5000 6000 7000 8000 9000-5
0
5x 10
-5
Points
D1
31
The fifth step is finding the wavelet modulus maxima of the detail coefficients.
Therefore, the sample number of the first and second wave peaks are found.
Figure 3.6: The Wavelet Modulus Maxima for Voltage Signal
Figure 3.6 represents the wavelet modulus maxima for the voltage signals. This
figure shows the sample number for the first and second traveling wave peaks: the
initial wave peak number is 103, and the second wave peak number is 305. This
figure shows the result of the fifth step of signal processing.
0 50 100 150 200 250 300 350 400 450 5000
0.1
0.2
0.3
0.4
0.5
0.6
0.7
0.8
0.9
1
X: 103
Y: 0.9516
Points
Voltage (
pu)
X: 305
Y: 0.4233
32
Figure 3.7: The Wavelet Modulus Maxima for Current Signal
Figure 3.7 represents the wavelet modulus maxima for the current signals. This
figure shows the sample number for the first and second traveling wave peaks: the
initial wave peak number is 105 and the second wave peak number is 307. This figure
shows the result of the fifth step of signal processing.
3.3 Testing Wave Velocity and Sample Rate
3.3.1 The Selection of Sample Rate
The accuracy of traveling wave method is affected by the sampling rate. In general,
the frequency of the transient traveling wave is over hundreds of KHz. Therefore, to
0 50 100 150 200 250 300 350 400 450 5000
0.1
0.2
0.3
0.4
0.5
0.6
0.7
0.8
0.9
1
X: 307
Y: 0.3953
Points
Curr
ent
(pu)
X: 105
Y: 1
33
ensure the accuracy of fault locations, the sample rate is at least hundreds of KHz. In
order to find a high accuracy sample rate, the various sample rates are tested by the
simulation system in this paper.
Assume there is one line to the ground fault at 30 km from bus A, the fault
resistance is negligible and the velocity of the traveling wave is 2.9188*105 km/s. The
fault transition time is 0.041 s to 1 s. The following table shows the result of using
different sample rates to record voltage signals.
Table 3.1: Different Sample Rate to Record Voltage Signals and Results of Evaluation
Sample Rate
(KHz)
Second Peak
Point (p2)
First Peak
Point (p1)
Calculate Fault location
(km)
Error
(%)
245.760 78 29 29.10 0.90
491.520 157 53 30.88 0.88
983.040 307 105 29.99 0.01
1966.080 609 205 29.99 0.01
Table 3.1 represents the calculation results of fault locations by using voltage
signal. This table shows that the smallest error, which is 0.01%, is obtained when
sample rate are 983.040 KHZ and 1966.080 Hz.
34
Table 3.2: Different Sample Rate to Record Current Signals and Results of Evaluation
Sample Rate
(KHz)
Second Peak
Point (p2)
First Peak
Point (p1)
Calculate Fault location
(km)
Error
(%)
245.760 78 29 29.10 0.90
491.520 154 55 29.39 0.61
983.040 305 103 29.99 0.01
1966.080 611 204 30.21 0.21
Table 3.2 represents the calculation results of fault locations by using the current
signals. This table shows the smallest error, which is 0.01%, is obtained when sample
rate is 983.040 KHz.
Table 3.1 and 3.2 shows the smallest error is 0.01% when the sample rate is
983.040 KHz for both voltage and current signals. Thus, the 983.040 KHz is selected
as the sample rate for the simulation system in this paper.
3.3.2 The Selection of Wave Velocity
The modal α and β have the same velocity V1, which is called line-modal velocity,
and zero module velocity is V0, which is called zero-modal velocity. In the section 3.1,
the equations (2-26) and (2-27) are given:
11
1
1
CLV
00
0
1
CLV
35
The traveling wave velocity can be calculated by system parameters. From section
5.1: the positive sequence line inductance L1 is 9.7066e-4 h/km; zero sequence line
inductance L0 is 0.003 h/km; the positive sequence line capacitance C1 is
1.2093e-8f/km; and the zero sequence line capacitance C0 is 7.4949e-9 f/km. Thus,
the wave velocity of α and 0 modules:
skm /101089.2 50
skm /109188.2 5
According to V. Kale, S. Bhide and P. Bedekars’ paper [16], the wave impedance
of the 0-modal component is large, so the velocity of the 0-modal is smaller than the
line-modal velocity. In addition, the 0-modal component is significant only when the
fault is a grounding fault. Therefore, the 0-modal signal cannot be used for all types of
faults. The velocity of line-modal is close to light speed because its wave impedance
is small and it is not affected by frequency and other conditions. Thus, the line-modal
velocity V1=2.9188*105 km/s is selected as the traveling wave velocity in this paper.
Assume there is one line to ground fault on transmission line, the fault transition
time is 0.041 s to 1 s, and the fault resistance is negligible. By using the voltage
transient signal and the V1 = 2.9188*105 km/s, the following table shows the result of
single ended traveling wave fault location method.
36
Table 3.3: The Fault Location Result with Line-Modal Velocity V1 = 2.9188*105 km/s
Table 3.3 represents the result of traveling wave fault location method by using
line-modal velocity.
In this paper, a method, which is utilize historical data, is provided to calculate
traveling velocity.
Actual Fault
Location (km)
Second Peak
Point (p2)
First Peak
Point (p1)
V1=2.9188*105km/s
Calculation
Fault
Location (km)
Error (%)
5 54 19 5.20 0.20
10 105 37 10.10 0.10
15 155 53 15.14 0.14
20 204 69 20.04 0.04
25 255 87 24.94 0.06
30 305 103 29.99 0.01
35 357 121 35.04 0.04
40 409 137 40.38 0.38
45 459 155 45.13 0.13
50 506 171 49.73 0.27
55 490 187 55.02 0.02
60 475 205 59.92 0.08
65 458 221 64.82 0.18
70 441 239 70.01 0.01
75 425 255 74.76 0.24
80 406 273 80.26 0.26
85 389 289 85.15 0.15
90 374 305 89.76 0.24
95 357 323 94.95 0.05
Average Error 0.14%
37
Assume there is one line to ground fault occurs 35 km from Bus A, the fault
transition time is 0.041 s to 1 s, and the fault resistance is negligible. The wave velocity
can be found by the following steps:
Step 1: using the system to simulate the fault location, thus, the voltage traveling wave
signals are recorded.
Figure 3.8: Voltage Signal for a AG Fault at 35km from bus A
Figure 3.8 shows the voltage waveforms represent half of a cycle following the
inception of the fault which is 35 km from Bus A.
0 1000 2000 3000 4000 5000 6000 7000 8000 9000-1.5
-1
-0.5
0
0.5
1
1.5
Points
Voltage (
pu)
38
Step 2: using the Karrenbauer transformation and the wavelet transform to get the time
difference between the arriving time of the initial wave and the arriving time of the
reflect wave from the fault point.
Figure 3.9: The Wavelet Modulus Maxima for Voltage Signal for Fault Location at 35
km
Figure 3.9 shows the wavelet modulus maxima focused view on the first 200 points.
This figure shows the sample number of the initial wave peak (p1) is 121, and the
sample number of the second wave peak (p2) is 357.
Step 3: Calculation
The sample time is 983040
1 s and the x = 35 km.
0 50 100 150 200 250 300 350 4000
0.1
0.2
0.3
0.4
0.5
0.6
0.7
0.8
0.9
1
X: 121
Y: 1
Points
Voltage (
pu)
X: 357
Y: 0.3866
39
t
xv
2 (3-1)
12 ppt (3-2)
The solution of (3-1) and (3-2) is:
skmv 5109158.2
121357
983040352
Table 3.4: The Calculation Result of Wave Velocity in Different Fault Locations
Fault Location
(km)
Wave Velocity
(105km/s)
Fault Location
(km)
Wave Velocity
(105km/s)
5 2.8087 55 2.9199
10 2.8913 60 2.9127
15 2.8913 65 2.9035
20 2.9127 70 2.9199
25 2.9257 75 2.8913
30 2.9199 80 2.9565
35 2.9158 85 2.9491
40 2.8913 90 2.8494
45 2.9103 95 2.8913
50 2.9344 Average Velocity 2.9050
Table 3.4 shows the calculation results for traveling wave velocity with various
fault locations. Assume the fault locations are known, using equation (3-1) and (3-2) to
calculate the wave velocity. This table shows the average of all traveling wave
velocities is 2.9050*105 km/s.
40
As a result, the traveling wave velocity is v= 2.9050*105 km/s. Assume there is one
line to ground fault on transmission line, the fault transition time is 0.041 s to 1 s, and
the fault resistance is negligible.
Table 3.5: The Fault Location Result with Line-Modal Velocity V1 = 2.9050*105 km/s
Actual Fault
Location (km)
Second Peak
Point (p2)
First Peak
Point (p1)
V=2.9050*105 km/s
Calculation Fault
Location (km)
Error (%)
5 54 19 5.17 0.17
10 105 37 10.05 0.05
15 155 53 15.07 0.07
20 204 69 19.95 0.05
25 255 87 24.82 0.18
30 305 103 29.85 0.15
35 357 121 34.87 0.13
40 409 137 40.19 0.19
45 459 155 44.92 0.08
50 506 171 49.50 0.50
55 490 187 55.23 0.23
60 475 205 60.11 0.11
65 458 221 64.98 0.02
70 441 239 70.15 0.15
75 425 255 74.88 0.12
80 406 273 80.35 0.35
85 389 289 85.22 0.22
90 374 305 89.80 0.20
95 357 323 94.98 0.02
Average Error 0.16%
41
Table 3.5 represents the result of traveling wave fault location method by using the
traveling wave velocity v= 2.9050*105 km/s. This table shows the average error is
0.16%, which is close to the average error by using the line-modal velocity v=
2.9188*105 km/s.
42
CHAPTER 4 EVALUATION STUDY
In this chapter, all kinds of faults are estimated to test the performance of the single
ended traveling wave fault location method. Those faults can be divided into three
aspects. The first aspect is fault type. In this section, four different fault types are
simulated. The second aspect is fault resistance. In this section, various fault resistances
are simulated with different fault types. The third aspect is the length of transmission
line. In this section, the 200 and 300 KM transmission lines are respectively simulated.
4.1 Fault Type
From section 3.2, the fault type can be classified. The single ended traveling wave
fault location method works for all fault types. The length of the transmission line in
this simulation system is 100 km. when the fault point is at 50 km from bus A, the first
peak point is 171 and the second peak point is 506. The initial point is captured when a
fault occurs. In this simulation system, when the first peak point is over than 171 and
second peak point is less than 506, the second wave is the reflected wave from the
remote end bus. Otherwise, the second peak is the reflected wave from fault point.
4.1.1 One Line to Ground Fault
Assume there is one line to ground fault that occurs 20 km from Bus A, the fault
transition time is from 0.041 s to 1 s, and the fault and ground resistance is negligible.
43
Figure 4.1: Voltage and Current Signal for the AG Fault at 20 km
The figure 4.1 shows the three-phase voltage and current signal which are recorded
by the simulation system. In this figure, the voltage and current waveforms represent
half of a cycle following the inception of fault, which is at 20 km from Bus A.
According to the signal processing section, those voltage and current phase values
are transformed to modal values by Karrenbauer transformation. Then, the α-modal
values of voltage and current are translated by DWT ‘db4’. In the end, the wavelet
modulus maxima are found from the detail coefficients.
0 1000 2000 3000 4000 5000 6000 7000 8000 9000-2
-1
0
1
2
Points
Voltage (
pu)
0 1000 2000 3000 4000 5000 6000 7000 8000 9000-10
-5
0
5
Points
Corr
ent
(pu)
44
By using the voltage signal data:
Figure 4.2: The Modulus Maxima of the Voltage Signal for the AG Fault at 20 km
Figure 4.2 shows the wavelet modulus maxima for voltage signal. This figure
shows the initial wave peak of voltage signal is p1 = 69 and the second wave peak of
voltage signal is p2 = 204, so the second peak is the reflected wave from fault point.
Therefore, the following equation is used to estimate the fault location.
kmvx 04.20692042
1
%04.0%100100
2004.20
error
0 50 100 150 200 250 3000
0.1
0.2
0.3
0.4
0.5
0.6
0.7
0.8
0.9
1
X: 69
Y: 1
Points
Voltage (
pu) X: 204
Y: 0.5089
45
By using the current signal data:
Figure 4.3: The Modulus Maxima of the Current Signal for the AG Fault at 20 km
Figure 4.3 shows the wavelet modulus maxima for current signal. This figure
shows the initial wave peak of current signal is the initial wave peak of current signal is
p1’ = 71 and the second wave peak of voltage signal is p2’ = 204.
kmvx 74.19712042
1
%26.0%100100
2074.19
error
0 50 100 150 200 250 3000
0.1
0.2
0.3
0.4
0.5
0.6
0.7
0.8
0.9
1
X: 71
Y: 1
Points
Curr
ent
(pu)
X: 204
Y: 0.2105
46
Assume there is one line to ground fault that occurs 70 km from Bus A,the fault
transition time is from 0.041 s to 1 s, and the fault and ground resistances are negligible.
Figure 4.4: Voltage and Current Signal for the AG Fault at 70 km
Figure 4.4 shows the three phases voltage and current signal which are recorded by
the simulation system. In this figure, the voltage and current waveforms represent half
of a cycle following the inception of fault, which is at 70 km from Bus A.
From the signal processing, the modulus maxima are obtained from the voltage and
the current signals.
0 1000 2000 3000 4000 5000 6000 7000 8000 9000-2
-1
0
1
2
Points
Voltage (
pu)
0 1000 2000 3000 4000 5000 6000 7000 8000 9000-6
-4
-2
0
2
Points
Corr
ent
(pu)
47
By using the voltage signal:
Figure 4.5: The Modulus Maxima of the Voltage Signal for the AG Fault at 70 km
Figure 4.5 shows the wavelet modulus maxima for voltage signal. In this figure, the
initial wave peak of voltage signal is p1 = 239 which is over 171, and the second wave
peak of voltage signal is p2 = 441 which is less than 506, so the second peak is the
reflected wave from remote end. Therefore, the following equation is used to estimate
the fault location.
kmvLx 01.702394412
1
%01.0%100100
7001.70
error
0 50 100 150 200 250 300 350 400 450 5000
0.1
0.2
0.3
0.4
0.5
0.6
0.7
0.8
0.9
1
X: 239
Y: 1
Points
Voltage (
pu)
X: 441
Y: 0.3572
48
By using the current signal:
Figure 4.6: The Modulus Maxima of the Current Signal for the AG Fault at 70 km
Figure 4.6 shows the wavelet modulus maxima for current signal. In this figure, the
initial wave peak of current signal is p1’ = 239 and the second wave peak of voltage
signal is p2’ = 441.
kmvLx 01.702394412
1
%01.0%100100
7001.70
error
0 50 100 150 200 250 300 350 400 450 5000
0.05
0.1
0.15
0.2
0.25
0.3
0.35
0.4
X: 239
Y: 0.3569
Points
Curr
ent
(pu)
X: 441
Y: 0.3366
49
Table 4.1: Fault Location Result for One Line to Ground Fault
Fault Location
(km)
Voltage Signal Current Signal
Estimation
(km)
Error (%) Estimation
(km)
Error (%)
5 5.20 0.20 4.60 0.40
10 10.10 0.10 10.10 0.10
15 15.14 0.14 15.29 0.29
20 20.04 0.04 19.74 0.26
25 24.94 0.06 25.24 0.24
30 29.99 0.01 29.99 0.01
35 35.04 0.04 34.89 0.11
40 40.38 0.38 40.08 0.08
45 45.13 0.13 44.69 0.31
50 49.73 0.27 50.18 0.18
55 55.02 0.02 55.31 0.31
60 59.92 0.08 59.62 0.38
65 64.82 0.18 64.96 0.04
70 70.01 0.01 70.01 0.01
75 74.76 0.24 74.61 0.39
80 80.26 0.26 80.26 0.26
85 85.15 0.15 84.86 0.14
90 89.76 0.24 89.90 0.10
95 94.95 0.05 94.80 0.20
Table 4.1 represents the estimations and errors of traveling wave fault location
method by using both voltage and current signal. In this table, all the errors of the
estimated fault locations are below 1%. This table shows that the error is large
50
compared to the others when the fault point is close to the end buses and the middle
point of the transmission line.
4.1.2 Line to Line Fault
Assume there is line-to-line fault that occurs 40 km from Bus A, the fault transition
time is from 0.041 s to 1 s, and the fault resistance is negligible.
Figure 4.7: Voltage and Current Signal for the L-L Fault at 40 km
Figure 4.7 represents the three-phase voltage and current signal for the L-L fault
which is at 40 km from Bus A. In this figure, the voltage and current waveforms
represent half of a cycle following the inception of fault.
0 1000 2000 3000 4000 5000 6000 7000 8000 9000-1
0
1
2
Points
Voltage (
pu)
0 1000 2000 3000 4000 5000 6000 7000 8000 9000-5
0
5
Points
Corr
ent
(pu)
51
After the signal processing, the wavelet modulus maxima for this fault will be
found.
By using the voltage signal data:
Figure 4.8: The Modulus Maxima of the Voltage Signal for the L_L Fault at 40 km
Figure 4.8 shows the wavelet modulus maxima of voltage signal for the L-L fault
which is at 40 km from bus A. In this figure, the initial wave peak of voltage signal is p1
= 137 which is less than 171 and the second wave peak of voltage signal is p2 = 409, so
the second peak is the reflected wave from fault point. Therefore, the following
equation is used to estimate the fault location.
kmvx 38.401374092
1
0 50 100 150 200 250 300 350 400 450 5000
0.1
0.2
0.3
0.4
0.5
0.6
0.7
0.8
0.9
1
X: 137
Y: 1
Points
Voltage (
pu)
X: 409
Y: 0.6784
52
%38.0%100100
4038.40
error
By using the current signal data:
Figure 4.9: The Modulus Maxima of the Current Signal for the L_L Fault at 40 km
Figure 4.9 shows the wavelet modulus maxima of current signal for the L-L
fault which is at 40 km from bus A. In this figure, the initial wave peak of current signal
is p1’ = 136 and the second wave peak of voltage signal is p2’ = 406.
kmvx 06.401364062
1
%06.0%100100
4006.40
error
0 50 100 150 200 250 300 350 400 450 5000
0.05
0.1
0.15
0.2
0.25
0.3
0.35
0.4
0.45
0.5
X: 136
Y: 0.4993
Points
Curr
ent
(pu)
X: 406
Y: 0.4544
53
Assume there is a line-to-line fault that occurs at 60 km from Bus A, the fault
transition time is from 0.041 s to 1 s, and the fault resistance is negligible.
Figure 4.10: Voltage and Current Signal for the L-L Fault at 60 km
The figure 4.10 represents the three-phase voltage and current signal for the L-L
fault which is at 60 km from Bus A. In this figure, the voltage and current waveforms
represent half of a cycle following the inception of fault.
After the signal processing, the wavelet modulus maxima for this fault will be
found. Different from the AG fault, the second wave of the L-L fault, which is recorded
at the end bus, is the reflected wave from the fault point when the fault point is in the
second half of the transmission line.
0 1000 2000 3000 4000 5000 6000 7000 8000 9000-1
-0.5
0
0.5
1
1.5
Points
Voltage (
pu)
0 1000 2000 3000 4000 5000 6000 7000 8000 9000-4
-2
0
2
4
Points
Corr
ent
(pu)
54
By using the voltage signal data:
Figure 4.11: The Modulus Maxima of the Voltage Signal for the L_L Fault at 60 km
Figure 4.11 shows the wavelet modulus maxima of voltage signal for the L-L fault
which is at 40 km from bus A. In this figure, the initial wave peak of voltage signal is p1
= 205 which is over 171, and the second wave peak of voltage signal is p2 = 609 which
is over 506. In this situation, the second wave is not a wave reflection from remote end,
but a wave reflection from fault point.
kmvx 98.592056092
1
%02.0%100100
60-98.59error
0 100 200 300 400 500 600 7000
0.1
0.2
0.3
0.4
0.5
0.6
0.7
0.8
0.9
1
X: 205Y: 1
Points
Voltage (
pu)
X: 609Y: 0.7251
55
By using the current signal data:
Figure 4.12: The Modulus Maxima of the Current Signal for the L_L Fault at 60 km
Figure 4.12 shows the wavelet modulus maxima of current signal for the L-L fault
which is at 60 km from bus A. In this figure, the initial wave peak of current signal is p1’
= 204 and the second wave peak of voltage signal is p2’ = 608.
kmvx 98.592046082
1
%02.0%100100
60-98.59error
0 100 200 300 400 500 600 7000
0.1
0.2
0.3
0.4
0.5
0.6
0.7
X: 204Y: 0.4142
Points
Curr
ent
(pu)
X: 608Y: 0.5678
56
Table 4.2: Fault Location Result for the L-L Fault by Using the Voltage Signal
Actual Fault
Location (km)
Second Peak
Point (p2)
First Peak
Point (p1)
Estimation
(km)
Error
(%)
5 54 19 5.20 0.20
10 105 37 10.10 0.10
15 155 53 15.14 0.14
20 204 69 20.04 0.04
25 255 87 24.94 0.06
30 305 103 29.99 0.01
35 357 121 35.04 0.04
40 409 137 40.38 0.38
45 459 155 45.13 0.13
50 506 171 49.73 0.27
55 558 187 55.08 0.08
60 609 205 59.98 0.02
65 660 221 65.17 0.17
70 711 239 70.07 0.07
75 761 255 75.12 0.12
80 810 273 79.72 0.28
85 861 289 84.92 0.08
90 911 305 89.97 0.03
95 963 323 95.01 0.01
Table 4.2 shows the result of line to line fault by using the voltage signal. In this
table, the error is large when the fault point is close to end buses.
57
Table 4.3: Fault Location Result for the L-L Fault by Using the Current Signal
Actual Fault
Location (km)
Second Peak
Point (p2)
First Peak
Point (p1)
Estimation
(km)
Error
(%)
5 52 21 4.60 0.40
10 105 37 10.10 0.10
15 155 52 15.29 0.29
20 204 71 19.74 0.26
25 257 87 25.24 0.24
30 307 105 29.99 0.01
35 357 122 34.89 0.11
40 406 136 40.08 0.08
45 456 155 44.69 0.31
50 509 171 50.18 0.18
55 558 189 54.78 0.22
60 608 204 59.98 0.02
65 661 223 65.02 0.02
70 711 239 70.07 0.07
75 761 254 75.27 0.27
80 810 273 79.72 0.28
85 863 289 85.21 0.21
90 913 307 89.97 0.03
95 964 322 95.31 0.31
Table 4.3 shows the result of line to line fault by using the current signal. In this
table, the error is large when the fault point is close to end buses.
58
4.1.3 Double Line to Ground Fault
Assume there is a double line to ground fault that occurs at 15 km from Bus A, the
fault transition time is from 0.041 s to 1 s, and the fault resistance is negligible.
Figure 4.13: Voltage and Current Signal for the L-L-G Fault at 15 km
Figure 4.13 represents the three-phase voltage and current signal for the L-L-G
fault which is at 15 km from Bus A. In this figure, the voltage and current waveforms
represent half of a cycle following the inception of fault.
After the signal processing, the wavelet modulus maxima for this L-L-G fault will
be plotted.
0 1000 2000 3000 4000 5000 6000 7000 8000 9000-2
-1
0
1
2
Points
Voltage (
pu)
0 1000 2000 3000 4000 5000 6000 7000 8000 9000-10
-5
0
5
10
Points
Corr
ent
(pu)
59
By using the voltage signal data:
Figure 4.14: The Modulus Maxima of the Voltage Signal for the L-L-G Fault at 15 km
Figure 4.14 shows the wavelet modulus maxima of voltage signal for the L-L-G
fault which is at 15 km from bus A. In this figure, the initial wave peak of voltage signal
is p1 = 53 and the second wave peak of voltage signal is p2 =155, so the second peak is
the reflected wave from fault point. Therefore, the following equation is used to
estimate the fault location.
kmvx 14.15531552
1
%14.0%100100
1514.15
error
0 20 40 60 80 100 120 140 160 180 2000
0.1
0.2
0.3
0.4
0.5
0.6
0.7
0.8
0.9
1
X: 53Y: 1
Points
Voltage (
pu)
X: 155Y: 0.8189
60
By using the current signal data:
Figure 4.15: The Modulus Maxima of the Current Signal for the L_L Fault at 15 km
Figure 4.15 shows the wavelet modulus maxima of current signal for the L-L-G
fault which is at 15 km from bus A. In this figure, the initial wave peak of current signal
is p1’ = 52 and the second wave peak of voltage signal is p2’ = 155.
kmvx 29.15521552
1
%29.0%100100
1529.15
error
Assume there is a line-to-line to ground fault that occurs 90 km from Bus A, the
fault transition time is from 0.041 s to 1 s, and the fault resistance is negligible.
0 20 40 60 80 100 120 140 160 180 2000
0.1
0.2
0.3
0.4
0.5
0.6
0.7
0.8
0.9
X: 52Y: 0.8076
Points
Curr
ent
(pu)
X: 155Y: 0.6424
61
Figure 4.16: Voltage and Current Signal for the L-L-G Fault at 90 km
Figure 4.16 represents the three-phase voltage and current signal for the L-L-G
fault which is at 15 km from Bus A. In this figure, the voltage and current waveforms
represent half of a cycle following the inception of fault.
After the signal processing, the wavelet modulus maxima for this L-L-G fault will
be plotted.
0 1000 2000 3000 4000 5000 6000 7000 8000 9000-2
-1
0
1
2
Points
Voltage (
pu)
0 1000 2000 3000 4000 5000 6000 7000 8000 9000-4
-2
0
2
4
Points
Corr
ent
(pu)
62
By using the voltage signal data:
Figure 4.17: The Modulus Maxima of the Voltage Signal for the L-L-G Fault at 90 km
Figure 4.17 shows the wavelet modulus maxima of voltage signal for the L-L-G
fault which is at 15 km from bus A. In this figure, the initial wave peak of voltage signal
is p1 = 305 which is over 171, and the second wave peak of voltage signal is p2 = 913
which is over 506, so the second peak is the reflected wave from fault point. Therefore,
the following equation is used to estimate the fault location.
kmvx 26.903059132
1
%26.0%100100
9026.90
error
0 100 200 300 400 500 600 700 800 900 10000
0.1
0.2
0.3
0.4
0.5
0.6
0.7
0.8
X: 305Y: 0.6928
Points
Voltage (
pu)
X: 913Y: 0.7308
63
By using the current signal data:
Figure 4.18: The Modulus Maxima of the Current Signal for the L_L Fault at 15 km
Figure 4.18 shows the wavelet modulus maxima of current signal for the L-L-G
fault which is at 15 km from bus A. In this figure, the initial wave peak of current signal
is p1’ = 307 and the second wave peak of voltage signal is p2’ = 913.
kmvx 97.893079132
1
%03.0%100100
9097.89
error
0 100 200 300 400 500 600 700 800 900 10000
0.1
0.2
0.3
0.4
0.5
0.6
0.7
0.8
X: 307Y: 0.7371
Points
Curr
ent
(pu)
X: 913Y: 0.7219
64
Table 4.4: Fault Location Result for Double Line to Ground Fault
Fault Location
(km)
Voltage Signal Current Signal
Estimation
(km)
Error (%) Estimation
(km)
Error (%)
5 5.20 0.20 4.60 0.40
10 10.10 0.10 10.10 0.10
15 15.14 0.14 15.29 0.29
20 20.04 0.04 19.74 0.26
25 24.94 0.06 25.24 0.24
30 29.99 0.01 29.99 0.01
35 35.04 0.04 34.89 0.11
40 40.38 0.38 40.08 0.08
45 45.13 0.13 44.69 0.31
50 49.73 0.27 50.18 0.18
55 55.08 0.08 54.78 0.22
60 59.98 0.02 59.98 0.02
65 65.17 0.17 65.02 0.02
70 70.07 0.07 70.07 0.07
75 75.12 0.12 75.27 0.27
80 79.72 0.28 79.72 0.28
85 84.92 0.08 85.21 0.21
90 90.26 0.26 89.97 0.03
95 95.01 0.01 95.31 0.31
Table 4.4 shows the result of double line to ground fault by using voltage and current
signal. This table is same as the result table of the line to line fault.
65
4.1.4 Three Line Fault
Assume there is a three line to ground fault that occurs at 55 km from Bus A, the
fault transition time is from 0.041 s to 1 s, and the fault resistance is negligible.
Figure 4.19: Voltage and Current Signal for the L-L-L-G Fault at 55 km
Figure 4.19 represents the three-phase voltage and current signal for the three line
to ground fault which is at 55 km from Bus A. In this figure, the voltage and current
waveforms represent half of a cycle following the inception of fault.
After the signal processing, the wavelet modulus maxima for this fault will be
plotted.
0 1000 2000 3000 4000 5000 6000 7000 8000 9000-4
-2
0
2
Points
Voltage (
pu)
0 1000 2000 3000 4000 5000 6000 7000 8000 9000-5
0
5
Points
Corr
ent
(pu)
66
By using the voltage signal data:
Figure 4.20: The Modulus Maxima of the Voltage Signal for the LLL-G Fault at 55 km
Figure 4.20 shows the wavelet modulus maxima of voltage signal for the three line
to ground fault which is at 55 km from bus A. In this figure, the initial wave peak of
voltage signal is p1 = 187 which is over 171 and the second wave peak of voltage signal
is p2 = 558 which is over 506, so the second peak is the reflected wave from fault point.
Therefore, the following equation is used to estimate the fault location.
kmvx 08.551875582
1
%08.0%100100
5508.55
error
0 100 200 300 400 500 600 700 800 9000
0.1
0.2
0.3
0.4
0.5
0.6
0.7
0.8
0.9
1
X: 187
Y: 0.7141
Points
Voltage (
pu)
X: 558
Y: 1
67
By using the current signal data:
Figure 4.21: The Modulus Maxima of the Current Signal for the LLL-G Fault at 55 km
Figure 4.21 shows the wavelet modulus maxima of current signal for the three line
to ground fault which is at 55 km from bus A. In this figure, the initial wave peak of
current signal is p1’ = 189 and the second wave peak of voltage signal is p2’ = 558.
kmvx 78.541895582
1
%22.0%100100
5578.54
error
0 100 200 300 400 500 600 700 800 9000
0.1
0.2
0.3
0.4
0.5
0.6
0.7
0.8
0.9
1
X: 189
Y: 1
Points
Curr
ent
(pu)
X: 558
Y: 0.3566
68
Table 4.5: Fault Location Result for Three Line to Ground Fault
Fault Location
(km)
Voltage Signal Current Signal
Estimation
(km)
Error (%) Estimation
(km)
Error (%)
5 5.20 0.20 4.60 0.40
10 10.10 0.10 10.10 0.10
15 15.14 0.14 15.29 0.29
20 20.04 0.04 19.74 0.26
25 24.94 0.06 25.24 0.24
30 29.99 0.01 29.99 0.01
35 35.04 0.04 34.89 0.11
40 40.38 0.38 40.08 0.08
45 45.13 0.13 44.69 0.31
50 49.73 0.27 50.18 0.18
55 55.08 0.08 54.78 0.22
60 59.98 0.02 59.98 0.02
65 65.17 0.17 65.02 0.02
70 70.07 0.07 70.07 0.07
75 75.12 0.12 75.27 0.27
80 79.72 0.28 79.72 0.28
85 84.92 0.08 85.21 0.21
90 90.26 0.26 89.97 0.03
95 95.01 0.01 95.31 0.31
Table 4.5 shows the result of three line to ground fault by using the voltage and
current signal.
69
4.2 Fault Resistance
In this part, the fault resistances and ground resistances are added to test the
accuracy of single ended traveling wave fault location method.
Table 4.6: The Result for the AG Fault with Different Resistances
Fault
Resistance
(Ω)
Actual Fault
Location
(km)
Voltage Signal Current Signal
Estimated
Fault
Location
(km)
Error (%)
Estimated
Fault
Location
(km)
Error (%)
1
5 5.20 0.20 4.60 0.40
30 29.99 0.01 29.99 0.01
50 49.73 0.27 50.18 0.18
70 70.01 0.01 70.01 0.01
95 94.95 0.05 94.80 0.20
10
5 5.20 0.20 4.60 0.40
30 29.99 0.01 29.99 0.01
50 49.73 0.27 50.18 0.18
70 70.01 0.01 70.01 0.01
95 94.95 0.05 94.80 0.20
50
5 5.20 0.20 4.60 0.40
30 29.99 0.01 29.99 0.01
50 49.73 0.27 50.18 0.18
70 70.01 0.01 70.01 0.01
95 94.95 0.05 94.80 0.20
100
5 5.20 0.20 4.60 0.40
30 29.99 0.01 29.99 0.01
50 49.73 0.27 50.18 0.18
70
70 70.01 0.01 70.01 0.01
95 94.95 0.05 94.80 0.20
200
5 5.20 0.20 4.60 0.40
30 29.99 0.01 29.99 0.01
50 49.73 0.27 50.18 0.18
70 70.01 0.01 70.01 0.01
95 94.95 0.05 94.80 0.20
Table 4.6 shows the result for the AG fault by using the single ended traveling wave
fault location method. The accuracy is same as the system without fault resistances.
Table 4.7: The Result for the L-L Fault with Different Resistances
Fault
Resistance
(Ω)
Actual Fault
Location
(km)
Voltage Signal Current Signal
Estimated
Fault
Location
(km)
Error (%)
Estimated
Fault
Location
(km)
Error (%)
1
5 5.20 0.20 4.60 0.40
30 29.99 0.01 29.99 0.01
50 49.73 0.27 50.18 0.18
70 70.07 0.07 70.07 0.07
95 95.01 0.01 95.31 0.31
10
5 5.20 0.20 4.60 0.40
30 29.99 0.01 29.99 0.01
50 49.73 0.27 50.18 0.18
70 70.07 0.07 70.07 0.07
95 95.01 0.01 95.31 0.31
71
Table 4.7 shows the result for the line to line fault by using the single ended traveling
wave fault location method. The accuracy is same as the system without fault
resistances.
Table 4.8: The Result for the L-L-G Fault with Different Resistances
Fault
Resistance
(Ω)
Actual Fault
Location
(km)
Voltage Signal Current Signal
Estimated
Fault
Location
(km)
Error (%)
Estimated
Fault
Location
(km)
Error (%)
Ron:1
Rg:1
5 5.20 0.20 4.60 0.40
30 29.99 0.01 29.99 0.01
50 49.73 0.27 50.18 0.18
70 70.07 0.07 70.07 0.07
95 95.01 0.01 95.31 0.31
Ron:1
Rg:200
5 5.20 0.20 4.60 0.40
30 29.99 0.01 29.99 0.01
50 49.73 0.27 50.18 0.18
70 70.07 0.07 70.07 0.07
95 95.01 0.01 95.31 0.31
Ron:10
Rg:1
5 5.20 0.20 4.60 0.40
30 29.99 0.01 29.99 0.01
50 49.73 0.27 50.18 0.18
70 70.07 0.07 70.07 0.07
95 95.01 0.01 95.31 0.31
Ron:10
Rg:200
5 5.20 0.20 4.60 0.40
30 29.99 0.01 29.99 0.01
72
50 49.73 0.27 50.18 0.18
70 70.07 0.07 70.07 0.07
95 95.01 0.01 95.31 0.31
Where Ron is the fault resistance; Rg is the ground resistance
Table 4.8 shows the result for the double line to ground fault by using the single ended
traveling wave fault location method. The accuracy is same as the system without fault
resistances.
Table 4.9: The Result for the Three Line to Ground Fault with Different Resistances
Fault
Resistance
(Ω)
Actual Fault
Location
(km)
Voltage Signal Current Signal
Estimated
Fault
Location
(km)
Error (%)
Estimated
Fault
Location
(km)
Error (%)
1
5 5.20 0.20 4.60 0.40
30 29.99 0.01 29.99 0.01
50 49.73 0.27 50.18 0.18
70 70.07 0.07 70.07 0.07
95 95.01 0.01 95.31 0.31
10
5 5.20 0.20 4.60 0.40
30 29.99 0.01 29.99 0.01
50 49.73 0.27 50.18 0.18
70 70.07 0.07 70.07 0.07
95 95.01 0.01 95.31 0.31
73
Table 4.9 shows the result for the three line to ground fault by using the single ended
traveling wave fault location method. The accuracy is same as the system without fault
resistances.
4.3 Transmission Line Length
In this section, the single ended traveling wave method is tested with different
transmission line lengths. Several AG faults are respectively simulated on the 200 km
and the 300 km transmission lines.
Table 4.10: Fault Location Estimation for A 200 KM 500 KV Line
Fault Location
(km)
Voltage Signal Current Signal
Estimation
(km)
Error (%) Estimation
(km)
Error (%)
5 5.20 0.10 4.60 0.20
10 10.10 0.05 10.10 0.05
15 15.14 0.07 15.29 0.15
95 95.01 0.01 95.76 0.38
100 100.21 0.10 99.62 0.19
105 104.99 0.01 104.99 0.01
185 184.86 0.07 185.01 0.01
190 189.90 0.05 190.50 0.25
195 194.80 0.10 195.40 0.20
Table 4.10 shows the fault location estimations for a 200 km transmission line.
Table 4.10 represents the single ended traveling wave fault location method is feasible
for the 200 km line.
74
Table 4.11: Fault Location Estimation for A 300 KM 500 KV Line
Fault Location
(km)
Voltage Signal Current Signal
Estimation
(km)
Error (%) Estimation
(km)
Error (%)
5 5.20 0.07 4.60 0.13
10 10.10 0.03 10.10 0.03
15 15.14 0.05 15.29 0.10
145 144.89 0.04 145.19 0.06
150 150.24 0.08 150.09 0.03
155 155.11 0.04 154.66 0.11
285 285.01 0.00 285.45 0.15
290 289.61 0.13 289.46 0.18
295 294.95 0.02 294.95 0.02
Table 4.11 shows the fault location estimations for a 300 km transmission line.
Table 4.11 represents the single ended traveling wave fault location method is feasible
for the 300 km line.
75
CHAPTER 5 CONCLUSION
The objective of this thesis is to present the single ended traveling wave fault
location method and to evaluate the performance of this method. Since the method is
based on the traveling wave, the fundamental theory and properties of the traveling
wave are introduced in this thesis. Using the traveling wave theory of transmission
line, the voltage and the current transient signals are translated into their modal
signals by Karrenbauer transformation. In addition, the traveling wave velocity and
fault type can be found by the Karrenbauer transformation. The modal signals are
transformed into the approximate coefficient and the detail coefficient by the wavelet
transform. The maxima modules of the detail coefficient are used to determine the
sample number of the peaks. Using the first two peaks sample number estimates the
fault location. In addition, the evaluation study presents that the single ended traveling
wave fault location method is applicable to all fault types, various fault resistances,
and different transmission line lengths.
76
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VITA
Author
Name: Jin Chang
Birthplace: Zhengzhou, Henan, China
Education
08/2010—05/2013
Bachelor of Engineering
Bachelor of Science in Electrical Engineering
University of Kentucky
Awards
Graduate Certificate of Power and Energy by Power and Energy Institute of
Kentucky. Spring 2014